I'm writing a PHP program and wanna to implement row-level locking to avoid concurrent user update/delete for the same record.
But I hit error "Unrecognised keyword" when using SELECT FOR UPDATE. Table type is innoDB.
Am i missing any setup for my database?
SELECT * FROM companyTable
WHERE companyId = "0000001"
FOR UPDATE;
Error
Static analysis:
1 errors were found during analysis.
Unrecognized keyword. (near "FOR" at position 57)
SQL query: Documentation
SELECT * FROM companyTable WHERE companyId = "0000001" FOR LIMIT 0, 30
MySQL said: Documentation
#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'LIMIT 0, 30' at line 3
There Is an Syntax Error Try this:
Its Select All Records From 1 - 30
SELECT * FROM companyTable WHERE companyId = "0000001" ORDER BY id LIMIT 30;
First problem seems to be, that in your SQL query is missing keyword UPDATE
SELECT * FROM companyTable WHERE companyId = "0000001" FOR LIMIT 0, 30
And the second issue can be, that syntax SELECT ... FOR UPDATE in MySQL doesn't support LIMIT.
So your SQL query should be:
SELECT * FROM companyTable WHERE companyId = "0000001" FOR UPDATE
In phpmyadmin, it is difficult to remove auto added LIMIT clause - try another MySQL client.
PhpMyAdmin is not build to handle(Test) transaction control, use Mysql Console or php session instead
and use "begin" to start the Transaction before the code
begin;
select * from `tblx` where `idx`=1 for update;
update `tblx` set `field`='xx' where `idx`=1;
commit;
Related
With MySQL 5 this query worked without any issue:
SELECT 1+COUNT(*) AS rank
FROM userpoints
WHERE points > COALESCE((SELECT points FROM userpoints WHERE userid=(SELECT userid FROM users WHERE handle='abc123' LIMIT 1)), 0)
With MySQL 8.0.23 it throws an error:
MySQL query error 1064: You have an error in your SQL syntax
Is it not allowed to "embed" SELECTs into other SELECTs anymore? See the userid=(SELECT... part.
Or is it a problem with COALESCE?
I am trying to Update Some row in my database. If I run without limit its working fine but if I run it with limit its giving me error like below
1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '35' at line 1
My Query is like below
UPDATE number_list SET sync = 0 WHERE server = 1 ORDER by id ASC LIMIT 0,35
Let me know if someone can correct me.
You can use limit in an update (in MySQL) but not an offset. So just do:
UPDATE number_list
SET sync = 0
WHERE server = 1
ORDER by id ASC
LIMIT 35;
This is a bit subtle, because SELECT supports offsets. However, it is clear in the syntax diagram for UPDATE.
SELECT * FROM customers WHERE Age > ALL (SELECT Age FROM customers WHERE Salary > 6800);
Actually I am trying to learn the usage of ALL in SQL. But unfortunately when I am trying to execute this query it's giving me the error in XAMPP.
Static analysis:
2 errors were found during analysis.
Unrecognized keyword. (near "ALL" at position 36) Unexpected token.
(near "(" at position 40) SQL query: Documentation
SELECT * FROM customers WHERE Age > ALL ( LIMIT 0, 25
MySQL said: Documentation
1064 - You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use
near 'LIMIT 0, 25' at line 1
I would like to know what is the exact syntactical error in my query.
Here's my Table:
Customer Table
There is nothing syntactically wrong with your query, you have an unfortunate version of phpMyAdmin which messes it up. The problem was present in 4.5.1, not present in 4.6.4, it was fixed some time in between.
This is the query that you send (OK):
SELECT * FROM customers WHERE Age > ALL (SELECT Age FROM customers WHERE Salary > 6800);
This is the query that server receives from phpMyAdmin (very wrong):
SELECT * FROM customers WHERE Age > ALL ( LIMIT 0, 25
Hence the problem.
I have such sql-query:
DELETE `LINK_LA_TYP`
FROM
`LINK_LA_TYP`
JOIN `LINK_ART` ON `LINK_LA_TYP`.LAT_LA_ID = `LINK_ART`.LA_ID
JOIN `ARTICLES` ON `LINK_ART`.LA_ART_ID = `ARTICLES`.ART_ID
WHERE
(
`ARTICLES`.ART_SUP_ID IN(
10008,
10439,
11005,
...
...
441
)
)
LIMIT 50000;
But i get error.... From mysql-doc i get that with delete+join+limit i will get errors....
But how can i change my code? (new to mysql and sql in all). How to change my code? To limit rows to delete....
Also in phpmyadmin i get
1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use
near 'limit 50' at line 1
From the docs For the multiple-table syntax, DELETE deletes from each tbl_name the rows that satisfy the conditions. In this case, ORDER BY and LIMIT cannot be used. dev.mysql.com/doc/refman/5.0/en/delete.html – Michael Berkowski 2 mins ago
I concur with this. Additionally,
The DELETE command cannot have a LIMIT clause. Also, generally speaking you cannot DELETE from multiple JOINed tables.
It MIGHT be possible to rewrite the statement using a subselect something like:
delete from LINK_LA_TYP
where LAT_LA_ID in
(select LA_ID
from LINK_ART
join ARTICLES on ARTICLES.ART_ID = LINK_ART.LA_ART_ID
where ARTICLES.ART_SUP_ID in (...));
I tried this with MySQL:
DELETE FROM `contact_hostcommands_relation` AS `ContactHostCommand` WHERE (`ContactHostCommand`.`chr_id` = 999999) LIMIT 1
And I get this:
#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'WHERE (`ContactHostCommand`.`chr_id` = 999999) LIMIT 1' at line 1
Note: This query is automatically generated and conditions are based on table aliases.
Why I get this error?
Is there any way to use table aliases in where clause?
Is this MySQL specific?
What #Matus and #CeesTimmerman said about MSSQL, works in MySQL 5.1.73 too:
delete <alias> from <table> <alias> where <alias>.<field>...
You can use SQL like this:
DELETE FROM ContactHostCommand
USING `contact_hostcommands_relation` AS ContactHostCommand
WHERE (ContactHostCommand.`chr_id` = 999999)
LIMIT 1
You cannot use AS in a DELETE clause with MySQL :
DELETE FROM `contact_hostcommands_relation` WHERE (`chr_id` = 999999) LIMIT 1