i have a row in my MySql table 'a' with values 'date'='2015-06-01' and 'hour' = 17:00:00
My problem is that i can select this row by
hour BETWEEN "16:30:00" AND "17:30:00"
but i cant by date = 2015-06-01.
I need my full statement like this:
SELECT * FROM `a`
WHERE (date = 2015-06-01)
AND (hour BETWEEN "16:30:00" AND "17:30:00")
You need quotes around the date too
SELECT * FROM `a`
WHERE `date` = '2015-06-01'
AND `hour` BETWEEN '16:30:00' AND '17:30:00'
Related
I have this query i use to get statistics of blogs in our own tracking system.
I use union select over 2 tables as we daily aggregate data in 1 table and keeps todays data in another table.
I want to have the last 10 months of traffic show.. This query does that, but of there is no traffic in a specific month that row is not in the result.
I have previously used a calendar table in mysql to join against to at avoid that, but im simply not skilled enoght to rewrite this query to join against that calendar table.
The calendart table has 1 field called "datefield" which i date format YYY-MM-DD
This is the current query i use
SELECT FORMAT(SUM(`count`),0) as `count`, DATE(`date`) as `date`
FROM
(
SELECT count(distinct(uniq_id)) as `count`, `timestamp` as `date`
FROM tracking
WHERE `timestamp` > now() - INTERVAL 1 DAY AND target_bid = 92
group by `datestamp`
UNION ALL
select sum(`count`),`datestamp` as `date`
from aggregate_visits
where `datestamp` > now() - interval 10 month
and target_bid = 92
group by `datestamp`
) a
GROUP BY MONTH(date)
Something like this?
select sum(COALESCE(t.`count`,0)),s.date as `date`
from DateTable s
LEFT JOIN (SELECT * FROM aggregate_visits
where `datestamp` > now() - interval 10 month
and target_bid = 92) t
ON(s.date = t.datestamp)
group by s.date
What is an efficient way to get all records with a datetime column whose value falls somewhere between yesterday at 00:00:00 and yesterday at 23:59:59?
SQL:
CREATE TABLE `mytable` (
`id` BIGINT,
`created_at` DATETIME
);
INSERT INTO `mytable` (`id`, `created_at`) VALUES
(1, '2016-01-18 14:28:59'),
(2, '2016-01-19 20:03:00'),
(3, '2016-01-19 11:12:05'),
(4, '2016-01-20 03:04:01');
If I run this query at any time on 2016-01-20, then all I'd want to return is rows 2 and 3.
Since you're only looking for the date portion, you can compare those easily using MySQL's DATE() function.
SELECT * FROM table WHERE DATE(created_at) = DATE(NOW() - INTERVAL 1 DAY);
Note that if you have a very large number of records this can be inefficient; indexing advantages are lost with the derived value of DATE(). In that case, you can use this query:
SELECT * FROM table
WHERE created_at BETWEEN CURDATE() - INTERVAL 1 DAY
AND CURDATE() - INTERVAL 1 SECOND;
This works because date values such as the one returned by CURDATE() are assumed to have a timestamp of 00:00:00. The index can still be used because the date column's value is not being transformed at all.
You can still use the index if you say
SELECT * FROM TABLE
WHERE CREATED_AT >= CURDATE() - INTERVAL 1 DAY
AND CREATED_AT < CURDATE();
You can use subdate to indicate "yesterday" and use date() to indicate that you want records where just the date part of the column matches. So:
SELECT *
FROM tablename
WHERE DATE(created_at) = SUBDATE(CURRENT_DATE(), INTERVAL 1 DAY)
Here is the same question with an answer. To summarize answer for you, use subdate() as suggested by Sajmon.
subdate(currentDate, 1)
using your table it should be.
select *
from tablename
where created_at between subdate(CURDATE(), 1)
and date (now() )
use:
subdate(current_date, 1)
it's awesome for your case!
SELECT subdate(current_date(), 1)
SELECT * FROM table
WHERE created_at >= subdate(current_date(), 1)
You can use this, just put tablename and columnName (Which Contain 2021/01/09 or 2022-01-11 14:56:07 etc)
select * from (TABLENAME) where DATE(columnNAME) = TODAY - 1;
My code:
$results = $GLOBALS['wpdb']->get_results( 'SELECT * FROM myTable WHERE date = 2014 ORDER BY id DESC', object );
The problem is date is stored in this format: 2014-01-01
So how do I select just the year ( I don't care about month and day for the time being ).
Thanks
Use the year() function:
WHERE year(date) = 2014
or use explicit comparisons:
WHERE (date >= '2014-01-01' and date < '2015-01-01')
The latter is better because it can make use of an index on the date column.
Try this Query :
SELECT * FROM myTable WHERE year(`date`)='2014' ORDER BY id DESC
Try this:
SELECT * FROM myTable WHERE date >= '2014-01-01 00:00:00' ORDER BY id DESC
To select all rows where the year of a date column (called date_col) is equal to 2014 use the year function:
SELECT * FROM `tbl` WHERE Year(`date_col`) = '2014';
You can select year for get posts with query_posts(); parameter is year. Example: query_posts("year=2014"); This is not full question for you, only alternative..
Here is an explanation of how my table is set up (in sqlfiddle)
http://sqlfiddle.com/#!2/86a54d/2
Basically, I have two columns. One is a varchar and contains a name. The other is a datetime and contains a certain date with a time.
I want to select rows where the date in the datetime matches today's date. I have tried things like...
select * from alerts_to_send where date_to_send = now()
select * from alerts_to_send where date_to_send = curdate()
I'm not exactly where to go from here... Any ideas would be greatly appreciated :)
Just to re-clarify, I want to select the rows where today's date matches the date part of my datetime type column.
try this
select * from alerts_to_send
where DATE_FORMAT(date_to_send,'%m-%d-%Y') = DATE_FORMAT(now(),'%m-%d-%Y')
fiddle
You can use the date_format function for mysql
select * from alerts_to_send where date_format(date_to_send, "%m/%d/%Y") = date_format(now(), "%m/%d/%Y")
Here is reference to date_format: http://dev.mysql.com/doc/refman/5.5/en/date-and-time-functions.html#function_date-format
An alternative to date_format function you can convert the datetime to date:
select * from alerts_to_send where cast(date_to_send as date) = curdate()
It could be even shorter:
select * from alerts_to_send where date(date_to_send) = date(now())
But you will have problem with using index on it so better will be:
select * from alerts_to_send where date_to_send >= date(now()) and date_to_send < date(now()) + INTERVAL 1 DAY
I have a database like this:
ID->INT
Date->DateTime
Now i want to write a SELECT to fetch all rows where Date column between "2008/1/1" and "2010/1/1".
SELECT * FROM mytable WHERE `Date` BETWEEN '2008-01-01' and '2010-01-01';
You just apply a filter in a WHERE clause
select *
from yourtable
where date >= '2008-01-01'
and date <= '2010-01-01'