SQL Sentence help select multiple tables - mysql

I have this setence that select a Product NAME from my table Produto and select the quantity from other table named Contagens where the Produto.EANU = Contagens.PRODUTO but I also have some QTD that are related to EANP istead of EANU and I want to them be shown as ARM instead of QTD.
Is there any way that I can get those 2 sentences in one ?
SELECT Produto.NAME, IFNULL(Contagens.QTD ,0) as QTD FROM Produto
LEFT
OUTER JOIN Contagens ON Produto.EANU = Contagens.PRODUTO
ORDER BY NAME
SELECT Produto.NAME, IFNULL(Contagens.QTD ,0) as ARM FROM Produto
LEFT
OUTER JOIN Contagens ON Produto.EANP = Contagens.PRODUTO
ORDER BY NAME

Combine the conditions, and then use IF in the SELECT list to test which condition was matched.
SELECT p.Name, IF(p.EANU = c.PRODUTO, Contagens.QTD, 0) AS QTD, IF(p.EANP = c.PRODUTO, Contagents.QTD, 0) AS ARM
FROM Produto AS p
LEFT JOIN Contagens AS c ON c.PRODUTO IN (p.EANU, p.EANP)
ORDER BY p.Name

Just join them using aliases:
SELECT Produto.NAME,
IFNULL(EANU_Contagens.QTD ,0) as QTD,
IFNULL(EANP_Contagens.QTD ,0) as ARM
FROM Produto
LEFT OUTER JOIN Contagens AS EANU_Contagens ON Produto.EANU = EANU_Contagens.PRODUTO
LEFT OUTER JOIN Contagens AS EANP_Contagens ON Produto.EANP = EANP_Contagens.PRODUTO
ORDER BY NAME

Related

Is there a method of counting an attribute that is in a GROUP BY clause?

I need have created a select statement to list out all the customers that have been to multiple merchants below.
I want to create another statement to display how many of those customers have been to each merchant.
What is the optimal method of approaching this problem?
Lists out all customers that have been to multiple merchants.
WITH valentinesDayMerchant AS (
SELECT m.MerchantId, m.MerchantGroupId, m.WebsiteName
FROM Merchant m
INNER JOIN OpeningHours oh ON m.MerchantId = oh.MerchantId AND oh.DayOfWeek = 'TUE'
LEFT JOIN devices.DeviceConnectionState AS dcs ON dcs.MerchantId = oh.MerchantId
WHERE MerchantStatus = '-' AND (m.PrinterType IN ('V','O') OR dcs.State = 1 OR dcs.StateTransitionDateTime > '2023-01-23')
)
SELECT DISTINCT ul.UserLoginId, ul.FullName, ul.EmailAddress, ul.Mobile
FROM dbo.UserLogin AS ul
INNER JOIN dbo.Patron AS p ON p.UserLoginId = ul.UserLoginId
INNER JOIN valentinesDayMerchant AS m ON (m.MerchantId = ul.ReferringMerchantId OR m.MerchantId IN (SELECT pml.MerchantId FROM dbo.PatronMerchantLink AS pml WHERE pml.PatronId = p.PatronId AND ISNULL(pml.IsBanned, 0) = 0))
LEFT JOIN (
SELECT mg.MerchantGroupId, mg.MerchantGroupName, groupHost.HostName [GroupHostName]
FROM dbo.MerchantGroup AS mg
INNER JOIN dbo.Merchant AS parent ON parent.MerchantId = mg.ParentMerchantId
INNER JOIN dbo.HttpHostName AS groupHost ON groupHost.MerchantID = parent.MerchantId AND groupHost.Priority = 0
) mGroup ON mGroup.MerchantGroupId = m.MerchantGroupId
LEFT JOIN (
SELECT po.PatronId, MAX(po.OrderDateTime) [LastOrder]
FROM dbo.PatronsOrder AS po
GROUP BY po.PatronId
) orders ON orders.PatronId = p.PatronId
INNER JOIN dbo.HttpHostName AS hhn ON hhn.MerchantID = m.MerchantId AND hhn.Priority = 1
WHERE ul.UserLoginId NOT IN (1,2,100,372) AND ul.UserStatus <> 'D' AND (
ISNULL(orders.LastOrder, '2000-01-01') > '2020-01-01' OR ul.RegistrationDate > '2022-01-01'
)
GROUP BY ul.UserLoginId, ul.FullName, ul.EmailAddress, ul.Mobile
HAVING COUNT(m.MerchantId) > 1
Methods I have tried include adding the merchant name to a group by and displaying the count of the customers, however this does not work as I cannot have anything related to the Merchant in the GROUP BY, or I wouldn't be able to use HAVING clause to identify the customers that have been to multiple merchants. I have also tried selecting all the merchants and counting the distinct customers which doesn't work as it takes into account all the customers, not specifically the customers that have been to multiple merchants only.

References Outer Query MySQL

i tried use "Total" in outer where, and i got error "Unknown "AL.Total", how to fix it ?
here my query :
SELECT
AL.CODE,
AL.NAME,
SUM(AL.BEGINING+AL.MUTATION) AS TOTAL
from
(SELECT
ACC.CODE,
ACC.NAME,
ACC.BEGINING,
SUM(JOURNAL.DEBIT-JOURNAL.KREDIT) AS MUTATION
FROM
G_JOURNAL INNER JOIN P ON Category.Category= G_JOURNAL.Category
INNER JOIN JOURNAL ON G_JOURNAL.NOINDEX = JOURNAL.NOINDEX_JOURNAL
INNER JOIN ACCOUNT ON JOURNAL.CODE = ACC.CODE
INNER JOIN SUBCLASS ON SUBCLASS.NOSUBCLASS= ACC.NOSUBCLASS
INNER JOIN CLASS ON SUBCLASS.NOSUBCLASS = CLASS.NOCLASS
WHERE
(MONTH(G_JOURNAL.DATE) <= '12' AND YEAR (G_JOURNAL.DATE<= '2020')
AND
SUBCLASS.NOSUBCLASS=120
GROUP BY ACC.NAME) AL
WHERE AL.TOTAL >0
GROUP BY AL.NAME
ORDER BY AL.CODE ASC
Try HAVING TOTAL >0 instead of WHERE AL.TOTAL >0,because TOTAL
is not in AL temp table
SELECT
AL.CODE,
AL.NAME,
SUM(AL.BEGINING+AL.MUTATION) AS TOTAL
from
(SELECT
ACC.CODE,
ACC.NAME,
ACC.BEGINING,
SUM(JOURNAL.DEBIT-JOURNAL.KREDIT) AS MUTATION
FROM
G_JOURNAL INNER JOIN P ON Category.Category= G_JOURNAL.Category
INNER JOIN JOURNAL ON G_JOURNAL.NOINDEX = JOURNAL.NOINDEX_JOURNAL
INNER JOIN ACCOUNT ON JOURNAL.CODE = ACC.CODE
INNER JOIN SUBCLASS ON SUBCLASS.NOSUBCLASS= ACC.NOSUBCLASS
INNER JOIN CLASS ON SUBCLASS.NOSUBCLASS = CLASS.NOCLASS
WHERE
(MONTH(G_JOURNAL.DATE) <= '12' AND YEAR (G_JOURNAL.DATE<= '2020')
AND
SUBCLASS.NOSUBCLASS=120
GROUP BY ACC.NAME) AL
GROUP BY AL.NAME
HAVING TOTAL >0
ORDER BY AL.CODE ASC

How to run two where clauses inside a Join?

Please check the below code.
SELECT
`order`.idorder
, order_status_code.idorder_status_code
, order_status_code.order_status_code
, user.iduser
, `order`.required_delivery_date
, `order`.cancel
, `order`.date_created
, `order`.last_updated
, COUNT(order_item.idorder_item)
from
`order`
INNER JOIN order_status_code
ON `order`.idorder_status_code = order_status_code.idorder_status_code
INNER JOIN user
ON `order`.iduser = user.iduser
INNER JOIN order_item
ON order_item.idorder = `order`.`idorder`
WHERE
`order`.iduser = 1
In here, I want the COUNT(order_item.idorder_item) to return the number of items under the idorder. In other words, if I run that SQL Part along, that would be like below
SELECT
COUNT(`idorder_item`)
from
order_item
where
idorder = 1
How can I get this done in my main query?
SELECT `order`.idorder,
order_status_code.idorder_status_code,
order_status_code.order_status_code,
user.iduser,
`order`.required_delivery_date,
`order`.cancel,
`order`.date_created,
`order`.last_updated,
COUNT(order_item.idorder_item),
(SELECT COUNT(`idorder_item`)
from order_item
where idorder=1) as count_idorder_item
from `order`
INNER JOIN order_status_code ON `order`.idorder_status_code = order_status_code.idorder_status_code
INNER JOIN user ON `order`.iduser = user.iduser
INNER JOIN order_item ON order_item.idorder = `order`.`idorder`
WHERE `order`.iduser= 1

MYSQL Merge two columns from two tables and still use LEFT JOIN

So I'm having a slight problem with having to save price on a product in two different tables due to a few reasons. Is it possible to merge two columns into one? I know UNION exists but does it work with LEFT JOIN's?
Any pointers is much appreciated.
Best Regards
SELECT
si.id AS shop_item_id,
si.item_price,
s.logo_file_name,
p.cat_id AS category_id,
api.item_price AS api_price,
MAX(c.campaign_desc) AS campaignDesc,
MAX(c.campaign_type_id) AS campaignType,
MAX(c.shop_id) AS campaign_shop_id,
MAX(ct.image_name) AS campaignLogo
FROM
shop_item si
LEFT JOIN
shop s ON
s.id = si.shop_id
LEFT JOIN
product p ON
si.product_id = p.id
LEFT JOIN
campaign_category cc ON
cc.category_id = p.cat_id
LEFT JOIN
campaign c ON
c.id = cc.campaign_id AND
c.shop_id = si.shop_id AND
c.show_in_pricetable = 1 AND
NOW() BETWEEN c.date_from and c.date_to
LEFT JOIN
campaign_type ct ON
c.campaign_type_id = ct.id
LEFT JOIN
shop_api_item api ON
si.rel_feed_api = api.unique_id AND si.shop_id = api.shop_id
WHERE
si.`product_id` = 586 AND
s.`active_shop` = 1
GROUP BY
s.name,
si.id ,
si.item_price
ORDER BY
si.`item_price`,
si.`shop_id`,
c.`campaign_desc` DESC
It looks like you would benefit from the COALESCE() function.
SELECT
si.id AS shop_item_id,
COALESCE(si.item_price, api.item_price) AS coalesced_price,
...
COALESCE() takes multiple arguments, and returns the first argument that is not NULL.

Using ORDER BY on a multiple LEFT JOIN query

I have this long query that I finally got to work but I am unable to ORDER BY date_time_added, which is a field that is in all the tables except for user_accounts and relationships table. How do i make it work correctly?
$sql = "select distinct pb.user_id, pb.Full_name,
tv.why_onsite3, tv.onsite3_id, tv.other_date as onsite3_date,
tv.user_allowed as tv_user_allowed, np.onsite4_name ,
np.onsite4_id, np.other_date as onsite4_date, np.user_allowed
as np_user_allowed, pml.med_name , pml.med_id, pml.other_date
as pml_date, pml.user_allowed as pml_user_allowed, pl.onsite5_name,
pl.onsite5_test_id, pl.other_date as some_stats_date, pl.user_allowed as
pl_user_allowed, chlp.problem_name_is , chlp.current_problem_id,
chlp.other_date as chlp_date, chlp.user_allowed as chlp_user_allowed,
pphl.onsite10_health_prob_id , pphl.onsite10_problem_name_is,
pphl.other_date as pphl_date, pphl.user_allowed as pphl_user_allowed,
al.onsite_id , al.onsite_name, al.other_date as onsite_date,
al.user_allowed as al_user_allowed, sl.onsite2_id , sl.onsite2_name,
sl.other_date as onsite2_date, sl.user_allowed as sl_user_allowed,
hal.onsite6_id , hal.reason_for_admit, hal.other_date as hal_date,
hal.user_allowed as hal_user_allowed, il.onsite9_id , il.onsite9_name,
il.other_date as il_date , il.user_allowed as il_user_allowed
from user_accounts pb left join some_stuff tv on pb.user_id = tv.user_id
left join some_onsite4s np on pb.user_id = np.user_id
left join some_med pml on pb.user_id = pml.user_id
left join list_hal hal on pb.user_id = hal.user_id
left join list_for_things il on pb.user_id = il.user_id
left join list_on sl on pb.user_id = sl.user_id
left join some_all al on pb.user_id = al.user_id
left join some_list pphl on pb.user_id = pphl.user_id
left join some_stats pl on pb.user_id = pl.user_id
left join some_probs chlp on pb.user_id = chlp.user_id
where (pb.user_id in (select fb.friend_id from relationships fb
where fb.user_id = '$uid')
or pb.user_id in (select fb1.user_id from relationships fb1
where fb1.friend_id = '$uid')
)
group by pb.user_id ORDER BY date_time_added DESC LIMIT $startrow, 20";
In ORDER BY clause, you have to specify what is the exact column you are ordering by. That means you have to prefix the column that is used for ordering, because you have multiple columns that are called the same in multiple tables.
Other option is to restructure the query completely and use UNION operator with multiple SELECT statements. Each SELECT statement would pickup a group of data from one table and order that group by column from that table.
The solution depend on the data that you want to output - the context of the data.