Select string till first or second space in string - mysql

Question

I have table column that contains in each row data like this:
| Simbols |
|--------------------------------------|
|H412 Text text |
|H413 Text text text text |
|EUH 001 Text text text text text text |
|EUH 006 text text |
|EUH 201/201A Text text. Text text |
And I need from that data get data like this:
|Simbols |
|------------|
|H412 |
|H413 |
|EUH 001 |
|EUH 006 |
|EUH 201/201A|
I tried with SUBSTRING and CHARINDEX but it till the end don't work... It takes only first space or something like that...
QUERY:
SELECT
CASE
WHEN SUBSTRING(Simbols, 1, CHARINDEX(' ', Simbols)) = ''
THEN Simbols + ' '
ELSE SUBSTRING(Simbols, 1, CHARINDEX(' ', Simbols))
END 'Simbols'
FROM dbo.table
RESULT:
| Simbols |
|------------|
|H412 |
|H413 |
|EUH |
|EUH |
|EUH |
How can I make this work, and where is the problem?
Maybe there is different way to get these Simbols?
P.S. "Text text text" is a example, there comes a explanations of "Simbols"

Answer 1

The CharIndex() function has an optional 3rd parameter - start_location - that will be key here.
SELECT your_column
, CharIndex(' ', your_column) As first_space
, CharIndex(' ', your_column, CharIndex(' ', your_column) + 1) As second_space
, SubString(your_column, 1, CharIndex(' ', your_column, CharIndex(' ', your_column) + 1)) As first_two_words
FROM your_table
Unfortunately when the CharIndex() function can't find the specified string (in this case a single space ' ') it will return 0 (zero).
This means that if there isn't a first or second space the result of first_two_words in my above example will return an empty string as SubString(your_column, 1, 0) = ''.
To get around this you need to be a little clever.
Essentially, if second_space = 0 then we need to return the full string. We have a few options for this:
SELECT your_column
, CharIndex(' ', your_column) As first_space
, CharIndex(' ', your_column, CharIndex(' ', your_column) + 1) As second_space
, SubString(your_column, 1, CharIndex(' ', your_column, CharIndex(' ', your_column) + 1)) As first_two_words
, SubString(your_column, 1, Coalesce(NullIf(CharIndex(' ', your_column, CharIndex(' ', your_column) + 1), 0), Len(your_column))) As first_two_words_option1
, CASE WHEN CharIndex(' ', your_column, CharIndex(' ', your_column) + 1) = 0 THEN your_column ELSE SubString(your_column, 1, CharIndex(' ', your_column, CharIndex(' ', your_column) + 1)) END As first_two_words_option2
FROM (
SELECT 'one' As your_column
UNION ALL SELECT 'one two'
UNION ALL SELECT 'one two three'
UNION ALL SELECT 'one two three four'
) As x

Answer 2

Try this: It works
SELECT CASE WHEN charindex(' ', Simbols, charindex(' ', Simbols) + 1) = 0
THEN Simbols
ELSE LEFT(Simbols, charindex(' ', Simbols, charindex(' ', Simbols) + 1))
END
FROM dbo.table
Here is screenshot what I tried.
Here is new EDIT
SELECT REPLACE(Simbols, 'text', '') FROM dbo.table
Here is screen shot

Answer 3

Try something like this:
select TRIM(REPLACE(lower(type),"text" ,"")) as T, type from supportContacts
Sql Fiddle: http://sqlfiddle.com/#!2/d5cf8/4
for more info :http://dev.mysql.com/doc/refman/5.0/en/string-functions.html#function_replace