Storing JSON output from multiple individual API calls into Pyspark Dataframe - json

Pyspark newbie here, currently working in Azure Databricks, using a single cluster with 8 cores.
I have a Pyspark dataframe (call this 'df'), where each entry is a property (house/apartment), and has columns for longitude and latitude. The entire dataframe has about 6 million rows.
longitude
latitude
35
97
36
95
...
...
I also have access to an API which, given longitude and latitude, outputs a JSON object containing information about that property (square footage, footprint, roof condition, etc). The output looks something like this ("structures" has a [] around it for some reason):
{"request_id":12345,"structures":[{"footPrint":{"area":275,"wkt":"-83.8 35.9"},"roof_condition":{"value":3.0}],"property_features":{"parcel_wkt":"-83.7 35.9", "requested_wkt":"-83.6 35.9"}}
My question is - How can I most efficiently construct a Pyspark dataframe like the following?
longitude
latitude
request_id
area
wkt
roof_condition
parcel_wkt
requested_wkt
35
97
12345
275
-83.8 35.9
3.0
-83.7 35.9
-83.6 35.9
36
95
12346
280
-81.5 35.4
5.0
-82.0 36.1
-81.1 35.0
...
...
...
...
...
...
...
...
What I have tried -
Create a function to process a single row of the dataframe, then use a UDF with withColumn. For 100 rows, this took over half an hour.
from pyspark.sql.functions import udf
from pyspark.sql.types import *
def process_row(longitude, latitude):
# Use API call to get attributes associated with each lat/lon coordinate
url = 'https://api-url.com/GetInfo?wkt=POINT({} {})&format=json&token=mytoken'.format(longitude, latitude)
data = get_api_info(url) # grabs the output of the API call as a json object
return (data['request_id'], \
data['structures'][0]['footPrint']['area'], \
data['structures'][0]['footprint']['wkt'], \
data['structures'][0]['roof_condition']['value'], \
data['property_features']['parcel_wkt'], \
data['property_features']['requested_wkt'])
schema = StructType([
StructField("request_id", StringType(), True),
StructField("area", FloatType(), True),
StructField("wkt", StringType(), True),
StructField("roof_condition", FloatType(), True),
StructField("parcel_wkt", StringType(), True),
StructField("requested_wkt", StringType(), True)
])
process_row_udf = udf(process_row, schema)
df_ret = df.withColumn('output', process_row_udf('longitude', 'latitude'))
display(df_ret)
Use withColumn to create a single new column 'json_data', which consists of the entire json object as a string. My idea was to then use pyspark.sql.functions.from_json to add new columns from the now existing 'json_data' column to create the request_id, area, wkt, roof_condition, parcel_wkt, and requested_wkt columns. But the first half of this idea was already taking too long (5 minutes for only 30 rows), so I gave up on the rest :(
def process_row2(longitude, latitude):
# Use API call to get attributes associated with each lat/lon coordinate
url = 'https://api-url.com/GetInfo?wkt=POINT({} {})&format=json&token=mytoken'.format(longitude, latitude)
data = get_api_info(url) # grabs the output of the API call as a json object
return str(data)
process_row2_udf = udf(process_row2, StringType())
df_ret2 = df.withColumn('json_data', process_row2_udf('longitude', 'latitude'))
display(df_ret2)
Ideally, I would like to process several rows per second, maybe 3-5, on average. Is there a way to achieve this? I'm confused as to why this is so slow, since I'm pretty sure running a sequential for loop in Pandas is fast than this. I have also checked that the API call itself runs in a fraction of a second, so that's not the bottleneck here. And since I have over 6 million rows to process, I really need this to complete in a reasonable amount of time. Thank you in advance for any help!

Related

unable to load csv from GCS bucket to BigQuery table accurately

I am trying to load the airbnb_nyc data set from GCS bucket to BigqueryTable. Link to the dataset.
I am using the following Code:
def parse_file(element):
for line in csv.reader([element],delimiter=','):
return line
class DataIngestion2:
def parse_method2(self, values):
row1 = dict(
zip(('id', 'name', 'host_id', 'host_name', 'neighbourhood_group', 'neighbourhood', 'latitude', 'longitude',
'room_type', 'price', 'minimum_nights', 'number_of_reviews', 'last_review', 'reviews_per_month',
'calculated_host_listings_count', 'availability_365'),
values))
return row1
with beam.Pipeline(options=pipeline_options) as p:
lines= p | 'Read' >> ReadFromText(known_args.input,skip_header_lines=1)\
| 'parse' >> beam.Map(parse_file)
pipeline2 = lines | 'Format to Dict _ original CSV' >> beam.Map(lambda x: data_ingestion2.parse_method2(x))
pipeline2 | 'Load2' >> beam.io.WriteToBigQuery(table_spec, schema=table_schema,
write_disposition=beam.io.BigQueryDisposition.WRITE_TRUNCATE,
create_disposition=beam.io.BigQueryDisposition.CREATE_IF_NEEDED
)
`
But my output on BigQuery Table is wrong.
I am only getting values for the first two columns and the rest of the 14 columns are showing NULL. I am not able to figure out what I am doing wrong. Can Someone Help me find the error in my logic. I basically want to know how to transfer a csv from GCS bucket to BigQuery through DataFlow pipeline.
Thank you,
You can use the ReadFromText method and then create your own transform by extending beam.DoFn. Attached the code below for reference.
https://beam.apache.org/releases/pydoc/2.32.0/apache_beam.io.textio.html#apache_beam.io.textio.ReadFromText
Note that you can use gs:// for GCS in file_pattern.
More details about Pardo and DoFn
https://beam.apache.org/documentation/programming-guide/#pardo
import apache_beam as beam
from apache_beam.io.textio import ReadAllFromText,ReadFromText
from apache_beam.io.gcp.bigquery import WriteToBigQuery
from apache_beam.io.gcp.gcsio import GcsIO
import csv
COLUMN_NAMES = ['id','name','host_id','host_name','neighbourhood_group','neighbourhood','latitude','longitude','room_type','price','minimum_nights','number_of_reviews','last_review','reviews_per_month','calculated_host_listings_count','availability_365']
def files(path='gs:/some/path'):
return list(GcsIO(storage_client='<ur storage client>').list_prefix(path=path).keys())
def transform_csv(element):
rows = []
with open(element,newline='\r\n') as f:
itr = csv.reader(f, delimiter = ',',quotechar= '"')
skip_head = next(itr)
for row in itr:
rows.append(row)
return rows
def to_dict(element):
rows = []
for item in element:
row_dict = {}
zipped = zip(COLUMN_NAMES,item)
for key,val in zipped:
row_dict[key] =val
rows.append(row_dict)
yield rows
with beam.Pipeline() as p:
read =(
p
|'read-file'>> beam.Create(files())
|'transform-dict'>>beam.Map(transform_csv)
|'list-to-dict'>>beam.FlatMap(to_dict )
|'print'>>beam.Map(print)
#|'write-to-bq'>>WriteToBigQuery(schema=COLUMN_NAMES,table='ur table',project='',dataset='')
)
EDITED1 The ReadFromText supports \r\n as newline char.But,this fails to consider the condition where column data itself has \r\n. Updating the code below.
EDITED 2 GcsIo error fixed.
Note - I have used GCSIO for getting the list of files.
Details here
Please Up-vote and mark as answer if this helps.
Let me suggest another approch for this use case. BiqQuery offers special feature for uploading from Google Could Storage (GCS) to Bigquery. You can load data in several formats and CSV is among them.
There is nice tutorial on Google documentation explaining how to do it. You do not have to use Dataflow or apache_beam. Such process is available through BigQuery API itself.
This is working in many languages, but you do not have to use any language as such process can be done from console or via Cloud SDK using bq command. Everything can be found in mentioned tutorial.

Extract fields from log file where data is stored half json and half plain text

I am new to Spark, and want to read a log file and create a dataframe out of it. My data is half json, and I cannot convert it into a dataframe properly. Here below is first row in the file;
[2017-01-06 07:00:01] userid:444444 11.11.111.0 info {"artist":"Tears For Fears","album":"Songs From The Big Chair","song":"Everybody Wants To Rule The World","id":"S4555","service":"pandora"}
See first part is plain text and the last part between { } is json, I tried few things, converting it first to RDD then map and split then convert back to DataFrame, but I cannot extract the values from Json part of the row, is there a trick to extract fields in this context?
Final output will be like;
TimeStamp userid ip artist album song id service
2017-01-06 07:00:01 444444 11.11.111.0 Tears For Fears Songs From The Big Chair Everybody Wants To Rule The World S4555 pandora
You just need to parse out the pieces with a Python UDF into a tuple then tell spark to convert the RDD to a dataframe. The easiest way to do this is probably a regular expression. For example:
import re
import json
def parse(row):
pattern = ' '.join([
r'\[(?P<ts>\d{4}-\d\d-\d\d \d\d:\d\d:\d\d)\]',
r'userid:(?P<userid>\d+)',
r'(?P<ip>\d+\.\d+\.\d+\.\d+)',
r'(?P<level>\w+)',
r'(?P<json>.+$)'
])
match = re.match(pattern, row)
parsed_json = json.loads(match.group('json'))
return (match.group('ts'), match.group('userid'), match.group('ip'), match.group('level'), parsed_json['artist'], parsed_json['song'], parsed_json['service'])
lines = [
'[2017-01-06 07:00:01] userid:444444 11.11.111.0 info {"artist":"Tears For Fears","album":"Songs From The Big Chair","song":"Everybody Wants To Rule The World","id":"S4555","service":"pandora"}'
]
rdd = sc.parallelize(lines)
df = rdd.map(parse).toDF(['ts', 'userid', 'ip', 'level', 'artist', 'song', 'service'])
df.show()
This prints
+-------------------+------+-----------+-----+---------------+--------------------+-------+
| ts|userid| ip|level| artist| song|service|
+-------------------+------+-----------+-----+---------------+--------------------+-------+
|2017-01-06 07:00:01|444444|11.11.111.0| info|Tears For Fears|Everybody Wants T...|pandora|
+-------------------+------+-----------+-----+---------------+--------------------+-------+
I have used the following, just some parsing utilizing pyspark power;
parts=r1.map( lambda x: x.value.replace('[','').replace('] ','###')
.replace(' userid:','###').replace('null','"null"').replace('""','"NA"')
.replace(' music_info {"artist":"','###').replace('","album":"','###')
.replace('","song":"','###').replace('","id":"','###')
.replace('","service":"','###').replace('"}','###').split('###'))
people = parts.map(lambda p: (p[0], p[1],p[2], p[3], p[4], p[5], p[6], p[7]))
schemaString = "timestamp mac userid_ip artist album song id service"
fields = [StructField(field_name, StringType(), True) for field_name in schemaString.split()]
With this I got almost what I want, and performance was super fast.
+-------------------+-----------------+--------------------+-------------------- +--------------------+--------------------+--------------------+-------+
| timestamp| mac| userid_ip| artist| album| song| id|service|
+-------------------+-----------------+--------------------+--------------------+--------------------+--------------------+--------------------+-------+
|2017-01-01 00:00:00|00:00:00:00:00:00|111122 22.235.17...|The United States...| This Is Christmas!|Do You Hear What ...| S1112536|pandora|
|2017-01-01 00:00:00|00:11:11:11:11:11|123123 108.252.2...| NA| Dinner Party Radio| NA| null|pandora|

How to use PySpark to load a rolling window from daily files?

I have a large number of fairly large daily files stored in a blog storage engine(S3, Azure datalake exc.. exc..) data1900-01-01.csv, data1900-01-02.csv,....,data2017-04-27.csv. My goal is to preform a rolling N-day linear regression but I am having trouble with the data loading aspect. I am not sure how to do this without nested RDD's.
The schema for every .csv file is the same.
In other words for every date d_t, I need data x_t and to join data (x_t-1, x_t-2,... x_t-N).
How can I use PySpark to load an N-day Window of these daily files? All of the PySpark examples I can find seem to load from one very large file or data set.
Here's an example of my current code:
dates = [('1995-01-03', '1995-01-04', '1995-01-05'), ('1995-01-04', '1995-01-05', '1995-01-06')]
p = sc.parallelize(dates)
def test_run(date_range):
dt0 = date_range[-1] #get the latest date
s = '/daily/data{}.csv'
df0 = spark.read.csv(s.format(dt0), header=True, mode='DROPMALFORM')
file_list = [s.format(dt) for dt in date_range[:-1]] # Get a window of trailing dates
df1 = spark.read.csv(file_list, header=True, mode='DROPMALFORM')
return 1
p.filter(test_run)
p.map(test_run) #fails with same error as p.filter
I'm on PySpark version '2.1.0'
I'm running this on an Azure HDInsight cluster jupyter notebook.
spark here is of type <class 'pyspark.sql.session.SparkSession'>
A smaller more reproducible example is as follows:
p = sc.parallelize([1, 2, 3])
def foo(date_range):
df = spark.createDataFrame([(1, 0, 3)], ["a", "b", "c"])
return 1
p.filter(foo).count()
You are better off with using Dataframes rather than RDD. Dataframe's read.csv api accepts list of paths like -
pathList = ['/path/to/data1900-01-01.csv','/path/to/data1900-01-02.csv']
df = spark.read.csv(pathList)
have a look at documentation for read.csv
You can form the list of paths to date files to your data files by doing some date operation over window of N days like "path/to/data"+datetime.today().strftime("%Y-%m-%d"))+.csv" (This will get you file name of today only but its not hard to figure out date calculation for N days)
However keep in mind that schema of all date csvs should be same for above to work.
edit : When you parallelize list of dates i.e. p, each date gets processed individually by different executors, so input to test_run2 wasnt really as list of dates, it was one individual string like 1995-01-01
Try this instead, see if this works.
# Get the list of dates
date_range = window(dates, N)
s = '/daily/data{}.csv'
dt0 = date_range[-1] # most recent file
df0 = spark.read.csv(s.format(dt0), header=True, mode='DROPMALFORM')
# read previous files
file_list = [s.format(dt) for dt in date_range[:-1]]
df1 = spark.read.csv(file_list, header=True, mode='DROPMALFORM')
r, resid = computeLinearRegression(df0,df1)
r.write.save('daily/r{}.csv'.format(dt0))
resid.write.save('/daily/resid{}.csv'.format(dt0))

Removing characters from column in pandas data frame

My goal is to (1) import Twitter JSON, (2) extract data of interest, (3) create pandas data frame for the variables of interest. Here is my code:
import json
import pandas as pd
tweets = []
for line in open('00.json'):
try:
tweet = json.loads(line)
tweets.append(tweet)
except:
continue
# Tweets often have missing data, therefore use -if- when extracting "keys"
tweet = tweets[0]
ids = [tweet['id_str'] for tweet in tweets if 'id_str' in tweet]
text = [tweet['text'] for tweet in tweets if 'text' in tweet]
lang = [tweet['lang'] for tweet in tweets if 'lang' in tweet]
geo = [tweet['geo'] for tweet in tweets if 'geo' in tweet]
place = [tweet['place'] for tweet in tweets if 'place' in tweet]
# Create a data frame (using pd.Index may be "incorrect", but I am a noob)
df=pd.DataFrame({'Ids':pd.Index(ids),
'Text':pd.Index(text),
'Lang':pd.Index(lang),
'Geo':pd.Index(geo),
'Place':pd.Index(place)})
# Create a data frame satisfying conditions:
df2 = df[(df['Lang']==('en')) & (df['Geo'].dropna())]
So far, everything seems to be working fine.
Now, the extracted values for Geo result in the following example:
df2.loc[1921,'Geo']
{'coordinates': [39.11890951, -84.48903638], 'type': 'Point'}
To get rid of everything except the coordinates inside the squared brackets I tried using:
df2.Geo.str.replace("[({':]", "") ### results in NaN
# and also this:
df2['Geo'] = df2['Geo'].map(lambda x: x.lstrip('{'coordinates': [').rstrip('], 'type': 'Point'')) ### results in syntax error
Please advise on the correct way to obtain coordinates values only.
The following line from your question indicates that this is an issue with understanding the underlying data type of the returned object.
df2.loc[1921,'Geo']
{'coordinates': [39.11890951, -84.48903638], 'type': 'Point'}
You are returning a Python dictionary here -- not a string! If you want to return just the values of the coordinates, you should just use the 'coordinates' key to return those values, e.g.
df2.loc[1921,'Geo']['coordinates']
[39.11890951, -84.48903638]
The returned object in this case will be a Python list object containing the two coordinate values. If you want just one of the values, you can slice the list, e.g.
df2.loc[1921,'Geo']['coordinates'][0]
39.11890951
This workflow is much easier to deal with than casting the dictionary to a string, parsing the string, and recapturing the coordinate values as you are trying to do.
So let's say you want to create a new column called "geo_coord0" which contains all of the coordinates in the first position (as shown above). You could use a something like the following:
df2["geo_coord0"] = [x['coordinates'][0] for x in df2['Geo']]
This uses a Python list comprehension to iterate over all entries in the df2['Geo'] column and for each entry it uses the same syntax we used above to return the first coordinate value. It then assigns these values to a new column in df2.
See the Python documentation on data structures for more details on the data structures discussed above.

How to fetch a JSON file to get a row position from a given value or argument

I'm using wget to fetch several dozen JSON files on a daily basis that go like this:
{
"results": [
{
"id": "ABC789",
"title": "Apple",
},
{
"id": "XYZ123",
"title": "Orange",
}]
}
My goal is to find row's position on each JSON file given a value or set of values (i.e. "In which row XYZ123 is located?"). In previous example ABC789 is in row 1, XYZ123 in row 2 and so on.
As for now I use Google Regine to "quickly" visualize (using the Text Filter option) where the XYZ123 is standing (row 2).
But since it takes a while to do this manually for each file I was wondering if there is a quick and efficient way in one go.
What can I do and how can I fetch and do the request? Thanks in advance! FoF0
In python:
import json
#assume json_string = your loaded data
data = json.loads(json_string)
mapped_vals = []
for ent in data:
mapped_vals.append(ent['id'])
The order of items in the list will be indexed according to the json data, since the list is a sequenced collection.
In PHP:
$data = json_decode($json_string);
$output = array();
foreach($data as $values){
$output[] = $values->id;
}
Again, the ordered nature of PHP arrays ensure that the output will be ordered as-is with regard to indexes.
Either example could be modified to use a mapped dictionary (python) or an associative array (php) if needs demand.
You could adapt these to functions that take the id value as an argument, track how far they are into the array, and when found, break out and return the current index.
Wow. I posted the original question 10 months ago when I knew nothing about Python nor computer programming whatsoever!
Answer
But I learned basic Python last December and came up with a solution for not only get the rank order but to insert the results into a MySQL database:
import urllib.request
import json
# Make connection and get the content
response = urllib.request.urlopen(http://whatever.com/search?=ids=1212,125,54,454)
content = response.read()
# Decode Json search results to type dict
json_search = json.loads(content.decode("utf8"))
# Get 'results' key-value pairs to a list
search_data_all = []
for i in json_search['results']:
search_data_all.append(i)
# Prepare MySQL list with ranking order for each id item
ranks_list_to_mysql = []
for i in range(len(search_data_all)):
d = {}
d['id'] = search_data_all[i]['id']
d['rank'] = i + 1
ranks_list_to_mysql.append(d)