How to query my JSON file for specific key - json

Question

I am working on a project where I want to query a JSon using Jquery but I am getting an error:
jq: error: syntax error, unexpected IDENT, expecting $end (Unix shell quoting issues?) at <top-level>, line 1:
..id
jq: 1 compile error
Error: Process completed with exit code 3.
I am using the command:
jq '..id' new_file.json
To query my JSON file which is named new_file.json
Here is my JSON file:
[
{
"type": "users_export",
"status": "pending",
"connection_id": "con_kmZIjREZWYzt39JI",
"format": "json",
"limit": 5,
"fields": [
{
"name": "user_id"
},
{
"name": "user_id",
"export_as": "provider"
},
{
"name": "username"
},
{
"name": "username",
"export_as": "provider"
},
{
"name": "nickname"
},
{
"name": "email"
},
{
"name": "email"
},
{
"name": "identities[0].connection",
"export_as": "provider"
},
{
"name": "email_verified",
"export_as": "provider"
}
],
"connection": "dev-default-evoyanbs",
"created_at": "2022-11-16T17:45:58.429Z",
"id": "job_aztDgKXWT8g8iZ5T"
}
]
I want the 'job_aztDgKXWT8g8iZ5T' as my output but I am getting the above mentioned error, can someone please help me out, thanks.

Answer 1

As you have an array, the command should be:
jq '.[].id' new_file.json
And the result will be: "job_aztDgKXWT8g8iZ5T".
If you want to get rid of double quotes in your output, you can add raw-output flag in your command, like this:
jq -r '.[].id' new_file.json
or
jq --raw-output '.[].id' new_file.json