I have these two query, the first I look for the users, who have transactions in the last two months the second I sum and tell these users, but with all transactions of all time, the question is how do to assemble this query, first I look and then sum and tell?
SELECT DISTINCT(id_ju1) from master where fecha_registro > DATE_SUB(NOW(), INTERVAL 2 MONTH)
SELECT sum(precio) / count(DISTINCT(id_ju1)) AS TOTAL FROM master
You can do it in one query:
SELECT sum(m.precio) / count(DISTINCT(m.id_ju1)) AS TOTAL FROM master m
WHERE EXISTS (SELECT * FROM master m1 WHERE m1.fecha_registro > DATE_SUB(NOW(), INTERVAL 2 MONTH)
AND m.id_ju1=m1.id_ju1)
Related
how can I count last 7 days data from SQL and group them by day/date (excluding today).
I should be able to use the result as $resultday1, $resultday2, $resultday3 etc.
If there was 10 total SQL entries in day 1 (yesterday) $resultday1 should show "10".
and the days should be last 7 only, and today/current day should not consider.
The following PHP SQL script shows the total count only
SELECT COUNT(1) FROM orders WHERE username='jondoe'
database is a list of referrals made by a registered user in previous days.
a single table contains all user's referral details, table name "orders" as per above example.
This is the exact query as you want
SELECT
COUNT(*), DATE(order_date) order_date
FROM
orders
WHERE
order_date < CURDATE()
AND order_date > DATE_SUB(NOW(), INTERVAL 7 DAY)
GROUP BY order_date
ORDER BY order_date DESC;
I simplified the query and the table, but to give you some context: I have an "orders" table that contains all the items ordered by customers.
I want to check which items have been ordered at least once in history, but then, for whatever reason, nobody ordered them anymore (in this case, 180 days but it's just an example).
SELECT DISTINCT (idItem)
FROM orders
WHERE myDate < DATE_SUB(NOW(),INTERVAL 180 DAY)
AND
(idItem NOT IN
(SELECT
DISTINCT(idItem)
FROM orders
WHERE myDate > DATE_SUB(NOW(),INTERVAL 180 DAY)
)
)
ORDER BY myDate
This was my reasoning: I pick all the items ordered MORE THAN 6 months ago, and from the result I keep only the ones that DO NOT APPEAR in the previous 6 months.
I have 2 problems: one, it gives me back basically all of them, and second, regardless of "distinct", I still get plenty of duplicates :(
I do not usually deal with SQL, I know enough for simple queries but this one is probably as complex as I can make them :)
SELECT idItem
FROM orders
GROUP BY idItem
HAVING 0 = SUM(myDate > (CURRENT_DATE - INTERVAL 180 DAY))
?
With NOT EXISTS:
SELECT DISTINCT o.idItem
FROM orders o
WHERE NOT EXISTS (
SELECT 1 FROM orders
WHERE idItem = o.idItem AND myDate > DATE_SUB(NOW(), INTERVAL 180 DAY)
)
I'm tring to write a query, without a good resultset.
I would to retreive a Number of reservations in last 7 days.
Grouped by NameOfResource.
When i'm tring to set a WHERE clause like this prenotazioni.Data >= CURDATE() - INTERVAL 7 DAY
I get only NameOfResource with reservations in latest 7 days,
but not the rooms without reservations.
My Query was like that: (without WHERE the result is good)
SELECT count(*) as NReservationsFromWeek,Nomeroom FROM reservations
INNER JOIN room ON reservations.FKRoom = room.IDRoom
WHERE reservations.Data >= CURDATE() - INTERVAL 7 DAY
group by room.IDRoom
Thank you to explain me where I was wrong.
You can use a LEFT JOIN, if you want all rooms, even those with a count of 0:
SELECT ro.IDRoom, ro.Nomeroom, COUNT(re.FKRoom) as NReservationsFromWeek,
FROM room ro LEFT JOIN
reservations re
ON re.FKRoom = ro.IDRoom AND
re.Data >= CURDATE() - INTERVAL 7 DAY
GROUP BY ro.IDRoom, ro.Nomeroom; -- Both unaggregated keys should be in the GROUP BY
Score Table
user_idx (int)
date (datetime)
score (int)
I need to find out how much total score has increased over a week from today's date. I know that I need two of the same user tables grouped by user_idx that one contains total scores from the past to today and the other contains total scores from the past to a date of a week ago.
After that, by substracting one from the other will give me the answer... but I'm struggling to write effective sql query that does it.
I've tried
SELECT BLAH BLAH
FROM (SELECT user_idx, COUNT(*) as last_week_study_amount
FROM user_table
WHERE date <= date_sub(now(),INTERVAL 1 WEEK)
GROUP BY user_idx)
AS a WHERE .....
Could you help me :( ?
Let me clear you want to get total count in last week.
Try below query
SELECT *
FROM (SELECT user_idx, COUNT(*) as last_week_study_amount
FROM user_table
WHERE date <= date_sub(now(),INTERVAL 1 WEEK)
GROUP BY user_idx)
AS a WHERE .....
SELECT (SUM(score) - last_week_score) AS increased_score,
FROM user a
JOIN (SELECT b.user_idx, COUNT(*) as last_week_score
FROM userb
WHERE date<= date_sub(now(),INTERVAL 1 WEEK)
GROUP BY b.user_idx) As c ON a.user_idx = c.user_idx
WHERE DATE(date) <= DATE(NOW())
GROUP BY a.user_idx
I ended up writing this code and I think this one is working okay... not sure if it's the best or has a critical error. I will update it if it turns out to be a bad one...
I am using the following to show a count of products added over the last 7 days...Can i somehow tailor the query to show all the last 7 days even if COUNT=0?
query as it stands:
SELECT DAYNAME(dateadded) DAY, COUNT(*) COUNT
FROM `products`
WHERE (`dateadded` BETWEEN DATE_SUB(CURDATE(), INTERVAL 7 DAY) AND CURDATE() && site_url = 'mysite.com')
GROUP BY DAY(dateadded)
Add a table with dates in it (a dates lookup table), then:
SELECT DAYNAME(d.FullDate) DAY, COUNT(*) COUNT
FROM dates d
LEFT OUTER JOIN products p ON d.FullDate = DATE(p.dateadded)
AND p.site_url = 'mysite.com'
WHERE d.FullDate BETWEEN DATE_SUB(CURDATE(), INTERVAL 7 DAY) AND CURDATE()
GROUP BY d.FullDate
It takes a little bit of storage, yes, but it will make queries like this a lot easier.
Alternatively, you can make a stored procedure that loops through dates between 7 days ago and today and returns one row for each.