how to call a function to another function in julia? - function

Question

I am writing a code in julia but I am unable to call a function from another function. Code is:
function add(x, y)
if x == 3 && y ==1
z =0
else x == 0 && y ==0
z =1
end
return z
end
function width(a, b, c)
add(x,y)
.....
end
The variables in add function will be used in width function but as I am new to julia, I am unable to call add in the other function. Kindly guide.
Edit:
I tried declaring with the z but it also didn't worked
struct z
a::Int
b::Int
end

Answer 1

There are two problems in your code that are not related to Julia per se. First problem in the add function: if x == 3 && y == 1 the output should be z = 0, else if x == 0 && y == 0, actually the if was missing, the output should be z = 1. Now what will be the output if, e.g., x = 1 && y == 1? The answer is nothing and z will be undefined.
To fix the add function, you should add a default branch for the if-else.
function add(x, y)
if x == 3 && y == 1
z = 0
elseif x == 0 && y == 0
z = 1
else
z = -1 # some default
end
return z
end
The same function could be written more concisely as:
function add(x, y)
x == 3 && y == 1 && return 0
x == 0 && y == 0 && return 1
return -1 # some default
end
which can even be written in a one-liner like this:
add(x, y) = x == 3 && y == 1 ? 0 : x == 0 && y == 0 ? 1 : -1 # some default
The second problem is with the width function. x and y are not defined inside the body of the width function. So, you can't call add(x, y). It should be z = add(a, b) where z should be used in subsequent calculations. Finally, check what the third argument c is for, otherwise, remove it.
function width(a, b, c)
z = add(a, b)
.....
end