I want to send email in yii2. I store the body of my email in sqlyog. But, I have an error when I get information from database as the body of my email. The error is:
quoted_printable_encode() expects parameter 1 to be string, object
given
. How can I solve it? This is my code:
$pesan = \frontend\models\Pesan::find()->select(['pesan'])->where(['kategori' => 'notifikasi_awal'])->one();
$message = $pesan;
$email = \Yii::$app->mailer->compose()
->setFrom([\Yii::$app->params['adminEmail'] => 'Sistem Informasi Paket'])
->setTo($tujuan)
->setSubject("[Pemberitahuan ]")
->setHtmlBody($message)
->send();
The instruction
$pesan = \frontend\models\Pesan::find()->select(['pesan'])
->where(['kategori' => 'notifikasi_awal'])->one();
return a model then an object
if you want a value you can obtain this value this way
$message = $pesan->your_message_field;
Related
I paid someone to make a plugin for my website 5 years ago and now I'm trying to get it to work again. I have no knowledge of how JSON works so this is my first experimenting with it. Basically my plugin would use the Iframely API to get a summary of an article and save the data to a custom field from a URL in the editor.
The code I have in question in my function.php is this:
function post_extra_save( $post_id, $post){
global $pagenow;
if ($pagenow == 'post.php') {
if ( has_post_format('link', $post_id)) {
$url = get_post_field('post_content', $post_id);
$request_url = 'https://iframe.ly/api/iframely?url='. urlencode($url) .'&api_key='.get_field_object('api_key', 'option')['value'];
$response = wp_remote_get( esc_url_raw( $request_url ) );
$api_response = json_decode( wp_remote_retrieve_body( $response ), true );
update_field('field_61942d74195e7', $api_response);
}
}
}
add_action( 'save_post', 'post_extra_save', 10, 2 );
What it does is send a URL plus the API key to Iframely API, returns the JSON and save the raw output to a custom field.
When I save the post, I get this error message:
Warning: htmlspecialchars() expects parameter 1 to be string, array given in /wp-includes/formatting.php on line 4529
Any idea what this means?
Found my problem. What I got it to work was it gets the URL from the post content, encode it from the raw JSON and decode it.
$request = wp_remote_get( 'https://iframe.ly/api/iframely?url='. urlencode($url) .'&api_key='.get_field_object('api_key', 'option')['value'] );
$data_raw = json_encode( wp_remote_retrieve_body( $request ));
$data = json_decode($data_raw);
I'm new to Laravel. I need to retrieve specific data from the database using the JSON decode. I am currently using $casts to my model to handle the JSON encode and decode.
This is my insert query with json encode:
$request->validate([
'subject' => 'required|max:255',
'concern' => 'required'
]);
$issue = new Issue;
$issue->subject = $request->subject;
$issue->url = $request->url;
$issue->details = $request->concern;
$issue->created_by = $request->userid;
$issue->user_data = $request->user_data; //field that use json encode
$issue->status = 2; // 1 means draft
$issue->email = $request->email;
$issue->data = '';
$issue->save();
The user_data contains {"id":37,"first_name":"Brian","middle_name":"","last_name":"Belen","email":"arcega52#gmail.com","username":"BLB-Student1","avatar":"avatars\/20170623133042-49.png"}
This is my output:
{{$issue->user_data}}
What I need to retrieve is only the first_name, middle_name, and last_name. How am I supposed to achieve that? Thank you in ADVANCE!!!!!
As per the above code shown by you it will only insert data into the database.For retrieving data you can make use of Query Builder as i have written below and also you can check the docs
$users = DB::table('name of table')->select('first_name', 'middle_name', 'last_name')->get();
I will recommend using Resources. It really very helpful laravel feature. Check it out. It is a reusable class. You call anywhere and anytime.
php artisan make:resource UserResource
Go to your the newly created class App/Http/Resources/UserResource.php and drfine the column you want to have in your response.
public function toArray($request) {
return [
"first_name" => $this->first_name,
"middle_name" => $this->middle_name,
"last_name" => $this->last_name
]
}
Now is your controller you can use the UserResource like folow:
public function index()
{
return UserResource::collection(User::all());
}
Or after inserting data you can return the newly added data(f_name, l_name...)
$user = new User;
$user->first_name= $request->first_name;
$user->middle_name= $request->middle_name;
$user->last_name= $request->last_name;
$user->save();
$user_data= new UserResource($user);
return $user_data;
I'm currently learning on how API works and my mentor gave me a task to create submit the form using API and store the data on database with laravel and the task also require mandatory if logic on some field.
I have succeeded with the first task (storing data to the database ) and I'm having difficulties writing the mandatory if.
I'm confused, on my task paper I'm told to create one controller, one model and two endpoints (request-schedule and request-leaving) where each endpoint should have some parameters.
and for the request-leaving parameter, there are 10 parameters, 6 of them have this requirement like (mandatory if request type Request Day Off)
There are 3 requests typewritten on there
1. Request Day off
2. Request Schedule
3. Change Schedule
I'm a super newbie in programming, does anyone know how to solve this?
public function CreateReqSchedule(Request $request)
{
$reqschedule = new B777();
$reqschedule->reqtype = $request->input('reqtype');
$reqschedule->startdate = $request->input('startdate');
$reqschedule->enddate = $request->input('enddate');
$reqschedule->reason = $request->input('reason');
$reqschedule->route = $request->input('route');
$reqschedule->actualschedule = $request->input('actualschedule');
$reqschedule->changetoschedule = $request->input('changetoschedule');
$reqschedule->swapcrewid = $request->input('swapcrewid');
$reqschedule->swapcrewschedule = $request->input('swapcrewschedule');
$reqschedule->note = $request->input('note');
$reqschedule->save();
return response()->json($reqschedule);
}
code above is my only work, I'm feeling anxious, because I've googled it myself but I'm still stuck.
So you are talking about validations. you can put laravel validation into it like below
Use required validation for mandotory data and return response in json
// Making validation for fields
$validator = \Validator::make($request->all(), [
'fields1' => 'required',
'fields2' => 'required',
'fields3' => 'required',
]);
if ($validator->fails())
{
// return response on validaton fails
return response()->json(['status'=>400,'errors'=>$validator->errors()->all()]);
}
// If validation passes store your data in database
I'm looking for 2 specific variables.
Wishlist - The var_message variable has some styling to it that im trying to edit.
Abandoned Carts - pulls on this extension URL : connector/email/basket/code/secret/quote_id/*****
And im unable to find the location of the file that is accessed by that URL or command.
Any assistance that can be provided would be greatly appreciated.
Also if someone could tell me how i might trace the locations of these things without "Just knowing" that would be grand too.
Kind Regards,
the correct variable name is message (not var_message)
variable message is populated in controller Mage_Wishlist_IndexController
inside method sendAction
here it is:
$emailModel = Mage::getModel('core/email_template');
$sharingCode = $wishlist->getSharingCode();
foreach ($emails as $email) {
$emailModel->sendTransactional(
Mage::getStoreConfig('wishlist/email/email_template'),
Mage::getStoreConfig('wishlist/email/email_identity'),
$email,
null,
array(
'customer' => $customer,
'salable' => $wishlist->isSalable() ? 'yes' : '',
'items' => $wishlistBlock,
'addAllLink' => Mage::getUrl('*/shared/allcart', array('code' => $sharingCode)),
'viewOnSiteLink' => Mage::getUrl('*/shared/index', array('code' => $sharingCode)),
'message' => $message
)
);
}
$wishlist->setShared(1);
$wishlist->save();
and the actual content of the message comes from a form input and gets fetched over here:
$message = nl2br(htmlspecialchars((string) $this->getRequest()->getPost('message')));
there is no actual styling or css assigned to it. In fact most of styles are defined inline in email templates
In CakePHP 3.1 I am redirecting to login page after a database update and I want to pass back the email so that form input is already populated.
I can do it the standard way with using the controller and action in the redirect.
Instead I am using just a url string
return $this->redirect('/login',['?' => ['email' => $email]]);
This gives me the error Unknown status code
The redirect method expects a status code as the second parameter. You will need to provide and array-based URL as the first parameter or append the query var to the current string.
return $this->redirect('/login?email=' . $email);
return $this->redirect([
'controller' => 'Users',
'action' => 'login',
'?' => [
'email' => $email
]
]);