SQL query to break down day by day for entire week - mysql

Question

I have a table of sales in MySQL. I'm trying in 1 query to get a view that looks like this:
AGENT, MONDAY_TOTAL, TUESDAY_TOTAL,WEDNESDAY_TOTAL,THURSDAY_TOTAL,FRIDAY_TOTAL,SATURDAY_TOTAL
What I have so far is this:
SELECT DISTINCT(repname), DAYOFWEEK(sub_date), COUNT(*)
FROM `NewDeals`
WHERE WEEK(sub_date) = WEEK(CURRENT_DATE)
GROUP BY repname, DAYOFWEEK(sub_date)
That gives me values that look like this:
AGENT, DAYOFWEEK, TOTAL
Naturally, I can turn the output of the second example into the first in my code, but if I can just do it with the SQL query I'd rather do that.
SELECT repname,
SUM(IF(DAYOFWEEK(sub_date)=2, 1, 0)) AS MONDAY_TOTAL,
SUM(IF(DAYOFWEEK(sub_date)=3, 1, 0)) AS TUESDAY_TOTAL,
SUM(IF(DAYOFWEEK(sub_date)=4, 1, 0)) AS WEDNESDAY_TOTAL,
SUM(IF(DAYOFWEEK(sub_date)=5, 1, 0)) AS THURSDAY_TOTAL,
SUM(IF(DAYOFWEEK(sub_date)=6, 1, 0)) AS FRIDAY_TOTAL,
SUM(IF(DAYOFWEEK(sub_date)=7, 1, 0)) AS SATURDAY_TOTAL,
SUM(IF(DAYOFWEEK(sub_date)=1, 1, 0)) AS SUNDAY_TOTAL
FROM `NewDeals`
WHERE WEEK(sub_date) = WEEK(CURRENT_DATE)
GROUP BY repname
But getting results for days that haven't happened yet.
Update: This was because we did not constrain the year:
Solution:
SELECT repname,
SUM(IF(DAYOFWEEK(sub_date)=2, 1, 0)) AS MONDAY_TOTAL,
SUM(IF(DAYOFWEEK(sub_date)=3, 1, 0)) AS TUESDAY_TOTAL,
SUM(IF(DAYOFWEEK(sub_date)=4, 1, 0)) AS WEDNESDAY_TOTAL,
SUM(IF(DAYOFWEEK(sub_date)=5, 1, 0)) AS THURSDAY_TOTAL,
SUM(IF(DAYOFWEEK(sub_date)=6, 1, 0)) AS FRIDAY_TOTAL,
SUM(IF(DAYOFWEEK(sub_date)=7, 1, 0)) AS SATURDAY_TOTAL,
SUM(IF(DAYOFWEEK(sub_date)=1, 1, 0)) AS SUNDAY_TOTAL
FROM `NewDeals`
WHERE WEEK(sub_date) = WEEK(CURRENT_DATE) AND YEAR(sub_date) = YEAR(CURRENT_DATE)
GROUP BY repname

Answer 1

You can use an IF function to select only DAYOFWEEK-related counts, then sum every counted element inside the SUM aggregate function as follows:
SELECT repname,
SUM(IF(DAYOFWEEK(sub_date)=2, 1, 0)) AS MONDAY_TOTAL,
SUM(IF(DAYOFWEEK(sub_date)=3, 1, 0)) AS TUESDAY_TOTAL,
SUM(IF(DAYOFWEEK(sub_date)=4, 1, 0)) AS WEDNESDAY_TOTAL,
SUM(IF(DAYOFWEEK(sub_date)=5, 1, 0)) AS THURSDAY_TOTAL,
SUM(IF(DAYOFWEEK(sub_date)=6, 1, 0)) AS FRIDAY_TOTAL,
SUM(IF(DAYOFWEEK(sub_date)=7, 1, 0)) AS SATURDAY_TOTAL,
SUM(IF(DAYOFWEEK(sub_date)=1, 1, 0)) AS SUNDAY_TOTAL
FROM `NewDeals`
WHERE WEEK(sub_date) = WEEK(CURRENT_DATE)
GROUP BY repname
Note: when the DISTINCT keyword is applied, it will work on every selected field of your SELECT clause, you can't make a distinct of a single field using parentheses.