I have a variable link, which sends a form but when the post happens I want the link to continue with the variable, this is my simplified code:
#app.route('/copass/<string:cod_ver>', methods=['GET', 'POST'])
def copass(cod_ver):
rut_gen="/copass/{}".format(cod_ver)
if request.method == 'POST':
"""Here is more code but it is not relevant, it is just compilation of the same form."""
return render_template('user/cam_pass.html',rut_gen=rut_gen)
else:
return render_template('user/cam_pass.html',rut_gen=rut_gen)
this is my form in html cam_pass:
<form action="{{ url_for(rut_gen) }}" method="post">
<input type="hidden" name="cod_fpass" value="{{cod_fpass}}"/>
<!--here are some input for the post -->
</form>
I have been looking at various comments about this error but it still isn't clear to me how to fix it, I have tried several but they haven't worked.
I hope that the variable link remains when I post
it was very easy, have solved, don't have to use the function url_for(), only you have to send the run_gen to form
this is coding in python:
from flask import Flask
from flask import render_template, request, redirect, url_for, flash, session,get_flashed_messages
app = Flask(__name__)
#app.route('/copass/<string:cod_ver>', methods=['GET', 'POST'])
def copass(cod_ver):
print("entro copass")
#print(url_for('/copass/{}'.format(cod_ver)))
url='/copass/{}'.format(cod_ver)
if request.method == 'POST':
return render_template('test.html',cod_fpass=cod_ver,url=url)
else:
return render_template('test.html',cod_fpass=cod_ver,url=url)
if __name__ == '__main__':
app.run()
this is coding html:
<form action="{{url}}" method="post">
<input name="cod_fpass" value="{{cod_fpass}}"/>
<input class="button-r" type="submit" value="REGISTER" />
</form>
Related
I am trying to build a login module in django. I already have a nice HTML form for login which has username and password field.
But in my views.py I have imported default Django AuthenticationForm, but if integrate it with my nice-looking HTML form, there will be two forms. How can I import the Authentication form and use it with the my HTML form??
My code is here:
My view:
def login(request):
if request.method == 'POST':
form = AuthenticationForm(data=request.POST)
if form.is_valid():
user = form.get_user()
authlog(request, user)
return redirect('home')
else:
messages.error(request, 'Invalid username or password')
# back_page = request.META.get('HTTP_REFERER')
return redirect('login')
# return HttpResponse(back_page)
else:
content = {
'form': AuthenticationForm()
}
return render(request, 'sign-in.html', content)
If I use Django default form, the code will be following, but it won't look good as my other Html login page.
My sign-in html:
<hr>
<form action="" method="post">
{% csrf_token %}
{{form|crispy}}
<button type="submit" class=" btn btn-success ">Sign-Up</button>
</form>
I haven't posted my other HTML form though as it is very large. Hope it explains.
I'm currently using django version 2.2.4 and trying to create an edit button that will update my models. When trying to save the updated value an TypeError occured which it stated that "full_clean() missing 1 required positional argument: 'self'". I can't seem to detect any error from my codes. Thanks in advance for helping me.
my views.py file
def lab_edit(request, pk, template_name='webapp/lab_edit.html'):
lab= get_object_or_404(Labs, pk=pk)
form = LabForm(request.POST or None, instance=Labs)
if request.method == "POST":
if form.is_valid():
form.save()
return redirect('lab')
return render(request, template_name, {'form':form})
my lab_edit.html file
<div class='container'>
<h2>EDIT LAB</h2>
<form method="post">{% csrf_token %}
{{ form.as_p }}
<input type="submit" value="Submit" />
</form>
</div>
my LabForm
class LabForm(forms.ModelForm):
class Meta:
model = Labs
fields = ('labcode', 'name','administrator')
Your LabForm gets as instance= the model class, not a model object. You should fix that by passing lab instead:
def lab_edit(request, pk, template_name='webapp/lab_edit.html'):
lab = get_object_or_404(Labs, pk=pk)
if request.method == 'POST':
form = LabForm(request.POST, instance=lab)
if form.is_valid():
form.save()
return redirect('lab')
else:
form = LabForm(instance=lab)
return render(request, template_name, {'form':form})
By passing a reference to the class , you have basically called full_clean on the class, hence the error.
Note that you should not use request.POST or None since an empty POST request can still be a valid POST request.
I need to upload file on a Django page, however, after following the official tutorial, I was not able to upload it, it always gives the error "invalid form", and when I tried to print out the error msg of the form, it says "This field is required".
One thing notable is: I have 2 forms on one page, one is this upload form and the other one is for filling out information. Not sure if this is the root cause.
I have tried all solutions provided on the Internet.
Template file:
<form id="uploadForm" action="" method="post" enctype="multipart/form-data">
{% csrf_token %}
{{ form.as_p }}
<input type="file" value="upload" name="sourcefile">
<button type="submit">Upload</button>
</form>
Forms.py:
from django import forms
from .models import SourceFile
class UploadFileForm(forms.ModelForm):
class Meta:
model = SourceFile
fields = ('file', 'title')
Models.py:
from django.db import models
# Create your models here.
class SourceFile(models.Model):
title = models.CharField(max_length=255, blank=True)
file = models.FileField(upload_to="media/")
Views.py
def model_form_upload(request):
if request.method == 'POST':
form = UploadFileForm(request.POST, request.FILES)
if form.is_valid():
instance = SourceFile(file_field=request.FILES['file'])
instance.save()
return JsonResponse({'error': False, 'message': 'Uploaded Successfully!'})
else:
print("Invalid form")
# return JsonResponse({'error': True, 'errors': form.errors})
else:
form = UploadFileForm()
return render(request, 'source_validation.html', {'form': form})
Your template is wrong. Either use {{ form.as_p }} which should display a file input field because file is a field in your form. (so remove the <input type="file" ...>)
Or don't use it and manually add the <input> fields, but then you must use the correct names. Your form expects a "file" parameter, not a "sourcefile" parameter:
<input type="file" name="file">
Also, you're overcomplicating things in your view (even though your current code will work if you fix your template):
if form.is_valid():
form.save() # this will save your model
return redirect(...)
I am having an issue when it cmoes to passing variables from templates to views. Even though I am able to pass variables from view to template, I canot seem to get it right. I have looked at similar questions here.
Following the Django docs I created a forms.py script as follows:
forms.py
GNU nano 2.7.4 File: forms.py
from django import forms
class TactForm(forms.Form):
tacttime = forms.CharField(label='Tact Time', max_length=100)
Updated View
# -*- coding: utf-8 -*-
from __future__ import unicode_literals
from django.shortcuts import render
from django.http import HttpResponse
from lineoee.models import Lineoee31
from .forms import TactForm
def details(request):
if request.method == 'POST':
form = TactForm(request.POST)
print(form)
else:
form = TactForm()
context = {'form' : form}
return render(request, 'linedetails/index.html',context)
Updated Template
<form method="POST" action="{% url 'details' %}">
{% csrf_token %}
{{ form.as_p }}
<label for="tacttime">Tact Time: </label>
<input id="tacttime" type="text" name="tacttime" value ="60">
<input type="submit" value="OK">
<form>
Updated URLS
from django.conf.urls import url
from django.contrib import admin
from lineoee.views import index
from lineoee.views import details
urlpatterns = [
url(r'lineoee/$', index, name='index'),
url(r'linedetails/', details, name='details'),
]
Still, no errors and no values passed to the view.
EDIT
I am now getting some data on pressing the OK button, however it is not what I was expecting. I want to be able to retrieve the text entered into the input field. How can I do this?
"POST /linedetails/ HTTP/1.1" 200 24580
<tr><th><label for="id_tacttime">Tact Time:</label></th><td><input
type="text" name="tacttime" value="60" required id="id_tacttime"
maxlength="100" /></td></tr>
Template
<div style="text-align:center;">
<form method="POST" action="{% url 'details' %}">
{% csrf_token %}
{{ form.as_p }}
<input type="submit" value="adsfadsfas">
</form>
</div>
Views (EDITED)
Whatever the name you use in your input on your HTML template, that's the key you're gonna use to get what comes in the request.POST. That's why you'd like to use {{ form.field }} in the template so you know beforehand the name of the fields you're expecting to come in the request.POST
def details(request):
if request.method == 'POST':
print(request.POST)
print(request.POST.get('tacttime')
form = TactForm(request.POST)
print(form)
else:
form = TactForm()
return render(request, 'linedetails/index.html', context)
URLS
from django.conf.urls import url
from django.contrib import admin
from lineoee.views import index
from lineoee.views import details
urlpatterns = [
url(r'lineoee/$', index, name='index'),
url(r'linedetails/', details, name='details'),
]
def details(request):
if request.method == 'POST':
var = request.POST['textfield']
print(var)
I have a login form. After pressing the login button the the post data is sent to the view login_auth that authenticates the user data and redirects accordingly. However,after pressing the login button, I am not being redirected to the appropriate page.
views.py
def login_successful(request):
return render(request,"login_successful.html")
def login_invalid(request):
return render(request,"login_invalid.html")
def login(request):
return render(request,'login.html',c)
def loginauth(request):
username=request.POST.get("username",'')
password=request.POST.get("password",'')
user=auth.authenticate(username=username,password=password)
if user is not none:
user.login(request.user)
return redirect(login_successful)
else:
return redirect(login_invalid)
urls.py
urlpatterns = [
url(r'^registration/',views.registration),
url(r'^registration_successful/',views.registration_successful),
url(r'^home/',views.home),
url(r'^login/',views.login),
url(r'^login_successful/',views.login_successful),
url(r'^login_invalid/',views.login_invalid),
url(r'^login/auth',views.loginauth)
]
login.html
<html>
<form action="/login/auth" method="POST">{% csrf_token %}
Username :<input type="textbox" name="username" >
Password :<input type="password" name="password">
<input type="submit" value="Login">
</form>
</html>
Your login url pattern is missing a trailing $. It should be:
url(r'^login/$', views.login),
Without the dollar, the /login/auth is matched by r'^login/, so the request is handled by your login view.
It's a bit unusual to process the form on a different url. Django comes with authentication views, including a login view. I would recommend using this rather than writing your own.
Use name for url
views.py
def login_successful(request):
return render(request,"login_successful.html")
def login_invalid(request):
return render(request,"login_invalid.html")
def login(request):
return render(request,'login.html',c)
def loginauth(request):
username=request.POST.get("username",'')
password=request.POST.get("password",'')
user=auth.authenticate(username=username,password=password)
if user is not none:
user.login(request.user)
return redirect('login_successful')
else:
return redirect('login_invalid')
urls.py
urlpatterns = [
url(r'^registration/',views.registration),
url(r'^registration_successful/',views.registration_successful),
url(r'^home/',views.home),
url(r'^login/$',views.login),
url(r'^login_successful/',views.login_successful, name='login_successful'),
url(r'^login_invalid/',views.login_invalid, name='login_invalid'),
url(r'^login/auth',views.loginauth)
]