i want to use seleted value in if sentence
ex)
select
(SELECT
ifnull(ROUND( count(case when a= 1 then 1 end) / count(case when a!=9 then 1 end) *100), 0)
FROM
ctable qt
where
qt.parent_id = t.id
) as percentage,
if (percentage = 100, 'pass', 'fail') as 'result'
from table t
where
top = 1;
parent_id
parent_id
top
a
0
null
1
0
1
0
0
1
percentage
result
100
true
Related
Given SQL: Is there a way to bring in the total of the result set?
SELECT
SUM(CASE
WHEN status = 3 THEN 1
ELSE 0
END) AS Open,
SUM(CASE
WHEN status = 4 THEN 1
ELSE 0
END) AS Close
FROM
Table1
WHERE
id = 2;
Result:
Open,Close
5,5
Desired Result:
Open,Close,Total
5,5,10
just add another case statement
SELECT
SUM(CASE
WHEN status = 3 THEN 1
ELSE 0
END) AS Open,
SUM(CASE
WHEN status = 4 THEN 1
ELSE 0
END) AS Close
SUM(CASE
WHEN status IN (3, 4) THEN 1
ELSE 0
END) AS Total
FROM
Table1
WHERE
id = 2;
You can use a CTE:
WITH sumCase AS (
SELECT
SUM(CASE
WHEN status = 3 THEN 1
ELSE 0
END) AS Open,
SUM(CASE
WHEN status = 4 THEN 1
ELSE 0
END) AS Close
FROM
Table1
WHERE
id = 2;)
SELECT Open,Close, Open + Close AS Total FROM Table1;
http://www.mysqltutorial.org/mysql-cte/
using sub-query
select open,close,open+close as total from
(
SELECT
SUM(CASE WHEN status = 3 THEN 1
ELSE 0
END ) AS Open,
SUM(CASE WHEN status = 4 THEN 1
ELSE 0
END) AS Close
FROM
Table1
WHERE id = 2 ) as T
This MySQL query gives me this error 'Unknown column 'winnings' in 'field list'
SELECT
o.user_id,
sum(case when o.result = 1 or o.result=2 or o.result = 0 then 1 else 0 end) as tahmins_no,
sum(case when o.result = 1 then 1 else 0 end) as winnings,
sum(case when o.result = 2 then 1 else 0 end) as loses,
sum(case when winnings = 10 then 0.5 else 0 end) as counter
FROM `odds_tahminler` o
I know that winnings is the value of the sum() aggregation function, But is there any way to check the winnings value within the query?
You can't use an aggregated column inside the select. However you can use a subquery to obtain the counter value after all the aggregated columns have been computed.
How is the counter value calculated? I assumed that the counter should be (winnings - 10) / 2 if there's at least 10 winnings and 0 otherwise. In that case you can obtain it with this query
SELECT O.*,
GREATEST( (O.winnings - 10) / 2, 0) as counter
FROM
(
SELECT u.username,
o.user_id,
sum(case when o.result = 1 or o.result=2 or o.result = 0 then 1 else 0 end) as tahmins_no,
sum(case when o.result = 1 then 1 else 0 end) as winnings,
sum(case when o.result = 2 then 1 else 0 end) as loses
FROM `odds_tahminler` o
) as O
you can try:
SELECT
o.user_id,
sum(case when o.result = 1 or o.result=2 or o.result = 0 then 1 else 0 end) as tahmins_no,
sum(case when o.result = 1 then 1 else 0 end) as winnings,
sum(case when o.result = 2 then 1 else 0 end) as loses,
sum(case when winnings = 10 then 0.5 else 0 end) as counter
FROM `odds_tahminler` o
GROUP BY o.user_id
HAVING counter>2
SELECT NAMA_DUN,
COUNT(case when ((RIGHT(noMyKid, 1))% 2) = 0 then 1 else 0 end) AS FEMALE,
COUNT(case when ((RIGHT(noMyKid, 1))% 2) = 1 then 1 else 0 end) AS MALE,
COUNT(DISTINCT(noMyKid)) as jumlah
FROM mohon
LEFT JOIN dun ON dun.KOD_DUN=mohon.dun_nama
WHERE status_proses = 'diproses'
AND concat('20', substr(noMyKid, 1, 2)) = '2008'
AND status_mohon = 'Layak'
AND status_semak = '1'
AND (
status_bayar = ''
OR status_bayar = 'Belum'
OR status_bayar = 'Sudah')
AND (
status_terima = ''
OR status_terima = 'Terima'
) GROUP BY dun_nama
ORDER BY NAMA_DUN
This is my mysql code. why is my 'COUNT CASE WHEN' give the same output for female and male column.
Usually COUNT() is used to count rows and is therefore very often used in the form COUNT(*). When you use a field (or anything else) as a parameter into the COUNT() it counts 1 for every no NULL value.
In your case all your values are not NULL (they are either 1 or 0) and consequently you end up with the same results.
So Abhik Chakraborty is right, use SUM() and everything should be fine.
The COUNT() function does only recognize non-null values, so when using case expressions such as you have here, you can explicitly return NULL where needed
SELECT NAMA_DUN,
COUNT(case when ((RIGHT(noMyKid, 1))% 2) = 0 then 1 else NULL end) AS FEMALE,
COUNT(case when ((RIGHT(noMyKid, 1))% 2) = 1 then 1 else NULL end) AS MALE,
COUNT(DISTINCT(noMyKid)) as jumlah
OR, implicitly return NULL by ignoring the else condition
SELECT NAMA_DUN,
COUNT(case when ((RIGHT(noMyKid, 1))% 2) = 0 then 1 end) AS FEMALE,
COUNT(case when ((RIGHT(noMyKid, 1))% 2) = 1 then 1 end) AS MALE,
COUNT(DISTINCT(noMyKid)) as jumlah
OR, mimic the effect of count by using SUM() provided you do use 1 and 0 (or 1 and NULL)
SELECT NAMA_DUN,
SUM(case when ((RIGHT(noMyKid, 1))% 2) = 0 then 1 else 0 end) AS FEMALE,
SUM(case when ((RIGHT(noMyKid, 1))% 2) = 1 then 1 else 0 end) AS MALE,
COUNT(DISTINCT(noMyKid)) as jumlah
I have two tables as below
tbl1
id qNum
1 1
2 2
3 3
tbl2
id qNum displayNum
1 1 3
2 2 1
3 2 2
4 2 4
Ideally I need a sql results to look like this
qNum display1 display2 display3 display4
1 0 0 1 0
2 1 1 0 1
3 0 0 0 0
I have tried the following sql but this was not correct
SELECT
tbl1.qNum,
CASE when tbl2.displayNum=1 then 1 else 0 end AS filter1,
CASE when tbl2.displayNum=2 then 1 else 0 end AS filter2,
CASE when tbl2.displayNum=3 then 1 else 0 end AS filter3,
CASE when tbl2.displayNum=4 then 1 else 0 end AS filter4,
CASE when tbl2.displayNum=5 then 1 else 0 end AS filter5
FROM
tbl1
Left Join tbl2 ON tbl1.qNum = tbl2.qNum
GROUP BY
tbl1.qNum
Could anyone help a little please!!
You have use MAX function to pivot the table
Try this:
SELECT tbl1.qNum,
MAX(CASE WHEN tbl2.displayNum=1 THEN 1 ELSE 0 END) AS filter1,
MAX(CASE WHEN tbl2.displayNum=2 THEN 1 ELSE 0 END) AS filter2,
MAX(CASE WHEN tbl2.displayNum=3 THEN 1 ELSE 0 END) AS filter3,
MAX(CASE WHEN tbl2.displayNum=4 THEN 1 ELSE 0 END) AS filter4,
MAX(CASE WHEN tbl2.displayNum=5 THEN 1 ELSE 0 END) AS filter5
FROM tbl1
LEFT JOIN tbl2 ON tbl1.qNum = tbl2.qNum
GROUP BY tbl1.qNum
Your query is almost correct, you're just missing an aggregate function:
SELECT
tbl1.qNum,
MAX(CASE when tbl2.displayNum=1 then 1 else 0 end) AS filter1,
MAX(CASE when tbl2.displayNum=2 then 1 else 0 end) AS filter2,
MAX(CASE when tbl2.displayNum=3 then 1 else 0 end) AS filter3,
MAX(CASE when tbl2.displayNum=4 then 1 else 0 end) AS filter4,
MAX(CASE when tbl2.displayNum=5 then 1 else 0 end) AS filter5
FROM
tbl1
Left Join tbl2 ON tbl1.qNum = tbl2.qNum
GROUP BY
tbl1.qNum
The columns you select should always be either in the group by clause or an aggregate function should be applied to them. A group by "collapses" a group of rows and if you don't have an aggregate function on a column (which is not in the group by) a random row of that group is displayed.
Here you can read about the different aggregate functions: GROUP BY (Aggregate) Functions
The MAX() function in our case here returns the greatest value (note: not the row with the greatest value. You can also have a query like this: select min(col), max(col) from whatever).
I just want to point out that in MySQL, you can simplify the expression. It doesn't need a case statement because booleans are treated as integers with values of 0 and 1:
SELECT tbl1.qNum,
MAX(tbl2.displayNum = 1) AS filter1,
MAX(tbl2.displayNum = 2) AS filter2,
MAX(tbl2.displayNum = 3) AS filter3,
MAX(tbl2.displayNum = 4) AS filter4,
MAX(tbl2.displayNum = 5) AS filter5
FROM tbl1 Left Join
tbl2
ON tbl1.qNum = tbl2.qNum
GROUP BY tbl1.qNum;
Normally, I prefer going with ANSI standard syntax. I do, however, find this easier to read than the case syntax.
Also, you may not need tbl1 for the query, if all values you are interested in are already in tbl2.
I have tables table_one, table_two, table_three, table_four all structure is about same.
it has columns id, name, status, user_id.
i.g. i have user John with user_id 345 in every table multiple times except table_four. and status for some entrys is 1 and other entry's is 0
Now i need to count with one query how many times status for this user was 1 in each of this tables.
So i do:
SELECT table_one.user_id,
SUM(CASE WHEN table_one.status = 1 THEN 1 ELSE 0 END) AS count_tblone
SUM(CASE WHEN table_two.status = 1 THEN 1 ELSE 0 END) AS count_tbltwo
SUM(CASE WHEN table_three.status = 1 THEN 1 ELSE 0 END) AS count_tblthree
SUM(CASE WHEN table_four.status = 1 THEN 1 ELSE 0 END) AS count_tblfour
FROM table_one
LEFT JOIN table_one ON table_one.user_id = table_one.user_id
LEFT JOIN table_two ON table_two.user_id = table_one.user_id
LEFT JOIN table_three ON table_three.user_id = table_one.user_id
LEFT JOIN table_four ON table_four.user_id = table_one.user_id
WHERE tbl_one.user_id = 345
Problem is that request outputs 4, 0, 0, 0 when it should be 2, 1, 1, 0
IF i just leave SUM(CASE WHEN table_one.status = 1 THEN 1 ELSE 0 END) AS count_tblone - count_tblone will equal 4 even if in table_one - status field equals 1 in only two records for user 345.
It's a lot more typing, but I'd recommend UNION, especially if user might not be in table_one.
SELECT
SUM(count_tblone) AS count_tblone,
SUM(count_tbltwo) AS count_tbltwo,
SUM(count_tblthree) AS count_tblthree,
SUM(count_tblfour) AS count_tblfour
FROM (
SELECT
SUM(CASE WHEN table_one.status = 1 THEN 1 ELSE 0 END) AS count_tblone,
0 AS count_tbltwo,
0 AS count_tblthree,
0 AS count_tblfour
FROM table_one
WHERE tbl_one.user_id = 345
UNION
SELECT
0 AS count_tblone,
SUM(CASE WHEN table_two.status = 1 THEN 1 ELSE 0 END) AS count_tbltwo,
0 AS count_tblthree,
0 AS count_tblfour
FROM table_two
WHERE tbl_one.user_id = 345
UNION
... tables 3 and 4 ...
) AS tblMyUnionedTables