MySQL - using "as" in inner select - mysql

Question

I have three tables I am selecting from and two of them have same column named "id". It is language.id and route.id
If I run this query
SELECT *
FROM route
LEFT JOIN route_has_languages
ON route.id = route_has_languages.route_id
LEFT JOIN language
ON language.id = route_has_languages.languages_id
WHERE route_has_languages.languages_id = 1
It runs fine, it cuts language.id, which is what I want
However I want to use it as inner select, but when I do this
SELECT * FROM (
SELECT *
FROM route
LEFT JOIN route_has_languages
ON route.id = route_has_languages.route_id
LEFT JOIN language
ON language.id = route_has_languages.languages_id
WHERE route_has_languages.languages_id = 1
) T1
It ends with Error Code: 1060. Duplicate column name 'id'
I have tried renaming it, this query runs fine showing noneed_id column as expected
SELECT *, language.id as noneed_id
FROM route
LEFT JOIN route_has_languages
ON route.id = route_has_languages.route_id
LEFT JOIN language
ON language.id = route_has_languages.languages_id
WHERE route_has_languages.languages_id = 1
But once again, using it as inner select ends with same error
SELECT * FROM (
SELECT *, language.id as noneed_id
FROM route
LEFT JOIN route_has_languages
ON route.id = route_has_languages.route_id
LEFT JOIN language
ON language.id = route_has_languages.languages_id
WHERE route_has_languages.languages_id = 1
) T1
I do not understand this behaviour, anyone can point me out?
PS : I know I can do something like this to make it work, but I would like to not name all tables/columns
SELECT * FROM (
SELECT route.*, route_has_languages.*, language.short_name, language.long_name
FROM route
LEFT JOIN route_has_languages
ON route.id = route_has_languages.route_id
LEFT JOIN language
ON language.id = route_has_languages.languages_id
WHERE route_has_languages.languages_id = 1
) T1
If someone wants to try it, you can run this
CREATE TABLE IF NOT EXISTS `language` (
`id` INT NOT NULL AUTO_INCREMENT,
`short_name` VARCHAR(7) NOT NULL,
`long_name` VARCHAR(15) NOT NULL,
`name` VARCHAR(63) NOT NULL,
`flag` TEXT NULL,
`language_order` INT NOT NULL,
PRIMARY KEY (`id`),
UNIQUE INDEX `short_name_UNIQUE` (`short_name` ASC),
UNIQUE INDEX `long_name_UNIQUE` (`long_name` ASC))
ENGINE = InnoDB;
CREATE TABLE IF NOT EXISTS `route` (
`id` INT NOT NULL AUTO_INCREMENT,
`length` DOUBLE NOT NULL,
`estimated_time` INT NOT NULL,
`accessibility` TINYINT(1) NOT NULL,
`version` INT NOT NULL,
`north_east_point_lat` DOUBLE NOT NULL,
`north_east_point_lng` DOUBLE NOT NULL,
`south_west_point_lat` DOUBLE NOT NULL,
`south_west_point_lng` DOUBLE NOT NULL,
`available` TINYINT(1) NOT NULL DEFAULT 1,
`store_id` VARCHAR(255) NULL,
`color` VARCHAR(63) NULL,
PRIMARY KEY (`id`)
)
ENGINE = InnoDB;
CREATE TABLE IF NOT EXISTS `route_has_languages` (
`route_id` INT NOT NULL,
`languages_id` INT NOT NULL,
`description` TEXT NOT NULL,
`voice` VARCHAR(63) NOT NULL,
`info_at_poi` TEXT NOT NULL,
PRIMARY KEY (`route_id`, `languages_id`),
INDEX `fk_route_has_languages_languages1_idx` (`languages_id` ASC),
INDEX `fk_route_has_languages_route1_idx` (`route_id` ASC),
CONSTRAINT `fk_route_has_languages_route1`
FOREIGN KEY (`route_id`)
REFERENCES `audioguide`.`route` (`id`)
ON DELETE NO ACTION
ON UPDATE NO ACTION,
CONSTRAINT `fk_route_has_languages_languages1`
FOREIGN KEY (`languages_id`)
REFERENCES `audioguide`.`language` (`id`)
ON DELETE NO ACTION
ON UPDATE NO ACTION)
ENGINE = InnoDB;

Answer 1

As long as you use * in both SELECT statements, you will have this error.
Renaming it like: , language.id as noneed_id will only add a column, but it will not remove the id column(s).
A solution can be to rename the fields in the database. For example, route.id to route_id etc.

Answer 2

Lets check the Problem-
Your first query-
SELECT *
FROM route
LEFT JOIN route_has_languages
ON route.id = route_has_languages.route_id
LEFT JOIN language
ON language.id = route_has_languages.languages_id
WHERE route_has_languages.languages_id = 1
Here mysql will follow fields order as per table order means first table all fields then 2nd table all fields and so on as per below-
In your second table you are using sub-query means mysql will treat same and povide results as per below-
id (first table), col12,col13,col14..., id(2nd table),col22,col23,col24..., other tables columns.....
means your results are -
id,col11,col12,col13,...,id,col21,col22,col23,....
Now your outer query will fetch results from here and will get id column 2 times and will throw error.
Solution
Either you have to mention all columns in sub-query and need to keep different alias for common fields or need to change column name in one table.