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I have table like this :
then i want query data like this :
how did to do that?
A subquery with group by should do the job:
select * from <table_name>
where (serial_number, attempt) in (select serial_number, max(attempt) from <table_name> group by serial_number)
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Image of two sequel queries
Basically, I want it to display all films with language name spanish and show the amount of actors in each.
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class table
class table
students table
students table
teacher's table
teacher's table
expected output table
expected output table
i tried left join but i am getting multiple record's getting.
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Closed last year.
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Wanted to delete complete row, which contains NULL entries in sql with command
DELETE FROM student WHERE ID=NULL;
What is wrong in this code?
Your syntax is incorrect you need to check for IS NULL
DELETE FROM student WHERE ID IS NULL;
Adding link to documentation thanks to D M
Working with NULL values
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I have the following table where there are two relevant fields for searching, this is 'from' and 'to' and represents the range of employees and then the field 'InitialQMSDays' represents the value that I want to return.
So if I have a search value of say 6, it would look at that value and find it between the 6 - 10 row, and return 2.
any ideas?
SELECT InitialQMSDays
FROM my_table
WHERE 6 BETWEEN `From` AND `To`;
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I have a MySQL table named camp_details which has the following columns :
camp_id, camp_name, location, category, months , pattern
I have input fields which accepts values for location, category, months and pattern.
Based on the details provided, the table should sort according to the preferences (1:location , 2:Months , 3:pattern and 4:category).
That is, the table should display first containing location, next months and so on.
Kindly help me out in this.
just use this query
SELECT * FROM camp_details ORDER BY location , months,patter,category ;
or use DESC after column name which you want to sort in desc like
SELECT * FROM camp_details ORDER BY location , months DESC,patter,category ;