Delete the duplicate values in the SUM with MySQL or SQL - mysql

Question

Hi I am doing a sum of a table, but the problem is that the table has duplicate rows, so I wonder how can I do the sum without duplicated rows:
The main table is this one:
folio
cashier_id
amount
date
0001
1
2500
2022-06-01 00:00:00
0002
2
10000
2022-06-01 00:00:00
0001
1
2500
2022-06-01 00:00:00
0003
1
1000
2022-06-01 00:00:00
If I sum that you can see that the first and the third row are duplicated, so when I do the sum it makes it wrong because, the result will be:
cashier_id
cash_amount
1
6000
2
10000
but it should be:
cashier_id
cash_amount
1
3500
2
10000
The query that I use to make the sum is this one:
SELECT `jysparki_jis`.`api_transactions`.`cashier_id` AS `cashier_id`,
SUM(`jysparki_jis`.`api_transactions`.`cash_amount`) AS `cash_amount`,,
COUNT(0) AS `ticket_number`,
DATE(`jysparki_jis`.`api_transactions`.`created_at`) AS `date`
FROM `jysparki_jis`.`api_transactions`
WHERE DATE(`jysparki_jis`.`api_transactions`.`created_at`) >= '2022-01-01'
AND (`jysparki_jis`.`api_transactions`.`dte_type_id` = 39
OR `jysparki_jis`.`api_transactions`.`dte_type_id` = 61)
AND `jysparki_jis`.`api_transactions`.`cashier_id` <> 0
GROUP BY `jysparki_jis`.`api_transactions`.`cashier_id`,
DATE(`jysparki_jis`.`api_transactions`.`created_at`)
How you can see the sum is this:
SUM(`jysparki_jis`.`api_transactions`.`cash_amount`).
I wonder how can I do the sum avoiding to duplicate the folio with same cashier_id?
I know that if I filter for the cashier_id and folio I can avoid the duplicate rows but I do not know how to do that, can you help me?
Thanks

Answer 1

Given your provided input tables, you can use the DISTINCT clause inside the SUM aggregation function to solve your problem:
SELECT cashier_id, SUM(DISTINCT amount)
FROM tab
GROUP BY cashier_id,
folio,
date
Check the demo here.
Then you can add up your conditions inside your WHERE clause to this query, and your aggregation on the "created_at" field (that should correspond to the "date" field of your sample table - I guess). This solution may give your the general idea.