More than 100 widgets in single page [duplicate] - widget

Is there any max number for sections while adding to card in googlescript?
I have a card with 13 sections in it, but it displays only 12 sections, Is there any specific limit on adding sections to the card
I have multiple sections which are going to add dynamically to the card,Is this possible to add n number of sections to the card?.

Yes, as of now the limit of sections a Card can have is 100.
However, 13 items are not a problem. The problem you are facing lies somewhere else in your code. Without that information we are not able to help.
As proof, here is some code that successfully shows how to adds 15 widgets:
function buildAddOn(e) {
var tempsections = [];
for (var i =0 ; i<15; i++) {
var tempsection = CardService.newCardSection().setHeader('Texts '+ i + 'aaaa.');
tempsection.addWidget(CardService.newTextButton().setText("Sections num"+i).setOnClickAction(CardService.newAction().setFunctionName("test")));
tempsections.push(tempsection);
}
// Build the main card after adding the section.
var card = CardService.newCardBuilder()
.setHeader(CardService.newCardHeader()
.setTitle('Quick Label')
.setImageUrl('https://www.gstatic.com/images/icons/material/system/1x/label_googblue_48dp.png'))
.addSection(tempsections[0])
.addSection(tempsections[1])
.addSection(tempsections[2])
.addSection(tempsections[3])
.addSection(tempsections[4])
.addSection(tempsections[5])
.addSection(tempsections[6])
.addSection(tempsections[7])
.addSection(tempsections[8])
.addSection(tempsections[9])
.addSection(tempsections[10])
.addSection(tempsections[11])
.addSection(tempsections[12])
.addSection(tempsections[13])
.addSection(tempsections[14])
.build();
return [card];
}
function test() {
return 0;
}
Also, for proof, here is the change to add 101 sections:
function buildAddOn(e) {
var tempsections = [];
for (var i =0 ; i<101; i++) {
var tempsection = CardService.newCardSection().setHeader('Texts '+ i + 'aaaa.');
tempsection.addWidget(CardService.newTextButton().setText("Sections num"+i).setOnClickAction(CardService.newAction().setFunctionName("test")));
tempsections.push(tempsection);
}
// Build the main card after adding the section.
var card = CardService.newCardBuilder()
.setHeader(CardService.newCardHeader()
.setTitle('Quick Label')
.setImageUrl('https://www.gstatic.com/images/icons/material/system/1x/label_googblue_48dp.png'));
for (var i =0 ; i<101; i++) {
card = card.addSections(tempsections[i]);
}
card = card.build();
return [card];
}

Related

Reorder the context menu and add dividers in Forge Viewer

Is there a way to rearrange the order of the context menu items and possibly add dividers between them for grouping?
I followed this post https://forge.autodesk.com/blog/customize-viewer-context-menu to make a custom context menu.
For dividers I found functionality in the source code:
menu.push({divider: true})
Snippet of the source code for show() in contextMenu:
for (var i = 0; i < menu.length; ++i) {
var defn = menu[i],
title = defn.title,
target = defn.target,
icon = defn.icon,
shortcut = defn.shortcut,
divider = defn.divider;
var hasChildren = Array.isArray(target);
if (hasChildren && !menu.isChild) {
addExpandDiv = true; // Keep track of any item that is expandable
} else {
// As described in the design, limit the the number of menu levels to two.
// We will flatten the target array
hasChildren = false;
}
if (divider) {
menuItem = this.createDivider();
menuDiv.appendChild(menuItem);
} else {

How to select all underlined text in a paragraph

I'm trying to create a google apps script that will format certain parts of a paragraph. For example, text that is underlined will become bolded/italicized as well.
One docs add-on I have tried has a similar feature: https://imgur.com/a/5Cw6Irn (this is exactly what I'm trying to achieve)
How can I write a function that will select a certain type of text and format it?
**I managed to write a script that iterates through every single letter in a paragraph and checks if it's underlined, but it becomes extremely slow as the paragraph gets longer, so I'm looking for a faster solution.
function textUnderline() {
var selectedText = DocumentApp.getActiveDocument().getSelection();
if(selectedText) {
var elements = selectedText.getRangeElements();
for (var index = 0; index < elements.length; index++) {
var element = elements[index];
if(element.getElement().editAsText) {
var text = element.getElement().editAsText();
var textLength = text.getText().length;
//For every single character, check if it's underlined and then format it
for (var i = 0; i < textLength; i++) {
if(text.isUnderline(i)) {
text.setBold(i, i, true);
text.setBackgroundColor(i,i,'#ffff00');
} else {
text.setFontSize(i, i, 8);
}
}
}
}
}
}
Use getTextAttributeIndices:
There is no need to check each character in the selection. You can use getTextAttributeIndices() to get the indices in which the text formatting changes. This method:
Retrieves the set of text indices that correspond to the start of distinct text formatting runs.
You just need to iterate through these indices (that is, check the indices in which text formatting changes), which are a small fraction of all character indices. This will greatly increase efficiency.
Code sample:
function textUnderline() {
var selectedText = DocumentApp.getActiveDocument().getSelection();
if(selectedText) {
var elements = selectedText.getRangeElements();
for (var index = 0; index < elements.length; index++) {
var element = elements[index];
if(element.getElement().editAsText) {
var text = element.getElement().editAsText();
var textRunIndices = text.getTextAttributeIndices();
var textLength = text.getText().length;
for (let i = 0; i < textRunIndices.length; i++) {
const startOffset = textRunIndices[i];
const endOffset = i + 1 < textRunIndices.length ? textRunIndices[i + 1] - 1 : textLength - 1;
if (text.isUnderline(textRunIndices[i])) {
text.setBold(startOffset, endOffset, true);
text.setBackgroundColor(startOffset, endOffset,'#ffff00');
} else {
text.setFontSize(startOffset, endOffset, 8);
}
}
}
}
}
}
Reference:
getTextAttributeIndices()
Based on the example shown in the animated gif, it seems your procedure needs to
handle a selection
set properties if the selected region is of some format (e.g. underlined)
set properties if the selected region is NOT of some format (e.g. not underlined)
finish as fast as possible
and your example code achieves all these goals expect the last one.
The problem is that you are calling the text.set...() functions at each index position. Each call is synchronous and blocks the code until the document is updated, thus your run time grows linearly with each character in the selection.
My suggestion is to build up a collection of subranges from the selection range and then for each subrange use text.set...(subrange.start, subrange.end) to apply the formatting. Now the run time will be dependent on chunks of characters, rather than single characters. i.e., you will only update when the formatting switches back and forth from, in your example, underlined to not underlined.
Here is some example code that implements this subrange idea. I separated the specific predicate function (text.isUnderline) and specific formatting effects into their own functions so as to separate the general idea from the specific implementation.
// run this function with selection
function transformUnderlinedToBoldAndYellow() {
transformSelection("isUnderline", boldYellowOrSmall);
}
function transformSelection(stylePredicateKey, stylingFunction) {
const selectedText = DocumentApp.getActiveDocument().getSelection();
if (!selectedText) return;
const getStyledSubRanges = makeStyledSubRangeReducer(stylePredicateKey);
selectedText.getRangeElements()
.reduce(getStyledSubRanges, [])
.forEach(stylingFunction);
}
function makeStyledSubRangeReducer(stylePredicateKey) {
return function(ranges, rangeElement) {
const {text, start, end} = unwrapRangeElement(rangeElement);
if (start >= end) return ranges; // filter out empty selections
const range = {
text, start, end,
styled: [], notStyled: [] // we will extend our range with subranges
};
const getKey = (isStyled) => isStyled ? "styled" : "notStyled";
let currentKey = getKey(text[stylePredicateKey](start));
range[currentKey].unshift({start: start});
for (let index = start + 1; index <= end; ++index) {
const isStyled = text[stylePredicateKey](index);
if (getKey(isStyled) !== currentKey) { // we are switching styles
range[currentKey][0].end = index - 1; // note end of this style
currentKey = getKey(isStyled);
range[currentKey].unshift({start: index}); // start new style range
}
}
ranges.push(range);
return ranges;
}
}
// a helper function to unwrap a range selection, deals with isPartial,
// maps RangeElement => {text, start, end}
function unwrapRangeElement(rangeElement) {
const isPartial = rangeElement.isPartial();
const text = rangeElement.getElement().asText();
return {
text: text,
start: isPartial
? rangeElement.getStartOffset()
: 0,
end: isPartial
? rangeElement.getEndOffsetInclusive()
: text.getText().length - 1
};
}
// apply specific formatting to satisfy the example
function boldYellowOrSmall(range) {
const {text, start, end, styled, notStyled} = range;
styled.forEach(function setTextBoldAndYellow(range) {
text.setBold(range.start, range.end || end, true);
text.setBackgroundColor(range.start, range.end || end, '#ffff00');
});
notStyled.forEach(function setTextSmall(range) {
text.setFontSize(range.start, range.end || end, 8);
});
}

Section Word Count in Google Docs

Is it possible for a Google Docs add-on to count word per heading (section)? The following image shows what I want.
Is there a way to display this kind of word count information in a sidebar or any other way?
Here is a script that does this. In Google Docs, headings are a kind of paragraph distinguished by their getHeading() attribute. There are thus 9 levels of paragraphs: title, subtitle, h1... h6, and normal.
The script first finds the level of each paragraph and the word count of each paragraph. Then, for each paragraph, it loops over all subsequent "normal" paragraphs, adding their word counts; this stops when another paragraph of equal or higher level is reached.
My understanding that the words in headings themselves should not be included in word counts, but that can be changed if desired.
Since this is not an add-on, there is no sidebar to display information in. I just append the results at the end, copying each heading there and appending (X words) to its text. It looks like this:
Book title (108 words)
Chapter 1 (54 words)
Section 1 (15 words)
Section 2 (20 words)
Chapter 2 (54 words)
Section 1 (54 words)
Subsection 1 (31 words)
Subsection 2 (13 words)
In my sample text, Chapter 1 has some "intro" normal text before its first section, which is why its word count is higher than the sum of word counts of its two sections.
Script:
function countPerSection() {
var body = DocumentApp.getActiveDocument().getBody();
var para = body.getParagraphs();
var levels = para.map(function(p) {
return [DocumentApp.ParagraphHeading.TITLE,
DocumentApp.ParagraphHeading.SUBTITLE,
DocumentApp.ParagraphHeading.HEADING1,
DocumentApp.ParagraphHeading.HEADING2,
DocumentApp.ParagraphHeading.HEADING3,
DocumentApp.ParagraphHeading.HEADING4,
DocumentApp.ParagraphHeading.HEADING5,
DocumentApp.ParagraphHeading.HEADING6,
DocumentApp.ParagraphHeading.NORMAL].indexOf(p.getHeading());
});
var paraCounts = para.map(function (p) {
return p.getText().split(/\W+/).length;
});
var counts = [];
for (var i = 0; i < para.length; i++) {
var count = 0;
for (var j = i+1; j < para.length; j++) {
if (levels[j] <= levels[i]) {
break;
}
if (levels[j] == 8) {
count += paraCounts[j];
}
}
counts.push(count);
}
for (var i = 0; i < para.length; i++) {
if (levels[i] < 8) {
body.appendParagraph(para[i].copy()).appendText(" (" + counts[i] + " words)");
}
}
}
I edited the previous answer to put the word count next to each header instead of all at the bottom, and you'll see it in the outline too. I also added a function that will remove all of the counts as well, so you can keep them without having to worry about CTRL-Z 'ing or manually deleting them. Hopefully this is useful for somebody else!
function countPerSection() {
var body = DocumentApp.getActiveDocument().getBody();
var para = body.getParagraphs();
var levels = para.map(function(p) {
return [DocumentApp.ParagraphHeading.TITLE,
DocumentApp.ParagraphHeading.SUBTITLE,
DocumentApp.ParagraphHeading.HEADING1,
DocumentApp.ParagraphHeading.HEADING2,
DocumentApp.ParagraphHeading.HEADING3,
DocumentApp.ParagraphHeading.HEADING4,
DocumentApp.ParagraphHeading.HEADING5,
DocumentApp.ParagraphHeading.HEADING6,
DocumentApp.ParagraphHeading.NORMAL].indexOf(p.getHeading());
});
var paraCounts = para.map(function (p) {
return p.getText().split(/\W+/).length;
});
// var counts = [];
for (var i = 0; i < para.length; i++) {
var count = 0;
for (var j = i+1; j < para.length; j++) {
if (levels[j] <= levels[i]) {
break;
}
if (levels[j] == 8) {
count += paraCounts[j];
}
}
if (levels[i] < 8) {
para[i].appendText(" (" + count + " words)");
}
}
}
function removeCountPerSection(){
var docBody = DocumentApp.getActiveDocument().getBody();
docBody.replaceText('\\([0123456789]* words\\)', "");
}

Can Google apps script be used to randomize page order on Google forms?

Update #2: Okay, I'm pretty sure my error in update #1 was because of indexing out of bounds over the array (I'm still not used to JS indexing at 0). But here is the new problem... if I write out the different combinations of the loop manually, setting the page index to 1 in moveItem() like so:
newForm.moveItem(itemsArray[0][0], 1);
newForm.moveItem(itemsArray[0][1], 1);
newForm.moveItem(itemsArray[0][2], 1);
newForm.moveItem(itemsArray[1][0], 1);
newForm.moveItem(itemsArray[1][1], 1);
newForm.moveItem(itemsArray[1][2], 1);
newForm.moveItem(itemsArray[2][0], 1);
...
...I don't get any errors but the items end up on different pages! What is going on?
Update #1:: Using Sandy Good's answer as well as a script I found at this WordPress blog, I have managed to get closer to what I needed. I believe Sandy Good misinterpreted what I wanted to do because I wasn't specific enough in my question.
I would like to:
Get all items from a page (section header, images, question etc)
Put them into an array
Do this for all pages, adding these arrays to an array (i.e: [[all items from page 1][all items from page 2][all items from page 3]...])
Shuffle the elements of this array
Repopulate a new form with each element of this array. In this way, page order will be randomized.
My JavaScript skills are poor (this is the first time I've used it). There is a step that produces null entries and I don't know why... I had to remove them manually. I am not able to complete step 5 as I get the following error:
Cannot convert Item,Item,Item to (class).
"Item,Item,Item" is the array element containing all the items from a particular page. So it seems that I can't add three items to a page at a time? Or is something else going on here?
Here is my code:
function shuffleForms() {
var itemsArray,shuffleQuestionsInNewForm,fncGetQuestionID,
newFormFile,newForm,newID,shuffle, sections;
// Copy template form by ID, set a new name
newFormFile = DriveApp.getFileById('1prfcl-RhaD4gn0b2oP4sbcKaRcZT5XoCAQCbLm1PR7I')
.makeCopy();
newFormFile.setName('AAAAA_Shuffled_Form');
// Get ID of new form and open it
newID = newFormFile.getId();
newForm = FormApp.openById(newID);
// Initialize array to put IDs in
itemsArray = [];
function getPageItems(thisPageNum) {
Logger.log("Getting items for page number: " + thisPageNum );
var thisPageItems = []; // Used for result
var thisPageBreakIndex = getPageItem(thisPageNum).getIndex();
Logger.log( "This is index num : " + thisPageBreakIndex );
// Get all items from page
var allItems = newForm.getItems();
thisPageItems.push(allItems[thisPageBreakIndex]);
Logger.log( "Added pagebreak item: " + allItems[thisPageBreakIndex].getIndex() );
for( var i = thisPageBreakIndex+1; ( i < allItems.length ) && ( allItems[i].getType() != FormApp.ItemType.PAGE_BREAK ); ++i ) {
thisPageItems.push(allItems[i]);
Logger.log( "Added non-pagebreak item: " + allItems[i].getIndex() );
}
return thisPageItems;
}
function shuffle(array) {
var currentIndex = array.length, temporaryValue, randomIndex;
Logger.log('shuffle ran')
// While there remain elements to shuffle...
while (0 !== currentIndex) {
// Pick a remaining element...
randomIndex = Math.floor(Math.random() * currentIndex);
currentIndex -= 1;
// And swap it with the current element.
temporaryValue = array[currentIndex];
array[currentIndex] = array[randomIndex];
array[randomIndex] = temporaryValue;
}
return array;
}
function shuffleAndMove() {
// Get page items for all pages into an array
for(i = 2; i <= 5; i++) {
itemsArray[i] = getPageItems(i);
}
// Removes null values from array
itemsArray = itemsArray.filter(function(x){return x});
// Shuffle page items
itemsArray = shuffle(itemsArray);
// Move page items to the new form
for(i = 2; i <= 5; ++i) {
newForm.moveItem(itemsArray[i], i);
}
}
shuffleAndMove();
}
Original post: I have used Google forms to create a questionnaire. For my purposes, each question needs to be on a separate page but I need the pages to be randomized. A quick Google search shows this feature has not been added yet.
I see that the Form class in the Google apps script has a number of methods that alter/give access to various properties of Google Forms. Since I do not know Javascript and am not too familiar with Google apps/API I would like to know if what I am trying to do is even possible before diving in and figuring it all out.
If it is possible, I would appreciate any insight on what methods would be relevant for this task just to give me some direction to get started.
Based on comments from Sandy Good and two SE questions found here and here, this is the code I have so far:
// Script to shuffle question in a Google Form when the questions are in separate sections
function shuffleFormSections() {
getQuestionID();
createNewShuffledForm();
}
// Get question IDs
function getQuestionID() {
var form = FormApp.getActiveForm();
var items = form.getItems();
arrayID = [];
for (var i in items) {
arrayID[i] = items[i].getId();
}
// Logger.log(arrayID);
return(arrayID);
}
// Shuffle function
function shuffle(a) {
var j, x, i;
for (i = a.length; i; i--) {
j = Math.floor(Math.random() * i);
x = a[i - 1];
a[i - 1] = a[j];
a[j] = x;
}
}
// Shuffle IDs and create new form with new question order
function createNewShuffledForm() {
shuffle(arrayID);
// Logger.log(arrayID);
var newForm = FormApp.create('Shuffled Form');
for (var i in arrayID) {
arrayID[i].getItemsbyId();
}
}
Try this. There's a few "constants" to be set at the top of the function, check the comments. Form file copying and opening borrowed from Sandy Good's answer, thanks!
// This is the function to run, all the others here are helper functions
// You'll need to set your source file id and your destination file name in the
// constants at the top of this function here.
// It appears that the "Title" page does not count as a page, so you don't need
// to include it in the PAGES_AT_BEGINNING_TO_NOT_SHUFFLE count.
function shuffleFormPages() {
// UPDATE THESE CONSTANTS AS NEEDED
var PAGES_AT_BEGINNING_TO_NOT_SHUFFLE = 2; // preserve X intro pages; shuffle everything after page X
var SOURCE_FILE_ID = 'YOUR_SOURCE_FILE_ID_HERE';
var DESTINATION_FILE_NAME = 'YOUR_DESTINATION_FILE_NAME_HERE';
// Copy template form by ID, set a new name
var newFormFile = DriveApp.getFileById(SOURCE_FILE_ID).makeCopy();
newFormFile.setName(DESTINATION_FILE_NAME);
// Open the duplicated form file as a form
var newForm = FormApp.openById(newFormFile.getId());
var pages = extractPages(newForm);
shuffleEndOfPages(pages, PAGES_AT_BEGINNING_TO_NOT_SHUFFLE);
var shuffledFormItems = flatten(pages);
setFormItems(newForm, shuffledFormItems);
}
// Builds an array of "page" arrays. Each page array starts with a page break
// and continues until the next page break.
function extractPages(form) {
var formItems = form.getItems();
var currentPage = [];
var allPages = [];
formItems.forEach(function(item) {
if (item.getType() == FormApp.ItemType.PAGE_BREAK && currentPage.length > 0) {
// found a page break (and it isn't the first one)
allPages.push(currentPage); // push what we've built for this page onto the output array
currentPage = [item]; // reset the current page to just this most recent item
} else {
currentPage.push(item);
}
});
// We've got the last page dangling, so add it
allPages.push(currentPage);
return allPages;
};
// startIndex is the array index to start shuffling from. E.g. to start
// shuffling on page 5, startIndex should be 4. startIndex could also be thought
// of as the number of pages to keep unshuffled.
// This function has no return value, it just mutates pages
function shuffleEndOfPages(pages, startIndex) {
var currentIndex = pages.length;
// While there remain elements to shuffle...
while (currentIndex > startIndex) {
// Pick an element between startIndex and currentIndex (inclusive)
var randomIndex = Math.floor(Math.random() * (currentIndex - startIndex)) + startIndex;
currentIndex -= 1;
// And swap it with the current element.
var temporaryValue = pages[currentIndex];
pages[currentIndex] = pages[randomIndex];
pages[randomIndex] = temporaryValue;
}
};
// Sourced from elsewhere on SO:
// https://stackoverflow.com/a/15030117/4280232
function flatten(array) {
return array.reduce(
function (flattenedArray, toFlatten) {
return flattenedArray.concat(Array.isArray(toFlatten) ? flatten(toFlatten) : toFlatten);
},
[]
);
};
// No safety checks around items being the same as the form length or whatever.
// This mutates form.
function setFormItems(form, items) {
items.forEach(function(item, index) {
form.moveItem(item, index);
});
};
I tested this code. It created a new Form, and then shuffled the questions in the new Form. It excludes page breaks, images and section headers. You need to provide a source file ID for the original template Form. This function has 3 inner sub-functions. The inner functions are at the top, and they are called at the bottom of the outer function. The arrayOfIDs variable does not need to be returned or passed to another function because it is available in the outer scope.
function shuffleFormSections() {
var arrayOfIDs,shuffleQuestionsInNewForm,fncGetQuestionID,
newFormFile,newForm,newID,items,shuffle;
newFormFile = DriveApp.getFileById('Put the source file ID here')
.makeCopy();
newFormFile.setName('AAAAA_Shuffled_Form');
newID = newFormFile.getId();
newForm = FormApp.openById(newID);
arrayOfIDs = [];
fncGetQuestionID = function() {
var i,L,thisID,thisItem,thisType;
items = newForm.getItems();
L = items.length;
for (i=0;i<L;i++) {
thisItem = items[i];
thisType = thisItem.getType();
if (thisType === FormApp.ItemType.PAGE_BREAK ||
thisType === FormApp.ItemType.SECTION_HEADER ||
thisType === FormApp.ItemType.IMAGE) {
continue;
}
thisID = thisItem.getId();
arrayOfIDs.push(thisID);
}
Logger.log('arrayOfIDs: ' + arrayOfIDs);
//the array arrayOfIDs does not need to be returned since it is available
//in the outermost scope
}// End of fncGetQuestionID function
shuffle = function() {// Shuffle function
var j, x, i;
Logger.log('shuffle ran')
for (i = arrayOfIDs.length; i; i--) {
j = Math.floor(Math.random() * i);
Logger.log('j: ' + j)
x = arrayOfIDs[i - 1];
Logger.log('x: ' + x)
arrayOfIDs[i - 1] = arrayOfIDs[j];
arrayOfIDs[j] = x;
}
Logger.log('arrayOfIDs: ' + arrayOfIDs)
}
shuffleQuestionsInNewForm = function() {
var i,L,thisID,thisItem,thisQuestion,questionType;
L = arrayOfIDs.length;
for (i=0;i<L;i++) {
thisID = arrayOfIDs[i];
Logger.log('thisID: ' + thisID)
thisItem = newForm.getItemById(thisID);
newForm.moveItem(thisItem, i)
}
}
fncGetQuestionID();//Get all the question ID's and put them into an array
shuffle();
shuffleQuestionsInNewForm();
}

Multiple-page printing from datagrid

From this tutorial i've got a good result printing , and this tutorial on how to print multiple pages from html, i'm trying to do the same with a Datagrid.
my problem is when the number of rows exceed the height of Datagrid so i tried to break it down to several pages, this is my code:
protected function button3_clickHandler(event:MouseEvent):void
{
var success:Boolean = printJob.start2(disablePageRange.selected ? this.printUIOptions : null, false);
var pjo:PrintJobOptions = new PrintJobOptions;
if (methodBitmap.selected){
pjo.printMethod = PrintMethod.BITMAP;
}
else if (methodVector.selected){
pjo.printMethod = PrintMethod.VECTOR;
}
else{
pjo.printMethod = PrintMethod.AUTO;
}
if (printJob.maxPixelsPerInch > 600){
pjo.pixelsPerInch = 600;
}
updateForm();
updateThePage();
updateTheWindow();
//--------------------------------------
var b:int = 0;
var H:int = myDataGrid.rowHeight *2;
for each (var item:Object in meme as ArrayCollection ){
if (H > myDataGrid.height){
myDataGrid.dataProvider = arlst;
printJob.addPage(thePrintableArea, null, pjo);
arlst.removeAll();
H = myDataGrid.rowHeight *2;
b++;
//Alert.show(b.toString());
}else{
arlst.addItem(item);
H += myDataGrid.rowHeight;
}
}
printJob.send();
}
The result: i get the first page but the rest are just blank Datagrid:
This answers: http://help.adobe.com/en_US/flex/using/WS2db454920e96a9e51e63e3d11c0bf69084-7c7e.html
Summary:
create external Itemrenderer and populate the data to it.