MIPS MARS ASSEMBLY CODE operand is of incorrect type - mips

Question

.data
prompt: .asciiz "Please enter an integer: "
x: .double 2.0
tolerance: .double 1e-6
.text
main:
# Prompt user for initial value of x
li $v0, 4
la $a0, prompt
syscall
# Read in user input
li $v0, 7
syscall
# Convert user input to double and store in x
mtc1 $v0, $f12
cvt.d.w $f0, $f12
sdc1 $f0, x
# Initialize counter and F(x) value
li $t0, 0
ldc1 $f12, x
add.d $f14, $f12, $f12
mul.d $f14, $f12, $f14
add.d $f14, $f14, 1
# Loop until F(x) is within tolerance
loop:
# Calculate x{n+1}
ldc1 $f12, x
add.d $f13, $f12, $f12
mul.d $f13, $f12, $f13
mul.d $f13, $f13, $f12
add.d $f13, $f13, -8
mul.d $f13, $f13, $f12
div.d $f12, $f14, $f13
# Calculate F(x)
ldc1 $f12, x
add.d $f14, $f12, $f12
mul.d $f14, $f12, $f14
add.d $f14, $f14, 1
# Print current x and F(x) values
li $v0, 3
ldc1 $f12, x
syscall
li $v0, 11
li $a0, ','
syscall
li $v0, 3
ldc1 $f14, $f14
syscall
li $v0, 11
li $a0, '\n'
syscall
# Check if F(x) is within tolerance
ldc1 $f12, x
ldc1 $f14, tolerance
c.lt.d $f12, $f14
beq $0, $0, done
# Increment counter and repeat loop
addi $t0, $t0, 1
b loop
done:
# Print root found
li $v0, 4
la $a0, "Root found: "
syscall
li $v0, 3
ldc1 $f12, x
syscall
# End program
li $v0, 10
syscall
line 29 column 19: "1": operand is of incorrect type
line 46 column 23: "1": operand is of incorrect type
line 56 column 5: "ldc1": Too few or incorrectly formatted operands. Expected: ldc$f2,-100($t2)
line 75 column 5: "la": Too few or incorrectly formatted operands. Expected: la $t1,($t2)
Does anyone know what I'm doing wrong here? My goal is to write a MIPS program which will find a value of xn such that F(xn)=0, to a tolerance of 10-6 with the given formula 𝑥𝑛+1 = 𝑥𝑛 − (𝐹(𝑥𝑛)/𝐹′(𝑥𝑛)).
For example consider a continuous function F(x)=x3-4x2+1 with its derivative F’(x)=3x2-8x. Thus, by calculating successive values of x, the value of F(xn) will approach 0, and hence be a root of F.
I am fairly new to MIPS and I'm having trouble.