inserting multiple notationed preg_match_all element into mysql - mysql

I have variables gathered from another website with preg_match_all and echo the value. But the value is in $var1[0][n], n>0 form;I couldn't inserted the value into mysql.
Thanks for any help.
$path='#<div class="comp-cell-row-div vtable infoColumn" style="width: 25%;">(.*?)</div>#si';
$vr12=file_get_contents('https://www....');
preg_match_all($path,$vr12,$ad12);
echo $ad12[0][14];
$value = array( var_dump($ad12));
foreach($value as $val){mysqli_query($conn,"UPDATE `test` SET `param1`='$val' WHERE `id`='118'");
}
or mysqli_query($conn,"INSERT INTO `test` VALUES .....");

First of all, we need to manipulate data. Choose db as varchar to see saved tags with data. Pregmatc_all also gets tags, strings in varchar format.
To eleminate unwanted tags or signs; use trim and substr expressions on php.
In the example I trim before 17th character. This is a property of strpos
$data12=trim(substr($ad12[0][n], 17, strpos($ad12[0][n],'')),$extratags);
mysqli_query($conn,"UPDATE `table` SET `val12` = '$data12' WHERE `col1` = 'data1'; ");

Related

Is it possible to insert sql query in php array value?

for($count = 0; $count < count($_POST["item_sub_category"]); $count++)
{
$data = array(
':item_sub_category_id'
=> SELECT r_name FROM Repair where r_id = $_POST["item_sub_category"][$count]
);
$query = "INSERT INTO Repairlog (description,visitID) VALUES (:item_sub_category_id,'1')";
$statement = $connect->prepare($query);
$statement->execute($data);
}
As far as concerns, your code won't work. The SQL query that you are passing as a parameter will simply be interpreted as a string.
You could avoid the need for a loop by taking advantage of the INSERT INTO ... SELECT ... syntax. The idea is to generate an IN clause that contains all values that are in the array, and then run a single query to insert all records at once.
Consider:
$in = str_repeat('?,', count($_POST["item_sub_category"]) - 1) . '?';
$query = "INSERT INTO Repairlog (description,visitID) SELECT r_name, 1 FROM Repair WHERE r_id IN ($in)";
$statement = $connect->prepare($query);
$statement->execute($_POST["item_sub_category"]);
Note: it is likely that visitID is an integer and not a string; if so, then it is better not to surround the value with single quotes (I removed them in the above code).
TLDR; No.
Your question can be re-framed as: Can I write SQL code in php. The answer is NO. You can write the SQL code within a String type variable (or parameter) in php.
This is a general rule for any programming language, you cannot have multiple languages within the same file, as the language parser will not be able understand which syntax is that.
In order to embed a different language in another language, you need some kind of separator that will define when the new language or special type will start and when it will end.

MySQL: SQL to insert rows using a string of ids

I need to insert ~150 simple rows (an id, and a static status of 'discard'). I have a string of the ids:
'123', '234r', '345', '456xyz'...
What's the simplest way to insert rows using this string of ids?
It seems like maybe there's some way to split the string on commas and... create a temp table to ...? I don't know - it just seems like this is the kind of thing that MySQL often manages to pull off in some cool, expedient way.
An example how to do create an INSERT statement with a few lines of PHP:
<?php
// copy your string of ids into this variable
$input = "'123', '234r', '345', '456xyz'";
// modify next line to get your desired filename
$filename = 'insert.sql'
// modify next line to your table name
$insert_statement = "INSERT INTO your_table_name (id, status) VALUES \n" .
'(' . implode(", 'discard')\n(", explode(', ', $input)) . ", 'discard');\n";
file_put_contents($filename, $insert_statement);
?>
Note
This is for this special use case. If the string of ids contains some special characters like single quotes, then this simple approach will fail.
The one way is to create CSV file with appropriate records and upload it at once to mysql.
Please follow this tutorial: http://www.mysqltutorial.org/import-csv-file-mysql-table/

Remove last char if it's a specific character

I need to update values in a table by removing their last char if they ends with a +
Example:
John+Doe and John+Doe+ should both become John+Doe.
What's the best way to achieve this?
UPDATE table
SET field = SUBSTRING(field, 1, CHAR_LENGTH(field) - 1)
WHERE field LIKE '%+'
If you are trying to display the field instead of update the table, then you can use a CASE statement:
select
case
when right(yourfield,1) = '+' then left(yourfield,length(yourfield)-1)
else yourfield end
from yourtable
SQL Fiddle Demo
you didn't explain exactly the situation.
but if you search for names in a text. I'll remove all the non chars (anything not a-z and A-Z) including spaces and then compare.
if you want just the last char, try the SUBSTRING_INDEX function.
if you are passing to the DB as a string, you can do this with str_replace
<?php
$str = "John+Doe+";
$str = str_replace("+"," ",$str);
echo $str;
?>

REGEX for selecting multiple value in string

I need an sql select statement to retrieve 04:30 and test.zip from this string:
{"TIME":"04:30","DATE":"11\/25\/2013","FILENAME":["test.zip"]}
use this \[(.*?)\]
it return value between [ and ]
and for 04:30 use TIME":(.*?),
it return value after "TIME":
Can't you just decode it and use PHP? (assuming you can't change the way it's stored in the db)
<?php
$str = '{"TIME":"04:30","DATE":"11/25/2013","FILENAME":["test.zip"]}';
$o = json_decode($str);
$time = $o->TIME;
$file = $o->FILENAME[0];
var_dump($time); //"04:30"
var_dump($file); //"test.zip"
Regex replaces etc in MySQL require a UDF (user-defined function) mysql-udf-regexp
If none of the above are viable solutions (change DB structure, do it with PHP, use a MySQL UDF), you'll need to get creative. It would require a known, static format of that string, but you could replace some parts and substring others. For example:
SELECT SUBSTRING(REPLACE(`column_name`,'{"TIME":"',''),1,5) AS `time` FROM `table_name`
File is more complex, this example assuming only one filename in the array
SELECT REPLACE(SUBSTRING(`column_name`,LOCATE('"FILENAME":["',`column_name`)+13),'"]}','') AS `file` FROM `table_name`
Those two field selections get 04:30 and test.zip respectively (you can of course use those functions in the same statement, rather than separately like I have, by comma separating them)

MYSQL Search by arrays

Got a question for you all...
What would be the best way to search my table by array, that has an array in the table.
EG:
$var = (1,4,7,9,14)
$Query = "SELECT * FROM business_listings WHERE category IN ($var)";
'category' would have 4,27,89,101
How can I get this to match if one of the numbers in the $var matches one of the numbers in the table.
If your database column is a list of comma separated values, and you're searching for one value in that list, then you're in a different situation.
If your category column contains the text value 410,406,149,152, like you commented below, and you're searching for fields whose category contains 152, then you'll need to use MySQL's FIND_IN_SET() function.
If you have to check multiple values, then you need to use more than one FIND_IN_SET. If you read the documentation, you'll see that the first argument for FIND_IN_SET must be a single string, not a string list (it can't contain a comma). Use the following instead:
$var = "401,320,152";
$items = explode(",", $var);
foreach ($items as &$i) {
$i = "FIND_IN_SET('" . $i . "', `category`)";
}
$search = implode(" OR ", $items);
unset($i);
$query = "SELECT * FROM business_listings WHERE " . $items;
This will output:
SELECT * FROM business_listings WHERE
FIND_IN_SET('401', `category`) OR
FIND_IN_SET('320', `category`) OR
FIND_IN_SET('152', `category`)
The above script will work even if $var contains only one value.
Finally, as tadman mentioned, since we're getting into queries that can be tricky to build with prepared statements, you need to make sure you're escaping and sanitizing your input properly. For an example, if $var is being retrieved from the user somehow, then before you modify it in any way, you need to escape it with mysqli_real_escape_string():
$var = $mysqli->real_escape_string($var);
Assuming that $mysqli is your open MySQLi connection.
Hope this helps!