I want to differentiate duplicate values in my query by adding an increment or a count of some sort.
The idea is to concatenate my two columns to create a new unique reference.
I tried this :
SELECT
value,
COUNT(*) OVER (PARTITION BY value) value_incr
FROM table
and got the following result :
| value | value_incr |
| --- | --- |
| a | 1 |
| b | 3 |
| b | 3 |
| b | 3 |
| c | 2 |
| c | 2 |
| d | 1 |
But what I would like to get is :
| value | value_incr |
| --- | --- |
| a | 1 |
| b | 1 |
| b | 2 |
| b | 3 |
| c | 1 |
| c | 2 |
| d | 1 |
Is there a way to differentiate my duplicates in Oracle 12 ?
My best solution for now is to add a ROWNUM column, but it's not really satisfying.
Thank you
Related
There are two tables,
Table A has a three-level structure that looks like
| id | name | level | up_level_id |
| :------- | :-------: | :------: | ----------:|
| 1 | lv1_name1 | 1 | null |
| 2 | lv1_name2 | 1 | null |
| 3 | lv2_name1 | 2 | 1 |
| 4 | lv2_name2 | 2 | 2 |
| 5 | lv3_name1 | 3 | 3 |
| 6 | lv3_name2 | 3 | 3 |
| 7 | lv3_name3 | 3 | 4 |
| 8 | lv3_name4 | 3 | 4 |
Table B looks like
| amount | org_id |
| -------- | -------- |
| 12,000 | 5 |
| 15,000 | 6 |
| 20,000 | 7 |
| 18,000 | 8 |
Table A and Table B can be joined on A.id=B.org_id, but they are all at the level-3 of Table A（Only level-3 has their amount）
I want to query the top-level name,level-1 name, and the summary amount that looks like
| sum_amount | top_lvl_name |
| -------- | -------- |
| 27,000 | lv1_name1 |
| 38,000 | lv1_name2 |
For Testing, I have already accomplished the query of the level-1 name from the level-3 id in TableA
The SQL is as follows
SELECT name
FROM TableA
WHERE id IN (
SELECT up_level_id
FROM Table A
WHERE id IN (
SELECT up_level_id
FROM Table A
WHERE id=5) --query the id:5's top-level name
);
But when I join these two tables as follows, it goes wrong
SELECT sum(amount) AS sum_amount, name AS top_lvl_name
FROM TableA, TableB
WHERE id = org_id
AND id IN (
SELECT up_level_id
FROM TableA
WHERE id IN (
SELECT up_level_id
FROM TableA
WHERE TableA.id IN(
SELECT org_id
FROM TABLEB
)
)
);
I get nothing as above
What can I do to make this query to be correct?
Thanks for everyone's answer and comment.
Finally, I find it very difficult to query the result as I wish. So, I've come up with a shortcut——create a new table that a three-level structure recorded horizontally, which looks like
| lv1_id | lv2_name | lv2_id | lv2_name | lv3_id | lv3_name |
| :------- | :-------: | :------: | :----------:| :------: | :----------:|
| 1 | lv1_name1 | 3 | lv2_name1 | 5 | lv3_name1 |
| 1 | lv1_name1 | 3 | lv2_name1 | 6 | lv3_name2 |
| 2 | lv1_name2 | 4 | lv2_name1 | 7 | lv3_name3 |
| 2 | lv1_name2 | 4 | lv2_name1 | 8 | lv3_name4 |
As above,I can easily connect two tables
For example, we have a table:
| id | field | value |
|----|-------|-------|
| 1 | X | Y |
| 1 | V | Y |
| 1 | Z | W |
| 1 | Z | T |
and I want to have a following output:
| id | field | value | field_occurencies |
|----|-------|-------|-------------------|
| 1 | X | Y | 1 |
| 1 | V | Y | 1 |
| 1 | Z | W | 2 |
| 1 | Z | T | 2 |
Is there any way to do this?
Windowing functions are for that very purpose:
COUNT(*) over (partition by field) as field_occurence
We can't tell if your particular database product supports window functions (you didn't tell us)
I am trying to write a sql logic which will compare rows for a user and based on a condition it will pick one.
For eg.
+-------+------+--+
| UseId | Code | |
+-------+------+--+
| 1 | A | |
| 2 | B | |
| 3 | C | |
| 4 | D | |
| 4 | E | |
| 5 | F | |
| 5 | G | |
+-------+------+--+
The output im trying to get is, if a user has 2 records compare the code like if code =D and code=E for user 4, then retain row with code E
for user 5 , if Code=F and Code=G then retain row with code F
so the output should look like
+-------+------+--+
| UseId | Code | |
+-------+------+--+
| 1 | A | |
| 2 | B | |
| 3 | C | |
| 4 | E | |
| 5 | F | |
| | | |
+-------+------+--+
I need to show all records from table A per user_id in table B, even if not matched. I have tried with LEFT JOIN and GROUP-ing but did not achieved my expected result. Also my skill on SQL is not good, so need help.
Here is my table data:
Table A : gateways
=========================
| ID | Gateway |
=========================
| 1 | Paypal |
| 2 | Webpay |
| 3 | Stripe |
=========================
Table B : gateway_user
==================================
| GatewayID | UserID | Active |
==================================
| 1 | 1 | Y |
| 1 | 2 | Y |
| 1 | 3 | N |
| 2 | 1 | Y |
| 2 | 2 | N |
| 3 | 1 | Y |
==================================
The result I expect is to see all results from left table per user_id on right, even if it doesn't exist in Right Table.
==================================
| GatewayID | UserID | Active |
==================================
| 1 | 1 | Y |
| 1 | 2 | Y |
| 1 | 3 | N |
| 2 | 1 | Y |
| 2 | 2 | N |
| 2 | 3 | null |
| 3 | 1 | Y |
| 3 | 2 | null |
| 3 | 3 | null |
==================================
Thank you.
You have to create artificial table containing list of all userId:
SELECT gw.id, ua.userId, gu.active
FROM gateways gw
JOIN (SELECT DISTINCT userId
FROM gateway_user) ua
LEFT JOIN gateway_user gu
ON gu.userId = ua.userId AND gu.gatewayId = gw.gatewayId
Is there a way in SQL (MySQL) to do a "round robin" ORDER BY on a particular field?
As an example, I would like to take a table such as this one:
+-------+------+
| group | name |
+-------+------+
| 1 | A |
| 1 | B |
| 1 | C |
| 2 | D |
| 2 | E |
| 2 | F |
| 3 | G |
| 3 | H |
| 3 | I |
+-------+------+
And run a query that produces results in this order:
+-------+------+
| group | name |
+-------+------+
| 1 | A |
| 2 | D |
| 3 | G |
| 1 | B |
| 2 | E |
| 3 | H |
| 1 | C |
| 2 | F |
| 3 | I |
+-------+------+
Note that the table may have many rows, so I can't do the ordering in the application. (I'd obviously have a LIMIT clause as well in the query).
I'd try something like:
SET #counter = 0;
SELECT (#counter:=#counter+1)%3 as rr, grp, name FROM table ORDER by rr, grp
What you can do is create a temporary column in which you create sets to give you something like this:
+-------+------+-----+
| group | name | tmp |
+-------+------+-----+
| 1 | A | 1 |
| 1 | B | 2 |
| 1 | C | 3 |
| 2 | D | 1 |
| 2 | E | 2 |
| 2 | F | 3 |
| 3 | G | 1 |
| 3 | H | 2 |
| 3 | I | 3 |
+-------+------+-----+
To learn how to create the sets, have a look at this question/answer.
Then its a simple
ORDER BY tmp, group, name
You can use MySQL variables to do this.
SELECT grp, name, #row:=#row+1 from table, (SELECT #row:=0) r ORDER BY (#row % 3);
+------+------+--------------+
| grp | name | #row:=#row+1 |
+------+------+--------------+
| 1 | A | 1 |
| 2 | D | 4 |
| 3 | G | 7 |
| 1 | B | 2 |
| 2 | E | 5 |
| 3 | H | 8 |
| 1 | C | 3 |
| 2 | F | 6 |
| 3 | I | 9 |
+------+------+--------------+