I'm using this query in my autocomplete feature:
SELECT description FROM my_table WHERE LIKE "%keyword%"
But this query returns the entire content of the field which is sometimes too long.
Is it possible to limit the number of characters before and after "keyword" ?
I suggest using MySQL's REGEXP operator here. For example, to accept a maximum of 10 characters before and after keyword, you could use:
SELECT description
FROM my_table
WHERE col REGEXP '^.{0,10}keyword.{0,10}$';
Note that if you intend to match keyword as a standalone word, you may want to surround it by word boundaries in the regex pattern:
SELECT description
FROM my_table
WHERE col REGEXP '^.{0,10}\\bkeyword\\b.{0,10}$';
To show for example 5 characters before and after you word you can do it using RIGHT, LEFT and SUBSTRING_INDEX
select description, concat(RIGHT(SUBSTRING_INDEX(description, 'keyword', 1),5), 'keyword', LEFT(SUBSTRING_INDEX(description, 'keyword', -1),5) ) as snippet
from my_table
where description like "%keyword%";
Check it here : https://dbfiddle.uk/MZcVJgEL
Related
I want to to create a regex to find all columns that only have a single character ([A-Z]) as name, like N or M but not NM.
I've tried:
SELECT * FROM 'table' WHERE Name REGEXP '^[A-Z]'
But it's not displaying the expected result.
Try ^[A-Z]$.
You then state that this character is first and also last character of the value.
The regex functions in Oracle work only on one column. So, to search for just one character in a column, you would do the following:
select * from yourTable where REGEXP_LIKE (col1, '^[A-z]$');
Now, to search all the char/varchar columns on your table, you'll need to chain the regex expressions together, like so:
select * from yourTable where REGEXP_LIKE (col1, '^[A-z]$') or REGEXP_LIKE (col3, '^[A-z]$');
SQL solution:
where name in ('N','M')
I want to search exact word from string like
id Description
1 This is nice pen looking good
2 This is nice pendrive looking good
Search String : pen
My Current query
SELECT * FROM `table` WHERE Description like '%pen%';
Above Query return both record but I want Only first record. Because pen word exact match with my search string.
Expected Output
1 This is nice pen looking good
Demo
Try using regular expressions:
SELECT
*
FROM
`table`
WHERE
Description regexp '(^|[[:space:]])pen([[:space:]]|$)';
Demo
Or using word boundaries:
SELECT
*
FROM
`table`
WHERE
Description regexp '[[:<:]]pen[[:>:]]';
You can use REGEXP and the [[:<:]] and [[:>:]] word boundary markers:
SELECT
*
FROM
`table`
WHERE
Description REGEXP '[[:<:]]pen[[:>:]]';
SQL Fiddle Demo
you can use fulltext match like as follow
$query="SELECT * FROM table_name WHERE MATCH (column_name) AGAINST
('search_word' IN NATURAL LANGUAGE MODE)" ;
you can select boolean mode also,it return exact word in search result
Try this to get exact word results
SELECT * FROM `table` WHERE Description ='pen';
I've got a search function which creates query. My goal is to search for exact word, so if the phrase is 'hello' it should return only results with 'hello' (not with 'xhello', 'helloxx' etc). My code looks like:
SELECT (...) WHERE x RLIKE '[[:<:]]word[[:>:]]'
And it works for most of the cases, BUT
the problem starts when the phrase is f.e. '$hello', or 'helloĊ' etc - the special chars ruin the functionality.
Is there a way to handle it ?
Try
SELECT * FROM table WHERE x RLIKE '(^|[[:space:]])Hello([[:space:]]|$)'
or
SELECT * FROM table WHERE x RLIKE '(^| )Hello( |$)'
or
SELECT * FROM table WHERE x REGEXP '(^|[[:space:]])Hello([[:space:]]|$)'
or
SELECT * FROM test WHERE name REGEXP '(^| )Hello( |$)'
I'm trying to select all rows that contain only alphanumeric characters in MySQL using:
SELECT * FROM table WHERE column REGEXP '[A-Za-z0-9]';
However, it's returning all rows, regardless of the fact that they contain non-alphanumeric characters.
Try this code:
SELECT * FROM table WHERE column REGEXP '^[A-Za-z0-9]+$'
This makes sure that all characters match.
Your statement matches any string that contains a letter or digit anywhere, even if it contains other non-alphanumeric characters. Try this:
SELECT * FROM table WHERE column REGEXP '^[A-Za-z0-9]+$';
^ and $ require the entire string to match rather than just any portion of it, and + looks for 1 or more alphanumberic characters.
You could also use a named character class if you prefer:
SELECT * FROM table WHERE column REGEXP '^[[:alnum:]]+$';
Try this:
REGEXP '^[a-z0-9]+$'
As regexp is not case sensitive except for binary fields.
There is also this:
select m from table where not regexp_like(m, '^[0-9]\d+$')
which selects the rows that contains characters from the column you want (which is m in the example but you can change).
Most of the combinations don't work properly in Oracle platforms but this does. Sharing for future reference.
Try this
select count(*) from table where cast(col as double) is null;
Change the REGEXP to Like
SELECT * FROM table_name WHERE column_name like '%[^a-zA-Z0-9]%'
this one works fine
In my table I have firstname and last name. Few names are upper case ( ABRAHAM ), few names are lower case (abraham), few names are character starting with ucword (Abraham).
So when i am doing the where condition using REGEXP '^[abc]', I am not getting proper records. How to change the names to lower case and use SELECT QUERY.
SELECT * FROM `test_tbl` WHERE cus_name REGEXP '^[abc]';
This is my query, works fine if the records are lower case, but my records are intermediate ,my all cus name are not lower case , all the names are like ucword.
So for this above query am not getting proper records display.
I think you should query your database making sure that the names are lowered, suppose that name is the name you whish to find out, and in your application you've lowered it like 'abraham', now your query should be like this:
SELECT * FROM `test_tbl` WHERE LOWER(cus_name) = name
Since i dont know what language you use, I've just placed name, but make sure that this is lowered and you should retrieve Abraham, ABRAHAM or any variation of the name!
Hepe it helps!
Have you tried:
SELECT * FROM `test_tbl` WHERE LOWER(cus_name) REGEXP '^[abc]';
I don't know since when, but nowadays MySql REGEXP is case insensitive.
https://dev.mysql.com/doc/refman/5.7/en/pattern-matching.html
You don't need regexp to search for names starting with a specific string or character.
SELECT * FROM `test_tbl` WHERE cus_name LIKE 'abc%' ;
% is wildcard char. The search is case insensitive unless you set the binary attribute for column cus_name or you use the binary operator
SELECT * FROM `test_tbl` WHERE BINARY cus_name LIKE 'abc%' ;
A few valid options already presented, but here's one more with just regex:
SELECT * FROM `test_tbl` WHERE cus_name REGEXP '^[abcABC]';