I have a query,
SELECT t2.id, t1.image, SUBSTRING(t2.start_time,1,10) AS mytime,
t2.user
FROM post_table t1
INNER JOIN watchUserList t2 ON t1.id = t2.movie_id
WHERE user = 'john#gmail.com'
ORDER BY id DESC;
In this query I want to fetch DISTINCT of mytime. I tried DISTINCT(SUBSTRING(t2.start_time,1,10)) AS mytime and SUBSTRING(t2.start_time,1,10) AS DISTINCT(mytime). But both doesn't work. How to get Distinct of a Substring in MySQL. Is there any way?
The correct syntax is
SELECT DISTINCT t2.id, t1.image, SUBSTRING(t2.start_time,1,10) AS mytime,
t2.user
FROM post_table t1
INNER JOIN watchUserList t2 ON t1.id = t2.movie_id
WHERE user = 'john#gmail.com'
ORDER BY id DESC;
But note, that its distinct over all the fields in the field-list.
Distinct on Multiple Columns
When we use MySQL Distinct on multiple columns, then the SELECT Statement writes the unique combination of multiple columns instead of unique individual records.
Distinct On Multiple Columns
Related
I want to get value from table1 and join all matching value from table2. The table1 has to be limited to 2 rows, but expecting output should own all matching values for those two ids.
How can I achieve this?
You would use a subquery:
select t1.*, t2.*
from (select t1.*
from table1 t1
limit 10
) t1 left join
table2 t2
on t1.id = t2.table1_id;
Note: This returns two arbitrary rows. Normally, you would have an order by to better specify the rows. And use order by rand() for random rows.
if you want all the value in join for only two row of table 1 you can use a subqiuery with limit 2
select b.id, a.value, b.value2, b.table1_ID
from (
select * from table1
limit 2
) a
inner join table2 on aid = b.table1_ID
The result of this query gives me 0 rows where it should give me the 3 latest rows (grouped by Table1.Name).
Table1 has: "Name", "Timestamp", "Voltage".
Table2 has: "Name", "data".
When I delete "ORDER BY Table1.Timestamp" I do get 3 rows (as expected) but they are the 3 oldest entries in the database where I want the 3 latest.
(I have 3 Name values in Table1 and Table2 that match).
The code:
SELECT * from Table1
INNER JOIN Table2
ON Table1.Name=Table2.Name
GROUP BY Table1.Name
ORDER BY Table1.Timestamp;
You can try to perform a query like this :
SELECT t.*,t2.* from Table1 t
INNER JOIN Table2 t2
ON t.Name=t2.Name
WHERE t.Timestamp = (
SELECT MAX(t3.Timestamp) FROM Table1 t3
WHERE t3.Name = t.Name
)
You could sort and taking the top 3:
SELECT * from Table1
INNER JOIN Table2
ON Table1.Name=Table2.Name
ORDER BY Table1.Timestamp DESC
LIMIT 3
When you are using join two or more tables then don't use * in select query. Use specific column name to avoid column ambiguously in select query , you can also use Table1., Table2. but good way to use specific columns in select query.
SELECT Table1.Name,Table1.Timestamp from Table1
INNER JOIN Table2
ON Table1.Name=Table2.Name
GROUP BY Table1.Name
ORDER BY Table1.Timestamp;
I have 3 tables and want to join all in one query to show latest 10 entries by datetime.
t1: id, username
t2: id, id_t1, med_id, ga_id, au_id, re_id, text, datetime
t3: id, id_t1, pro_id, au_id, re_id, text, datetime
First I saw it would be easy with simple left join and where id, but i got double results. Then i tried inner and outer join, also group by, but the result was bad.
So my question is how can i join all without double results of the last 10 of t2 and t3?
Hard to tell what exactly you are trying to acheive, but here is a clue how it could be complemented.
SELECT TOP 10 DISTINCT T1.*
FROM T1
INNER JOIN T2 ON T1.id = T2.id_t1
INNER JOIN T3 ON T1.id = T3.id_t1
ORDER BY (CASE WHEN T2.[DateTime] > T3.[DateTime] THEN
T2.[DateTime]
ELSE
T3.[DateTime]
END) DESC
If you need to select field from T2 and T3, GROUP BY on all T1 field with aggregate on field from t2 and t3 is an option. Otherwise, linked-subquery is the way to go.
As sgeddes commented already, it's hard to know what you need, without seeing some example data from your tables. It would really help to know what the relationship between the three tables is.
One question I have, in particular, is: how are t2 and t3 related, if at all? It looks like they might not be, as each of them has its own datetime column.
Perhaps the following could do the job, but we need some more info to know for sure:
(SELECT DISTINCT t1.*, t2.id, t2.au_id, t2.re_id, t2.text, t2.`datetime`, t2.med_id, t2.ga_id, NULL AS pro_id
FROM t1
INNER JOIN t2 ON t1.id = t2.id_t1)
UNION
(SELECT DISTINCT t1.*, t3.id, t3.au_id, t3.re_id, t3.text, t3.`datetime`, NULL AS med_id, NULL AS ga_id, t3.pro_id
FROM t1
INNER JOIN t3 ON t1.id = t3.id_t1)
ORDER BY datetime DESC
LIMIT 10
The following selects the username and the datetime for the last ten posts.
SELECT username, last_ten.`datetime` AS lastpost
FROM t1
INNER JOIN (
SELECT 't2' AS tab, id, `datetime`, t2.id_t1
FROM t2
UNION ALL
SELECT 't3' AS tab, id, `datetime`, t3.id_t1
FROM t3
ORDER BY datetime DESC
LIMIT 10
) AS last_ten ON t1.id = last_ten.id_t1
On this solution the user is querying on id to display other columns in the select but query only distinct on a single column. I've tried to do this but can't get the syntax right. Here is the query but I only want distinct on DevelopmentDisplay column.
SELECT DISTINCT
`RESI`.`DevelopmentDisplay`,
`RESI`.`City`,
`RESI`.`ZipCode`
FROM
`RESI`
WHERE
`RESI`.`ZipCode` = '91263'
ORDER BY
`RESI`.`DevelopmentDisplay` ASC
Yes you can self join tables.
I see two options like this. However i would suggest you index DevelopmentDisplay column. Depending on the number of records it can get very slow.
SELECT
t1.DevelopmentDisplay,
t1.City,
t1.ZipCode
FROM
RESI t1,
(SELECT DISTINCT DevelopmentDisplay FROM RESI) t2
WHERE
t1.ZipCode = '91263' AND
t1.DevelopmentDisplay = t2.DevelopmentDisplay;
Alternatively:
SELECT
t1.DevelopmentDisplay,
t1.City,
t1.ZipCode
FROM
RESI t1,
WHERE
t1.ZipCode = '91263' AND
t1.DevelopmentDisplay IN (SELECT DISTINCT DevelopmentDisplay FROM RESI);
I'm trying to do a join between tables 1 and 2 which have a 1 to many relationship.
table1 has the following fields
createdate
contact
tkey (surrogate key)
table2 has the following fields
tkey (primary key)
status
userfld1
description
I want to show all items in table2 with their corresponding items in table1 grouped by table2.userfld1
select distinct t2.userfld1, t2.status, t2.description, t1.createdate, t1.contact
from table2 as t2 left join table1 as t1
on t2.tkey = t1.tkey
group by t2.userfld1
is this correct?
No that's not correct, you can't select columns that aren't in the group by unless they are contained in an aggregate function. And I think what you are asking for doesn't even make sense. My best guess is that you mean ORDER BY, not GROUP BY:
SELECT DISTINCT t2.userfld1, t2.status, t2.description, t1.createdate, t1.contact
FROM table2 t2
LEFT JOIN table1 t1
ON t2.tkey = t1.tkey
ORDER BY t2.userfld1
Three other errors that I've fixed:
SELECT ... FROM not SELECT ... WHERE
You should join with a table, not a column.
You had no aliases after the table names, but later refer to these missing aliases.
I think what you're looking for is order by, not group by, and I also fixed your query:
select t2.userfld1, t2.status, t2.description, t1.createdate, t1.contact
where table2 t2 left join table1 t1
on t2.tkey = t1.tkey
order by t2.userfld1
Is this what you were looking for?