Hi I have a query that I have built as follows
SELECT brand, model, buyer_rate, DATE_ADD(finish_dt, INTERVAL 33 HOUR), bid_price, g.status, ga.idx AS gai, ab.idx as abi
FROM auction_bid ab
INNER JOIN goods_auction ga ON ab.goods_auction_idx=ga.idx
INNER JOIN auction_info ai ON ga.auction_info_idx=ai.idx
INNER JOIN goods g ON ai.goods_idx= g.idx
INNER JOIN user u on g.user_idx=u.idx
WHERE g.status='A008' AND DATEDIFF(Now(), ab.created_at)<5 GROUP BY bid_price DESC, ab.created_at
The result of the query is something like the picture below
The result that I am hoping to retrieve is the maximum bid_price value for the same brand and model.
So in this case I would like to retrieve the 1st and 10th row.
Would there be any way to edit my existing query to get this desired result.
Thank you in advance
Related
I tried to write a query, but unfortunately I didn't succeed.
I want to know how many packages delivered over a given period by a person.
So I want to know how many packages were delivered by John (user_id = 1) between 01-02-18 and 28-02-18. John drives another car (another plate_id) every day.
(orders_drivers.user_id, plates.plate_name, orders.delivery_date, orders.package_amount)
I have 3 table:
orders with plate_id delivery_date package_amount
plates with plate_id plate_name
orders_drivers with plate_id plate_date user_id
I tried some solutions but didn't get the expected result. Thanks!
Try using JOINS as shown below:
SELECT SUM(o.package_amount)
FROM orders o INNER JOIN orders_drivers od
ON o.plate_id=od.plate_id
WHERE od.user_id=<the_user_id>;
See MySQL Join Made Easy for insight.
You can also use a subquery:
SELECT SUM(o.package_amount)
FROM orders o
WHERE EXISTS (SELECT 1
FROM orders_drivers od
WHERE user_id=<user_id> AND o.plate_id=od.plate_id);
SELECT sum(orders.package_amount) AS amount
FROM orders
LEFT JOIN plates ON orders.plate_id = orders_drivers.plate_id
LEFT JOIN orders_driver ON orders.plate_id = orders_drivers.plate_id
WHERE orders.delivery_date > date1 AND orders.delivery_date < date2 AND orders_driver.user_id = userid
GROUP BY orders_drivers.user_id
But seriously, you need to ask questions that makes more sense.
sum is a function to add all values that has been grouped by GROUP BY.
LEFT JOIN connects all tables by id = id. Any other join can do this in this case, as all ids are unique (at least I hope).
WHERE, where you give the dates and user.
And GROUP BY userid, so if there are more records of the same id, they are returned as one (and summed by their pack amount.)
With the AS, your result is returned under the name 'amount',
If you want the total of packageamount by user in a period, you can use this query:
UPDATE: add a where clause on user_id, to retrieve John related data
SELECT od.user_id
, p.plate_name
, SUM(o.package_amount) AS TotalPackageAmount
FROM orders_drivers od
JOIN plates p
ON o.plate_id = od.plate_id
JOIN orders o
ON o.plate_id = od.plate_id
WHERE o.delivery_date BETWEEN convert(datetime,01/02/2018,103) AND convert(datetime,28/02/2018,103)
AND od.user_id = 1
GROUP BY od.user_id
, p.plate_name
It groups rows on user_id and plate_name, filter a period of delivery_date(s) and then calculate the sum of packageamount for the group
Currently I have a simple SQL request to get aall group departure date and the associated group size (teamLength) between 2 dates but it doesn't work properly.
SELECT `groups`.`departure`, COUNT(`group_users`.`group_id`) as 'teamLength'
FROM `groups`
INNER JOIN `group_users`
ON `groups`.`id` = `group_users`.`group_id`
WHERE departure BETWEEN '2017-03-01' AND '2017-03-31'
In fact, if I have more than 1 group between the 2 dates, only 1 date will be recovered in association with the total number of teamLength.
For exemple, if I have 2 groups in the same interval with, for group 1, 2 people and for group 2, 1 people, the result will be:
Here are 2 screenshots of the current state of my groups and group_users tables:
Is it even possible to do what I want in only 1 SQL request ? Thanks
In addition to what jarlh commented (JOIN with ON). Don't ever group data without an explicit GROUP BY. I don't know why MYSQL still allows this...
Change your query to something like this and you should get the result you are looking for. Currently, the other departure dates get lost in the aggregation.
SELECT
groups.departure,
COUNT(1) as team_length
FROM
groups
INNER JOIN group_users
ON groups.id = group_users.group_id
WHERE
groups.departure BETWEEN '2017-03-01' AND '2017-03-31'
GROUP BY
groups.departure
I think that you have a syntax issue in your query. You are missing the ON statement so your database could be trying to get a cartesian product since there is no join clause.
SELECT `groups`.`departure`, COUNT(`group_users`.`id`) as 'teamLength'
FROM `groups`
INNER JOIN `group_users` ON `groups`.`id` = `group_users`.`group_id`
WHERE departure BETWEEN '2017-03-01' AND '2017-03-31'
GROUP BY `groups`.`departure`
You also are missing the GROUP BYclause which is not mandatory in all RDBS but it is a good practice to set it.
I have a two tables, one called entities with these relevant columns:
id, company_id ,and integration_id. The other table is transactions with columns id, entity_id and created_at. The foreign keys linking the two tables are integration_id and entity_id.
The transactions table shows the number of transactions received from each company from the entities table.
Ultimately, I want to find date range with highest volume of transactions occurring and then from that range find the average number of days between transaction for each company.
To find the date range I used this query.
SELECT DATE_FORMAT(t.created_at, '%Y/%m/%d'), COUNT(t.id)
FROM entities e
JOIN transactions t
ON ei.id = t.entity_id
GROUP BY t.created_at;
I get this:
Date_FORMAT(t.created_at, '%Y/%m/%d') | COUNT(t.id)
+-------------------------------------+------------
2015/11/09 4
etc
From that I determine the range I want to use as 2015/11/09 to 2015/12/27
and I made this query
SELECT company_id, COUNT(t.id)
FROM entities e
INNER JOIN transactions t
ON e.integration_id = t.entity_id
WHERE tp.created_at BETWEEN '2015/11/09' AND '2015/12/27'
GROUP BY company_id;
I get this:
company_id | COUNT(t.id)
+-----------+------------
1234 17
and so on
Which gives me the total transactions made by each company over this date range. What's the best way now to query for the average number of days between transactions by company? How can I sub-query or is there a way to use the AVG function on dates in a WHERE clause?
EDIT:
playing around with the query, I'm wondering if there is a way I can
SELECT company_id, (49 / COUNT(t.id))...
49, because that is the number of days in that date range, in order to get the average number of days between transactions?
I think this might be it, does that make sense?
I think this may work:
Select z.company_id,
datediff(max(y.created_at),min(created_at))/count(y.id) as avg_days_between_orders,
max(y.created_at) as latest_order,
min(created_at) as earliest_order,
count(y.id) as orders
From
(SELECT entity_id, max(t.created_at) latest, min(t.created_at) earliest
FROM entities e, transactions t
Where e.id = t.entity_id
group by entity_id
order by COUNT(t.id) desc
limit 1) x,
transactions y,
entities z
where z.id = x.entity_id
and z.integration_id = y.entity_id
and y.created_at between x.earliest and x.latest
group by company_id;
It's tough without the data. There's a possibility that I have reference to integration_id incorrect in the subquery/join on the outer query.
Im trying to get the SUM of all user balances in a specific month, and grouped by the user's region, which depends on the Point of Sell they work at.
balance
id_balance
date
id_user
value ($$$)
user
id_user
id_pos
name (not relevant)
pos (Point of Sell)
id_pos
id_region
name (not relevant)
location_region
id_region
name (Florida, Texas, etc)
Basically, I would need it to present this data (filtered by month):
location_region.name | SUM(balance.value)
---------------------|-------------------
Florida | 45730
Texas | 43995
I've tried a few approaches with no luck. This was my closest attempt.
SELECT location_region.name, SUM(balance.value) AS money
FROM balance
LEFT JOIN user ON user.id_user
LEFT JOIN pos ON pos.id_pos = user.id_pos
LEFT JOIN location_region ON location_region.id_region = pos.id_region
WHERE balance.date BETWEEN '2014-02-01' AND DATE_ADD('2014-02-01', INTERVAL 1 MONTH)
GROUP BY location_region.id_region
ORDER BY money DESC
Any ideas? Thanks!
Your current query has a logical error, JOIN condition between balance and user tables is incomplete (missing balance.id_user). So instead of balance LEFT JOIN user ON user.id_user you should have balance LEFT JOIN user ON user.id_user=balance.id_user. This is causing the JOINed table to have more rows (number of rows in balance times number of rows in user table). So the final SUM is bringing a way too higher value.
I tried the following query on your sample data (I changed some values) and it seems to be working fine:
SELECT location_region.name, SUM(balance.value) AS money
FROM balance
LEFT JOIN user USING(id_user)
LEFT JOIN pos USING(id_pos)
LEFT JOIN location_region USING(id_region)
WHERE balance.date BETWEEN '2014-02-01' AND DATE_ADD('2014-02-01', INTERVAL 1 MONTH)
GROUP BY location_region.id_region
ORDER BY money DESC
Working demo: http://sqlfiddle.com/#!2/dda28/3
On having a detailed look at your table structure and the query that you gave, what I feel is this mismatch could happen because of duplicate number of rows that might be cropping up due to the JOIN. What I suggest in this case is to find the DISTINCT rows and summing it up so that you get an exact result. Now since SUM DISTINCT is not available in MySQL, you could try this different approach to accomplish what you want:
SELECT location_region.name,
SUM(balance.value)*COUNT(DISTINCT id_user)/COUNT(id_user) AS money
FROM balance
LEFT JOIN user ON user.id_user = balance.id_user
LEFT JOIN pos ON pos.id_pos = user.id_pos
LEFT JOIN location_region ON location_region.id_region = pos.id_region
WHERE balance.date BETWEEN '2014-02-01' AND DATE_ADD('2014-02-01', INTERVAL 1 MONTH)
GROUP BY location_region.id_region
ORDER BY money DESC
In my comment, was wondering why u did not JOIN user table with ON clause as user.id_user = balance.id_user. I have added that however in my query. Hope this helps.
I'm fairly new to Mysql and need help trying to combine two mysql queries that give a "total" for each "storeid" from the orders total. I'm currently using two queries to get the result:
SELECT storeid, storenum, name FROM store ORDER BY storeid DESC
SELECT SUM((1+0.07125)*qty*discprice) as total FROM items WHERE orderid IN (SELECT orderid FROM orders WHERE store = '".$row['storeid']."' AND date >= '2012-01-01' AND date < '2013-01-01')
I'm running a while loop and running the second query with the "storeid". However, I know I can do this is one query and group by "storeid" and create a total for all stores combined. But I can't figure it out.
Thanks!
SELECT s.storeid, s.storenum, s.name
SUM((1+0.07125)*i.qty*i.discprice) AS total
FROM items AS i
LEFT JOIN orders AS o
ON i.orderid=o.orderid
LEFT JOIN stores AS s
ON o.store=s.storeid
WHERE o.date >= '2012-01-01'
AND o.date < '2013-01-01'
GROUP BY s.storeid, s.storenum, s.name;
The trick is to join the three tables and then use an aggregate function on the items table.
SELECT stores.storeid, stores.storenum, stores.name, SUM((1+0.07125)*items.qty*items.discprice) as total
FROM stores
LEFT JOIN orders ON orders.storeid=stores.storeid AND orders.date>='2012-01-01' AND orders.date<'2013-01-01'
LEFT JOIN items ON items.orderid=orders.orderid
GROUP BY stores.storeid, stores.storenum, stores.name
What this does it this:
It will select every store from the stores table, and sum up the orders in that store. I chose a LEFT JOIN instead of straight JOINs, so that stores without any order in that time span will still show up with a total of NULL.
P.S. I don't have a copy of your database's schema, above SQL query might not actually work as expected - it is just supposed to point you in the right direction.