I try to find a function where I can extract the result of the last month only
(for exemple if I launch the query in november, I want to display only the resultat of october)
There the result :
I dont know if I have to enter the function in my select or where clause
Thanks for you help!!
CHeers!
I tried the function month(date, -1)
I want to see all the result for the previous month
You can try getting the date and applying in the where clause.
Note that there may be more efficient options available.
Query to Use:
WHERE
DATE_TRANSACTION BETWEEN
trunc(date_sub(CURRENT_DATE, dayofmonth(CURRENT_DATE)),'MM')
AND
date_sub(CURRENT_DATE, dayofmonth(CURRENT_DATE))
Explanation:
CURRENT_DATE - Gives the current Date
dayofmonth(CURRENT_DATE) - Gives the day part of current date.
date_sub(CURRENT_DATE, dayofmonth(CURRENT_DATE)) - Gives the last day of previous month. Assume current_date is 2022-11-23, dayofmonth will give 23, when you subtract 23 days, it goes to the last day of previous month i.e. 2022-10-31.
trunc(date_sub(CURRENT_DATE, dayofmonth(CURRENT_DATE)),'MM') - Truncates date to first day of month.
DATE_TRANSACTION - between these two days.
Related
I am trying to get data by week, month and year.
I store date YYYY-MM-DD HH:MM:SS.
What I am doing is below;
Fetch one week old data;
query + AND WEEK(date) = WEEK(CURDATE())
Fetch a month old data;
query + AND MONTH(date) = MONTH(CURDATE())
The thing is I couldnt be able to get the data correct. For instance when I want to get week old data, I am gettin a year old one too.
Is there any other query that I could use? I have tried DATE(NOW()) - INTERVAL 30 DAY. It works but very slow.
Thanks!
I believe that the problem is that the WEEK function returns the week of the year. So, Jan 1st 2017 might be week 1 (also might be week 53 of the previous year depending on the day of the week and how MySQL handles it). But then, Jan 1st of 2016 is also week 1 - just for a different year.
Trying changing it to:
query + AND WEEK(date) = WEEK(CURDATE()) AND YEAR(date) = YEAR(CURDATE())
Also, if you're storing this as a string then definitely change it to a DATETIME
WHERE ...
AND date >= CURDATE() - INTERVAL 7 DAY
AND date < CURDATE()
Gives you the 7 days ending with yesterday. Use other techniques to get a particular month or week.
This technique is also much faster for large tables with a suitable index. Hiding date inside a function, such as WEEK() prevents the use of an index.
I need some help with running a query at month end. Each 1st working day of a month may differ, and therefore I may only be at work on the 3rd of a given month.
I am trying to figure out what my WHERE statement would look like to select data for the current month, unless it is:
1st of a month, then it will need to select everything from the previous month
1st working day of a month, which could be the 3rd. It will then also need to select the previous month's data.
These are two scenarios I am currently playing with, and don't have data to test it with as yet.
I have thought about doing
WHERE
MONTH(action_date) = MONTH(DATE_SUB(CURDATE(),INTERVAL 1 DAY))
But this then also returns data from 2016.
I have also thought of doing
WHERE
action_date = DATE_SUB(CURDATE(),INTERVAL 1 DAY)
But this would not work if today was say Monday the 3rd.
I would appreciate any answers that would give me the best way of doing this
You could simply subtract a few more days or even a month from the date, as all you will actually get from the subtraction is a month anyway
MONTH(DATE_SUB(CURDATE(),INTERVAL 5 DAY))
OR
MONTH(DATE_SUB(CURDATE(),INTERVAL 1 MONTH))
SELECT DATE(STR_TO_DATE(CONCAT(CONCAT(YEAR('$uDate1'), week), ' Monday'), '%X%V %W') +
INTERVAL (7 - DAYOFWEEK(STR_TO_DATE(CONCAT(CONCAT(YEAR('$uDate1'), week), ' Monday'),
'%X%V %W'))) DAY)
as week_end_date
What this statement does is take the date I give it ($uDate1) and give me the week end date (Saturday) of that week. This works well and I am happy with it, kinda.
I was wondering if there were some things I missed that would either make this more efficient or even if I missed some shortcuts to this.
Any suggestions for me?
week >= WEEK('$uDate1') AND week <= WEEK('$uDate2')
This is in my WHERE clause. So basically if I use this...
DATE('$uDate1', INTERVAL 7 - DAYOFWEEK('$uDate1') DAY)
...then it returns the same day for all records. I need it to be able to go over a span of a few weeks.
I have a column in my database named 'week'. It simply stores an INT that corresponds to the week of the year. (ex. 21 for this week)
I then have two date picker boxes. The output gets the week end date based of each week that is BETWEEN and INCLUDES the days chosen.
5/10/2016 & 5/26/2016 outputs 5/14/2016, 5/21/2016, 5/28/2016
What gets exported to CSV file looks something like this..
WEEK END, LAST NAME, FIRST NAME, ...
5/10/2016, Smith, John, ...
5/26/2016, Jones, James, ...
It outputs anyone who had hours during the week, with the week end date.
SIDE NOTE: I do appreciate the comments and help. I don't want anyone to stress over this though! Just curious if better way. :)
I am not sure why your current SQL is so complicated.
You say it is just to take a date and give me the week end date (Saturday) of that week .
How you are doing this at the moment is:-
Yours is taking the year
Adding the week of the year (I assume - should be WEEK('$uDate1') I think)
Adding on the day as a string (so for example for today it would be 2016 21 Monday )
Changing that string back to a date a datetime value
Converting that datetime value back to a date.
Then taking the year again
Adding the week of the year again
Getting the day of the week of the resulting string. As you have concatenated Monday on to the date then the day of the week will always be 2.
Taking that resulting day of the week and subtracting it from 7. As the day of the week will always be 2 this will always result in 5
Adding on the day as a string (so for example for today it would be 2016 21 Monday ).
This value is then added on to the previously calculated date, taking the Monday date and adding 5 days.
My suggestion was to just use:-
DATE_ADD($uDate1, INTERVAL 7 - DAYOFWEEK($uDate1) DAY)
which is far simpler, and appears to cover your requirements.
EDIT
Looking at your edit you want a list of all the Saturdays for weeks all or partially between 2 passed dates.
If so I think the following will do it and hopefully be more efficient as there is no need to translate dates to and from string. Note it relies on your week table to add to the date, hence only copes with date ranges of up to that many weeks.
SELECT DATE_ADD(DATE_ADD('$uDate1', INTERVAL 7 - DAYOFWEEK('$uDate1') DAY), INTERVAL `week` WEEK) AS aDate
FROM `week`
HAVING aDate BETWEEN '$uDate1' AND DATE_ADD('$uDate2', INTERVAL 7 - DAYOFWEEK('$uDate2') DAY)
ORDER BY aDate
As I mentioned in comment you should move this transformation from mysql query to php code.
I see no reason to do this calculation on mysql side.
http://ideone.com/48zLvF
$week_day = intval(date('w',$uDate1));
if ($week_day<6) {
$end_of_week = $uDate1+(86400*(6-$week_day));
} else {
$end_of_week = $uDate1;
}
I need to access criteria Currently Month and Next Month
For example : For Today i need 01.04.15 to 31.05.15 but next Month ill need 01.05.15 to 31.06.15
I wrote to criteria this code but i could not get any solution
**
BETWEEN DateSerial(Year(Date()); Month(Date()); 1) AND
DateSerial(Year(Date()); Month(Date()) + 2; 0)
**
if you have a solution about this problem. Please Share with me
Thanks
Y.Ö.
Between DateSerial(Year(Date()); Month(Date()); 1) And DateSerial(Year(Date()); Month(Date()) + 2; 0)
is correct, so perhaps you just don't have any data within this range.
Think about it. What happens when current month is Nov & Dec then month + 2 = 13 or 14 and not a valid month. Hence, you will need a IIf statement to handle the year being advanced to next year and to handle the Year and the month accordingly. Also, think of the Day again you will need a IIF statement to handle months ending 28, 30 and 31.
Sorry, I was wrong how Access handle the Yearend and the month. Here's some more info. that was posted on https://access-excel.tips/; So; I am not taking the credit.
Unlike first date of month, we cannot directly input “31” in the day argument because every month has different number of days. Instead we can find the first day of next month and then minus 1 day. Access is very clever that when you add 1 month to December, the year also adds 1, so this trick also works for year end. The formula below returns the last date of current month.
DateSerial(Year(Date()),Month(Date())+1,1)-1
We can also simply this formula using 0 in the day argument instead of using -1. 0 returns the last date of previous month.
DateSerial(Year(Date()), Month(Date()) + 1, 0)
I want to select all dates within the last week.
But not by simply counting the current date - 7, as all posts Ive come across suggest.
This is how I actually have it for the SUM now....
SELECT SUM(total) FROM payforms WHERE user_id = 1 GROUP BY WEEK(date)
This gives me a nice total...
But I want to retrieve all individual records within the last week.
So I can use a BETWEEN query....but how do I get it to look in the current week.
Example...
Tuesday I want it to only find values from Sun, Mon, Tue.
On wednesday, I want it to find Sun, Mon, Tue, Wed.
On Saturday it finds the whole previous week. etc
So to be more clear....
I dont want it to find last Monday, on a monday.
On Mondays it should only display Mondays, if you get what I mean.
Can I do this??
Thanks
select * from payforms where yearweek(date) = yearweek(now());
Although I think MySQL weeks start on Sunday
You can make use of the WEEKDAY date function, which returns the day index of the week.
If I understand your question correctly, you could use this query:
SELECT date, SUM(total)
FROM payforms
WHERE date >= CURDATE() - INTERVAL DAYOFWEEK(CURDATE())-1 DAY
GROUP BY date
Please see fiddle here.
This will SUM all totals for every day of the current week, starting on last Sunday. If you want it to start on last Monday you can use this:
WHERE date >= CURDATE() - INTERVAL WEEKDAY(CURDATE()) DAY