I have a table like the following with 1 and null value by year. I need to count the consecutive max count per Id, in an Access query. I am not good in VBA so trying to get it done in Access query.
ID 2001 2002 2004 2005 2006 2007
101 1 1 1 1
102 1 1 1 1 1
103 1
104 1 1 1 1 1
105 1 1 1 1 1 1
106 1 1 1
Could be, though not sure what "max count" could mean:
Select
ID,
Nz([2001],0)+Nz([2002],0)+Nz([2003],0)+Nz([2004],0)+Nz([2005],0)+Nz([2006],0)+Nz([2007],0) As YearCount
From
YourTable
For three consecutive years:
Select
ID,
([2001]+[2002]+[2003] Is Not Null) Or
([2002]+[2003]+[2004] Is Not Null) Or
([2003]+[2004]+[2005] Is Not Null) Or
([2004]+[2005]+[2006] Is Not Null) Or
([2005]+[2006]+[2007] Is Not Null) As Count3
From
YourTable
And/or:
Select
ID,
([2001]+[2002]+[2003] Is Not Null) As [2001-2003],
([2002]+[2003]+[2004] Is Not Null) As [2002-2004],
([2003]+[2004]+[2005] Is Not Null) As [2003-2005],
([2004]+[2005]+[2006] Is Not Null) As [2004-2006],
([2005]+[2006]+[2007] Is Not Null) As [2005-2007]
From
YourTable
Related
I have two tables to join in SQL using the ID column in both. Table 1 has only unique values of ID as follows and I want to keep all columns of this table:
ID code 1 code 2
1 123 99
2 222 09
3 344 13
Table 2 has multiple rows of each ID as follows:
ID application_time Application Number
1 11jan2004 123
2 15oct2010 124
1 24nov2008 845
3 05sep2010 166
1 07feb2001 865
2 24aug2017 545
3 12mar2009 233
2 11dec2001 811
So, from table 2, I want to add the total count of each ID, and Min and Max of Application_time to table 1. I also need to count the number Application Numbers that start with 8. of I do not know where I should use group by (). So the outcome should look like:
ID code 1 code 2 count Min (application_time) Max (application_time)
1 123 99 3 07feb2001 24nov2008
2 222 09 3 11dec2001 24aug2017
3 344 13 2 12mar2009 05sep2010
Count of Application Number starting with 8
2
1
0
here is how you can do it:
select
t1.Id
,t1.code1
,t1.code2
, count(*) count
,min(application_time)
,max(application_time)
, sum( case when left( t2.application number, 1 ) = '8' then 1 else 0 end )
from table1 t1
join table2 t2
on t1.Id = t2.Id
group by
t1.Id
,t1.code1
,t1.code2
Below is my database table, where I will have Check In and Check Out entry records for attending the conference room.
id registration_id roomno day type
1 101 1 2 In
2 103 1 2 In
3 101 1 2 Out
4 105 1 2 In
5 103 1 2 Out
6 101 1 2 In
7 103 1 2 In
8 101 1 2 Out
9 105 1 2 In
10 103 1 2 Out
Now, I want to select those records, which are still attending the conference. Condition is like their last record should be type = In. There can be multiple In/Out entries for each user during a day.
Please let me know the quickest possible MySQL query.
Thanks
Answer which I ended up using:
select * from `registrations_inouts` t
group by t.registration_id
having max(id) = max(case when type = 'In' then id end)
order by rand() limit 1;
Here is one method using not exists:
select *
from t
where t.type = 'In' and
not exists (select 1
from t t2
where t2.registration_id = t.registration_id and t2.type = 'Out'
);
Another method uses conditional aggregation:
select t.registration_id
from t
group by t.registration_id
having max(id) = max(case when type = 'In' then id end);
Note: both of these assume that the ids are assigned sequentially in time, so larger ids are later in time.
I have this table in MYSQL:
Year Type Value ID
0 0 5 1
2010 1 6 1
2011 1 4 1
2012 1 5 1
2013 1 7 1
2014 1 8 1
2015 1 5 1
0 0 6 2
2009 1 7 2
2010 1 4 2
2011 1 2 2
2012 1 8 2
2013 1 8 2
2014 1 5 2
I want to select the minimum and maximum year for each person (IDs 1 and 2), but I also want to select the value associated with type 0 for each person as well. Ideally this is what the query result would look like:
ID MinYear MaxYear Type0Value
1 2010 2015 5
2 2009 2014 6
The query should look, I think, something like this...
select ID,
(min(year) where type = 1) as MinYear,
(max(year) where type = 1) as MaxYear,
(value where type = 0) as Type0Value
from table
group by ID
But this is obviously not correct SQL syntax. How do I do this?
strange table structure, but:
select
_type0.id,
_type0.value,
_type1._min,
_type1._max
from
tbl as _type0
inner join (
select
id,
min(year) as _min,
max(year) as _max
from
tbl
where
1 = type
group by
id
) as _type1 on
_type0.id = _type1.id
where
0 = _type0.type;
you should use inner join.
one half will handle the min and max, second half the type0value:
select a.minYear, a.maxYear, a.id, b.type0value from
(select min(year) as minYear, max(year) as maxYear, id from table where id = 1 group by id) as a
inner join table as b on a.id = b.id
where b.type = 0
Your pseudo-code is actually pretty close. You just need conditional aggregation:
select ID,
min(case when type = 1 then year end) as MinYear,
max(case when type = 1 then year end) as MaxYear,
max(case when type = 0 then value end) as Type0Value
from table
group by ID;
If there could be multiple rows with type = 0, you might want group_concat() instead.
Let's say I have the following data.
id name_id completed
1 10 1
2 10 0
3 15 1
4 10 0
5 20 1
6 15 0
7 20 1
8 15 0
I'm trying to find a count by the name id, which is pretty simple
SELECT name_id, COUNT(*) FROM db
GROUP BY name_id
Now, I have a second component which I want to include in the query.
For name_id 10, I want to count just those values where completed is 1. For the other name_id's, I want to select them regardless of whether they are 0 or 1.
So I should end up with:
name_id count(*)
10 1
15 3
20 2
Name_id 10 only has a count of 1 because it's just the 1 which is completed, while the other counts include both 0 and 1.
Can anyone help with this task.
Thanks!
You can use a CASE expression inside of your aggregate function.
SELECT name_id,
sum(case
when name_id = 10
then case when completed = 1 then 1 else 0 end
else 1 end) Total
FROM db
GROUP BY name_id;
See SQL Fiddle with Demo.
Exclude the rows where name_id = 10 and completed = 0:
SELECT name_id, COUNT(*) FROM db
WHERE NOT (completed = 0 AND name_id = 10)
GROUP BY name_id
SELECT name_id, COUNT(*) FROM db
WHERE name_id != 10 or completed = 1
GROUP BY name_id
Count when name_id is not 10. If it is 10, count when completed = 1:
SELECT
name_id,
COUNT(CASE WHEN name_id <> 10 or completed = 1 THEN 1 END)
FROM db
GROUP BY name_id
I am trying to compare 2 rows and display the same ones.I did browse but was not able to find the right solution.
Table A
Count status Division
20 A 1
30 B 2
10 c 1
12 z 1
From the above table I want to display whose division is same.
Count status Division
20 A 1
10 c 1
12 z 1
Try this
Select * from TableA
Group By Division
Having Count(*) > 1
Select * from TableA
Group By Division
having Count(*) = 1
Here i used case statement , it worked for me
select CompanyCode ,'Commission Pec', Year
,sum(case when CommissionType='Commission Recevied' then JAN else 0 end)/sum(case when CommissionType='Net Payments from WM' and isnull(JAN,0)<>0 then JAN else 1 end)
from Commission_Consolidate
group by CompanyCode,Year
end