how to get a particular field from django model - mysql

I want a command for getting a query set from the model.
The SQL command will be like
SELECT teamName FROM TABLE WHERE userName=userName;

I found the answer
teamNameQuery=userInfo.objects.filter(userName=userName).values('teamName').first()

you can retrive list of field from model by using values_list
Model.Objects.filter(userName = userName).values_list('teamName')

Related

How to select database with dot in its name with laravel?

i have a project to show database value...
but, the database name has dot in it.
my database name is "t.produk".
How can i select the database in laravel?
i run it and got an error says it invalid like below
EDIT:
and i also did it with just string, came out error too :
Here the picture
First of all - avoid naming database tables like that. You should not use any dots there. It could be t_produk as example.
But table name should be descriptive so go for something like products. Than name your entity as Product.
You get this error here because you can't set variable as (t.produk). You should pass a string as I see here. So do it like this:
protected $table = 't.produk';
EDIT:
I saw the error with a string variable. So now you see why the current table naming you choose is quite not good. DB reads it as follows:
select from database t table produk
If you will name your table like t_produk problem should be no longer here.
My bad, so the tables name can't have dot in it. noted.
Btw y'all thanks for the answers :)

how to include hard-coded value to output from mysql query?

I've created a MySQL sproc which returns 3 separate result sets. I'm implementing the npm mysql package downstream to exec the sproc and get a result structured in json with the 3 result sets. I need the ability to filter the json result sets that are returned based on some type of indicator in each result set. For example, if I wanted to get the result set from the json response which deals specifically with Suppliers then I could use some type of js filter similar to this:
var supplierResultSet = mySqlJsonResults.filter(x => x.ResultType === 'SupplierResults');
I think SQL Server provides the ability to include a hard-coded column value in a SQL result set like this:
select
'SupplierResults',
*
from
supplier
However, this approach appears to be invalid in MySQL b/c MySQL Workbench is telling me that the sproc syntax is invalid and won't let me save the changes. Do you know if something like what I'm trying to achieve is possible in MySQL and if not then can you recommend alternative approaches that would help me achieve my ultimate goal of including some type of fixed indicator in each result set to provide a handle for downstream filtering of the json response?
If I followed you correctly, you just need to prefix * with the table name or alias:
select 'SupplierResults' hardcoded, s.* from supplier s
As far as I know, this is the SQL Standard. select * is valid only when no other expression is added in the selec clause; SQL Server is lax about this, but most other databases follow the standard.
It is also a good idea to assign a name to the column that contains the hardcoded value (I named it hardcoded in the above query).
In MySQL you can simply put the * first:
SELECT *, 'SupplierResults'
FROM supplier
Demo on dbfiddle
To be more specific, in your case, in your query you would need to do this
select
'SupplierResults',
supplier.* -- <-- this
from
supplier
Try this
create table a (f1 int);
insert into a values (1);
select 'xxx', f1, a.* from a;
Basically, if there are other fields in select, prefix '*' with table name or alias

Can i use question mark in MySQL this way

i'm using node.js to build a web. I connect to my database (Mysql) and
get the data then return to the client side.
I know that i can use the literal template to write my sql expression like below
promise(`SELECT table.name FROM table WHERE name = ?`,[parameter])
and i'm would like to know can i write my sql expression like this?
promise(`SELECT table.? FROM table`,[parameter])
I know the result is different, i just want to know it is right or not.
thank you and have a nice day.
No, but you could use string interpolation like:
promise(`SELECT table.name FROM table WHERE name = ${parameter}`)

Spring data Couchbase #n1ql.fields query

I'm trying to make a N1QL based query on Spring Data Couchbase. The documentation says
#n1ql.fields will be replaced by the list of fields (eg. for a SELECT clause) necessary to reconstruct the entity.
My repository implementation is this one:
#Query("#{#n1ql.fields} WHERE #{#n1ql.filter}")
List<User> findAllByFields(String fields);
And I'm calling this query as follows:
this.userRepository.findAllByFields("SELECT firstName FROM default");
I'm getting this error:
Caused by: org.springframework.data.couchbase.core.CouchbaseQueryExecutionException: Unable to execute query due to the following n1ql errors:
{"msg":"syntax error - at AS","code":3000}
After a little bit of researching, I also tryed:
#Query("SELECT #{#n1ql.fields} FROM #{#n1ql.bucket} WHERE #{#n1ql.filter}")
With this query, I don't get an error, I get all the documents stored but only the ID the other fields are set to null, when my query tries to get the firstName field.
this.userRepository.findAllByFields("firstName");
Anyone knows how to do such a query?
Thank you in advance.
You're misunderstanding the concept, I encourage you to give the documentation more time and see more examples. I'm not sure what exactly you're trying to achieve but I'll throw some examples.
Find all users (with all of their stored data)
#Query("#{#n1ql.selectEntity} WHERE #{#n1ql.filter}")
List<User> findAllUsers();
This will basically generate SELECT meta().id,_cas,* FROM bucket WHERE type='com.example.User'
Notice findAllUsers() does not take any parameters because there are no param placeholders defined in the #Query above.
Find all users where firstName like
#Query("#{#n1ql.selectEntity} WHERE #{#n1ql.filter} AND firstName like $1")
List<User> findByFirstNameLike(String keyword);
This will generate something like the above query but with an extra where condition firstName like
Notice this method takes a keyword because there is a param placeholder defined $1.
Notice in the documentation it says
#{#n1ql.selectEntity} WHERE #{#n1ql.filter} AND test = $1
is equivalent to
SELECT #{#n1ql.fields} FROM #{#n1ql.bucket} WHERE
#{#n1ql.filter} AND test = $1
Now if you don't want to fetch all the data for user(s), you'll need to specify the fields being selected, read following links for more info
How to fetch a field from document using n1ql with spring-data-couchbase
https://docs.spring.io/spring-data/couchbase/docs/2.2.4.RELEASE/reference/html/#_dto_projections
I think you should try below query, that should resolve the issue to get fields based parameter you have sent as arguments.
Please refer blow query.
#Query("SELECT $1 FROM #{#n1q1.bucket} WHERE #{#n1ql.filter}")
List findByFirstName(String fieldName);
Here, bucket name resolve to the User entity and and n1ql.filter would be a default filter.

creating command in yii for mysql

How to write or create command as
select * from profile where name like r% limit 12,16;
in mysql to get the appropriate result in yii.
please any help would be appreciated. thank you in advance
You should use this code:
$queryResult = Yii::app()->db->createCommand('select * from profile where name like "r%" limit 12,16;')->queryAll();
Result will be an array of associative arrays where keys will represents column names, and values are values fetched from DB.