I want to convert the string "balm" to a table. Balm was imported from a JSON File using dkjson
balm =
{
"a": "test"
"b" : { "test1":1, "test2":2, "test3":3},
"c" : { "test4: 4, "test5": "/path/to/folder"}
}
Like in the comment wrote, it is easy, if you follow the datatype rules.
Example using NeoVIM...
...it will output "test" under the nvim status line.
Related
I am new to Apache Spark and I am trying to compare two json files.
My requirement is to find out that which key/value is added, removed or modified and what is its path.
To explain my problem, I am sharing the code which I have tried with a small json sample here.
Sample Json 1 is:
{
"employee": {
"name": "sonoo",
"salary": 57000,
"married": true
} }
Sample Json 2 is:
{
"employee": {
"name": "sonoo",
"salary": 58000,
"married": true
} }
My code is:
//Compare two multiline json files
val sqlContext = new org.apache.spark.sql.SQLContext(sc)
//Load first json file
val jsonData_1 = sqlContext.read.json(sc.wholeTextFiles("D:\\File_1.json").values)
//Load second json file
val jsonData_2 = sqlContext.read.json(sc.wholeTextFiles("D:\\File_2.json").values)
//Compare both json files
jsonData_2.except(jsonData_1).show(false)
The output which I get on executing this code is:
+--------------------+
|employee |
+--------------------+
|{true, sonoo, 58000}|
+--------------------+
But here only one field i.e. salary was modified so output should be only the updated field with its path.
Below is the expected output details:
[
{
"op" : "replace",
"path" : "/employee/salary",
"value" : 58000
}
]
Can anyone point me in the right direction?
Assuming each json has an identifier, and that you have two json groups (e.g. folders), you need to compare b/w the jsons in the two groups:
Load the jsons from each group into a dataframe, providing a schema matching the structure of the son. After this, you have two dataframes.
Compare the jsons (by now rows in a dataframe) by joining on the identifiers, looking for mismatched values.
I have converted some columns to JSON using the columns to json node. The output from that is:
{
"Material" : 101,
"UOM" : "GRAM",
"EAN" : 7698,
"Description" : "CHALK BOX"
}
I would like to add the value of the material property as a key to each JSON object. So, my desired output is:
"101": {
"Material" : 101,
"UOM" : "GRAM",
"EAN" : 7698,
"Description" : "CHALK BOX"
}
I have tried entering the following expression in the JSON transformer node but all I get is a question mark in the new column it generates:
$Material$:{"Material":$Material$,"UOM":$UOM$,"EAN":$EAN$,"Description":$Description$}
I have also tried replacing the $Material$ with "Material" but got the same result.
How would I go about this, please?
In case you convert the Material column to String (for example with String Manipulator), you can easily configure the Columns to JSON:
As you can see the Data bound key is the important part.
The String Manipulator node configuration (string($Material$)):
I finally managed to solve this by a different method.
I split the JSON data into several columns, then used the join function to create a string in the required order. I put the resulting string through the string to JSON node to create the new JSON object.
Thanks for all your tips and comments !
I'm wondering if there is a JSON format for editing JSON ?
eg if I had some json
{ "first name" : "Joe" }
and + another json file
{ "action" : "add",
"dest" : "root" -- json pointer maybe
"value" : { "surname : "Blogs" }
}
would get me =
{ "first name" : "Joe", "surname : "Blogs" }
similarly a delete , and change ..
Is there a JSON format that does this? It may be part of a noSQL db or may not be or some javascript library - but i'm not after a JS library more is there a JSON format to do this, One would assume someone has done this before!
It doesn't work like that. JSON is just a data-interchange format (http://www.json.org/). There is no transactional semantic or anything that goes with it.
A reverse to the question asked at How to format Json output ...
EclipseLink makes JSON output code from JAXB objects like this:
{
"test" : {
"count" : 10,
"text" : "Craig"
}
}
How do I make it put quotes around the number?
Thanks!
My fetched DBObject looks like following
{ "_id" : { "$oid" : "50c28ac1de86acf0bdfbeca0"} ,
"schedule" : { "startAt" : 1354926785198 , "endAt" : 1391155200000 , "repeatForever" : true , "interval" : 3600} , "destination" : "Storage-East"}
I want to extract JSON string sans "_id" so that I can deserialize it back to my Java object. If I use following I can remove the '_id' field and it is fine to get the Java object back from JSON String. Is there any other elegant way of doing this ?
dbObj.removeField("_id");
String jsonString = dbObj.toString();
// Now readValue from the json string
thanks.
Instead of removing the data afterwords, just use results projections. You simply remove the _id by using the result projections in a find statement:
//find all documents where destination equals Storage-East, but exclude _id from result set
db.inventory.find( { "destination": 'Storage-East' }, { _id:0 } )
You can find the documentation http://docs.mongodb.org/manual/core/read-operations/#result-projections.