I am using this code:
function copyInfo() {
var ss = SpreadsheetApp.getActiveSpreadsheet();
var copySheet = ss.getSheetByName("Product-analyse");
var pasteSheet = ss.getSheetByName("Blad18"); // get source range
var source = copySheet.getRange(93,7,39,6); // get destination range
var destination = pasteSheet.getRange(pasteSheet.getLastRow()+1,1,39,6); // copy values to destination range
source.copyTo(destination); // clear source values
source.clearContent();
}
Now its pasting in "Blad18". Instead I want it to be pasted in another file.
I tried adding {contentOnly: TRUE}. Though this didnt seem to work
I cannot figure this out unfortunately. Everything else is correctly set already.
Any help is greatly appreciated.
Updated script I am using:
function copyInfo() {
var ssSource = SpreadsheetApp.getActiveSpreadsheet();
var copySheet = ssSource.getSheetByName("Product-analyse");
var ssPaste = SpreadsheetApp.openById("1qhnA8L3ZkU-iEyOJtszAC4OW58sg2TJZSa_rmN_EXBI"); // the id of the other spreadsheet
var pasteSheet = ssPaste.getSheetByName("Submitted Data"); // get source range
var source = copySheet.getRange(93,7,39,6); // get destination range
var destination = pasteSheet.getRange(pasteSheet.getLastRow()+1,1,39,6); // copy values to destination range
source.copyTo(destination); // clear source values
source.clearContent();
}
Try this:
function copyInfo() {
var ss = SpreadsheetApp.getActive();
var csh = ss.getSheetByName("Sheet0");
var psh = ss.getSheetByName("Sheet1");
const cshsr = 2;
var crg = csh.getRange(cshsr, 1, csh.getLastRow() - cshsr + 1, csh.getLastColumn());
var prg = psh.getRange(psh.getLastRow() + 1, 1);
crg.copyTo(prg);
}
I believe what you want to do is copy from one spreadsheet file to another spreadsheet file. Here is an example
function copyInfo() {
var ssSource = SpreadsheetApp.getActiveSpreadsheet();
var copySheet = ssSource.getSheetByName("Product-analyse");
var ssPaste = SpreadsheetApp.openById("dfsfhsfhskfhaskjfhsjkfas"); // the id of the other spreadsheet
var pasteSheet = ssPaste.getSheetByName("Blad18"); // get source range
var source = copySheet.getRange(93,7,39,6); // get destination range
var destination = pasteSheet.getRange(pasteSheet.getLastRow()+1,1,39,6); // copy values to destination range
source.copyTo(destination); // clear source values
source.clearContent();
}
Reference
SpreadsheetApp.openById()
Related
I am using the following app script to copy data from a certain range to another file. But for some reason this script is also copying and pasting the whole sheet. How to stop this?
function copyInfo() {
var destinationSpreadsheetUrl = "https://docs.google.com/spreadsheets/d/189hJTiUlwubZdeN1HZ9n98U-gdaGdFSAu1-ARvlGMKo/edit#gid=0"; // Please set your Spreadsheet URL.
var destinationSheetName = "RawDataCopyPaste"; // Please set the destination sheet name.
// Source sheet.
var ss = SpreadsheetApp.getActiveSpreadsheet();
var copySheet = ss.getSheetByName("Product-analyse");
var temp1 = copySheet.copyTo(ss);
var r = temp1.getDataRange();
r.copyTo(r, { contentsOnly: true });
// Destination sheet.
var dstSS = SpreadsheetApp.openByUrl(destinationSpreadsheetUrl);
var dstSheet = dstSS.getSheetByName(destinationSheetName);
var temp2 = temp1.copyTo(dstSS);
temp2.getRange(93, 6, 40, ).copyTo(dstSheet.getRange(dstSheet.getLastRow() + 2, 1));
// clear source values
copySheet.getRange(1, 2, 300, 9)
}
Example Source Sheet: https://docs.google.com/spreadsheets/d/1EKvIACMU7DMfuK9SQk8o6mmTTQ8_8a1qPt2jWy_q2MU/edit#gid=495001425
Example Dest Sheet: https://docs.google.com/spreadsheets/d/1mSDRsHPiPUlqg94x1Ocdssxr7fMJhqztch7kd_Xh_cE/edit#gid=0
Try it this way:
function copyInfoToAnotherFile() {
const sss = SpreadsheetApp.getActive();
const dss = SpreadsheetApp.openById("dssid");
const ssh = sss.getSheet("Sheet0");
const svs = ssh.getDataRange().getValues();
const dsh = dss.getSheetByName("Sheet0");
dsh.getRange(dsh.getLastRow() + 1, 1, svs.length,svs[0].length).setValues(svs);
}
I am using the below code to copy my data from sheet1 to sheet2 and append the data in sheet2 if script runs again? The issue is that my range is not fixed in sheet 1,I want to copy whatever range contains the content should be copied to sheet2 Can anyone guide that what to change in the below code to get the result?
function copyInfo() {
var ss = SpreadsheetApp.getActiveSpreadsheet();
var copySheet = ss.getSheetByName("sheet1");
var pasteSheet = ss.getSheetByName("sheet2");
var source = copySheet.getrange(2,1,200,7);
var destination = pasteSheet.getRange(pasteSheet.getLastRow()+1,1,200,7);
source.copyTo(destination, {contentsOnly:true});
var data = copySheet.getRange(2,1,200,6)
data.clearContent()
}
Method1:
Include:
var paste_lr = pasteSheet.getLastRow()
Modify:
var source = copySheet.getrange(paste_lr+1,1,200,7);
Similarly change 200 using same function.
Method2:
var sp = PropertiesService.getScriptProperties();
var SourceLr = sp.getProperty("Source_Data_Rows") || 0;
var source = copySheet.getrange(SourceLr+1,1,200,7);
var Source_Lr = copySheet.getLastRow();
sp.setProperty("Source_Data_Rows", Source_Lr);
Background
I wrote script for copying range of cells from one document to another. It works correctly. But depending on volume of data it could run for 10+ minutes. Which is odd, because manual copy-pasting of this data without script will took 2 minutes. I ran some tests that revealed most time-consuming piece of code that needs to be speed up
Question
What is the quickest method of copying range of cells from one Google Spreadsheet document to another? Or how should I change my code to speed it up?
// Copying 1st batch of data
var srcLastRow = srcSheet1.getLastRow();
var srcLastCol = srcSheet1.getLastColumn();
var srcRange = srcSheet1.getRange(2, 1, srcLastRow-1, srcLastCol);
var transfValues = srcRange.getValues();
destSheet.getRange(destLastRow + 1,1,srcLastRow-1, srcLastCol).setValues(transfValues);
Appendix
And here is full script, that runs correctly but slow, just in case
function sborka() {
// Destination sheet variables
var destSpreadSheet = SpreadsheetApp.getActiveSpreadsheet();
var destSheet = destSpreadSheet.getSheetByName("destination");
// Source sheet variables
var srcSpreadSheet1 = SpreadsheetApp.openById('xxxxxx');
var srcSheet1 = srcSpreadSheet1.getSheetByName("source 1");
var srcSpreadSheet2 = SpreadsheetApp.openById('ууууууу');
var srcSheet2 = srcSpreadSheet2.getSheetByName("source 2");
// Clear all except 1st row with headers
var destLastRow = destSheet.getLastRow();
destSheet.deleteRows(2,destLastRow)
// What is last row in destination sheet?
var destLastRow = destSheet.getLastRow();
// Copying 1st batch of data
var srcLastRow = srcSheet1.getLastRow();
var srcLastCol = srcSheet1.getLastColumn();
var srcRange = srcSheet1.getRange(2, 1, srcLastRow-1, srcLastCol);
var transfValues = srcRange.getValues();
destSheet.getRange(destLastRow + 1,1,srcLastRow-1, srcLastCol).setValues(transfValues);
// What is last row in destination sheet now?
var destLastRow = destSheet.getLastRow();
// Copying 2nd batch of data
var srcLastRow = srcSheet2.getLastRow();
var srcLastCol = srcSheet2.getLastColumn();
var srcRange = srcSheet2.getRange(2, 1, srcLastRow-1, srcLastCol);
var transfValues = srcRange.getValues();
destSheet.getRange(destLastRow + 1,1,srcLastRow-1, srcLastCol).setValues(transfValues);
// Done
}
Try this:
var srcSheet1 = SpreadsheetApp.getActiveSpreadsheet().getActiveSheet();
var destSS = SpreadsheetApp.openById("destination ss id");
//Copy Source Sheet
srcSheet1.copyTo(destSS);
var newSrcSheet1 = destSS.getSheetByName("Copy of "+srcSheet1.getName());
Logger.log(newSrcSheet1);
//Copy range
var destSheet = destSS.getSheetByName("Sheet1");
var srcLastRow = newSrcSheet1.getLastRow();
var srcLastCol = newSrcSheet1.getLastColumn();
var srcRange = newSrcSheet1.getRange(2, 1, srcLastRow-1, srcLastCol);
srcRange.copyTo(destSheet.getRange(destSheet.getLastRow() + 1,1));
//Delete Sheet
destSS.deleteSheet(newSrcSheet1);
I copied first the source sheet to the destination spreadsheet. The name of the copied sheet will be "Copy of [original sheet name]". Refer to Sheet.copyTo()
Then, I copied the range from the new source sheet to the destination sheet using Range.copyTo(destination)
Lastly, I deleted the new source sheet.
I need to copy a sheet on google SpreadSheet to another SpreadSheet document.
I´ve done my research, and I found two methods that do this, however both have problems that I don´t know how to fix.
The first method copies the sheet with format, but it keeps the referenced cells, so I get a reference error in the new document (#ref). I need a function that copies the format and the values (not references).
function copySheet() {
var source = SpreadsheetApp.getActiveSpreadsheet();
var sheet = source.getSheets()[0];
var destination = SpreadsheetApp.openById("15ucPbZrIYXZAOCYVdpK6OA0oyQT1NcsmuiJmDRfdpHQ");
sheet.copyTo(destination);
}
This second method copies the values without references, however it copies only values, without format.
function copySheetValues()
{
var source = SpreadsheetApp.getActiveSheet();
var sourcename = source.getSheetName();
var sourceDataRange = source.getDataRange();
var sourceSheetValues = sourceDataRange.getValues();
var sourceRows = sourceDataRange.getNumRows();
var sourceColumns = sourceDataRange.getNumColumns();
var destination = SpreadsheetApp.openById('15ucPbZrIYXZAOCYVdpK6OA0oyQT1NcsmuiJmDRfdpHQ');
destination.insertSheet(sourcename, 0);
destination.getDataRange().offset(0, 0, sourceRows, sourceColumns).setValues(sourceSheetValues);
}
How do I write a function that keeps the format and copies the values?
Since you seem to know how to get and set values using the whole data range, just use the other methods to get and set all the other parameters.
The script editor autocomplete is a great help in this case to try not to forget one !
I hope the list is complete, it is a bit of a pain to write though !.
code below, if one of them is not useful to you just delete it (in both directions (set and get).
function copySheetValues(){
var source = SpreadsheetApp.getActiveSheet();
var sourcename = source.getSheetName();
var sValues = source.getDataRange().getValues();
var sBG = source.getDataRange().getBackgrounds();
var sFC = source.getDataRange().getFontColors();
var sFF = source.getDataRange().getFontFamilies();
var sFL = source.getDataRange().getFontLines();
var sFFa = source.getDataRange().getFontFamilies();
var sFSz = source.getDataRange().getFontSizes();
var sFSt = source.getDataRange().getFontStyles();
var sFW = source.getDataRange().getFontWeights();
var sHA = source.getDataRange().getHorizontalAlignments();
var sVA = source.getDataRange().getVerticalAlignments();
var sNF = source.getDataRange().getNumberFormats();
var sWR = source.getDataRange().getWraps();
var destination = SpreadsheetApp.openById('15ucPbZrIYXZAOCYVdpK6OA0oyQT1NcsmuiJmDRfdpHQ');
var destinationSheet = destination.insertSheet(sourcename, 0);
destinationSheet.getRange(1,1,sValues.length,sValues[0].length).setValues(sValues)
.setBackgrounds(sBG)
.setFontColors(sFC)
.setFontFamilies(sFF)
.setFontLines(sFL)
.setFontFamilies(sFFa)
.setFontSizes(sFSz)
.setFontStyles(sFSt)
.setFontWeights(sFW)
.setHorizontalAlignments(sHA)
.setVerticalAlignments(sVA)
.setNumberFormats(sNF)
.setWraps(sWR);
}
Edit :
Bryan's answer and your comment made me think of another solution, much more simple and that handles merged cells as well. Here is the code :
function copySheetValuesV2(){
var source = SpreadsheetApp.getActiveSheet();
var sourceName = source.getSheetName();
var sValues = source.getDataRange().getValues();
var destination = SpreadsheetApp.openById('15ucPbZrIYXZAOCYVdpK6OA0oyQT1NcsmuiJmDRfdpHQ');
source.copyTo(destination)
var destinationSheet = destination.getSheetByName('Copy of '+sourceName)
destinationSheet.getRange(1,1,sValues.length,sValues[0].length).setValues(sValues);// overwrite all formulas that the copyTo preserved
}
In both script be sure that the destination sheet name does not already exist. I didn't handle that case although it is quite easy to do with a try/catch structure.
Another route to try that I think Serge was alluding to here.
function myFunction() {
var source = SpreadsheetApp.openById('SOURCE_ID');
var sourceSheet = source.getSheetByName('Sheet1');
var sourceRange = sourceSheet.getDataRange();
var sourceValues = sourceRange.getValues();
var tempSheet = source.getSheetByName('temp');
var tempRange = tempSheet.getRange('A1');
var destination = SpreadsheetApp.openById('DEST_ID');
sourceRange.copyTo(tempRange); // paste all formats?, broken references
tempRange.offset(0, 0, sourceValues.length, sourceValues[0].length)
.setValues(sourceValues); // paste all values (over broken refs)
tempSheet.copyTo(destination); // now copy temp sheet to another ss
}
This is a variation upon Sergei's answer.
This script will copy all visible sheets and export them in to a new spreadsheet with " Final" appended to the document title.
function copySheetValuesV4(){
var sourceSpreadsheet = SpreadsheetApp.getActiveSpreadsheet();
var sourceSheets = sourceSpreadsheet.getSheets();
var destination = SpreadsheetApp.create(sourceSpreadsheet.getName()+' Final');
for (var i = 0; i < sourceSheets.length; i++){
var sourceSheet = sourceSheets[i];
if (!sourceSheet.isSheetHidden()) {
var sourceSheetName = sourceSheet.getSheetName();
var sValues = sourceSheet.getDataRange().getValues();
sourceSheet.copyTo(destination)
var destinationSheet = destination.getSheetByName('Copy of '+sourceSheetName).setName(sourceSheetName);
destinationSheet.getRange(1,1,sValues.length,sValues[0].length).setValues(sValues);// overwrite all formulas that the copyTo preserved */
}
destination.getSheetByName("sheet1").hideSheet() // Remove the default "sheet1" */
}
}
I want to copy data from one spreadsheet into another one. But
1. The Data are on several sheets
2. Only certain Columns (just to speed it up, don't need all columns)
For the beginning I used the following script:
function CopyDataToNewFile() {
var sss = SpreadsheetApp.openById('0AjN7uZG....'); // sss = source spreadsheet
var ss = sss.getSheetByName('Monthly'); // ss = source sheet
//Get full range of data
var SRange = ss.getDataRange();
//get A1 notation identifying the range
var A1Range = SRange.getA1Notation();
//get the data values in range
var SData = SRange.getValues();
var tss = SpreadsheetApp.openById('8AjN7u....'); // tss = target spreadsheet
var ts = tss.getSheetByName('RAWData'); // ts = target sheet
//set the target range to the values of the source data
ts.getRange(A1Range).setValues(SData);
}
I took this one from user2741, which was posted here:
..this one works fine for one sheet.
But now I am unsure how to get the data from more sheets and actually sort it. Does anybody has a good idea on how to do this?
Thank you all,
Sascha
This one here works, if everything happens in the same spreadsheet
SpreadsheetApp.getActiveSpreadsheet().getSheetByName("SummarySheet").clear();
mergeSheet2("SummarySheet", "123");
mergeSheet2("SummarySheet", "345");
mergeSheet2("SummarySheet", "748");
mergeSheet2("SummarySheet", "293");
function mergeSheet2(targetSheetName, sourceSheetName) {
var ss = SpreadsheetApp.getActiveSpreadsheet();
var sourceSheet = ss.getSheetByName(sourceSheetName);
var lastRow = sourceSheet.getLastRow();
var lastCol = sourceSheet.getLastColumn();
var source = sourceSheet.getRange(1,1,lastRow,lastCol); // Error after some iterations: The coordinates or dimensions of the range are invalid. (line 11, file "copy-m.js") -> might be empty spreadsheet
var destSheet = ss.getSheetByName(targetSheetName);
var destRange = destSheet.getRange(destSheet.getLastRow()+1,1);
source.copyTo(destRange, {contentsOnly: true});
}
but for some reason I don't get it run when using different spreadsheets
Error: "Target range and source range must be on the same spreadsheet"
I tried it with:
SpreadsheetApp.getActiveSpreadsheet().getSheetByName("SummarySheet").clear();
SpreadsheetApp.openById('ID');
mergeSheet2("SummarySheet", "123");
function mergeSheet2(targetSheetName, sourceSheetName) {
var ss = SpreadsheetApp.openById('ID');
var ssd = SpreadsheetApp.openById('ID');
var sourceSheet = ss.getSheetByName(sourceSheetName);
var lastRow = sourceSheet.getLastRow();
var lastCol = sourceSheet.getLastColumn();
var source = sourceSheet.getRange(1,1,lastRow,lastCol); // Error after some iterations: The coordinates or dimensions of the range are invalid. (line 11, file "copy-m.js") -> might be empty spreadsheet
var destSheet = ssd.getSheetByName(targetSheetName);
var destRange = destSheet.getRange(destSheet.getLastRow()+1,1);
source.copyTo(destRange, {contentsOnly: true});
Any ideas?
The solution is simpler than what you tried, since you want to copy values only and knowing that copyTo only works in the same spreadsheet, just get the values from source and paste it in destination like this:
function copyFromSourceToTarget(targetSheetName, sourceSheetName) {
var ss = SpreadsheetApp.openById('ID');
var ssd = SpreadsheetApp.openById('ID');
var sourceSheet = ss.getSheetByName(sourceSheetName);
var sourceData = sourceSheet.getDataRange().getValues();
var destSheet = ssd.getSheetByName(targetSheetName);
destSheet.getRange(destSheet.getLastRow()+1,1,sourceData.length,sourceData[0].length).setValues(sourceData);
}
To make it more flexible I'd recommend to use 4 parameters and simplify again the code :
function copyFromSourceToTarget(targetSheetName,targetSsId, sourceSheetName,sourceSsId) {
var ss = SpreadsheetApp.openById(sourceSsId)getSheetByName(sourceSheetName);
var ssd = SpreadsheetApp.openById(targetSsId).getSheetByName(targetSheetName);
var sourceData = ss.getDataRange().getValues();
ssd.getRange(ssd.getLastRow()+1,1,sourceData.length,sourceData[0].length).setValues(sourceData);
}