Method template.copy is not working - Google Script - google-apps-script

Question

I am facing a problem that is leaving me without a real solution.
I want that the script create a new Google Doc copy from a template, then transfer data from Sheet toward the new Doc.
The script is running without a bug, but fail to create a copy of the document as it supposed to do.
function transferData() {
var sheet = SpreadsheetApp.getActive().getSheetByName("Tour de Contrôle");
var templateId = "119ORijiWNQEdpG4KqjNCYzilbf_ob7SMdOPXUK3woMQ";
var folder = DriveApp.getFolderById("166g1akWuHR3MtoDzbh9ydMhEpr4euCts");
var data = sheet.getDataRange().getValues();
for (var i = 3; i < data.length; i++) {
if (data[i][12] === true) {
var nom = data[i][3];
var nFonction = data[i][6];
var template = DocumentApp.openById(templateId);
var newDoc = template.copy("Mouvement_" + nFonction + "_" + nom + "_EMBA");
newDoc.getAs(MimeType.GOOGLE_DOCS).getFile().moveTo(folder);
var docBody = newDoc.getBody();
var matricule = data[i][4];
var compta = data[i][16];
var division = data[i][1];
var fonction = data[i][6];
var respDoss = sheet.getRange("GDD!B3").getValue();
var endosGDD = sheet.getRange("GDD!B6").getValue();
var sign = sheet.getRange("GDD!B7").getValue();
docBody.replaceText("{Nom}", nom);
docBody.replaceText("{Matricule}", matricule);
docBody.replaceText("{NFonction}", nFonction);
docBody.replaceText("{Compta}", compta);
docBody.replaceText("{division}", division);
docBody.replaceText("{Fonction}", fonction);
docBody.replaceText("{RespDoss}", respDoss);
docBody.replaceText("{EndosGDD}", endosGDD);
docBody.replaceText("{Sign}", sign);
}
}
}

Answer 1

There's no DocumentApp.openById(templateId).copy() method. To make a copy of a doc you should use Driveapp instead.
You should change these lines of code
var template = DocumentApp.openById(templateId);
var newDoc = template.copy("Mouvement_" + nFonction + "_" + nom + "_EMBA");
newDoc.getAs(MimeType.GOOGLE_DOCS).getFile().moveTo(folder);
For these ones:
var template = DriveApp.openById(templateId);
var newDoc = template.makeCopy("Mouvement_" + nFonction + "_" + nom + "_EMBA", folder);
makeCopy(name, destination)
With SpreadsheetApp you can make a copy of a spreadsheet but you can't choose the folder where it will be created (it's created in the same folder where your spreadsheet "file" is located).
copy(name)

Answer 2

Finally, I modified const googleDocTemplate = DriveApp.getFolderById by const googleDocTemplate = DriveApp.getFileById
It worked.
Thanks for your help.
function transferData() {
//Here we store the sheet as a variable
const sheet = SpreadsheetApp.getActiveSpreadsheet().getSheetByName("Tour de Contrôle");
//This value should be the id of your document template that we created in the last step
const googleDocTemplate = DriveApp.getFileById('119ORijiWNQEdpG4KqjNCYzilbf_ob7SMdOPXUK3woMQ');
//This value should be the id of the folder where you want your completed documents stored
const destinationFolder = DriveApp.getFolderById('166g1akWuHR3MtoDzbh9ydMhEpr4euCts');
const respDoss = sheet.getRange("GDD!B3").getValue();
const endosGDD = sheet.getRange("GDD!B6").getValue();
const sign = sheet.getRange("GDD!B7").getValue();
const rows = sheet.getDataRange().getValues();
//Logger.log(rows)
rows.forEach(function(row, index){
//Here we check if this row is the headers, if so we skip it
if (index === 0) return;
//Here we check if a document has already been generated by looking at 'Generated date', if so we skip it
//if (row[16] === true);
//Here we check if the value in column Q (index 17) is true, if not we skip this row
if (index >= 4) {
if (row[17] !== true){
return;
}
}
Logger.log(rows);
//Using the row data in a template literal, we make a copy of our template document in our destinationFolder
const copy = googleDocTemplate.makeCopy(`Mouvement_${row[6]}, ${row[3]}_EMBA` , destinationFolder);
//Once we have the copy, we then open it using the DocumentApp
const doc = DocumentApp.openById(copy.getId());
//All of the content lives in the body, so we get that for editing
const body = doc.getBody();
...