Getting wrong column default value - mysql

Question

In my MySQL, I have created a table called categories with a trending and a status column, both are set to have a default value of 0:
![the structure of the table categories in xampp mysql][1]
But when I insert a new record, the columns are set to 1, no matter if I give a value or not.
After the insert:
![the data in the table categories where none of trending and status field is selected even though showing 1 values for both trending and status][2]
Can anyone help me out to solve this error?
-code to push the data in the database is given below:
<div class="card card-outline card-info">
<div class="card-header">
<h4>
New Category
<button type="button" class="btn btn-primary btn-md
float-right" data-toggle="modal" data-target="#modal-
default">
ADD
</button>
</h4>
</div>
<div class="card-body"></div>
</div>
<div class="modal fade" id="modal-default">
<div class="modal-dialog">
<div class="modal-content">
<div class="modal-header">
<h4 class="modal-title">Add New Category</h4>
<button type="button" class="close" data-
dismiss="modal" aria-label="Close">
<span aria-hidden="true">×</span>
</button>
</div>
<form action="code.php" method="POST" id="cat_form">
<div class="modal-body">
<div class="form-group">
<label for="">Category Name</label>
<input type="text" name="name"class="form-
control" required>
</div>
<div class="form-group">
<label for="">Description</label>
<textarea name="description" class="form-
control" required rows="5">
</textarea>
</div>
<div class="form-group">
<label for="">Trending</label>
<input type="checkbox" name="trending">Trending
</div>
<div class="form-group">
<label for="">Status</label>
<input type="checkbox"name="status">Status
</div>
</div>
<div class="modal-footer justify-content-between">
<button type="button" class="btn btn-default"
data-dismiss="modal">Close</button>
<button type="submit" name="category_save"
class="btn btn-primary">Save</button>
</div>
</form>
</div>
</div>
</div>
-code for submit button:
if (isset($_POST['category_save']))
{
$name = $_POST['name'];
$description = $_POST['description'];
$trending = $_POST['trending'] = true ? '1':'0';
$status = $_POST['status'] = true ? '1':'0';
$category_query = "INSERT INTO categories
(name,description,trending,status) VALUES
('$name','$description','$trending','$status')";
$cate_query_run = mysqli_query($con, $category_query);
if ($cate_query_run)
{
echo "<script>
alert(' - Category Inserted Succesfully!');
window.location.href='category.php';
</script>";
}
else
{
echo "<script>
alert(' - Category Insertion Failed!');
window.location.href='category.php';
</script>";
}
}
table structure before data insertion
[1]: https://i.stack.imgur.com/SEX7H.png
table after data insertion
[2]: https://i.stack.imgur.com/dPfmo.png
thanks in advance

Answer 1

If you just want to get "1" when checked and "0" when unchecked.
The HTML and PHP code below should be able to help you
<form name="myForm" id="myForm" method="post" action="my_page.php">
<input type="checkbox" name="myCase" id="myCase" value="1"><label for="myCase">My Case</label>
</form>
And "my_page.php" code
$myCase = (isset($_POST["myCase"]))?$_POST["myCase"]:"0";
echo "<br />myCase : ".$myCase;