I am trying to fetch the count of records entered in each month of the financial year
For example, I have declared a column called issue in varchar because the data what I am taking is issues of the particular machine. And for example, let's say one issue is raised in July month I enter the data as 'Jul 19-1' and the again issue is raised in the month of September again I go back to the issue happened in July and enter the data as 'sep19-2'.
So in the backend, it takes as jul19-1 sep19-2
What can be the query that I can write for counting the number of issues raised in each month
I tried the below query but
SELECT COUNT(month_nc)
FROM `ncr`
WHERE month_nc='Jul18-1'
In some months there will be only one issue so I can the count of the month given in the above query
What will be the query if I want to fetch the count of each month
id issue issue_month
1 bearing jul18-1
sep18-2
2 motor jul18-2
3 battery apr18-3
ps: issue_month is declared in varchar(10)
Here are two methods. One using strings:
select left(issue_month, 5), count(*)
from t
group by left(issue_month, 5), count(*)
This will not order the values correctly.
You can convert to a date to order properly:
order by str_to_date(concat('01', left(issue_month, 5)), '%d%b%y')
Or, represent the dates correctly:
select str_to_date(concat('01', left(issue_month, 5)), '%d%b%y') as yyyymm, count(*)
from t
group by yyyymm
order by yyyymm;
Here is what you can do to split your issue_month into "month_year" and "issue_count"
yourTable
select id,
issue,
issue_month,
REGEXP_SUBSTR(issue_month, '[^-]+', 1) as month_year,
REGEXP_SUBSTR(issue_month, '[^-]+', 1,2 ) as issue_count
from yourTable;
Now you can aggregate the issue_count across issues or year_months or any other field in your table.
For example, to get the sum of all the issues for any given month_year
select
month_year,
sum(issue_count) issue_count
from
(select
id, issue, issue_month,
REGEXP_SUBSTR(issue_month, '[^-]+', 1) as month_year,
REGEXP_SUBSTR(issue_month, '[^-]+', 1,2 ) as issue_count
from yourTable) foo
group by month_year;
I have a "transaction" table that has the following columns
ID TIMESTAMP USER ID DESCRIPTION AMOUNT REF_ID TYPE
The description column contains the payment platform used for example "STRIPE-ch_1745". We currently have 4 platforms all described in the reference as in the example above. What I want is to get the payment platform, the total amount processed by the platform and the count of transactions. Like this
Platform Amount Count
Stripe 100,000 78
iOS 78,000 50
My current code only gives me these values for one platform, I've been unable to structure this properly to give me the desired result. I assumed I needed nested select statements, so I wrote the code in that manner
SELECT txn_count, sum
FROM
(SELECT count(*) AS txn_count, sum(`transaction`.`amount`) AS `sum`
FROM `transaction`
WHERE (`transaction`.`type` = 'credit'
AND (`transaction`.`description` like 'stripe%')
AND str_to_date(concat(date_format(`transaction`.`timestamp`, '%Y-%m'), '-01'), '%Y-%m-%d') = str_to_date(concat(date_format(now(), '%Y-%m'), '-01'), '%Y-%m-%d'))) t1
What this gives me right now is
Txn Count Sum
311 501,000
Would appreciate some help on how to get the expected table
Try this : ( edited to remove the reference part, assuming the reference is always separated by the platform by '-' )
SELECT
LEFT(t.description,LOCATE('-',t.description) - 1) as 'Platform',
SUM(t.amount) as 'Amount',
COUNT(*) as 'Count'
FROM transaction t
GROUP BY Platform
My Boss want to know how many times each of these shipping number of days occurred. Ordered by number of days DESC.
So far have :
SELECT DateDiff(shippedDate,orderDate) As '#Days', COUNT(*)
FROM datenumtest
I think I need condition, can someone help me out with this?
Calculate the DateDiff across all records first in a data set r, then you can do the grouping on that data set which becomes data set r1 then sort the r1 data set:
select r.NumDays, count(1) as the_count
from (
SELECT DateDiff(shippedDate,orderDate) as 'NumDays'
FROM datenumtest
) r
group by r.NumDays
order by r.NumDays desc;
We have a statistics database of which we would like to group some results. Every entry has a timestamp 'tstarted'.
We would like to group by every quarter of the day. For each quarter, we would like to know the day count where we have > 0 results (for that quarter).
We could resolve this by using a subquery:
select quarter, sum(q), count(quarter), sum(q) / count(quarter) as average
from (
select SEC_TO_TIME((TIME_TO_SEC(tstarted) DIV 900) * 900) as quarter, sum(qdelivered) as q
from statistics
where stat_field = 1
group by SEC_TO_TIME((TIME_TO_SEC(tstarted) DIV 900) * 900), date(tstarted)
order by SEC_TO_TIME((TIME_TO_SEC(tstarted) DIV 900) * 900) asc
) as sub
group by quarter
My question: is there a more efficient way to retrieve this result (e.g. join or other way)?
Efficiency could be improved by eliminating the inline view (derived table aliased as sub), and doing all the work in a single query. (This is because of the way that MySQL processes the inline view, creating and populating a temporary MyISAM table.)
I don't understand why the expression date(tstarted) needs to be included in the GROUP BY clause; I don't see that removing that would change the result set returned by the query.
I do now see the effect of including the date(tstarted) in the GROUP BY of the inline view query.
I think this query returns the same result as the original:
SELECT SEC_TO_TIME((TIME_TO_SEC(s.tstarted) DIV 900) * 900) AS `quarter`
, SUM(s.qdelivered) AS `q`
, COUNT(DISTINCT DATE(s.tstarted)) AS `day_count`
, SUM(s.qdelivered) / COUNT(DISTINCT DATE(s.tstarted)) AS `average`
FROM statistics s
WHERE s.stat_field = 1
GROUP BY SEC_TO_TIME((TIME_TO_SEC(s.tstarted) DIV 900) * 900)
This should be more efficient since it avoids materializing an intermediate derived table.
Your question said you wanted a "day count"; that sounds like you want a count of the each day that had a row within a particular quarter hour.
To get that, you could just add an aggregate expression to the SELECT list,
, COUNT(DISTINCT DATE(s.tstarted)) AS `day_count`
I would be tempted to set up a table of quarters in the day. Use this table and LEFT JOIN your statistics table it.
CREATE TABLE quarters
(
id INT,
start_qtr INT,
end_qtr INT
);
INSERT INTO quarters (id, start_qtr, end_qtr) VALUES
(1,0,899),
(2,900,1799),
(3,1800,2699),
(4,2700,3599),
(5,3600,4499),
(6,4500,5399),
(7,5400,6299),
(8,6300,7199),
etc;
Your query can then be:-
SELECT SEC_TO_TIME(quarters.start_qtr) AS quarter,
sum(statistics.qdelivered),
count(statistics.qdelivered),
sum(statistics.qdelivered) / count(statistics.qdelivered) as average
FROM quarters
LEFT OUTER JOIN statistics
ON TIME_TO_SEC(statistics.tstarted) BETWEEN quarters.start_qtr AND quarters.end_qtr
AND statistics.stat_field = 1
AND DATE(statistics.tstarted) = '2014-06-30'
GROUP BY quarter
ORDER BY quarter;
Advantage of this is that it will give you entries with a count of 0 (and an average of NULL) for quarters where there are no statistics, and it saves some of the calculations.
You could save more calculations by adding time columns to the quarters table:-
CREATE TABLE quarters
(
id INT,
start_qtr INT,
end_qtr INT
start_qtr_time TIME,
end_qtr_time TIME,
);
INSERT INTO quarters (id, start_qtr, end_qtr, start_qtr_time, end_qtr_time) VALUES
(1,0,899, '00:00:00', '00:14:59'),
(2,900,1799, '00:15:00', '00:29:59'),
(3,1800,2699, '00:30:00', '00:44:59'),
(4,2700,3599, '00:45:00', '00:59:59'),
(5,3600,4499, '01:00:00', '01:14:59'),
(6,4500,5399, '01:15:00', '01:29:59'),
(7,5400,6299, '01:30:00', '01:44:59'),
(8,6300,7199, '01:45:00', '01:59:59'),
etc
Then this saves the use of a function on the JOIN:-
SELECT start_qtr_time AS quarter,
sum(statistics.qdelivered),
count(statistics.qdelivered),
sum(statistics.qdelivered) / count(statistics.qdelivered) as average
FROM quarters
LEFT OUTER JOIN statistics
ON TIME(statistics.tstarted) BETWEEN quarters.start_qtr_time AND quarters.end_qtr_time
AND statistics.stat_field = 1
AND DATE(statistics.tstarted) = '2014-06-30'
GROUP BY quarter
ORDER BY quarter;
These both assume you are interested in a particular day.
I have a table name invoices. There is a column named user and late_fee. I am trying to find out the percentage of late invoices compared to how many invoices total.
He has 16 invoices, which 2 of those invoices are late. I feel like this should be an easy pie query but I can't figure it out for the life of me?
You could use something like this. It gets the count of the late_fee depending on it's value.
select sum( case
when late_fee = 1
then 1
else 0
end
)
/ count(*)
from invoices
group
by user
As #Ravinder pointed out, in MySQL this is also valid (does not work on other platforms though):
select sum( late_fee = 1
)
/ count(*)
from invoices
group
by user