I have a table with an id column and a source column.
I want to return only the source values that all ids share.
E.g. in the table below id 1,2,3 all share 10 and 20, but id 3 is missing the source value 30, so 30 is not valid and I want to return 10 and 20.
I'm using MySQL and want to put this in a stored procedure.
How do I do this?
id
source
1
10
1
20
1
30
2
10
2
20
2
30
3
10
3
20
You may use COUNT(DISTINCT) function as the following:
SELECT source FROM
table_name
GROUP BY source
HAVING COUNT(DISTINCT id)=(SELECT COUNT(DISTINCT id) FROM table_name)
To do this within a stored procedure:
CREATE PROCEDURE getSourceWithAllIds()
BEGIN
SELECT source FROM
table_name
GROUP BY source
HAVING COUNT(DISTINCT id)=(SELECT COUNT(DISTINCT id) FROM table_name);
END
The idea is to select the count of distinct id values for each source, which is done by COUNT(DISTINCT id)... GROUP BY source, then match this count with the distinct count of all id values existed in the table; HAVING COUNT(DISTINCT id)=(SELECT COUNT(DISTINCT id) FROM table_name).
If the two counts are equal, then the source have all the distinct ids existed in the table.
i.e. All distinct ids in the table are (1, 2, 3) count = 3, and distinct ids for a source =10 are (1, 2, 3) count=3. For source = 30, the distinct ids are (1, 2) count=2 so it will not be returned by the query (2<>3).
See a demo.
Related
I apologize for the possible incorrectness in the presentation, I use a translator. Let's say there is a users table in which there is an id field. And there is a list that lists the id numbers and some of them are repeated. My query
select id, count(*)
from users
where id in (3, 10, 10, 10)
group by id;
returns the following 3 - 1, 10 - 1. And I would like to get 3 - 1, 10 - 3, and so on. Is it possible to get it somehow?
UPD.
The data in the list (3, 10, 10, 10) is just an example, the exact number of digits is not known because they are returned from another question.
You would need to use a join. You can put the values in a derived table for this:
select id, count(*)
from users u join
(select 3 as id union all
select 10 as id union all
select 10 as id union all
select 10 as id union all
) i
using(id)
group by id;
I am super new to access and having difficulty with a query. My table (tblpacks) is the following:
id user_id group_id quota_id
1 1 1 1
2 1 2 1
3 2 1 1
4 3 1 1
Ideally, what I now is to get hte number of unique users and groups for quota_id=1
The result will be:
total_users = 3
total_groups = 2
If you only wanted to count one field, there would by a simple solution, but since you want to count 2 separate fields, you in fact need at least 2 separate queries.
My answer is to use a UNION query as the source for counting. This UNION query returns the distinct user_id values (with Null as group_id) and the distinct group_id values (with Null as user_id). I omitted the DISTINCT keyword, because UNION (without ALL) does a DISTINCT query automatically. As the datatypes where not recognized correctly when using a constant Null field in the first SELECT statement of the UNION query, I added a third SELECT statement as the first one, which selects both fields from the table but returns no records:
SELECT Count(user_id) AS total_users, Count(group_id) AS total_groups
FROM (
SELECT user_id, group_id FROM tblpacks WHERE Yes=No
UNION
SELECT user_id, Null FROM tblpacks WHERE quota_id=1
UNION
SELECT Null, group_id FROM tblpacks WHERE quota_id=1
) AS qsub;
my Ui return id in this format 1:6:3 so i want to sum the value corresponding to that id. example if id return is = 1:6:3
then output will= 100+50+140=290
How about SELECT SUM(value) FROM table WHERE ID IN (1,6,3) ?
Took some time to figure out what's the question. I think I got it now - it is about Apex and its "capability" to allow multiple selection from, for example, a select list or shuttle item. When you do that, those multiple values are represented as a colon-separated string.
If we suppose that it was a select list item, it requires two values: display and return. The resulting string contains those return values, which means that you selected several items whose return values were 1, 6 and 3 and - as described above - stored as 1:6:3.
In order to do something with them - in your example, sum values from the table - you'll have to first parse that string into rows and join the result with the "real" table (the one whose image you posted). Let's call it the TEST table; here it is:
SQL> create table test (id number, value number, name varchar2(2));
Table created.
SQL> insert into test
2 select 1, 100, 'a' from dual union
3 select 2, 110, 'b' from dual union
4 select 3, 140, 'c' from dual union
5 select 4, 203, 'd' from dual union
6 select 5, 230, 'e' from dual union
7 select 6, 50 , 'f' from dual;
6 rows created.
In Apex, you'd do it as follows: P1_ITEM is a Page 1 item that contains the '1:6:3' string:
select sum(t.value) result
from test t join (select regexp_substr(:P1_ITEM, '[^:]+', 1, level) id
from dual
connect by level <= regexp_count(:P1_ITEM, ':') + 1
) a on a.id = t.id;
Just to demonstrate it in SQL*Plus, this is the result:
SQL> select sum(t.value) result
2 from test t join (select regexp_substr('&&P1_ITEM', '[^:]+', 1, level) id
3 from dual
4 connect by level <= regexp_count('&&P1_ITEM', ':') + 1
5 ) a on a.id = t.id;
Enter value for p1_item: 1:6:3
RESULT
----------
290
SQL>
I would like to select multiple values from a single column in a database table that equal to a number of values. I want all these values to match otherwise it should return no rows. I do not want to use "IN" as that is equal to "OR".
The following is a basic mockup of what it should do but it needs to be dynamic as I wish to use it with a PDO statement. If the database only contains id's 1 and 2 it should fail ie return no rows.
SELECT
id
FROM
reports
WHERE
id=1 AND id=2 AND id=3
I have the current code as follow which is incorrectly returning zero rows:
SELECT id,title
FROM reports
WHERE id IN (1,2)
GROUP BY title
HAVING COUNT(DISTINCT id) = 2
My current table structure is as follows:
http://www.sqlfiddle.com/#!2/ce4aa/1
You have to use HAVING COUNT(id) = 3 to ensure that the selected rows have all the three id's. Something like:
SELECT *
FROM reports
WHERE id = 1 OR id = 2 OR id = 3 -- Or id IN(1, 2, 3)
GROUP BY SomeOtherField
HAVING COUNT(DISTINCT id) = 3;
Or:
SELECT *
FROM reports
WHERE SomeOtherField IN (SELECT SomeOtherField
FROM reports
WHERE id = 1 or id = 2 -- Or id IN(1, 2, 3)
GROUP BY SomeOtherField
HAVING COUNT(DISTINCT id) = 3
);
Note that: You have to GROUP BY SomeOtherField where SomeOtherField is other field than id because if you GROUP BY id with HAVING COUNT(id) you won't get any records, since COUNT(id) will be always = 1.
Edit: fixed WHERE clause, OR's instead of AND's.
SQL Fiddle Demo
just a quick question:
i have to have one single query that has multiple rows - some rows are identicle - and the order of rows must be preserved in the result -
some idea of what im refering to:
SELECT id,date
FROM items
WHERE id IN (1,2,1,3)
ORDER BY id=1 DESC,id=2 DESC,id=1 DESC,id=3 DESC;
unfortunately mysql result is this:
1,2,3
not 1,2,1,3
it removes the duplicate which i have to have in my result to display in multiple panels on the same webpage -
i really dont want to loop thru each id one by one to get them the way i want to display -
is there a way to actually have one single query that will preserve the order and pull out rows based on request whether its unique or not -
Your query as it stands will never work, because duplicate values in a list of values of an IN clause are ignored. The only way to make this work is by using UNION ALL:
SELECT id, date FROM items where id = 1
UNION ALL
SELECT id, date FROM items where id = 2
UNION ALL
SELECT id, date FROM items where id = 1
UNION ALL
SELECT id, date FROM items where id = 3;
But to be frank, I suspect your data model so far past screwed it's unusable.
try
SELECT
id,
date
FROM items
WHERE id IN (1,2,1,3)
ORDER BY FIND_IN_SET(id, '1,2,1,3')
Another scrupulous way to answer a suspicious question:
SELECT
items.id,
items.date
FROM
items
JOIN
( SELECT 1 AS id, 1 AS ordering
UNION ALL
SELECT 2, 2
UNION ALL
SELECT 1, 3
UNION ALL
SELECT 3, 4
) AS auxilary
ON
auxilary.id = items.id
ORDER BY
auxilary.ordering
Another approach (untested, but should give you the idea):
CREATE TEMPORARY TABLE tt (id INT, ai int unsigned auto_increment primary key);
INSERT INTO tt (id) VALUES (1), (2), (1), (3);
SELECT
id,
date
FROM items JOIN tt USING (id)
ORDER BY tt.ai;
keeps the given order.
If you want to include the records with id=1 and the order doesn't matter as long as you get them, you can split your query into two queries, one for (1,2,3) union all the other query for id=1 or just do:
... In (1,2)
Union all
... In (1,3)
Example:
Select * from
(Select case id when 1 then 1 when 2 then 2 as pseudocol, othercolumns
From table where Id in (1,2)
Union all
Select case id when 1 then 3 when 3 then 4 as pseudocol, othercolumns
From table where Id in (1,3)) t order by pseudocol
Instead of doing what you are trying to, just select the unique rows you need. In the frontend code, store each unique row once in a key=>value structure, where key is the item ID and value is whatever data you need about that item.
Once you have that you can use frontend logic to output them in the desired order including duplicates. This will reduce the amount of redundant data you are trying to select.
For example This is not usable code - exact syntax required depends on your scripting language
-- setup a display order
displayOrder= [1,2,1,3];
-- select data from database, order doesn't matter here
SELECT id,date
FROM items
WHERE id IN (displayOrder);
-- cache the results in a key=> value array
arrCachedRows = {};
for (.... each db row returned ...) {
arrCachedRows[id] = date;
}
-- Now output in desired order
for (listIndex in displayOrder) {
-- Make sure the index is cached
if (listIndex exists in arrCachedRow) {
echo arrCachedRows[listIndex ];
}
}
If you must persist in using UNION despite my warnings
If you go against the above recommendation and absolutely MUST have them back in 1 query in that order then add on an additional row which will enforce the row order. See below query where I use variable #subIndex to add an incrementing value as subIndex. This in turn lets you reorder by that and it'll be in the requested order.
SELECT
i.*
FROM (
SELECT #subIndex:=#subIndex+1 AS subIndex, id, date FROM items where id = 1
UNION
SELECT #subIndex:=#subIndex+1 AS subIndex, id, date FROM items where id = 2
UNION
SELECT #subIndex:=#subIndex+1 AS subIndex, id, date FROM items where id = 1
UNION
SELECT #subIndex:=#subIndex+1 AS subIndex, id, date FROM items where id = 3
) AS i,(SELECT #subIndex:=0) v
ORDER BY i.subIndex
Or a slightly cleaner version that keeps item selection until the outside and hides the subindex
SELECT
items.*
FROM items
-- initialise variable
INNER JOIN (SELECT #subIndex:=0) v
-- create a meta-table with the ids desired in the order desired
INNER JOIN (
SELECT #subIndex:=#subIndex+1 AS subIndex, 1 AS id
UNION
SELECT #subIndex:=#subIndex+1 AS subIndex, 2 AS id
UNION
SELECT #subIndex:=#subIndex+1 AS subIndex, 1 AS id
UNION
SELECT #subIndex:=#subIndex+1 AS subIndex, 3 AS id
) AS i
ON i.id = items.id
-- order by the subindex from i
ORDER BY i.`subIndex` ASC