MySQL. Can i choose rows with map? - mysql

Question

So, I have an array id=>time and a table.
| id | text | created_at |
How to get all rows where CREATED_AT>array['id'] and ID=id in one query?
i can do, something like this
foreach (array as $key=>$value) {
query("SELECT * FROM table WHERE CREATED_AT>$value and ID=$key");
}
but i would like to put it all in one query.
Sample data:
| id | text | created_at |
--------------------------
| 1 | aaaa | 123 |
| 2 | bbbb | 124 |
| 1 | cccc | 122 |
| 3 | dddd | 125 |
| 1 | eeee | 125 |
array( '1' => 123, '2' => 125, '3' => 124);
Query should return this rows:
| 1 | aaaa | 123 |
| 3 | dddd | 125 |
| 1 | eeee | 125 |

Answer 1

You could do a long series of
$my_query = "SELECT * FROM table WHERE";
$counter = 0;
foreach (array as $key=>$value) {
if ($counter > 0)
$my_query += " OR ";
$my_query += "(CREATED_AT>$value and ID=$key)";
$counter++;
}
However this is ugly. I wouldn't recommend doing it. Aside from that I think there's no easy way to do this in one query. It would be easy if there was just a single batch of IDs you are querying for, but given both criteria I can't think of any other way.
I don't think it's such a bad idea to do it in a for loop... It's definitely more readable than the code I gave above.