CakePHP 2: new exceptions - exception

I'd like to create a new exception, called SecurityException.
Where should I put the code?
class SecurityException extends CakeException {};
Thanks!

Create an exceptions.php file, put it on the Lib folder and fill it up with all your *Exception classes. Then include it on your application's bootstrap file.
require APP . 'Lib' . DS . 'exceptions.php';
All exceptions will become available application wide.

I followed luchomolina's 2nd answer (commented on his own answer), and thought it deserved to be an official answer:
Here's another approach: "put exceptions in ([plugin-if-any])/Lib/Error/Exception/NameOfTheException.php and use App::uses('NameOfTheException', 'Error/Exception') where they're needed.
Seemed like a Cake'ish way to do it, and they're not included unless one is actually thrown." –luchomolina

Related

Yii2: differences between init() and bootstrap() and best place to add dynamical URLs on a module

I dont understand exactly what is the difference between use init() and bootstrap() on a class.
My case:
I want to add dynamical urls from my module by using Yii::$app->urlManager->addRules(...) but NOT loading the module in order to improve the performance.
So, I thought if bootstraping the module from the main configuration file like: 'bootstrap' => ['mymodule'], the Module::bootstrap() function will be executed ONLY and exclusively. But actually always runs Module::init() function, and then Module::bootstrap().
On this documentation http://www.yiiframework.com/doc-2.0/guide-runtime-routing.html#adding-rules say:
'Note that you should also list these modules in yii\web\Application::bootstrap() so that they can participate the bootstrapping process.'
But Module::bootstrap() is not executed if the module is listed on yii\web\Application::bootstrap()
I want to set only the dynamic rules with no module loading. How is it possible? What is the best place to set dynamical URLs with no impact to performance?
i decide resolve this issue(adding dynamic rules for module) by watching working extensions.
for example https://github.com/dmstr/yii2-pages-module extension uses bootstrap interface.
don`t forget write in composer.json "type" attribute as "yii2-extension".

How to have class loaded without using "use" but call it as if I used it

I have studied these 2 sources, but none of those works for me.
http://www.yiiframework.com/doc-2.0/guide-concept-autoloading.html
Yii2 - How do I AutoLoad a custom class?
I have created custom helper class which I want to include in every model, controller and view in my application. I am using Yii2 advanced app version 2.0.11, IDE I am using is PHPStorm
QUESTION:
What I want to achieve is to not use use keyword at the beggining of every class but still be able to simply call AppHelper::myMethod() in models, controllers and views.
How is that possible?
Closest I got it working was using this solution https://stackoverflow.com/a/35160997/5395463
All other solutions did not work for me. I am getting errors like:
PHP Fatal Error – yii\base\ErrorException
Class 'frontend\controllers\AppHelper' not found
when I simply dont include use commons\commands\AppHelper;
or when not using namespace as they suggest there with other settings:
Fatal error: Uncaught exception 'yii\base\UnknownClassException'
with message 'Unable to find 'common\commands\AppHelper'
in file: C:\xampp\htdocs\domain.com\web\common/commands/AppHelper.php.
Namespace missing?' in ...
SOLUTION:
Thanks for your responses, I got it working finaly. https://stackoverflow.com/a/42330631/5395463 solution works best for me.
So I removed namespace from that class, but left it in common\commands folder, added require to frontend/web/index.php and backend/web/index.php files (not sure if I should add it to yii file in root too, I didnt, so far it is working good anyways), and changed calls of class from AppHelper::myMethod() to \AppHelper::myMethod() looks like eveything is working now.
In Yii2 You can use an explicit way adding \ to full namespaced name
\frontend\controllers\AppHelper
so you can sue your method
\frontend\controllers\AppHelper::yourMethod();
Solution for not lazy coders:
create component with your class so you can use it like \Yii::$app->my_component
if even this is too much and your IDE is better than Windows Notepad prepare macro that will print this for you
Solution for lazy coders:
Save your class in single PHP file without namespace.
Modify you entry script to include this class - i.e. for Basic Project Template it's /web/index.php; add there
require(__DIR__ . '/path/to/MyClass.php');
For Advanced Project Template modify it properly.
Now you can use your class by calling it like \MyClass (yes, \ is required and yes, your IDE probably will modify it anyway to MyClass with use MyClass; added at the beginning.

How to log in Cakephp vendor Table class?

I try to debug a EmailQueueTable (extends Cake\ORM\Table) located in vendor folder, but I can't find how to get logs.
I tried $this->out() (the method is called by SenderShell extends Cake\Console\Shell)
I tried $this->log
I tried Log::write
The only solution I found is to throw an Exception...
I would like to say that $this->log works well in other classes of the app.
If someone as an idea of the problem ?
Thanks a lot !
$this->log works in classes that have included the LogTrait. This includes Cake's core View, Controller and Component classes. I'm not sure why Table doesn't also include this, but you can get the same functionality with \Cake\Log\Log::write(LogLevel::ERROR, $xxx);

Grails package change for domain class caused DuplicateMappingException

While working through a tutorial to start learning Grails, I made a mistake and ran:
grails create-domain-class com.FooBar
instead of:
grails create-domain-class com.acme.FooBar
It was immediately obvious I had made an error so I tried the following:
Searched for a function that reverses the create-domain-class command, it seems there isn't one.
Searched for advice on the web and the consensus is that you can delete a domain class file, any associated views and tests, then to be safe run a text search for your class name in your project directory for any references you may have missed. I have done all this.
Then I ran the correct command to create com.acme.FooBar, which worked.
After this the app fails to run and reports the following error:
org.hibernate.DuplicateMappingException: duplicate import: FooBar refers to both com.acme.FooBar and com.FooBar (try using auto-import="false")
After adding the following code to com.acme.FooBar:
...
static mapping = {
autoImport false
}
...
The app now runs as expected.
However as an experienced Java developer who occasionally does refactor a package I would like to understand how to do that without causing a DuplicateMappingException or resorting to the "autoImport false" solution.
Thanks.
You shouldn't be doing
static mapping = {
autoImport false
}
As, by doing this you said that don't check for domain just by name and look up for package as well. Hence, once you do that you will have to use Fully qualified name of the class in your queries / hqls which may itch sometimes.
You should be removing the Domain completely i.e.
remove the Domain
remove the view folder creating by default with very same name and so do the controller
Now, do grails clean-all(Make it a thumb rule to use grails clean-all first for any issue unexpectedly occuring).
To be more accurate do remove target directory from your project and then do run grails run-app.
I had done very same thing many times and got it resolved by above steps.
Hope it helps.

Adobe Flex compiler include classes

I'm trying to create and instance of an object by reference the class object of the class using
getDefinitionByName()
the problem is that if I don't create at least one instance of the class before when try to use getDefinitionByName() it say
ReferenceError: Error #1065: Variable XXXXXX is not defined.
how can I include the class in the binary without using and instance first??, also I had tried to juts leave in the import but still don't include the class, it could be a compiler param I can pass??
I'm using Flex SDK 4.6 thanks!!!!!
As described in the documentation:
-includes class Links one or more classes to the resulting application SWF file, whether or not those classes are required at compile time
There is a bunch of compiler options which allow you to include classes, but they aren't very scalable / require some manual labour. For example, there's -includes option, but you must know what symbols to include. There's -include-libraries, but again, you'd have to compile a SWC library with the classes you need. -include-namespace - you'd need to write the namespace definition, listing all classes that you want to include.
Since I imagine that the task in the end will get automated one way or another, it would make more sense to just generate an AS file of the following format:
package your.app {
import fully.qualified.class.Name;Name; // it is enough to just mention it
. . .
}
And then include only this this class.
Well I think I found the solution, just add to the compiler the argument -includes like thised
-includes com.example.Myclass
that will include the class object in the binary even though u haven't used and after tried to load it with getDefinitionByName()
hopes this help to someone else, also here is a complete list of arguments for the compiler
http://help.adobe.com/en_US/flex/using/WS2db454920e96a9e51e63e3d11c0bf69084-7a92.html