I am creating a form with a check box called "agreement". The user must click this to confirm that he has agreed to the agreements. But how do I add this to the validation? Can I do this from the model? This is a field that is not in the database.
In cake 2.0 I could do it like this:
$this->Model->set($this->data['Form']['agree']);
if($this->Model->validates($this->data)){
// okay
$this->Model->Save();
}else{
pr($this->Model->invalidFields());
}
How to do it in cakephp 3?
In model you can add custom patch method, that will check 'confirm' field in request->data. if it's empty then just call errors('data.confirm'). So your entity will have errors, and you just need to render this error to your form. Something like:
public function customPatch($data) {
$entity = $this->newEntity($data);
if (!$entity->confirm) {
$entity->errors('data.confirm', 'You have to...');
}
return $entity;
}
Related
So I am have made a laravel authentication application that can log in/register users based on a type and depending on a type they can see different information in this case data tables. I used the laratrust package to do this and works well, but if I want to make this with a vue component that will show the data using some special data grid how would go about doing it as the controller which I am using where the data is collected but is also the place where the view which the user will see depending on the type of user is also checked. So, how will I send the json data to the vue component and what other things do I need to consider.
Here is the controller in laravel:
class DashboardController extends Controller
{
public function index()
{
if(Auth::user()->hasRole('user')){
$posts = DB::select('select * from office');
return view('userdash',['posts'=>$posts]);
}elseif(Auth::user()->hasRole('administrator')){
$posts = Post::all();
return view('administratordash',['posts'=>$posts]);
}elseif(Auth::user()->hasRole('admin')){
$people = DB::select('select * from office');
$posts = Post::all();
return view('dashboard',['posts'=>$posts,'people'=>$people]);
}
}
}
One of the things I tried was
return response(view('userdash',array('posts'=>$posts)),200,['Content-Type' => 'application/json']);
This way I can just send the json data and then render it in the view component. But I am not sure if it is working as I get back a bunch of html and some of the data in the database but not all of it. Also not sure how this can be passed to the view component. Maybe as a prop but not sure.
Any and all help and suggestions are appreciated.
As you are responding from the controller with different views, you can just check for any variables sent with the wiew in your view and once your variables are at your disposal in the view yo can serialize them using $myVar=$myVariable->toJson() if they are laravel collections or json_encode($myVariable) if they are simple arrays.
Then you can
<my-component :data ={{$myVar}}/>
Form 1 is a set of filters, and the "submit" button applies those filters to a GET method. Form 2 is a set of data, and the "submit" button saves that data and also continues the filters via a POST method. The filter options are passed back and forth - the user GETs the initial page, possibly sets up some filters which GETs the same page again in terms of controller method, then the user can modify some data and save via a POST, which then returns back with a GET for the same filtered page.
Simplified (lots more that is likely to be irrelevant):
#model PagedList.IPagedList<xxx.Models.WttPlatformGridRow>
#using (Html.BeginForm("PlatformGridEdit", "Wtt", FormMethod.Get))
{
#Html.CheckBox("ExcludeThrough", (bool)ViewBag.ExcludeThrough)
<input type="submit" value="Filter" />
}
#using (Html.BeginForm("PlatformGridEdit", "Wtt", FormMethod.Post))
{
#Html.Hidden("ExcludeThrough", (bool)ViewBag.ExcludeThrough)
<input type="submit" value="Save" />
}
Simplified controller:
[HttpPost]
[ValidateAntiForgeryToken]
public ActionResult PlatformGridEdit(List<WttPlatformGridRow> rows, bool? excludeThrough)
{ etc }
public ActionResult PlatformGridEdit(bool? excludeThrough)
{ etc }
Obviously naming two elements the same is illegal in HTML, and it doesn't work anyway (parameter is null in the C# method).
The answers I've seen so far suggest a single BeginForm with all the data. Fine. Except one is a GET (no data changes) and one is a POST (data changes). User need to be able to bookmark the filter so I can't handle it all as a POST anyway, otherwise the browser will ask the user if resubmitting form data is okay.
I'm also using an IPagedList which (as far as I know) precludes the use of a single model with a list field instead of using ViewBag.
Another option seems to be using client side scripting to copy the value from one field to another. But I don't see how to do this when the parameter name in the controller method is the same for both client side fields.
What is the best way of handling this please?
I have a solution but I can't help thinking there must be a better way.
FWIW, this is what I've done. The two fields have non-identical names (but similar). The "master" version (visible checkbox) has script that copies the value to the "slave" version (hidden field) on submit. The controller method takes both names and decides which is relevant - one or both should be null, but both shouldn't have a value, but we handle that just in case.
Finally, the controller returns the view with the combined value (using the "master" identity).
View - form 1:
bool excludeThrough = ViewBag.ExcludeThrough != null ? ViewBag.ExcludeThrough : false;
#Html.CheckBox("ExcludeThrough", excludeThrough, new
{
#class = "form-control",
onchange = "document.getElementById('ExcludeThroughFilter').value = document.getElementById('ExcludeThrough').value;"
})
View - form 2:
#Html.Hidden("ExcludeThroughFilter", excludeThrough)
Controller:
public ActionResult PlatformGridEdit(..., bool? excludeThrough, bool? excludeThroughFilter)
{
bool excThru = false;
if (excludeThrough.HasValue) excThru = excludeThrough.Value;
if (excludeThroughFilter.HasValue && excludeThroughFilter.Value) excThru = true;
...etc...
}
Edit :
I have a function for generate a reference, in my controller and I'd save it returns at the same time add that my form is saved, but I would avoid spending the variable view and make a hidden input, how can I do? I try to use the model but without success!
public function afterSave(Event $event, Entity $entity){
if($this->Adverts->save()){
$ref = $this->ref();
$ref = $this->Adverts->reference;
}
}
I tried using special variable $message described here http://www.symfony-project.org/cookbook/1_2/en/error_templates but it seems this variable isn't defined in symfony 1.4, at least it doesn't contain message passed to exception this way throw new sfException('some message')
Do you know other way to pass this message to error.html.php ?
You'll need to do some custom error handling. We implemented a forward to a custom symfony action ourselves. Be cautious though, this action itself could be triggering an exception too, you need to take that into account.
The following might be a good start. First add a listener for the event, a good place would be ProjectConfiguration.class.php:
$this->dispatcher->connect('application.throw_exception', array('MyClass', 'handleException'));
Using the event handler might suffice for what you want to do with the exception, for example if you just want to mail a stack trace to the admin. We wanted to forward to a custom action to display and process a feedback form. Our event handler looked something like this:
class MyClass {
public static function handleException(sfEvent $event) {
$moduleName = sfConfig::get('sf_error_500_module', 'error');
$actionName = sfConfig::get('sf_error_500_action', 'error500');
sfContext::getInstance()->getRequest()->addRequestParameters(array('exception' => $event->getSubject()));
$event->setReturnValue(true);
sfContext::getInstance()->getController()->forward($moduleName, $actionName);
}
}
You can now configure the module and action to forward to on an exception in settings.yml
all:
.actions:
error_500_module: error
error_500_action: error500
In the action itself you can now do whatever you want with the exception, eg. display the feedback form to contact the administrator. You can get the exception itself by using $request->getParameter('exception')
I think I found a much simpler answer. On Symfony 1.4 $message is indeed not defined, but $exception is (it contains the exception object).
So just echo $exception->message.
Et voilà!
I've found another trick to do that - sfContext can be used to pass exception message to error.html.php but custom function have to be used to throw exception. For example:
class myToolkit {
public static function throwException($message)
{
sfContext::getInstance()->set('error_msg', $message);
throw new sfException($message);
}
than insted of using throw new sfException('some message') you should use myToolkit::throwException('some message')
To display message in error.html.php use <?php echo sfContext::getInstance()->get('error_msg') ?>
I have a FormPanel in GWT that should send a TextBox input to a new page (newPage.html). Below is my code. How do I receive this input in newPage.html, so that I can work with it from the associate newPage.java class? Thanks
final FormPanel form = new FormPanel();
form.setEncoding(FormPanel.ENCODING_MULTIPART);
form.setMethod(FormPanel.METHOD_POST);
TextBox userid = new TextBox();
userid.setName("userid");
form.add(userid);
form.add(new Button("Submit", new ClickListener()
{
public void onClick(Widget sender)
{
form.submit();
}
}));
form.setAction("newPage.html");
RootPanel.get("demo").add(form);
If what you are trying to do is POST variables from one gwt-page using a formpanel to another gwt-page to process these POST results you can not, simply because gwt-pages are coded with java but in the end they are translated into javascript and javascript alone can not access POST variables.
You need to define a backend that can process your form in your form.setAction() method that should execute on the server-side and produce a valid html/text response. To get these results produced by your backend you need to add a FormHandler to your FormPanel. There is an example showing how to do that on javadocs. Then evaluating these results you can redirect accordingly.
If you want to handle what you send with a java class meaning you have a java backend, why not use GWT-RPC?