I'm creating an employee tracking app.
I have a MySQL table which is as follows:
ID
PersonID
TypeID
DateTime
1
001
IN
2022-09-01T13:21:12
2
001
OUT
2022-09-01T13:25:12
3
001
IN
2022-09-01T14:21:12
4
001
OUT
2022-09-01T14:25:12
5
002
IN
2022-09-03T13:21:12
6
002
OUT
2022-09-03T13:25:12
7
002
IN
2022-09-03T14:21:12
8
002
IN
2022-09-03T14:25:12
9
002
OUT
2022-09-03T14:25:12
10
002
OUT
2022-09-03T16:25:12
11
002
OUT
2022-09-03T17:25:12
12
002
IN
2022-09-04T16:25:12
13
002
IN
2022-09-05T17:25:12
I would like to create a view that returns records first sorted by PersonID and then by the ID but transforms the rows into columns.
Something like this:
PersonID
InID
In_DateTime
OutID
Out_DateTime
001
1
2022-09-01T13:21:12
2
2022-09-01T13:25:12
001
3
2022-09-01T14:21:12
4
2022-09-01T14:25:12
002
5
2022-09-03T13:21:12
6
2022-09-03T13:25:12
002
7
2022-09-03T14:21:12
null
null
002
8
2022-09-03T14:25:12
9
2022-09-03T14:25:12
002
null
null
10
2022-09-03T16:25:12
002
null
null
11
2022-09-03T17:25:12
002
12
2022-09-04T16:25:12
null
null
002
13
2022-09-05T17:25:12
null
null
Does anyone have an idea how to do this in MySQL?
Thanks for any suggestions.
Use window functions LEAD() or LAG() to get for each row its pair row, depending on its TypeID and do a left join of the results to the table:
WITH cte AS (
SELECT *,
CASE
WHEN TypeID = 'IN' AND LEAD(TypeID) OVER w = 'OUT' THEN LEAD(ID) OVER w
WHEN TypeID = 'OUT' AND LAG(TypeID) OVER w = 'IN' THEN LAG(ID) OVER w
END other_ID
FROM tablename
WINDOW w AS (PARTITION BY PersonID ORDER BY DateTime)
)
SELECT DISTINCT c.PersonID,
CASE WHEN c.TypeID = 'IN' THEN c.ID ELSE t.ID END InID,
CASE WHEN c.TypeID = 'IN' THEN c.DateTime ELSE t.DateTime END In_DateTime,
CASE WHEN c.TypeID = 'IN' THEN t.ID ELSE c.ID END OutID,
CASE WHEN c.TypeID = 'IN' THEN t.DateTime ELSE c.DateTime END Out_DateTime
FROM cte c LEFT JOIN tablename t
ON t.ID = c.other_ID
ORDER BY c.PersonID, COALESCE(In_DateTime, Out_DateTime);
See the demo.
Related
I have the following table:
id
date
type
001
2022-01-01
A
001
2022-01-03
B
001
2022-01-02
B
001
2022-02-02
A
002
2022-01-01
A
002
2022-01-03
B
004
2022-01-01
A
004
2022-01-03
B
And I need to sort the dates decending, group by ID and Type and get the time between the dates by ID and Type, either in seconds or months days
id
date
type
time diff
001
2022-01-01
A
0
001
2022-01-02
B
1
001
2022-01-03
B
1
001
2022-02-02
A
31
002
2022-01-01
A
0
002
2022-01-03
B
2
004
2022-01-01
A
0
004
2022-01-03
B
2
We can use DATEDIFF() here along with the LAG() analytic function:
SELECT id, date, type,
DATEDIFF(date, LAG(date, 1, date) OVER (PARTITION BY id ORDER BY date)) AS diff
FROM yourTable
ORDER BY id, date;
If you are using MySQL 8.0,window functions are strongly recommended. Otherwise,you might have to go a long way. Here is the query written and tested in workbench using 5.7 :
select tb1.id,tb1.date,tb1.type,ifnull(datediff(tb1.date,tb2.date),0) as 'time diff'
from
(select id,date,type, #row_id:=#row_id+1 as row_id
from
(select id,date,type
from test
group by id,date,type
order by id,date)t1,
(select #row_id:=0) t
) tb1
left join
(select id,date,type, #row_num:=#row_num+1 as row_num
from
(select id,date,type
from test
group by id,date,type
order by id,date)t2,
(select #row_num:=0) t
) tb2
on tb1.id=tb2.id and tb1.row_id-tb2.row_num=1
order by tb1.id,tb1.date
;
hello please help me to solve this,, i am using mysql.. and I think, needing a full outer join to solve it,.
this is my query:
SELECT
e.NIK,
e.name,
a.dt
FROM
employee e
LEFT JOIN
attandence a
ON e.NIK=a.NIK
WHERE
month(a.dt)=12 AND year(a.dt)=2021
GROUP BY
e.NIK
this is the result:
NIK
name
dt
001
ana
23/12/2021
001
ana
24/12/2021
001
ana
26/12/2021
001
ana
27/12/2021
002
susi
23/12/2021
002
susi
24/12/2021
002
susi
25/12/2021
002
susi
26/12/2021
but i need to join it one more time with this table :
holidayTable
id
mark
dt
1
off_day
22/12/2021
2
chrismast
25/12/2021
I've tried using left/right/cross join, but it doesn't work
The result I want is like this:
NIK
name
dtWork
holiday
001
ana
null
22/12/2021
001
ana
23/12/2021
null
001
ana
24/12/2021
null
001
ana
null
25/12/2021
001
ana
26/12/2021
null
001
ana
27/12/2021
null
002
susi
null
22/12/2021
002
susi
23/12/2021
null
002
susi
24/12/2021
null
002
susi
25/12/2021
25/12/2021
002
susi
26/12/2021
null
You need a calendar table to achieve the output.
As of now I used union between holidaytable and attendance as Calendar.
You can achieve your desired result with below query.
SELECT e.nik,
e.name,
a.dt AS dtWork,
h.dt AS holiday
FROM employee e
CROSS JOIN(SELECT dt
FROM holidaytable
UNION
SELECT dt
FROM attendance)cal
LEFT JOIN attendance a
ON e.nik = a.nik
AND a.dt = cal.dt
LEFT JOIN holidaytable h
ON h.dt = cal.dt
WHERE a.dt IS NOT NULL
OR h.dt IS NOT NULL
ORDER BY nik ASC,
cal.dt ASC
SQLFiddle: Try it here
A union where the first part gets attendence and the second gets holidays (with as you thought a cross join) including a dummy column to assist ordering
select e.id,employeelastname,a.dt attendence,null holiday,a.dt as orderdt
from employees e
left join attendence a on a.nik = e.id
union
select e.id,employeelastname,null,h.dt holiday,h.dt
from employees e
cross join holidays h
order by id,orderdt;
I have 4 tables (1 to many):
Dont say anything about that "email" relation. It is how my developer boss built it years ago.
EMPLOYEES (+-50 results)
------------------------------------------------
id name
1 EmpName 1
2 EmpName 2
CUSTOMERS (+50k results)
------------------------------------------------
id name email employee_assigned
1 John john#doe.com 12
2 Donald donald#duck.com 6
INTERESTS_CATEGORIES (+650k results)
------------------------------------------------
id customer_email category_id
1 john#doe.com 97
2 john#doe.com 13
3 donald#duck.com 56
4 donald#duck.com 126
5 donald#duck.com 45
INTERESTS_PRODUCTS (+650k results)
------------------------------------------------
id customer_email product_id
1 john#doe.com 78
2 john#doe.com 23
3 donald#duck.com 19
4 donald#duck.com 56
5 donald#duck.com 45
So I need to filter the customers by their assigned employee and their interests.
And here is the query:
SELECT
*
FROM
(
SELECT
customers.id AS 'id',
customers.name AS 'first_name',
customers.email,
employees.id AS 'employee_id'
FROM
customers,
employees
WHERE
employees.id = 2
AND
customers.employee_assigned = employees.id
) AS myCustomers
LEFT JOIN interests_categories
ON interests_categories.customer_email = myCustomers.email
LEFT JOIN interests_products
ON interests_categories.customer_email = myCustomers.email
WHERE
(
interests_categories.category_id = 20
OR
interests_categories.category_id = 21
)
GROUP BY myCustomers.email
So, the problem:
If the employee has a low number of assigned customers (like 3) query
is successfull.
If the employee has a medium-high number of assigned customers (over 100) query stucks.
I execute SHOW PROCESSLIST and it is stucked "Generating temp table".
Anyone has idea? :(
Thank you.
Check the indexes on your tables and try this:
SELECT
c.id AS 'id',
c.name AS 'first_name',
c.email,
e.id AS 'employee_id'
ic.*,
ip.*
FROM customers c
JOIN employees e
ON c.employee_assigned = e.id
LEFT JOIN interests_categories ic
ON ic.customer_email = c.email
LEFT JOIN interests_products ip
ON ic.customer_email = c.email
WHERE
(
ic.category_id IN (20,21)
AND e.id = 2
)
GROUP BY myCustomers.email
Incidentally, a less dumb design might look like as follows. If it was me, I'd start with this, and provide properly representative CREATE and INSERT statements accordingly. Also, I'm curious about where category_id comes from - because that's potentially an area for further optimization.
EMPLOYEES
------------------------------------------------
employee_id name
6 EmpName 1
12 EmpName 2
CUSTOMERS
------------------------------------------------
customer_id name email employee_assigned
1 John john#doe.com 12
2 Donald donald#duck.com 6
INTERESTS_CATEGORIES
------------------------------------------------
customer_id category_id
1 97
1 13
2 56
2 126
2 45
INTERESTS_PRODUCTS
------------------------------------------------
customer_id product_id
1 78
1 23
2 19
2 56
2 45
I am trying to make the notification system for my project as simple as possible on the user's side.
"john brown and 4 others liked your photo"
I tried:
Select a.id, a.item_id, a.type u.f_name, u.l_name, count(a)
From alerts
Join users on a.user_id = u.u_id
Where owner_id = {THE_USER_ID}
but it doesnt "work"
The users table
u_id | f_name | l_name
==========================
234 roy wright
654 pam brown
564 kim harris
334 tory plummer
876 rick forbes
123 paul nichol
980 mario chang
454 todd thompson
886 sam richards
215 tash gates
... ..... ........
The alerts table
id | item_id | type | user_id | owner_id
===================================================
1 21 like 234
2 21 comment 654
3 32 share 876
4 21 like 778
5 21 like 890
6 21 share 123
7 54 share 454
8 32 comment 655
9 60 comment 886
10 32 like 215
.. .. ...... ...
The results I want
id | item_id | type | u_id | f_name | l_name | amount_more
============================================================
1 21 like 234 roy wright 2
2 21 comment 654 pam brown
3 32 comment 876 rick forbes
6 21 share 123 paul nichol
7 54 share 454 todd thompson
9 60 comment 886 sam richards
10 32 like 215 tash gates
.. .. .... ... ..... ........
SELECT
MIN(CASE WHEN RowNumber = 1 THEN id END) as Id
,item_id
,type
,MIN(CASE WHEN RowNumber = 1 THEN u_id END) as u_id
,MIN(CASE WHEN RowNumber = 1 THEN f_name END) as f_name
,MIN(CASE WHEN RowNumber = 1 THEN l_name END) as l_name
,COUNT(*) - 1 as amount_more
FROM
(
SELECT
t.*
,(#rn:= if((#item = t.item_id) AND (#type = t.type),#rn + 1,
if((#item:=t.item_id) AND (#type:=t.type),1,1)
)
) as RowNumber
FROM
(SELECT *
FROM
alerts a
LEFT JOIN usersTbl u
ON a.user_id = u.u_id
WHERE
a.owner_id = 201
ORDER BY
a.item_id
,a.type
,a.id) t
CROSS JOIN (SELECT #rn:=0,#item:=0,#type:='') var
ORDER BY
item_id
,type
,id
) t2
GROUP BY
item_id
,type
ORDER BY
id
;
So you need to create a partitioned row number to identify which record you want to be considered first. Then using conditional aggregation you can choose that as your User. this works check it out here: http://rextester.com/VXZONO82847
In the Query you are not using aliases a and u properly, Use this:
Select
a.id,
a.item_id,
a.type,
u.f_name,
u.l_name,
count(a.*)
From alerts a Join users u
on(a.user_id = u.u_id)
Where owner_id = {THE_USER_ID}
group by 1,2,3,4,5;
I am using MySQL. I'm trying to build something and just can't find a solution to a problem.
I am selecting a value from the lookup table based on my table as shown in the below example.
Select Criteria:
my.id<>l.id AND my.route1=l.route1 AND my.route2=l.route2 AND my.utc=l.utc
where my.stime is closest or same as l.stime
ex) my.id=2's col should get the l.id=1, l.etime=7777 since my.id<>l.id and the rest are the same.
ex) my,id=5's col has options l.id=3, l.etime=9999 and l.id=4, l.etime=7979 since my.id<>l.id, my.route=l.route, my.utc=l.utc. Yet, since my.stime=2220 is closer to l.stime=2222 than l.stime=3333 , l.id=3, l.etime=9999 will be chosen.
ex) my,id=6's col example is to select either value if "closest" is the same.
ex) my,id=7's col example is to return NULL when the criteria is not met.
Table: lookup (l.)
id route1 route2 utc stime etime
---|--------|--------|-----|-------|------
1 11 22 111 1111 7777
2 11 22 111 1111 8888
3 22 33 222 2222 9999
4 22 33 222 3333 7979
5 22 33 222 3335 8989
Table: my (my.) | result
id route1 route2 utc stime | l.id l.etime
---|--------|--------|-----|------- |-------|----------|
2 11 22 111 1111 | 1 7777
5 22 33 222 2220 | 3 9999
6 22 33 222 3334 | 4or5 7979or8989
7 22 33 999 9999 | null null
A new table should be created where the result is appended to the last col of my.
Any help is appreciated. Thanks in advance.
This solution is a bit convoluted, but it's a starting point.
First, let's create an auxiliary table:
CREATE TEMP TABLE temp AS
SELECT m.id mid, l.id lid, ABS(l.stime-m.stime) timediff
FROM my m JOIN lookup l
WHERE m.route1 = l.route1 AND m.route2 = l.route2 AND
m.utc = l.utc AND m.id <> l.id;
From this table we can get the minimum timediff for each my.id:
SELECT mid, min(timediff) mtimediff FROM temp GROUP BY mid
Result:
mid mtimediff
---------- ----------
2 0
5 2
6 1
Now we can find which rows in lookup have this stime difference, and choose the smallest id:
SELECT t.mid mid, min(lid) lid
FROM temp t JOIN (
SELECT mid, min(timediff) mtimediff FROM temp GROUP BY mid
) mt ON t.mid = mt.mid AND t.timediff = mt.mtimediff
GROUP BY t.mid
This is the result:
mid lid
---------- ----------
2 1
5 3
6 4
And finally we use those ids to extract the data from the tables:
SELECT m.id, m.route1, m.route2, m.utc, m.stime, l.id, l.etime
FROM my m JOIN lookup l JOIN (
SELECT t.mid mid, min(lid) lid
FROM temp t JOIN (
SELECT mid, min(timediff) mtimediff FROM temp GROUP BY mid
) mt ON t.mid = mt.mid AND t.timediff = mt.mtimediff
GROUP BY t.mid
) ON m.id = mid AND l.id = lid;
Giving:
id route1 route2 utc stime id etime
---------- ---------- ---------- ---------- ---------- ---------- ----------
2 11 22 111 1111 1 7777
5 22 33 222 2220 3 9999
6 22 33 222 3334 4 7979