This question already has answers here:
Why is the regex to match 1 to 10 written as [1-9]|10 and not [1-10]?
(9 answers)
Closed 7 months ago.
I am working on an exercise where we are testing form validation in an Angular template. The restrictions for the one input field are that the selection should be a number from 1-10.
My first try was below, as I was taught using pipes could separate literals.
pattern="[1|2|3|4|5|6|7|8|9|10]"
When that did not work for 10, I tried the below two lines, which still did not let me include 10, but did allow 0.
pattern="[1|2|3|4|5|6|7|8|9|(10)]"
pattern="[1|2|3|4|5|6|7|8|9|(10)]{1}"
This is my first stackoverflow question, so I think I included enough, but I will provide more information if needed.
Use this RegEx: ^([1-9]|10)$
Explanation:
^ Assert position at start of line.
( Capture group open.
[1-9] Match a single character in the range between 1 and 9.
| Equivalent to logical OR.
) Capture group close.
$ Assert position at the end of the line.
Related
Table has field containing the list of IDs separated by "-".
Example: 559-3319-3537-4345-29923
I need to check rows that use at least 4 of the specified identifiers using regex
Example: before inserting to the db, I need to check the value 559-3319-3537-29923-30762 for this condition.
I've build a pattern that only works in the specified order, but if the IDs are swapped, it doesn't work.
Template: ^.*\b(-*(559|3319|3537|29923|30762)-*){4,}\b.*$
Initially, I thought that a simple (559|3319|3537|29923|30762){4,} should be enough, but in this case it also doesn't work, although it sees all 4 values without a quantifier.
Please tell me how to write such an expression correctly.
For ease of reading/testing, I've simplified the Ids being searched for to single digit integers 1-5. The following pattern will match strings with at least 4 out of the 5 ids:
(\b(1|2|3|4|5)\b.*){4,}
(Play with this here)
OR MySQL's regex dialect:
([[:<:]](1|2|3|4|5)[[:>:]].*){4,}
(Play with MySQL version here)
Here are some examples:
#
Example
Is Match?
Description
1
1-2-3-4-5
YES
All the Ids
2
1-2-3-9-5
YES
Enough Ids
3
1-1-9-1-1
YES
Enough Ids, but there are repeats
4
9-8-7-6-0
NO
None of the Ids
5
1-2-3-9-9
NO
Some, but not enough of the Ids
If the repeated Ids as shown in example 3 are an issue, then regex is probably not a good fit for this problem.
Edit:
^.*\b((559|3319|3537|29923|30762)-?([0-9]*)?-?){4,}\b.*$
The reasoning behind this is that each group is not just one of the 5 numbers, but it can include some extra characters. So the matched groups in your example are:
(559-)
(3319-)
(3537-4345-)
(29923)
Original answer:
This would be one way to do it (not sure if there are other ways to do it):
^.*\b(559|3319|3537|29923|30762)[0-9-]*(559|3319|3537|29923|30762)[0-9-]*(559|3319|3537|29923|30762)[0-9-]*(559|3319|3537|29923|30762)\b.*$
This question already has answers here:
How to write Fortran Output as CSV file?
(5 answers)
Closed 1 year ago.
I'm the beginner of Fortran.
I would like to ask you how to get CSV file.
In my case, I use this code for get output:
However, Unfortunately, after calculation, I get this result like this:
I would like to write the value at one line.
Does anyone know how to fix this problem? Or please tell me another best method how to fix it.
Thank you.
Steve's first rule of Fortran - never use list-directed output when you care about the layout.
Fortran has several features that can help you here:
The G0.d format that will accept any intrinsic datatype and format numerics in a form Excel will accept
The * infinite group repeat count that repeats the following format group as many times as is needed by the input data
The : edit descriptor that stops processing non-data-transmitting format elements
Combining these can serve you well in your quest for CSV output. For example:
implicit none
real :: x(2),y(2),rou(2)
integer :: i
x = [-1.,-1.0007]
y = [0.,0.]
rou = [-1.499337,-1.499337]
do i=1,2
write (*,'(*(G0.7,:,","))') x(i),y(i),0.0,rou(i)
end do
end
outputs:
-1.000000,.000000,.000000,-1.499337
-1.000700,.000000,.000000,-1.499337
Use a format statement. Assuming you want the number formats shown in your image
do i = 1, mx
do j = 1, my
write(99, 900) x(i,j), ",", y(i,j), ",", 0.d0, ",", rou(i,j)
end do
end do
900 format (F8.4, A, 2(E8.2,A), F8.6)
If you want the file to have a header row, write it before the do loop using a different format statement
This question already has answers here:
Regular expression to stop at first match
(9 answers)
Closed 2 years ago.
I have this gigantic ugly string:
J0000000: Transaction A0001401 started on 8/22/2008 9:49:29 AM
J0000010: Project name: E:\foo.pf
J0000011: Job name: MBiek Direct Mail Test
J0000020: Document 1 - Completed successfully
I'm trying to extract pieces from it using regex. In this case, I want to grab everything after Project Name up to the part where it says J0000011: (the 11 is going to be a different number every time).
Here's the regex I've been playing with:
Project name:\s+(.*)\s+J[0-9]{7}:
The problem is that it doesn't stop until it hits the J0000020: at the end.
How do I make the regex stop at the first occurrence of J[0-9]{7}?
Make .* non-greedy by adding '?' after it:
Project name:\s+(.*?)\s+J[0-9]{7}:
Using non-greedy quantifiers here is probably the best solution, also because it is more efficient than the greedy alternative: Greedy matches generally go as far as they can (here, until the end of the text!) and then trace back character after character to try and match the part coming afterwards.
However, consider using a negative character class instead:
Project name:\s+(\S*)\s+J[0-9]{7}:
\S means “everything except a whitespace and this is exactly what you want.
Well, ".*" is a greedy selector. You make it non-greedy by using ".*?" When using the latter construct, the regex engine will, at every step it matches text into the "." attempt to match whatever make come after the ".*?". This means that if for instance nothing comes after the ".*?", then it matches nothing.
Here's what I used. s contains your original string. This code is .NET specific, but most flavors of regex will have something similar.
string m = Regex.Match(s, #"Project name: (?<name>.*?) J\d+").Groups["name"].Value;
I would also recommend you experiment with regular expressions using "Expresso" - it's a utility a great (and free) utility for regex editing and testing.
One of its upsides is that its UI exposes a lot of regex functionality that people unexprienced with regex might not be familiar with, in a way that it would be easy for them to learn these new concepts.
For example, when building your regex using the UI, and choosing "*", you have the ability to check the checkbox "As few as possible" and see the resulting regex, as well as test its behavior, even if you were unfamiliar with non-greedy expressions before.
Available for download at their site:
http://www.ultrapico.com/Expresso.htm
Express download:
http://www.ultrapico.com/ExpressoDownload.htm
(Project name:\s+[A-Z]:(?:\\w+)+.[a-zA-Z]+\s+J[0-9]{7})(?=:)
This will work for you.
Adding (?:\\w+)+.[a-zA-Z]+ will be more restrictive instead of .*
This question already has answers here:
Regular expression to stop at first match
(9 answers)
Closed 2 years ago.
I have this gigantic ugly string:
J0000000: Transaction A0001401 started on 8/22/2008 9:49:29 AM
J0000010: Project name: E:\foo.pf
J0000011: Job name: MBiek Direct Mail Test
J0000020: Document 1 - Completed successfully
I'm trying to extract pieces from it using regex. In this case, I want to grab everything after Project Name up to the part where it says J0000011: (the 11 is going to be a different number every time).
Here's the regex I've been playing with:
Project name:\s+(.*)\s+J[0-9]{7}:
The problem is that it doesn't stop until it hits the J0000020: at the end.
How do I make the regex stop at the first occurrence of J[0-9]{7}?
Make .* non-greedy by adding '?' after it:
Project name:\s+(.*?)\s+J[0-9]{7}:
Using non-greedy quantifiers here is probably the best solution, also because it is more efficient than the greedy alternative: Greedy matches generally go as far as they can (here, until the end of the text!) and then trace back character after character to try and match the part coming afterwards.
However, consider using a negative character class instead:
Project name:\s+(\S*)\s+J[0-9]{7}:
\S means “everything except a whitespace and this is exactly what you want.
Well, ".*" is a greedy selector. You make it non-greedy by using ".*?" When using the latter construct, the regex engine will, at every step it matches text into the "." attempt to match whatever make come after the ".*?". This means that if for instance nothing comes after the ".*?", then it matches nothing.
Here's what I used. s contains your original string. This code is .NET specific, but most flavors of regex will have something similar.
string m = Regex.Match(s, #"Project name: (?<name>.*?) J\d+").Groups["name"].Value;
I would also recommend you experiment with regular expressions using "Expresso" - it's a utility a great (and free) utility for regex editing and testing.
One of its upsides is that its UI exposes a lot of regex functionality that people unexprienced with regex might not be familiar with, in a way that it would be easy for them to learn these new concepts.
For example, when building your regex using the UI, and choosing "*", you have the ability to check the checkbox "As few as possible" and see the resulting regex, as well as test its behavior, even if you were unfamiliar with non-greedy expressions before.
Available for download at their site:
http://www.ultrapico.com/Expresso.htm
Express download:
http://www.ultrapico.com/ExpressoDownload.htm
(Project name:\s+[A-Z]:(?:\\w+)+.[a-zA-Z]+\s+J[0-9]{7})(?=:)
This will work for you.
Adding (?:\\w+)+.[a-zA-Z]+ will be more restrictive instead of .*
How does one capture a value recursively with regex, where value is a part of a group that repeats?
I have a serialized array in mysql database
These are 3 examples of a serialized array
a:2:{i:0;s:2:"OR";i:1;s:2:"WA";}
a:1:{i:0;s:2:"CA";}
a:4:{i:0;s:2:"CA";i:1;s:2:"ID";i:2;s:2:"OR";i:3;s:2:"WA";}
a:1 stands for array:{number of elements}
then in between {} i:0 means element 0, i:1 means element 1 etc.
then the actual value s:2:"CA" means string with length of 2
so I have 2 elements in first array, 1 element in the second and 4 elements in the last
I have this data in mysql database and I DO NOT HAVE an option to parse this with back-end code - this has to be done in mysql (10.0.23-MariaDB-log)
the repeating pattern is inside of the curly braces
the number of repeats is variable (as in 3 examples each has a different number of repeating patterns),
the number of repeating patterns is defined by the number at 3rd position (if that helps)
for the first example it's a:2:
and so there are 2 repeating blocks:
i:0;s:2:"OR";
i:1;s:2:"WA";
I only care to extract the values in bold
So I came up with this regex
^a:(?:\d+):\{(?:i:(?:\d+);s:(?:\d+):\"(\w\w)\";)+}$
it captures the values I want all right but problem is it only captures the last one in each repeating group
so going back to the example what would be captured is
WA
CA
WA
What I would want is
OR|WA
CA
CA|ID|OR|WA
these are the language specific regex functions available to me:
https://mariadb.com/kb/en/library/regular-expressions-functions/
I don't care which one is used to solve the problem
Ultimately I need this in as sensible form that can be presented to the client e.g. CA,ID,OR or CA|ID|OR
Current thoughts are perhaps this isn't possible in a one liner, and I have to write a multi-step function where
extract the repeating portion between the curly braces
then somehow iterate over each repeating portion
then use the regex on each
then return the results as one string with separated elements
I doubt if such a capture is possible. However, this would probably do the job for your specific purpose.
REGEXP_REPLACE(
REGEXP_REPLACE(
REGEXP_REPLACE(str1, '^a:\\d+:\{', ''),
'i:\\d+;s:\\d+:\"(\\w\\w)\";',
'\\1,'
),
'\,?\}$',
''
)
Basically, this works with the input string (or column) str1 like
remove the first part
replace every cell with the string you want
remove the last 2 characters, ,}
and voila! You get a string CA,ID,OR.
Aftenote
It may or may not work well when the original array before serialised is empty (it depends how it is serialised).