I have a list of numbers, some of them have leading underscores, some of them don't.
A
B
_12
34
99
_42
Which is the best way of adding up these numbers?
Note: I tried this custom script formula which for some reason doesn"t work (only returns the first item passed in the range), and anyway I guess there should be an easier way just using native GoogleSheet formulas.
function sum_with_underscores(underscored_nums) {
let nums = underscored_nums.map( x => String(x).replace("_", ""))
return nums.reduce((pv, cv) => parseFloat(pv) + parseFloat(cv), 0);
}
=SUM(ARRAYFORMULA(VALUE(SUBSTITUTE(<your_range>, "_", ""))))
Assuming you would like to achieve this result using a script instead of a formula, the code below worked for me.
Make sure to flatten the array before manipulating the data. Hope this helps.
let values = sheet.getDataRange().getValues() // returns array of arrays
let nums = values.flat() // converts [[_12, 34.0], [99.0, _42]] to [_12, 34.0, 99.0, _42]
nums = nums.map( n => {
return typeof(n) === 'number' ? n : parseFloat(n.replace("_", ""));
})
let sum = nums.reduce((acc, num)=> acc + num, 0)
}
Related
I'm trying to figure out what my options are here when I need to use a column number in a formula, and if I really need to write a column number to column letter method to accomplish what I'm trying to do.
See this method I have here:
createFormulas(lookupField, lookupColumns) {
// Iterate through the lookupColumn array
lookupColumns.forEach(value => {
let columnNumber = this.getColumn(this.headers, value);
let range = this.sheet.getRange(2, columnNumber, this.lastRow - 1, 1);
// range.setFormula('=$A2');
range.setFormula('=' + columnNumber + '2' ); // doesn't work obviously
})
}
I'm trying to add formulas in a column based on the column.
this.getColumn() returns the column number based on the column name being passed in.
let range sets the range I want to set the formula in
range.setFormula('=$A2') pastes this formula into range and updates the reference accordingly (i.e., $A3, $A4, etc.). This isn't the formula I ultimately want to use, just a simplified example.
I need to set the column in the reference dynamically, however.
What I have obviously won't work: range.setFormula('=' + columnNumber + '2' );. That would just result in something like 72 where 7 is the column number.
I know I can write a method that will convert the column number into a letter. I'm just surprised there isn't a built in method for doing that or some other native way of accomplishing this.
For example, in Excel VBA I think you can do something like "=" & Cells(2, columnNumber).Address or something like that (been a while, I could be wrong), which should equate to =A2, =A3, =A4, etc. in the range.
So before writing this column number to letter method, I just wanted to check: is that the only way to accomplish what I'm after or is there a native way of handling this that I'm just not seeing?
Actually, was able to do this using .getA1Notation().
Refactored to the following and it works as expected:
createFormulas(lookupField, lookupColumns) {
// Iterate through the lookupColumn array
lookupColumns.forEach(value => {
let columnNumber = this.getColumn(this.headers, value);
let formulaRange = this.sheet.getRange(2, columnNumber, this.lastRow - 1, 1);
let referenceRange = this.sheet.getRange(2, this.idColumn, this.lastRow - 1, 1);
formulaRange.setFormula("=" + referenceRange.getCell(1, 1).getA1Notation());
})
}
Column To Letters
I followed Yuri's path to the numbers to letter functions and I'm a bit baffled that we have forgotten that there are 26 letters in the alphabet and so after looking at the various functions at that reference none of them seem to have worked for me. So here's my replacement:
function colToletters(num) {
let a = " ABCDEFGHIJKLMNOPQRSTUVWXYZ";
if (num < 27) return a[num % a.length];
if (num > 26) {
num--;
let letters = '';
while (num >= 0) {
letters = 'ABCDEFGHIJKLMNOPQRSTUVWXYZ'[num % 26] + letters;
num = Math.floor(num / 26) - 1;
}
return letters;
}
}
This will calculate the column letters for 1 to 1000 and I check all the way to 703 where the letters go to AAA and they look good all the way.
Just in case. Based on https://stackoverflow.com/a/64456745/14265469
function numberToLetters(num) {
// num--; // if you need 1 --> A, 2 --> B, 26 --> Z
let letters = '';
while (num >= 0) {
letters = 'ABCDEFGHIJKLMNOPQRSTUVWXYZ'[num % 26] + letters;
num = (num - num % 26) / 26 - 1;
}
return letters;
}
console.log(numberToLetters(0)); // --> A
console.log(numberToLetters(25)); // --> Z
console.log(numberToLetters(26)); // --> AA
I need to write some functions that involve the same function as the Sheets function MATCH() with parameter 'sort type' set to TRUE or 1, so that a search for 35 in [10,20,30,40] will yield 2, the index of 30, the next lowest value to 35.
I know I can do this by looping over the array to search, and testing each value against my search value until a value greater than the search value is found, but it seems to me there must be a shorthand way of doing this. We don't have to do this when seeking an exact value; we can just use indexOf(). I was surprised when I first learned that indexOf() does not have a parameter for search type, but can only return a -1 if an exact value is not found.
Is there no function akin to indexOf() that will do this, or is it actually necessary to loop over the array every time you need to do this?
Probably you're looking for the array.find() method. The impelentation could be something like this:
var arr = [10,20,30,40]
// make a copy of the array, reverse it and do find with condition
var value = arr.slice().reverse().find(x => x < 35)
console.log(value) // output --> 30 (first element less than 35 in the reversed array)
var index = arr.indexOf(value)
console.log(index) // output --> 2 (index of the element in the original array)
https://www.w3schools.com/jsref/jsref_find.asp
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/find
There is another method array.findIndex(). Probably you can use it as well:
var arr = [10,20,30,40]
// find more or equal 35 and return previous index
var index = arr.findIndex(x => x >= 35) - 1
console.log(index) // output --> 2
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/findIndex
Try this:
function lfunko(tgt = 35) {
Logger.log([10,20,30,40].reduce((a,c,i) => { a.r = (a.x >= c)? i:a.r;return a;},{x:tgt}).r)
}
My current table looks like this:
Status
Draft
Pending
Complete
I want to sort them based on the value of the cells. Is there a way to do that? I've only been able to sort them using this code:
onChange(status: string){
const sortState: Sort = {active: status, direction: 'desc'};
this.sort.active = sortState.active;
this.sort.direction = sortState.direction;
this.sort.sortChange.emit(sortState);
}
But I want to sort using the values of the status themselves since I'd want to create a button which when click sorts starting from complete or draft or pending.
I'm a little confused by your question, but I think I understand what you're asking.
You're going to want to convert your values into an array and then use the .sort() function. So, assuming you have an array of your cells, we can call that let array = Cell[], you can then access the status of the cells like this:
sortCells(){
let array = Cell[]; // here we're assuming there is already a cell type and a cell.active parameter, like shown in your example.
let possibleValues = ["Draft","Pending","Complete"]; // easier way to compare two values
array.sort((a,b)=>{
let aIndex = possibleValues.indexOf(a.active); // index of gets the location of the element in an array
let bIndex = possibleValues.indexOf(b.active);
if(a > b){
return -1;
} else if(b > a){
return 1;
}else{
return 0; // they are equal
}
})
}
You can read more about sort here: https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/sort
This question relates to an animated map template which we have developed at the UKs Office for National Statistics. It has been applied to many datasets and geographies many uses without problem. For example,
http://www.ons.gov.uk/ons/interactive/vp3-census-map/index.html
http://www.statistica.md/pageview.php?l=ro&idc=390&id=3807
The .fla calls on a supporting .as file (see below) to introduce a thousand separator (in the UK a comma, in Germany a full stop (period) defined elsewhwere.
However, the dataset I am currently mapping has large negative values, and it tutrns out that the ORIGINAL HELPER FUNCTION below does not like negative values with 3, 6, 9 or 12 (etc) digits.
-100 to -999 for instance are rendered NaN,100 to NaN,999.
This is because such values are recognised as being 4 digits long. They are being split, the comma introduced, and the -ve sign is misunderstood.
I reckon the approach must be to use absolute values, add in the comma and then (for the negative values) add the -ve sign back in afterwards. But so far, trials of the ADAPTED HELPER FUNCTION have produced only error. :-(
Can anyone tell me how to put the -ve sign back in , please?
Many thanks.
Bruce Mitchell
==================================================================================
//ORIGINAL HELPER FUNCTION: ACCEPTS A NUMBER AND RETURNS A STRING WITH THOUSANDS SEPARATOR ATTACHED IF NECESSARY
function addThouSep(num) {
/*
a. Acquire the number - 'myTrendValue' or 'myDataValue' - from function calcValues
b. Record it (still as a number) to data precision.
1. Turn dataORtrend into a string
2. See if there is a decimal in it.
3. If there isn't, just run the normal addThouSep.
4. If there is, run addThouSep just on the first bit of the string - then add the decimal back on again at the end.
*/
var myNum:Number = correctFPE(num); // Create number variable myNum and populate it with 'num'
// (myTrendvalue or myData Value from calcValues function) passed thru 'correctPFE'
var strNum:String = myNum+""; // Create string version of the dataORtrend number - so instead of 63, you get '63'
var myArray = strNum.split("."); // Create array representing elements of strNum, split by decimal point.
//trace(myArray.length); // How long is the array?
if (myArray.length==1) { // Integer, no decimal.
if (strNum.length < 4)//999 doesn't need a comma.
return strNum;
return addThouSep(strNum.slice(0, -3))+xmlData.thouSep+strNum.slice(-3);
}
else { // Float, with decimal
if (myArray[0].length < 4)//999 doesn't need a comma
return strNum;
return (addThouSep(myArray[0].slice(0, -3))+xmlData.thouSep+myArray[0].slice(-3)+"."+myArray[1]);
}
}
==================================================================================
//ADAPTED HELPER FUNCTION: ACCEPTS A NUMBER AND RETURNS A STRING WITH THOUSANDS SEPARATOR ATTACHED IF NECESSARY
function addThouSep(num) {
/*
a. Acquire the number - 'myTrendValue' or 'myDataValue' - from function calcValues
b. Record it (still as a number) to data precision.
1. Turn dataORtrend into a string
2. See if there is a decimal in it.
3. If there isn't, just run the normal addThouSep.
4. If there is, run addThouSep just on the first bit of the string - then add the decimal back on again at the end.
*/
var myNum:Number = correctFPE(num); // Create number variable myNum and populate it with 'num'
// (myTrendvalue or myData Value from calcValues function) passed thru 'correctPFE'
var myAbsNum:Number = Math.abs(myNum); // ABSOLUTE value of myNum
var strNum:String = myAbsNum+""; // Create string version of the dataORtrend number - so instead of 63, you get '63'
var myArray = strNum.split("."); // Create array representing elements of strNum, split by decimal point.
//trace(myArray.length); // How long is the array?
if (myNum <0){ // negatives
if (myArray.length==1) { // Integer, no decimal.
if (strNum.length < 4)//999 doesn't need a comma.
return strNum;
return addThouSep(strNum.slice(0, -3))+xmlData.thouSep+strNum.slice(-3);
}
else { // Float, with decimal
if (myArray[0].length < 4)//999 doesn't need a comma
return strNum;
return (addThouSep(myArray[0].slice(0, -3))+xmlData.thouSep+myArray[0].slice(-3)+"."+myArray[1]);
}
}
else // positive
if (myArray.length==1) { // Integer, no decimal.
if (strNum.length < 4)//999 doesn't need a comma.
return strNum;
return addThouSep(strNum.slice(0, -3))+xmlData.thouSep+strNum.slice(-3);
}
else { // Float, with decimal
if (myArray[0].length < 4)//999 doesn't need a comma
return strNum;
return (addThouSep(myArray[0].slice(0, -3))+xmlData.thouSep+myArray[0].slice(-3)+"."+myArray[1]);
}
}
==================================================================================
If you're adding commas often (or need to support numbers with decimals) then you may want a highly optimized utility function and go with straightforward string manipulation:
public static function commaify( input:Number ):String
{
var split:Array = input.toString().split( '.' ),
front:String = split[0],
back:String = ( split.length > 1 ) ? "." + split[1] : null,
pos:int = input < 0 ? 2 : 1,
commas:int = Math.floor( (front.length - pos) / 3 ),
i:int = 1;
for ( ; i <= commas; i++ )
{
pos = front.length - (3 * i + i - 1);
front = front.slice( 0, pos ) + "," + front.slice( pos );
}
if ( back )
return front + back;
else
return front;
}
While less elegant it's stable and performant — you can find a comparison suite at my answer of a similar question https://stackoverflow.com/a/13410560/934195
Why not use something simple like this function I've made?
function numberFormat(input:Number):String
{
var base:String = input.toString();
base = base.split("").reverse().join("");
base = base.replace(/\d{3}(?=\d)/g, "$&,");
return base.split("").reverse().join("");
}
Tests:
trace( numberFormat(-100) ); // -100
trace( numberFormat(5000) ); // 5,000
trace( numberFormat(-85600) ); // -85,600
Explanation:
Convert the input number to a string.
Reverse it.
Use .replace() to find all occurrences of three numbers followed by another number. We use $&, as the replacement, which basically means take all of those occurences and replace it with the value we found, plus a comma.
Reverse the string again and return it.
Did you try using the built in Number formatting options that support localized number values:
Localized Formatting with NumberFormatter
I have got an array that consists of strings. I have made a function that searches the array based on the search term parameter. However, when i run the code it only ever outputs the string at index 0 of the array. I want it to return the corresponding url in the array when a search is run.
Any help would be very much appreciated. Thanks in advance.
So you are trying to return URL based on the String after the ~?
Do the line
arrayOfURL[i].toLowerCase().split('~')[i];
seem weird to you? Imagine as i increases, eg. i = 4
arrayOfURL[4].toLowerCase().split('~')[4];
Does that last [4] make sense?
I am guessing the reason it never got past the first element is because the code actually erroring out on that part.
I think what you want is (likewise for the return line, you'll want [0]
arrayOfURL[i].toLowerCase().split('~')[1];
I would also take a look at
if (z >= searchtoLower)
what are you trying to compare there?
The problem may be in the second i param:
var z = arrayOfURL[i].toLowerCase().split('~')[i];
The string will be splitted into 2 parts (index 0, 1). Why did you select part i?
This is a correct version of your program:
var arrayOfURL = [
"http://www.google.co.uk~Google is a search engine.",
"http://www.yahoo.co.uk~Yahoo is another search engine.",
"http://bing.com~Bing is a decision engine."
];
function findURL(arrayOfURL,search)
{
var searchtoLower = search.toLowerCase();
for (var i = 0; i < arrayOfURL.length; i++)
{
var z = arrayOfURL[i].toLowerCase().split('~')[1];
if (z.indexOf(searchtoLower) != -1)
return arrayOfURL[i];
}
return "Nothing Found!";
}
findURL(arrayOfURL,"decision")
I hope it can help you.
I think you should be doing
var terms = arrayOfURL[i].toLowerCase().split('~');
if(0 <= terms[1].indexOf(searchToLower))
// ^ ^
// | |-- 0 <= indexOf method determines
// | if searchToLower is a substring of terms[1]
// |
// |-- term[1] gets the part after the first "~"
and
return terms[0]; //terms[0] is the part before the first "~"
I would also consider returning null or the empty string "" in case of failure (instead of returning the arbritrary "Nothing Found!" message)