pygame know when I am in the X range and Y range - pygame

Question

I was making a game and now I want to see how could pygame know that I am in x of player and y of player.
I have to break in safe, to do that I must stand where it is and stay there for 3 seconds.
problem is even that I managed to alert pygame that I am in area where safe is,
is how could pygame know that I am in safe for 3 sec.
This is non-optimal:
import time
now = time.time()
future = now + 3
while future > now:
#IT DOESNT WORK WELL IN WHILE LOOP TO ALERT YA,
Is there a better solution?

Answer 1

What you could do to "alert" pygame/your code is you could use if statements if your using non-OOP and all you have is a list of coordinates for your player location, or if you do have an object for your player you could pygame.sprite.Sprite as a super class. Here's the solution if your using a coordinate list and not a big class.
loc = [x, y] # Don't run this because it won't understand what x and y are. This is just an example
safe_rect = ( x , y , w , h ) # Using tuple because I assume that the safe doesn't move
while True:
if loc[0] >= safe_rect[0] and # The newlines are for readability
loc[0] < safe_rect[0] + safe_rect[2] and
loc[1] >= safe_rect[1] and
loc[1] < safe_rect[1] + safe_rect[3]:
not_yet_existent_do_something_function() # Performs statements once inside the safe
If you want to include a timer, do this:
import time
loc = [x, y]
safe_rect = ( x , y , w , h )
# Time variables
time = time.time()
time_wanted = time + 3 # 3 seconds after the time is assigned to time
while True:
if loc[0] >= safe_rect[0] and
loc[0] < safe_rect[0] + safe_rect[2] and
loc[1] >= safe_rect[1] and
loc[1] < safe_rect[1] + safe_rect[3]:
if time.time() > time_wanted:
not_yet_existent_do_something_function()
I hope this works for you, if you have a question about what I did please ask me.