I have an Angular form. The fields are validated using the ng-pattern attribute. I also have a reset button. I'm using the Ui.Utils Event Binder to handle the reset event like so:
<form name="searchForm" id="searchForm" ui-event="{reset: 'reset(searchForm)'}" ng-submit="search()">
<div>
<label>
Area Code
<input type="tel" name="areaCode" ng-model="areaCode" ng-pattern="/^([0-9]{3})?$/">
</label>
<div ng-messages="searchForm.areaCode.$error">
<div class="error" ng-message="pattern">The area code must be three digits</div>
</div>
</div>
<div>
<label>
Phone Number
<input type="tel" name="phoneNumber" ng-model="phoneNumber" ng-pattern="/^([0-9]{7})?$/">
</label>
<div ng-messages="searchForm.phoneNumber.$error">
<div class="error" ng-message="pattern">The phone number must be seven digits</div>
</div>
</div>
<br>
<div>
<button type="reset">Reset</button>
<button type="submit" ng-disabled="searchForm.$invalid">Search</button>
</div>
</form>
As you can see, when the form is reset it calls the reset method on the $scope. Here's what the entire controller looks like:
angular.module('app').controller('mainController', function($scope) {
$scope.resetCount = 0;
$scope.reset = function(form) {
form.$setPristine();
form.$setUntouched();
$scope.resetCount++;
};
$scope.search = function() {
alert('Searching');
};
});
I'm calling form.$setPristine() and form.$setUntouched, following the advice from another question here on Stack Overflow. The only reason I added the counter was to prove that the code is being called (which it is).
The problem is that even after reseting the form, the validation messages don't go away. You can see the full code on Plunker. Here's a screenshot showing that the errors don't go away:
I started with the comment from #Brett and built upon it. I actually have multiple forms and each form has many fields (more than just the two shown). So I wanted a general solution.
I noticed that the Angular form object has a property for each control (input, select, textarea, etc) as well as some other Angular properties. Each of the Angular properties, though, begins with a dollar sign ($). So I ended up doing this (including the comment for the benefit of other programmers):
$scope.reset = function(form) {
// Each control (input, select, textarea, etc) gets added as a property of the form.
// The form has other built-in properties as well. However it's easy to filter those out,
// because the Angular team has chosen to prefix each one with a dollar sign.
// So, we just avoid those properties that begin with a dollar sign.
let controlNames = Object.keys(form).filter(key => key.indexOf('$') !== 0);
// Set each control back to undefined. This is the only way to clear validation messages.
// Calling `form.$setPristine()` won't do it (even though you wish it would).
for (let name of controlNames) {
let control = form[name];
control.$setViewValue(undefined);
}
form.$setPristine();
form.$setUntouched();
};
$scope.search = {areaCode: xxxx, phoneNumber: yyyy}
Structure all models in your form in one place like above, so you can clear it like this:
$scope.search = angular.copy({});
After that you can just call this for reset the validation:
$scope.search_form.$setPristine();
$scope.search_form.$setUntouched();
$scope.search_form.$rollbackViewValue();
There doesn't seem to be an easy way to reset the $errors in angular. The best way would probably be to reload the current page to start with a new form. Alternatively you have to remove all $error manually with this script:
form.$setPristine(true);
form.$setUntouched(true);
// iterate over all from properties
angular.forEach(form, function(ctrl, name) {
// ignore angular fields and functions
if (name.indexOf('$') != 0) {
// iterate over all $errors for each field
angular.forEach(ctrl.$error, function(value, name) {
// reset validity
ctrl.$setValidity(name, null);
});
}
});
$scope.resetCount++;
You can add a validation flag and show or hide errors according to its value with ng-if or ng-show in your HTML. The form has a $valid flag you can send to your controller.
ng-if will remove or recreate the element to the DOM, while ng-show will add it but won't show it (depending on the flag value).
EDIT: As pointed by Michael, if form is disabled, the way I pointed won't work because the form is never submitted. Updated the code accordingly.
HTML
<form name="searchForm" id="searchForm" ui-event="{reset: 'reset(searchForm)'}" ng-submit="search()">
<div>
<label>
Area Code
<input type="tel" name="areaCode" ng-model="areaCode" ng-pattern="/^([0-9]{3})?$/">
</label>
<div ng-messages="searchForm.areaCode.$error">
<div class="error" ng-message="pattern" ng-if="searchForm.areaCode.$dirty">The area code must be three digits</div>
</div>
</div>
<div>
<label>
Phone Number
<input type="tel" name="phoneNumber" ng-model="phoneNumber" ng-pattern="/^([0-9]{7})?$/">
</label>
<div ng-messages="searchForm.phoneNumber.$error">
<div class="error" ng-message="pattern" ng-if="searchForm.phoneNumber.$dirty">The phone number must be seven digits</div>
</div>
</div>
<br>
<div>
<button type="reset">Reset</button>
<button type="submit" ng-disabled="searchForm.$invalid">Search</button>
</div>
</form>
JS
$scope.search = function() {
alert('Searching');
};
$scope.reset = function(form) {
form.$setPristine();
form.$setUntouched();
$scope.resetCount++;
};
Codepen with working solution: http://codepen.io/anon/pen/zGPZoB
It looks like I got to do the right behavior at reset. Unfortunately, using the standard reset failed. I also do not include the library ui-event. So my code is a little different from yours, but it does what you need.
<form name="searchForm" id="searchForm" ng-submit="search()">
pristine = {{searchForm.$pristine}} valid ={{searchForm.$valid}}
<div>
<label>
Area Code
<input type="tel" required name="areaCode" ng-model="obj.areaCode" ng-pattern="/^([0-9]{3})?$/" ng-model-options="{ allowInvalid: true }">
</label>
<div ng-messages="searchForm.areaCode.$error">
<div class="error" ng-message="pattern">The area code must be three digits</div>
<div class="error" ng-message="required">The area code is required</div>
</div>
</div>
<div>
<label>
Phone Number
<input type="tel" required name="phoneNumber" ng-model="obj.phoneNumber" ng-pattern="/^([0-9]{7})?$/" ng-model-options="{ allowInvalid: true }">
</label>
<div ng-messages="searchForm.phoneNumber.$error">
<div class="error" ng-message="pattern">The phone number must be seven digits</div>
<div class="error" ng-message="required">The phone number is required</div>
</div>
</div>
<br>
<div>
<button ng-click="reset(searchForm)" type="reset">Reset</button>
<button type="submit" ng-disabled="searchForm.$invalid">Search</button>
</div>
</form>
And JS:
$scope.resetCount = 0;
$scope.obj = {};
$scope.reset = function(form_) {
$scope.resetCount++;
$scope.obj = {};
form_.$setPristine();
form_.$setUntouched();
console.log($scope.resetCount);
};
$scope.search = function() {
alert('Searching');
};
Live example on jsfiddle.
Note the directive ng-model-options="{allowinvalid: true}". Use it necessarily, or until the entry field will not be valid, the model value is not recorded. Therefore, the reset will not operate.
P.S. Put value (areaCode, phoneNumber) on the object simplifies purification.
Following worked for me
let form = this.$scope.myForm;
let controlNames = Object.keys(form).filter(key => key.indexOf('$') !== 0);
for (let name of controlNames) {
let control = form [name];
control.$error = {};
}
In Short: to get rid of ng-messages errors you need to clear out the $error object for each form item.
further to #battmanz 's answer, but without using any ES6 syntax to support older browsers.
$scope.resetForm = function (form) {
try {
var controlNames = Object.keys(form).filter(function (key) { return key.indexOf('$') !== 0 });
console.log(controlNames);
for (var x = 0; x < controlNames.length; x++) {
form[controlNames[x]].$setViewValue(undefined);
}
form.$setPristine();
form.$setUntouched();
} catch (e) {
console.log('Error in Reset');
console.log(e);
}
};
I had the same problem and tried to do battmanz solution (accepted answer).
I'm pretty sure his answer is really good, but however for me it wasn't working.
I am using ng-model to bind data, and angular material library for the inputs and ng-message directives for error message , so maybe what I will say will be useful only for people using the same configuration.
I took a lot of look at the formController object in javascript, in fact there is a lot of $ angular function as battmanz noted, and there is in addition, your fields names, which are object with some functions in its fields.
So what is clearing your form ?
Usually I see a form as a json object, and all the fields are binded to a key of this json object.
//lets call here this json vm.form
vm.form = {};
//you should have something as ng-model = "vm.form.name" in your view
So at first to clear the form I just did callback of submiting form :
vm.form = {};
And as explained in this question, ng-messages won't disappear with that, that's really bad.
When I used battmanz solution as he wrote it, the messages didn't appear anymore, but the fields were not empty anymore after submiting, even if I wrote
vm.form = {};
And I found out it was normal, because using his solution actually remove the model binding from the form, because it sets all the fields to undefined.
So the text was still in the view because somehow there wan't any binding anymore and it decided to stay in the HTML.
So what did I do ?
Actually I just clear the field (setting the binding to {}), and used just
form.$setPristine();
form.$setUntouched();
Actually it seems logical, since the binding is still here, the values in the form are now empty, and angular ng-messages directive is triggering only if the form is not untouched, so I think it's normal after all.
Final (very simple) code is that :
function reset(form) {
form.$setPristine();
form.$setUntouched();
};
A big problem I encountered with that :
Only once, the callback seems to have fucked up somewhere, and somehow the fields weren't empty (it was like I didn't click on the submit button).
When I clicked again, the date sent was empty. That even more weird because my submit button is supposed to be disabled when a required field is not filled with the good pattern, and empty is certainly not a good one.
I don't know if my way of doing is the best or even correct, if you have any critic/suggestion or any though about the problem I encountered, please let me know, I always love to step up in angularJS.
Hope this will help someone and sorry for the bad english.
You can pass your loginForm object into the function ng-click="userCtrl.login(loginForm)
and in the function call
this.login = function (loginForm){
loginForm.$setPristine();
loginForm.$setUntouched();
}
So none of the answers were completely working for me. Esp, clearing the view value, so I combined all the answers clearing view value, clearing errors and clearing the selection with j query(provided the fields are input and name same as model name)
var modelNames = Object.keys($scope.form).filter(key => key.indexOf('$') !== 0);
modelNames.forEach(function(name){
var model = $scope.form[name];
model.$setViewValue(undefined);
jq('input[name='+name+']').val('');
angular.forEach(model.$error, function(value, name) {
// reset validity
model.$setValidity(name, null);
});
});
$scope.form.$setPristine();
$scope.form.$setUntouched();
I've got a load of checkboxes that are checked by default. My users will probably uncheck a few (if any) of the checkboxes and leave the rest checked.
Is there any way to make the form POST the checkboxes that are not checked, rather than the ones that are checked?
The solution I liked the most so far is to put a hidden input with the same name as the checkbox that might not be checked. I think it works so that if the checkbox isn't checked, the hidden input is still successful and sent to the server but if the checkbox is checked it will override the hidden input before it. This way you don't have to keep track of which values in the posted data were expected to come from checkboxes.
<form>
<input type='hidden' value='0' name='selfdestruct'>
<input type='checkbox' value='1' name='selfdestruct'>
</form>
Add a hidden input for the checkbox with a different ID:
<input id='testName' type='checkbox' value='Yes' name='testName'>
<input id='testNameHidden' type='hidden' value='No' name='testName'>
Before submitting the form, disable the hidden input based on the checked condition:
form.addEventListener('submit', () => {
if(document.getElementById("testName").checked) {
document.getElementById('testNameHidden').disabled = true;
}
}
I solved it by using vanilla JavaScript:
<input type="hidden" name="checkboxName" value="0"><input type="checkbox" onclick="this.previousSibling.value=1-this.previousSibling.value">
Be careful not to have any spaces or linebreaks between this two input elements!
You can use this.previousSibling.previousSibling to get "upper" elements.
With PHP you can check the named hidden field for 0 (not set) or 1 (set).
My personal favorite is to add a hidden field with the same name that will be used if the check-box is unchecked. But the solution is not as easy as it may seems.
If you add this code:
<form>
<input type='hidden' value='0' name='selfdestruct'>
<input type='checkbox' value='1' name='selfdestruct'>
</form>
The browser will not really care about what you do here. The browser will send both parameters to the server, and the server has to decide what to do with them.
PHP for example takes the last value as the one to use (see: Authoritative position of duplicate HTTP GET query keys)
But other systems I worked with (based on Java) do it the way around - they offer you only the first value.
.NET instead will give you an array with both elements instead
I'll try to test this with node.js, Python and Perl at sometime.
you don't need to create a hidden field for all checkboxes just copy my code.
it will change the value of checkbox if not checked the value will assign 0 and if checkbox checked then assign value into 1
$("form").submit(function () {
var this_master = $(this);
this_master.find('input[type="checkbox"]').each( function () {
var checkbox_this = $(this);
if( checkbox_this.is(":checked") == true ) {
checkbox_this.attr('value','1');
} else {
checkbox_this.prop('checked',true);
//DONT' ITS JUST CHECK THE CHECKBOX TO SUBMIT FORM DATA
checkbox_this.attr('value','0');
}
})
})
A common technique around this is to carry a hidden variable along with each checkbox.
<input type="checkbox" name="mycheckbox" />
<input type="hidden" name="mycheckbox.hidden"/>
On the server side, we first detect list of hidden variables and for each of the hidden variable, we try to see if the corresponding checkbox entry is submitted in the form data or not.
The server side algorithm would probably look like:
for input in form data such that input.name endswith .hidden
checkboxName = input.name.rstrip('.hidden')
if chceckbName is not in form, user has unchecked this checkbox
The above doesn't exactly answer the question, but provides an alternate means of achieving similar functionality.
I know this question is 3 years old but I found a solution that I think works pretty well.
You can do a check if the $_POST variable is assigned and save it in a variable.
$value = isset($_POST['checkboxname'] ? 'YES' : 'NO';
the isset() function checks if the $_POST variable is assigned. By logic if it is not assigned then the checkbox is not checked.
$('input[type=checkbox]').on("change",function(){
var target = $(this).parent().find('input[type=hidden]').val();
if(target == 0)
{
target = 1;
}
else
{
target = 0;
}
$(this).parent().find('input[type=hidden]').val(target);
});
<p>
<input type="checkbox" />
<input type="hidden" name="test_checkbox[]" value="0" />
</p>
<p>
<input type="checkbox" />
<input type="hidden" name="test_checkbox[]" value="0" />
</p>
<p>
<input type="checkbox" />
<input type="hidden" name="test_checkbox[]" value="0" />
</p>
If you leave out the name of the checkbox it doesn't get passed.
Only the test_checkbox array.
You can do some Javascript in the form's submit event. That's all you can do though, there's no way to get browsers to do this by themselves. It also means your form will break for users without Javascript.
Better is to know on the server which checkboxes there are, so you can deduce that those absent from the posted form values ($_POST in PHP) are unchecked.
I also like the solution that you just post an extra input field, using JavaScript seems a little hacky to me.
Depending on what you use for you backend will depend on which input goes first.
For a server backend where the first occurrence is used (JSP) you should do the following.
<input type="checkbox" value="1" name="checkbox_1"/>
<input type="hidden" value="0" name="checkbox_1"/>
For a server backend where the last occurrence is used (PHP,Rails) you should do the following.
<input type="hidden" value="0" name="checkbox_1"/>
<input type="checkbox" value="1" name="checkbox_1"/>
For a server backend where all occurrences are stored in a list data type ([],array). (Python / Zope)
You can post in which ever order you like, you just need to try to get the value from the input with the checkbox type attribute. So the first index of the list if the checkbox was before the hidden element and the last index if the checkbox was after the hidden element.
For a server backend where all occurrences are concatenated with a comma (ASP.NET / IIS)
You will need to (split/explode) the string by using a comma as a delimiter to create a list data type. ([])
Now you can attempt to grab the first index of the list if the checkbox was before the hidden element and grab the last index if the checkbox was after the hidden element.
image source
I would actually do the following.
Have my hidden input field with the same name with the checkbox input
<input type="hidden" name="checkbox_name[]" value="0" />
<input type="checkbox" name="checkbox_name[]" value="1" />
and then when i post I first of all remove the duplicate values picked up in the $_POST array, atfer that display each of the unique values.
$posted = array_unique($_POST['checkbox_name']);
foreach($posted as $value){
print $value;
}
I got this from a post remove duplicate values from array
"I've gone with the server approach. Seems to work fine - thanks. – reach4thelasers Dec 1 '09 at 15:19" I would like to recommend it from the owner. As quoted: javascript solution depends on how the server handler (I didn't check it)
such as
if(!isset($_POST["checkbox"]) or empty($_POST["checkbox"])) $_POST["checkbox"]="something";
Most of the answers here require the use of JavaScript or duplicate input controls. Sometimes this needs to be handled entirely on the server-side.
I believe the (intended) key to solving this common problem is the form's submission input control.
To interpret and handle unchecked values for checkboxes successfully you need to have knowledge of the following:
The names of the checkboxes
The name of the form's submission input element
By checking whether the form was submitted (a value is assigned to the submission input element), any unchecked checkbox values can be assumed.
For example:
<form name="form" method="post">
<input name="value1" type="checkbox" value="1">Checkbox One<br/>
<input name="value2" type="checkbox" value="1" checked="checked">Checkbox Two<br/>
<input name="value3" type="checkbox" value="1">Checkbox Three<br/>
<input name="submit" type="submit" value="Submit">
</form>
When using PHP, it's fairly trivial to detect which checkboxes were ticked.
<?php
$checkboxNames = array('value1', 'value2', 'value3');
// Persisted (previous) checkbox state may be loaded
// from storage, such as the user's session or a database.
$checkboxesThatAreChecked = array();
// Only process if the form was actually submitted.
// This provides an opportunity to update the user's
// session data, or to persist the new state of the data.
if (!empty($_POST['submit'])) {
foreach ($checkboxNames as $checkboxName) {
if (!empty($_POST[$checkboxName])) {
$checkboxesThatAreChecked[] = $checkboxName;
}
}
// The new state of the checkboxes can be persisted
// in session or database by inspecting the values
// in $checkboxesThatAreChecked.
print_r($checkboxesThatAreChecked);
}
?>
Initial data could be loaded on each page load, but should be only modified if the form was submitted. Since the names of the checkboxes are known beforehand, they can be traversed and inspected individually, so that the the absence of their individual values indicates that they are not checked.
I've tried Sam's version first.
Good idea, but it causes there to be multiple elements in the form with the same name. If you use any javascript that finds elements based on name, it will now return an array of elements.
I've worked out Shailesh's idea in PHP, it works for me.
Here's my code:
/* Delete '.hidden' fields if the original is present, use '.hidden' value if not. */
foreach ($_POST['frmmain'] as $field_name => $value)
{
// Only look at elements ending with '.hidden'
if ( !substr($field_name, -strlen('.hidden')) ) {
break;
}
// get the name without '.hidden'
$real_name = substr($key, strlen($field_name) - strlen('.hidden'));
// Create a 'fake' original field with the value in '.hidden' if an original does not exist
if ( !array_key_exists( $real_name, $POST_copy ) ) {
$_POST[$real_name] = $value;
}
// Delete the '.hidden' element
unset($_POST[$field_name]);
}
You can also intercept the form.submit event and reverse check before submit
$('form').submit(function(event){
$('input[type=checkbox]').prop('checked', function(index, value){
return !value;
});
});
I use this block of jQuery, which will add a hidden input at submit-time to every unchecked checkbox. It will guarantee you always get a value submitted for every checkbox, every time, without cluttering up your markup and risking forgetting to do it on a checkbox you add later. It's also agnostic to whatever backend stack (PHP, Ruby, etc.) you're using.
// Add an event listener on #form's submit action...
$("#form").submit(
function() {
// For each unchecked checkbox on the form...
$(this).find($("input:checkbox:not(:checked)")).each(
// Create a hidden field with the same name as the checkbox and a value of 0
// You could just as easily use "off", "false", or whatever you want to get
// when the checkbox is empty.
function(index) {
var input = $('<input />');
input.attr('type', 'hidden');
input.attr('name', $(this).attr("name")); // Same name as the checkbox
input.attr('value', "0"); // or 'off', 'false', 'no', whatever
// append it to the form the checkbox is in just as it's being submitted
var form = $(this)[0].form;
$(form).append(input);
} // end function inside each()
); // end each() argument list
return true; // Don't abort the form submit
} // end function inside submit()
); // end submit() argument list
$('form').submit(function () {
$(this).find('input[type="checkbox"]').each( function () {
var checkbox = $(this);
if( checkbox.is(':checked')) {
checkbox.attr('value','1');
} else {
checkbox.after().append(checkbox.clone().attr({type:'hidden', value:0}));
checkbox.prop('disabled', true);
}
})
});
I see this question is old and has so many answers, but I'll give my penny anyway.
My vote is for the javascript solution on the form's 'submit' event, as some has pointed out. No doubling the inputs (especially if you have long names and attributes with php code mixed with html), no server side bother (that would require to know all field names and to check them down one by one), just fetch all the unchecked items, assign them a 0 value (or whatever you need to indicate a 'not checked' status) and then change their attribute 'checked' to true
$('form').submit(function(e){
var b = $("input:checkbox:not(:checked)");
$(b).each(function () {
$(this).val(0); //Set whatever value you need for 'not checked'
$(this).attr("checked", true);
});
return true;
});
this way you will have a $_POST array like this:
Array
(
[field1] => 1
[field2] => 0
)
What I did was a bit different. First I changed the values of all the unchecked checkboxes. To "0", then selected them all, so the value would be submitted.
function checkboxvalues(){
$("#checkbox-container input:checkbox").each(function({
if($(this).prop("checked")!=true){
$(this).val("0");
$(this).prop("checked", true);
}
});
}
I would prefer collate the $_POST
if (!$_POST['checkboxname']) !$_POST['checkboxname'] = 0;
it minds, if the POST doesn't have have the 'checkboxname'value, it was unckecked so, asign a value.
you can create an array of your ckeckbox values and create a function that check if values exist, if doesn`t, it minds that are unchecked and you can asign a value
Might look silly, but it works for me. The main drawback is that visually is a radio button, not a checkbox, but it work without any javascript.
HTML
Initialy checked
<span><!-- set the check attribute for the one that represents the initial value-->
<input type="radio" name="a" value="1" checked>
<input type="radio" name="a" value="0">
</span>
<br/>
Initialy unchecked
<span><!-- set the check attribute for the one that represents the initial value-->
<input type="radio" name="b" value="1">
<input type="radio" name="b" value="0" checked>
</span>
and CSS
span input
{position: absolute; opacity: 0.99}
span input:checked
{z-index: -10;}
span input[value="0"]
{opacity: 0;}
fiddle here
I'd like to hear any problems you find with this code, cause I use it in production
The easiest solution is a "dummy" checkbox plus hidden input if you are using jquery:
<input id="id" type="hidden" name="name" value="1/0">
<input onchange="$('#id').val(this.checked?1:0)" type="checkbox" id="dummy-id"
name="dummy-name" value="1/0" checked="checked/blank">
Set the value to the current 1/0 value to start with for BOTH inputs, and checked=checked if 1. The input field (active) will now always be posted as 1 or 0. Also the checkbox can be clicked more than once before submission and still work correctly.
Example on Ajax actions is(':checked') used jQuery instead of .val();
var params = {
books: $('input#users').is(':checked'),
news : $('input#news').is(':checked'),
magazine : $('input#magazine').is(':checked')
};
params will get value in TRUE OR FALSE..
Checkboxes usually represent binary data that are stored in database as Yes/No, Y/N or 1/0 values. HTML checkboxes do have bad nature to send value to server only if checkbox is checked! That means that server script on other site must know in advance what are all possible checkboxes on web page in order to be able to store positive (checked) or negative (unchecked) values. Actually only negative values are problem (when user unchecks previously (pre)checked value - how can server know this when nothing is sent if it does not know in advance that this name should be sent). If you have a server side script which dynamically creates UPDATE script there's a problem because you don't know what all checkboxes should be received in order to set Y value for checked and N value for unchecked (not received) ones.
Since I store values 'Y' and 'N' in my database and represent them via checked and unchecked checkboxes on page, I added hidden field for each value (checkbox) with 'Y' and 'N' values then use checkboxes just for visual representation, and use simple JavaScript function check() to set value of if according to selection.
<input type="hidden" id="N1" name="N1" value="Y" />
<input type="checkbox"<?php if($N1==='Y') echo ' checked="checked"'; ?> onclick="check(this);" />
<label for="N1">Checkbox #1</label>
use one JavaScript onclick listener and call function check() for each checkboxe on my web page:
function check(me)
{
if(me.checked)
{
me.previousSibling.previousSibling.value='Y';
}
else
{
me.previousSibling.previousSibling.value='N';
}
}
This way 'Y' or 'N' values are always sent to server side script, it knows what are fields that should be updated and there's no need for conversion of checbox "on" value into 'Y' or not received checkbox into 'N'.
NOTE: white space or new line is also a sibling so here I need .previousSibling.previousSibling.value. If there's no space between then only .previousSibling.value
You don't need to explicitly add onclick listener like before, you can use jQuery library to dynamically add click listener with function to change value to all checkboxes in your page:
$('input[type=checkbox]').click(function()
{
if(this.checked)
{
$(this).prev().val('Y');
}
else
{
$(this).prev().val('N');
}
});
#cpburnz got it right but to much code, here is the same idea using less code:
JS:
// jQuery OnLoad
$(function(){
// Listen to input type checkbox on change event
$("input[type=checkbox]").change(function(){
$(this).parent().find('input[type=hidden]').val((this.checked)?1:0);
});
});
HTML (note the field name using an array name):
<div>
<input type="checkbox" checked="checked">
<input type="hidden" name="field_name[34]" value="1"/>
</div>
<div>
<input type="checkbox">
<input type="hidden" name="field_name[35]" value="0"/>
</div>
<div>
And for PHP:
<div>
<input type="checkbox"<?=($boolean)?' checked="checked"':''?>>
<input type="hidden" name="field_name[<?=$item_id?>]" value="<?=($boolean)?1:0?>"/>
</div>
All answers are great, but if you have multiple checkboxes in a form with the same name and you want to post the status of each checkbox. Then i have solved this problem by placing a hidden field with the checkbox (name related to what i want).
<input type="hidden" class="checkbox_handler" name="is_admin[]" value="0" />
<input type="checkbox" name="is_admin_ck[]" value="1" />
then control the change status of checkbox by below jquery code:
$(documen).on("change", "input[type='checkbox']", function() {
var checkbox_val = ( this.checked ) ? 1 : 0;
$(this).siblings('input.checkbox_handler').val(checkbox_val);
});
now on change of any checkbox, it will change the value of related hidden field. And on server you can look only to hidden fields instead of checkboxes.
Hope this will help someone have this type of problem. cheer :)
You can add hidden elements before submitting form.
$('form').submit(function() {
$(this).find('input[type=checkbox]').each(function (i, el) {
if(!el.checked) {
var hidden_el = $(el).clone();
hidden_el[0].checked = true;
hidden_el[0].value = '0';
hidden_el[0].type = 'hidden'
hidden_el.insertAfter($(el));
}
})
});
The problem with checkboxes is that if they are not checked then they are not posted with your form. If you check a checkbox and post a form you will get the value of the checkbox in the $_POST variable which you can use to process a form, if it's unchecked no value will be added to the $_POST variable.
In PHP you would normally get around this problem by doing an isset() check on your checkbox element. If the element you are expecting isn't set in the $_POST variable then we know that the checkbox is not checked and the value can be false.
if(!isset($_POST['checkbox1']))
{
$checkboxValue = false;
} else {
$checkboxValue = $_POST['checkbox1'];
}
But if you have created a dynamic form then you won't always know the name attribute of your checkboxes, if you don't know the name of the checkbox then you can't use the isset function to check if this has been sent with the $_POST variable.
function SubmitCheckBox(obj) {
obj.value = obj.checked ? "on" : "off";
obj.checked = true;
return obj.form.submit();
}
<input type=checkbox name="foo" onChange="return SubmitCheckBox(this);">
If you want to submit an array of checkbox values (including un-checked items) then you could try something like this:
<form>
<input type="hidden" value="0" name="your_checkbox_array[]"><input type="checkbox">Dog
<input type="hidden" value="0" name="your_checkbox_array[]"><input type="checkbox">Cat
</form>
$('form').submit(function(){
$('input[type="checkbox"]:checked').prev().val(1);
});