Maintain multiple row data in single row mysql [duplicate] - mysql

This question already has answers here:
How can I return pivot table output in MySQL?
(10 answers)
Closed 9 days ago.
There is my table look like
id
name
deduction
amount
01
teat
Home Rent
1000
01
test
GPF
500
i want show my data in deduction report like below table
id
name
home_rent
gpf
01
teat
1000
500
mysql code
SELECT a.* , a.amount as home_rent ,b.amount as gpf FROM my_table as a ,my_table as b where a.deduction = Home Rent and b.deduction = GPF
what i have done wrong please let me know ? what can i do for my report to it look like my second table thank you ...

We can use conditional aggregation and pivoting here:
SELECT
id,
name,
MAX(CASE WHEN deduction = 'Home Rent' THEN amount END) AS home_rent,
MAX(CASE WHEN deduction = 'GPF' THEN amount END) AS gpf
FROM my_table
GROUP BY 1, 2;

use conditional aggregation
Schema (MySQL v5.7)
CREATE TABLE my_table (
`id` INTEGER,
`name` VARCHAR(4),
`deduction` VARCHAR(9),
`amount` INTEGER
);
INSERT INTO my_table
(`id`, `name`, `deduction`, `amount`)
VALUES
('01', 'test', 'Home Rent', 1000),
('01', 'test', 'GPF', 500);
Query #1
SELECT
id,
name,
SUM(CASE WHEN deduction = 'Home Rent' THEN amount ELSE 0 END) AS home_rent,
SUM(CASE WHEN deduction = 'GPF' THEN amount ELSE 0 END) AS gpt
FROM my_table
GROUP BY 1, 2;
id
name
home_rent
gpt
1
test
1000
500
View on DB Fiddle

Related

Group by column. If null, group by other column MySQL

I have this query:
SELECT
vcl.id,
vcl.batch_id,
vcl.type,
vcl.amount,
vcl.date
FROM vrcorporateledger vcl
LEFT JOIN payroll_list pl ON pl.id = vcl.batch_id
which gives the following output:
Whenever there is "CREDIT" in col type I want to increase the running balance by the value in col amount; whenever there is "DEBIT" in col type I want to decrease the accumulated balance by the value in col amount after grouping by batch_id col. So expected result is:
1000-2+5-4-49=950.
If possible I want to also create a column "balance" where at each point/step I see the resulting balance.
expected output like:
WITH cte AS (
SELECT type,
SUM(amount) OVER (PARTITION BY CASE type WHEN 'CREDIT' THEN RAND()
WHEN 'DEBIT' THEN batchID
ELSE 0 END ) amount,
MIN(`date`) OVER (PARTITION BY CASE type WHEN 'CREDIT' THEN RAND()
WHEN 'DEBIT' THEN batchID
ELSE 0 END ) `date`,
SUM(CASE type WHEN 'CREDIT' THEN amount
WHEN 'DEBIT' THEN -amount
ELSE 0 END) OVER (ORDER BY `date`) balance,
batchID,
LEAD(batchID) OVER (ORDER BY `date`) next_batchID
FROM source_data
)
SELECT type,
amount,
balance,
`date`
FROM cte
WHERE CASE WHEN batchID = next_batchID THEN 0 ELSE 1 END
https://dbfiddle.uk/?rdbms=mysql_8.0&fiddle=75255728f6d64a91a2ebf62edc2d0a0b
I think you're looking for SQL Window functions. They basically allow you to do an aggregate "over a partition".
On a side note: This is a really bad way of calculating doing running balance.
I would strongly suggest storing balance in a separate column at runtime. This should allow you to:
have a strict check even when rows are changed or deleted
normal speed when you have millions of records
If your MySQL version is 8 or above then you can use common table expression with window function as below:
Schema (MySQL v8.0)
create table vrcorporateledger (id int,batch_id int,type varchar(10),amount float,Tdate timestamp);
insert into vrcorporateledger values (1,null,'CREDIT',1000,'2021/03/04 06:19:00');
insert into vrcorporateledger values (2,1,'DEBIT',1,'2021/03/04 07:00:19');
insert into vrcorporateledger values (3,1,'DEBIT',1,'2021/03/04 07:00:25');
insert into vrcorporateledger values (4,null,'CREDIT',5,'2021/03/05 06:19:00');
insert into vrcorporateledger values (5,2,'DEBIT',1,'2021/03/04 08:58:10');
insert into vrcorporateledger values (6,2,'DEBIT',3,'2021/03/04 08:58:16');
insert into vrcorporateledger values (7,null,'DEBIT',49,'2021/03/04 16:42:33');
Query #1
WITH cte AS (
SELECT id,type,
(case when batch_id is null then (case when type='DEBIT' then -amount else amount end) else
SUM(case when type='DEBIT' then -amount else amount end) OVER (PARTITION BY batch_id)end) amount,
(case when batch_id is null then Tdate else
MIN(Tdate) OVER (PARTITION BY batch_id ) end) Trandate,
batch_id,
LEAD(batch_id) OVER (ORDER BY id) next_batch
FROM vrcorporateledger
)
SELECT type,
amount,
sum(amount)over(order by id) running_balance,
Trandate date
FROM cte
WHERE batch_id is null or batch_id =next_batch
order by id;
type
amount
date
running_balance
CREDIT
1000
2021-03-04 06:19:00
1000
DEBIT
-2
2021-03-04 07:00:19
998
CREDIT
5
2021-03-05 06:19:00
1003
DEBIT
-4
2021-03-04 08:58:10
999
DEBIT
-49
2021-03-04 16:42:33
950
View on DB Fiddle

SQL - PIVOT for one column and add new column

I am fairly new to SQL. I have got this input table as
TypeId EventDescription FeedHeader FeedHeaderValue
---------------------------------------------------------
166 Financial AllocRule 130
166 Financial DealID 0
175 Partner Capital InvestorID OV_P1
175 Investment Querter Q1
175 Investment DealID offset
175 Investment InvestorID OV_P2
I need an output as follows
Financial value Partner Capital value Investment value
-------------------------------------------------------------------------------
AllocRule 130 InvestorID OV_P1 Querter Q1
DealID 0 DealID offset
InvestorID OV_P2
Not sure if that is even possible. I tried using pivot but its not giving desired output
select
[Financial] as FinancialHeader
, [Partner Capital] as PartnerCapitalHeader
, [Investment] as Investmentheader
from
(
select EventDescription, FeedHeader
from [Feeder]
) x
pivot
(
MAX(FeedHeader)
for EventDescription in([Financial], [Partner Capital], [Investment])
)p
Another approach i tried
Select
Min(Case [EventDescription] When 'Financial' Then [FeedHeader] End)
Financial,
Min(Case [EventDescription] When 'Financial' Then [FeedHeaderValue] End)
value,
Min(Case [EventDescription] When 'Partner Capital' Then [FeedHeader]
End) PartnerCapital,
Min(Case [EventDescription] When 'Partner Capital' Then
[FeedHeaderValue] End) value,
Min(Case [EventDescription] When 'Investment' Then [FeedHeader] End)
Investment,
Min(Case [EventDescription] When 'Investment' Then [FeedHeaderValue] End)
value
From [Feeder]
Group By EventDescription
Is there a another way to do it?
I was curious and did some research with PIVOT on SO and google and finally my luck clicked (at least what I think now)
The key point here is that you create new EventDescription values by appending 1 or 2 to the end depending on how many columns we want to PIVOT.
Without doing this, the pivot query won't work properly and would lead to error as per my experience with this task.
select max([Financial]) as FinancialHeader
, max([Financial1]) as FinancialHeaderValue
, max([Partner Capital]) as PartnerCapitalHeader
, max([Partner Capital1]) as PartnerCapitalHeaderValue
, max([Investment]) as InvestmentHeader
, max([Investment1]) as InvestmentHeaderValue
from
(select EventDescription,
EventDescription+'1' as EventDescription1,
FeedHeader,
FeedHeaderValue,
row_number() over (partition by EventDescription order by EventDescription) rn
from [testtable]
) x
pivot
(
MAX(FeedHeader)
for EventDescription in([Financial], [Partner Capital], [Investment])
) p
pivot
(
MAX(FeedHeaderValue)
for EventDescription1 in([Financial1], [Partner Capital1] , [Investment1] )
) v
group by [RN]
DEMO: db<>fiddle

SQL multi query

I need some help to do it right in one query (if it possible).
(this is a theoretical example and I assume the presence of events in event_name(like registration/action etc)
I have 3 colums:
-user_id
-event_timestamp
-event_name
From this 3 columns we need to create new table with 4 new columns:
-user year and month registration time
-number of new user registration in this month
-number of users who returned to the second calendar month after registration
-return probability
Result must be looks like this:
2019-1 | 1 | 1 | 100%
2019-2 | 3 | 2 | 67%
2019-3 | 2 | 0 | 0%
What I've done now:
I'm use this toy example of my possible main table:
CREATE TABLE `main` (
`event_timestamp` timestamp,
`user_id` int(10),
`event_name` char(12)
) DEFAULT CHARSET=utf8;
INSERT INTO `main` (`event_timestamp`, `user_id`, `event_name`) VALUES
('2019-01-23 20:02:21.550', '1', 'registration'),
('2019-01-24 20:03:21.550', '2', 'action'),
('2019-02-21 20:04:21.550', '3', 'registration'),
('2019-02-22 20:05:21.550', '4', 'registration'),
('2019-02-23 20:06:21.550', '5', 'registration'),
('2019-02-23 20:06:21.550', '1', 'action'),
('2019-02-24 20:07:21.550', '6', 'action'),
('2019-03-20 20:08:21.550', '3', 'action'),
('2019-03-21 20:09:21.550', '4', 'action'),
('2019-03-22 20:10:21.550', '9', 'action'),
('2019-03-23 20:11:21.550', '10', 'registration'),
('2019-03-22 20:10:21.550', '4', 'action'),
('2019-03-22 20:10:21.550', '5', 'action'),
('2019-03-24 20:11:21.550', '11', 'registration');
I'm trying to test some queries to create 4 new columns:
This is for column #1, we select month and year from timestamp where action is registration (as I guess), but I need to sum it for month (like 2019-11, 2019-12)
SELECT DATE_FORMAT(event_timestamp, '%Y-%m') AS column_1 FROM main
WHERE event_name='registration';
For column #2 we need to sum users with even_name registration in this month for every month, or.. we can trying for searching first time activity by user_id, but I don't know how to do this.
Here is some thinks about it...
SELECT COUNT(DISTINCT user_id) AS user_count
FROM main
GROUP BY MONTH(event_timestamp);
SELECT COUNT(DISTINCT user_id) AS user_count FROM main
WHERE event_name='registration';
For column #3 we need to compare user_id with the event_name registration and last month event with any event of the second month so we get users who returned for the next month.
Any idea how to create this query?
This is how to calc column #4
SELECT *,
ROUND ((column_3/column_2)*100) AS column_4
FROM main;
I hope you will find the following answer helpful.
The first column is the extraction of year and month. The new_users column is the COUNT of the unique user ids when the action is 'registration' since the user can be duplicated from the JOIN as a result of taking multiple actions the following month. The returned_users column is the number of users who have an action in the next month from the registration. The returned_users column needs a DISTINCT clause since a user can have multiple actions during one month. The final column is the probability that you asked from the two previous columns.
The JOIN clause is a self-join to bring the users that had at least one action the next month of their registration.
SELECT CONCAT(YEAR(A.event_timestamp),'-',MONTH(A.event_timestamp)),
COUNT(DISTINCT(CASE WHEN A.event_name LIKE 'registration' THEN A.user_id END)) AS new_users,
COUNT(DISTINCT B.user_id) AS returned_users,
CASE WHEN COUNT(DISTINCT(CASE WHEN A.event_name LIKE 'registration' THEN A.user_id END))=0 THEN 0 ELSE COUNT(DISTINCT B.user_id)/COUNT(DISTINCT(CASE WHEN A.event_name LIKE 'registration' THEN A.user_id END))*100 END AS My_Ratio
FROM main AS A
LEFT JOIN main AS B
ON A.user_id=B.user_id AND MONTH(A.event_timestamp)+1=MONTH(B.event_timestamp)
AND A.event_name='registration' AND B.event_name='action'
GROUP BY CONCAT(YEAR(A.event_timestamp),'-',MONTH(A.event_timestamp))
What we will do is to use window functions and aggregation -- window functions to get the earliest registration date. Then some conditional aggregation.
One challenge is the handling of calendar months. To handle this, we will truncate the dates to the beginning of the month to facilitate the date arithmetic:
select yyyymm_reg, count(*) as regs_in_month,
sum( month_2 > 0 ) as visits_2months,
avg( month_2 > 0 ) as return_rate_2months
from (select m.user_id, m.yyyymm_reg,
max( (timestampdiff(month, m.yyyymm_reg, m.yyyymm) = 1) ) as month_1,
max( (timestampdiff(month, m.yyyymm_reg, m.yyyymm) = 2) ) as month_2,
max( (timestampdiff(month, m.yyyymm_reg, m.yyyymm) = 3) ) as month_3
from (select m.*,
cast(concat(extract(year_month from event_timestamp), '01') as date) as yyyymm,
cast(concat(extract(year_month from min(case when event_name = 'registration' then event_timestamp end) over (partition by user_id)), '01') as date) as yyyymm_reg
from main m
) m
where m.yyyymm_reg is not null
group by m.user_id, m.yyyymm_reg
) u
group by u.yyyymm_reg;
Here is a db<>fiddle.
Here you go, done in T-SQL:
;with cte as(
select a.* from (
select form,user_id,sum(count_regs) as count_regs,sum(count_action) as count_action from (
select FORMAT(event_timestamp,'yyyy-MM') as form,user_id,event_name,
CASE WHEN event_name = 'registration' THEN 1 ELSE 0 END as count_regs,
CASE WHEN event_name = 'action' THEN 1 ELSE 0 END as count_action from main) a
group by form,user_id) a)
select final.form,final.count_regs,final.count_action,((CAST(final.count_action as float)/(CASE WHEN final.count_regs = '0' THEN '1' ELSE final.count_regs END))*100) as probability from (
select a.form,sum(a.count_regs) count_regs,CASE WHEN sum(b.count_action) is null then '0' else sum(b.count_action) end count_action from cte a
left join
cte b
ON a.user_id = b.user_id and
DATEADD(month,1,CONVERT(date,a.form+'-01')) = CONVERT(date,b.form+'-01')
group by a.form ) final where final.count_regs != '0' or final.count_action != '0'

How to get summary data for every months in mysql

I want to count the number of items sold(item_count) every month for every item,
--
-- Table structure for table `sales`
--
CREATE TABLE `sales` (
`id` int(11) NOT NULL,
`item_id` int(11) NOT NULL,
`date` date NOT NULL,
`item_count` int(11) NOT NULL,
`amount` float NOT NULL
) ENGINE=InnoDB DEFAULT CHARSET=latin1;
--
-- Dumping data for table `sales`
--
INSERT INTO `sales` (`id`, `item_id`, `date`, `item_count`, `amount`) VALUES
(1, 1, '2018-01-15', 11, 110),
(2, 2, '2018-01-21', 5, 1000),
(3, 1, '2018-02-02', 7, 700),
(4, 2, '2018-02-11', 3, 3000);
I have tried this SQL, but it's not showing the data correctly.
SELECT `sales`.`item_id`,
(CASE WHEN MONTH(sales.date)=1 THEN sum(sales.item_count) ELSE NULL END) as JAN,
(case when MONTH(sales.date)=2 THEN sum(sales.item_count) ELSE NULL END) as FEB
FROM sales WHERE 1
GROUP BY sales.item_id
ORDER BY sales.item_id
This is my expected result,
item_id JAN FEB
1 11 7
2 5 3
I am getting this,
item_id JAN FEB
1 18 NULL
2 8 NULL
Here is an immediate fix to your query. You need to sum over a CASE expression, rather than the other way around.
SELECT
s.item_id,
SUM(CASE WHEN MONTH(s.date) = 1 THEN s.item_count END) AS JAN,
SUM(CASE WHEN MONTH(s.date) = 2 THEN s.item_count END) AS FEB
FROM sales s
GROUP BY
s.item_id
ORDER BY
s.item_id;
But the potential problem with this query is that in order to support more months, you need to add more columns. Also, if you want to cover mulitple years, then this approach also might not scale. Assuming you only have a few items, here is another way to do this:
SELECT
DATE_FORMAT(date, '%Y-%m') AS ym,
SUM(CASE WHEN item_id = 1 THEN item_count END) AS item1_total,
SUM(CASE WHEN item_id = 2 THEN item_count END) AS item2_total
FROM sales
GROUP BY
DATE_FORMAT(date, '%Y-%m');
This would generate output looking something like:
ym item1_total item2_total
2018-01 11 5
2018-02 7 3
Which version you use depends on how many months your report requires versus how many items might appear in your data.

How to calculate ratio using sql query?

I have a table like below:
ID Name Department Gender
1 Crib MA MALE
2 Lucy Bsc FEMALE
3 Phil Bcom MALE
4 Ane MA FEMALE
I have 1000 row of records like this. I want to find the ratio from column Gender( MALE & FEMALE) of all students.
I need a query to perform this.
SQL Fiddle
MySQL 5.5.32 Schema Setup:
CREATE TABLE table1
(`ID` int, `Name` varchar(4), `Department` varchar(4), `Gender` varchar(6))
;
INSERT INTO table1
(`ID`, `Name`, `Department`, `Gender`)
VALUES
(1, 'Crib', 'MA', 'MALE'),
(2, 'Lucy', 'Bsc', 'FEMALE'),
(3, 'Phil', 'Bcom', 'MALE'),
(4, 'Ane', 'MA', 'FEMALE')
;
Query 1:
SELECT sum(case when `Gender` = 'MALE' then 1 else 0 end)/count(*) as male_ratio,
sum(case when `Gender` = 'FEMALE' then 1 else 0 end)/count(*) as female_ratio
FROM table1
Results:
| MALE_RATIO | FEMALE_RATIO |
|------------|--------------|
| 0.5 | 0.5 |
Try something like this
select sum(case when gender = 'MALE' then 1 else 0 end) / count(*) * 100 as perc_male,
sum(case when gender = 'FEMALE' then 1 else 0 end) / count(*) * 100 as perc_female
from students
This should give you the actual ratio, and should work with little or no modifcation in MySQL and SQL Server. You may have to modify the cast statement a little - my MySQL is rusty, and I think it may handle that slightly differently.
SELECT
(CAST((SELECT COUNT(*) FROM tblName WHERE Gender='MALE') AS FLOAT) /
CAST((SELECT COUNT(*) FROM tblName WHERE Gender='FEMALE') AS FLOAT))
AS ratioMaleFemale;
You're pretty close:
select (select count(*)
from table where gender='MALE' )/count(*)*100 as percentage_male,
(select count(*)
from table where gender='FEMALE' )/count(*)*100 as percentage_female
from table;
How about
select gender, count(*)
from table
group by gender
then it's very simple to calculate the ratio yourself.