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Screenshot of the problem provided
Was expenting output of Line 4 and Line 8 should be similar whereas experiencing difference .
Hard to tell without the source data, but I'm guessing that some students have a null for hrs_studied. Most aggregate functions skip nulls, but count(*) does not. If you replace the count(*) with a count(hrs_studied), you should get the same result as `avg(hrs_studied). I.e.:
SUM(hrs_studied) / COUNT(hrs_studied) AS agg_avg_study_time
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I am separating the comments from the code with 2 to 3 line break, but still it's getting removed.
How to fix this issue?
I have tried all the available comment syntaxes ( /**/, --, and # ), not all the comments are getting removed, but a few.
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How to retrieve all the data pertaining to company name and agent from mysql? How to write the query statement?
Have you tried this?
SELECT *
FROM agent_info
WHERE policyCompany = 'Avia' and policyAgent = 'Ron';
I have to guess because you didn't tell us much about your tables, but this might work.
SELECT policyCompany,
GROUP_CONCAT(DISTINCT policyAgent ORDER BY policyAgent) agents
FROM mytable
GROUP BY policyCompany
You can read about GROUP_CONCAT() here.
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Hello I've a little question.
Here is my query :
select *
from (select substr(filename,1,30) from reports limit 1,1)query
In my reports table I've a row named filename (VARCHAR(300))
I'm looking to select the filename row but in 30 char max
I explain, my filename "a-long-file-name-with-more-30-chars.txt"
In want to 30 first chars in a line "a-long-file-name-with-more-30-" and the rest in another line "chars.txt"
Like this (It's an inspected element)
https://i.imgur.com/EMEyiWZ.png
Somethings like this https://stackoverflow.com/a/52722082/13304872
Thank you
to recover the first part
select substr(filename,1,30) from reports limit 1,1
the second part
select substr(filename,31) from reports limit 1,1
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I need to display the list of staffs who check into work late in a week. For example the staff checks in at 8.10 when the supposed check in time is at 8.00 AM. I am using datetime for the datetimein and datetimeout field. Can anyone suggest how should I do it?
Well, with no sample tables to work from, it's hard to give a clear answer. But I think what you're looking for is the TIME() function.
This should get you started in the right direction:
SELECT * FROM timeclock_records where TIME(datetimein) > "08:00:00";
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Here im going to create a database in phpMyadmin.it shows this is not a number error.Here i have attached the image.When im going to save it shows
This is not a number!
You have to enter length for IsActive as it is of type BIT. In Mysql BIT field requires a length to be assigned.
For more details about Data types and their lengths , check out this page
http://www.tutorialspoint.com/mysql/mysql-data-types.htm
http://www.peachpit.com/articles/article.aspx?p=30885&seqNum=7