SQL Query relationship between 3 tables - mysql

I have a scenario where I have the following tables:
Inventories
delivery_items
deliveries
I seek a query where, having the inventory id, I get the delivery_item(fk_inventory),
which then I get the delivery from the (fk_delivery).
Manually, I go to the delivery_items table, then I search for the fk_inventory that matches the id from the inventory that I'm looking for,
then I get the fk_delivery, and get the delivery.
But I need to run a report on 15k+ items.
How to write a query where from a list of inventory ids I can get to the delivery following the relationship that I mentioned above?

There are many sites on writing SQL queries, differentiating between a normal (inner) join vs outer join, left join, right join, subqueries, etc. What you are looking to do is probably best (due to all inventory items in question) is simple joins.
Try to think of it this way, and maybe do it this way. Have a sheet of paper, one representing each table and write the columns on it.
Now, visually looking at the available tables, put them next to each other based on how they are related. Note the column in table A that is the foreign key to the next table. Then again, from the second to the third.
Once you have this done (or even if just mentally), you can SEE how they are related. This is the basis of the FROM clause
select *
from
YourFirstTable yft
JOIN YourSecondTable yst
on yft.WhateverKey = yst.MatchingKeyColumn
JOIN YourThirdTable ytt
on yst.KeyToThirdTable = ytt.KeyInThisTable
Now that you have all your relationships established, you can always declare the individual columns you want from those respective tables. Easier to use with the aliases such as I provided here via yft, yst, ytt representing the first, second and third tables. Use aliases appropriate to your tables such as i=inventories, di = delivery_items, d = deliveries.
Then add whatever FILTERING conditions you want. If the condition is based on the FIRST Table such as yft above, that would go into the WHERE clause such as
where
yft.SomeColumn = 'blah'
If the filtering criteria is specific to your second or third table, just add that to the JOIN / ON condition so it stays with the table and you know contextually it is associated HERE. It makes it easier when you are getting into LEFT JOINs.
from
YourFirstTable yft
JOIN YourSecondTable yst
on yft.WhateverKey = yst.MatchingKeyColumn
AND yst.SecondTableColumn = 'someOtherValue'
AND yst.SomeOtherColumn = 'somethingElse'
So now, the engine can go through all inventory items, to the corresponding details, to the actual deliveries without having to do individual searches each time which would be painful to trace / run / and performance.

Related

MySQL 1:N Data Mapping

Something really bugs me and im not sure what is the "correct" approach.
If i make a select to get contacts from my database there are a decent amount of joins involved.
It will look something like this (around 60-70 columns):
SELECT *
FROM contacts
LEFT JOIN company
LEFT JOIN person
LEFT JOIN address
LEFT JOIN person_communication
LEFT JOIN company_communication
LEFT JOIN categories
LEFT JOIN notes
company and person are 1:1 cardinality so its straight forward.
But "address", "communication" and "categories" are 1:n cardinality.
So depending on the amount of rows in the 1:n tables i will get a lot of "double" rows (I don't know whats the real term for that, the rows are not double i know that the address or phone number etc is different). For myself as a contact, a fairly filled contact, i get 85 rows back.
How do you guys work with that?
In my PHP application i always wrote some "Data-Mapper" where the array key was the "contact.ID aka primary" and then checked if it exists and then pushed the additional data into it. Also PHP is not really type strict what makes it easy.
Now I'm learning GO(golang) and i thought screw that LOOOONG select and data mapping just write selects for all the 1:n.... yeah no, not enough connections to load a table full of contacts. I know that i can increase the connections but the error seems to imply that this would be the wrong way.
I use the following driver: https://github.com/go-sql-driver/mysql
I also tried GROUP_CONCAT but then i running in trouble parsing it back.
Do i have to do my mapping approach again or is there some nice solution out there? I found it quite dirty at points tho?
The solution is simple: you need to execute more than one query!
The cause of all the "duplicate" rows is that you're generating a result called a Cartesian product. You are trying to join to several tables with 1:n relationships, but each of these has no relationship to the other, so there's no join condition restricting them with respect to each other.
Therefore you get a result with every combination of all the 1:n relationships. If you have 3 matches in address, 5 matches in communication, and 5 matches in categories, you'd get 3x5x5 = 75 rows.
So you need to run a separate SQL query for each of your 1:n relationships. Don't be afraid—MySQL can handle a few queries. You need them.

PHP / MySQL selecting records from multiple tables

i have a MySQL statement which works - i can get the records requested - movies.* & groups.name.
$stmt= $mysqli->query("SELECT DISTINCT ebooks.*, groups.name FROM ebooks
INNER JOIN ebooks_groups ON ebooks.uuid = ebooks_groups.ebookuuid
INNER JOIN groups_users ON ebooks_groups.groupuuid = groups_users.groupuuid
INNER JOIN groups ON groups_users.groupuuid = groups.uuid
WHERE useruuid=".$get_useruuid."
ORDER BY groups.name");
1/ However i need to grab another column from the groups table - namely groups.uuid
i tried
SELECT DISTINCT movies.*, groups.* FROM movies, groups
&
SELECT DISTINCT movies.*, groups.name, groups.uuid FROM movies, groups
but it retrieved no records.
2/ Then I had another look at my original code - ... FROM movies ... - how is this even working if i'm not selecting FROM movies, groups tables?
AFAIK, this is pure MySQL. PHP or not doesn't come into play.
First to understand is the implicit join:
Explicit vs implicit SQL joins
That understanding should solve at least half of your problem.
Secondly, I'd never code a SELECT * without a very good reason (and there's few). It makes much more sense to select just the columns you need instead of getting them all and even if you need all that are currently there, if you work on the database model later on, there might be more (or less!!) columns in the database and it'll be much harder to detect that your code needs updating if you don't have them explicitly listed.
For the rest I build my SQL queries slowly step by step. That helps a lot to debugging your queries esp. as you have the actual tables and some sample data ...
[That should solve your other half of the question]

Extremely basic SQL Misunderstanding

I'm preparing for an exam in databases and SQL and I'm solving an exercise:
We have a database of 4 tables that represent a human resources company. The tables are:
applicant(a-id,a-name,a-city,years-of-study),
job(job-name,job-id),
qualified(a-id,job-id)
wish(a-id,job-id).
the table applicant represents the table of applicants obviously. And jobs is the table of available jobs. the table qualified shows what jobs a person is qualified for, and the table wish shows what jobs a person is interested in.
The question was to write a query that displays for each job-id, the number of applicants that are both qualified and interested to work in.
Here is the solution the teacher wrote:
Select q1.job_id
, count(q1.a_id)
from qualified as q1
, wish as w1
Where q1.a_id = w1.a_id
and q1.job_id = w1.job_id
Group by job_id;
That's all well and good, I'm not sure why we needed that "as q1" and "as w1", but i can see why it works.
And here is the solution I wrote:
SELECT job-id,COUNT(a-id) FROM job,qualified,wish WHERE (qualified.a-id=wish.a-id)
GROUP BY job-id
Why is my solution wrong? And also - From which table will it select the information? Suppose I write SELECT job-id FROM job,qualified,wish. From which table will it take the information? because job-id exists in all 3 of these tables.
You can only refer to tables mentioned in the FROM clause. If it's ambiguous (because more than one has a column of the same name) then you need to be explicit by qualifying the name. Usually the qualifier is an alias but it could also be the table name itself if an alias wasn't specified.
There's a concept of a "natural join" which joins tables on common column(s) between two tables. Not all systems support that notation but I think MySQL does. I believe these systems usually collapse the joined pairs into a single column.
select q1.job_id, count(q1.a_id) from qualified as q1, wish as w1
where q1.a_id = w1.a_id and q1.job_id = w1.job_id
group by job_id;
I don't think I've worked on any systems that would have accepted the query above because the grouping column would have been strictly unclear even though the intention really is not. So if it truly does work correctly on MySQL then my guess is that it recognizes the equivalence of the columns and cuts you some slack on the syntax.
By the way, your query appears to be incorrect because you only included a single column in a join that requires two columns. You also included a third table which means that your result will effectively do a cross join of every row in that table. The grouping is going to still going to reduce it to one row per job_id but the count is going to be multiplied by the number of rows in the job table. Perhaps you added that table thinking it would hurt to add it just in case you need it but that is not what it means at all.
Your query will list non-existing jobs in case the database has orphan records in applicant and qualified, and might also omit jobs that have no qualified and willing candidates.
I'm not exactly sure, because I have no idea if there's any database that will accept COUNT(a-id) when there's no information about the table from which to take this value.
edit: Interestingly it looks like both of these problems are shared by both of the solutions, but shawnt00 has a point: your solution makes a huge pointless cartesian of three tables: see it without the group by.
My current best guess for a working answer would therefore be http://sqlfiddle.com/#!9/09d0c/6

Creating View: Multiple Foreign Key Relations to Single Table

I have a table, tblNoComp, that has two columns, both foreign keys pointing to tblPackage.ID. The purpose of tblNoComp is to store which packages are not compatible with each other, by simply storing the ID of those packages in two columns, OneID and TwoID.
May not be the best way of storing it, but since multiple packages aren't compatible with others, it seemed to be the most logical.
Attempting to create a view that shows the tblPackage.Name for the two side by side - I have the following, but unsure how to get the TwoID Package Name..
SELECT tblNoComp.OneID, tblPackages.Package,tblNoComp.TwoID,tblPackages.Package
FROM tblNoComp, tblPackages
WHERE (tblNoComp.OneID = tblPackages.PID)
Currently the second tblPackages.Package is simply showing OneID name, not TwoID.. Not sure how to resolve?
Thank you!
--Apologies if a simple question, I've searched for an hour but haven't quite been able to describe my problem correctly.
The code you have in your comment:
SELECT
tblNoComp.OneID,
tblPackages.Package AS OneIDPackageName,
tblNoComp.TwoID,
tblPackages.Package AS TwoIDPackageName
FROM
tblNoComp
LEFT JOIN tblPackages
ON tblNoComp.OneID = tblPackages.PID
Is aliasing the columns instead of the tables. The idea behind the aliasing is to JOIN the same table twice as two different tables, using two different aliases. You're only joining it once and trying to use it twice.
You probably intent something more like this:
SELECT
tblNoComp.OneID,
tblOnePackages.Package AS OneIDPackageName,
tblNoComp.TwoID,
tblTwoPackages.Package AS TwoIDPackageName
FROM
tblNoComp
LEFT JOIN tblPackages AS tblOnePackages
ON tblNoComp.OneID = tblOnePackages.PID
LEFT JOIN tblPackages AS tblTwoPackages
ON tblNoComp.TwoID = tblTwoPackages.PID
(Note that I don't have a MySQL syntax checker handy, so this may need to be tweaked in order to run properly.)
Note that the same table is joined twice on two different keys, and that each time it's given a different alias so that it can be referenced within the SELECT clause as two separate tables.

Joining a table stored within a column of the results

I want to try and keep this as one query and not use PHP, but it's proving to be tough.
I have a table called applications, that stores all the applications and some basic information about them.
Then, I have a table with all the types of applications in it, and that table contains a reference to another table which stores more specific data about the specific type of application in question.
select applications.id as appid, applications.category, type.title as type, type.id as tid, type.valuefld, type.tablename
from applications
left join type on applications.typeid=type.id
left join department on type.deptid=department.id
where not isnull(work_cat)
and work_cat != ''
and applications.deleted=0
and datei between '10-04-14' and '11-04-14'
order by type, work_cat
Now, in the old version, there is another query on every single result. Over hundreds of results... that sucks.
This is the query I'd like to integrate so I can get all the data in one result row. (Old is ASP, I'm re-writing it in PHP)
query = "select sum("&adors.fields("valuefld")&") as cost, description from "&adors.fields("tablename")&" where appid = '"&adors.fields("tablename")&"'"
Prepared statements, I'm aware, are the best solution, but for now they are not an option.
You can't do this with a plain SQL query - you need to have a defined set of tables that your query is based on. The fact that your current implementation queries from whatever table is named by tablename from the first result-set means that to get this all in one query, you will have to restructure your data. You have to know what tables you're querying from rather than having it dynamic.
If the reason for these different tables is the different information stored in each requiring different record (column) structures, you might want to look into Key/Value pair storage in a large table. Once you combine the dynamically named ones into a single location you can integrate your two queries together.