Is it possible to search of a text in SSRS via Filters? - reporting-services

Question

I would like to have a multiple values Paramter with text1, text2, text3
SSRS should only show me the rows that contain one or all of this Parameter values in a column.
I notice you can set a filter in a Dataset or the tablix. The problem is I do not have something a function that do both LIKE and IN
Do you someone have an idea?
I tried already the LIKE function and the VALUE =”*”+”Parameters!PAR.Value”+”*”.
It did work, but not on a multiple values parameter.

Answer 1

I don't think you will be able to do this using dataset filters using a multi-value parameter.
However, you should be able to change your dataset query to handle this.
CREATE PROC myProc (#myParameter varchar(1000))
AS
SELECT * FROM myTable t
JOIN string_split(#myParameter, ',') p on t.myColumn like '%' + p.value + '%'
When you pass the parameter to the stored proc you can use the following expression
=JOIN(Parameters!myParameter.Value, ",")
This will simply join each of your parameter values into a single comma separated string string ready to pass to the procedure.
If you do not have a version of SQL Server that support string_split
Hers's the code to create one. There are smaller versions around on the internet but this one was designed to handle special cases as well as the typical single character delimiters.
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
CREATE FUNCTION [Split](#sText varchar(8000), #sDelim varchar(20) = ' ')
RETURNS #retArray TABLE (idx smallint Primary Key, value varchar(8000))
AS
BEGIN
DECLARE #idx smallint,
#value varchar(8000),
#bcontinue bit,
#iStrike smallint,
#iDelimlength tinyint
IF #sDelim = 'Space'
BEGIN
SET #sDelim = ' '
END
SET #idx = 0
SET #sText = LTrim(RTrim(#sText))
SET #iDelimlength = DATALENGTH(#sDelim)
SET #bcontinue = 1
IF NOT ((#iDelimlength = 0) or (#sDelim = 'Empty'))
BEGIN
WHILE #bcontinue = 1
BEGIN
--If you can find the delimiter in the text, retrieve the first element and
--insert it with its index into the return table.
IF CHARINDEX(#sDelim, #sText)>0
BEGIN
SET #value = SUBSTRING(#sText,1, CHARINDEX(#sDelim,#sText)-1)
BEGIN
INSERT #retArray (idx, value)
VALUES (#idx, #value)
END
--Trim the element and its delimiter from the front of the string.
--Increment the index and loop.
SET #iStrike = DATALENGTH(#value) + #iDelimlength
SET #idx = #idx + 1
SET #sText = LTrim(Right(#sText,DATALENGTH(#sText) - #iStrike))
END
ELSE
BEGIN
--If you can't find the delimiter in the text, #sText is the last value in
--#retArray.
SET #value = #sText
BEGIN
INSERT #retArray (idx, value)
VALUES (#idx, #value)
END
--Exit the WHILE loop.
SET #bcontinue = 0
END
END
END
ELSE
BEGIN
WHILE #bcontinue=1
BEGIN
--If the delimiter is an empty string, check for remaining text
--instead of a delimiter. Insert the first character into the
--retArray table. Trim the character from the front of the string.
--Increment the index and loop.
IF DATALENGTH(#sText)>1
BEGIN
SET #value = SUBSTRING(#sText,1,1)
BEGIN
INSERT #retArray (idx, value)
VALUES (#idx, #value)
END
SET #idx = #idx+1
SET #sText = SUBSTRING(#sText,2,DATALENGTH(#sText)-1)
END
ELSE
BEGIN
--One character remains.
--Insert the character, and exit the WHILE loop.
INSERT #retArray (idx, value)
VALUES (#idx, #sText)
SET #bcontinue = 0
END
END
END
RETURN
END
GO
To test this try something like
select * from Split('abc,def,ghi', ',')
which will return