The following query works
SELECT score, DENSE_RANK() OVER(ORDER BY score DESC) AS 'rank' FROM Scores
But when I do the following below it doesn't work
SELECT score, DENSE_RANK() OVER(ORDER BY score DESC) AS 'rank' FROM Scores ORDER BY rank
RANK is a reserved keyword in MySQL 8.0, see https://dev.mysql.com/doc/refman/8.0/en/keywords.html#keywords-8-0-detailed-R
In your ORDER BY clause, the parser thinks you are using the RANK function, and it gets confused when it reaches the end and finds you have not put () after the function name RANK. The error shows what follows the point where it got confused, which is the end of the query, so what follows is ''.
ERROR 1064 (42000): You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 1
You can fix this and use reserved keywords as identifiers by enclosing them in back-ticks:
SELECT score, DENSE_RANK() OVER(ORDER BY score DESC) AS 'rank'
FROM Scores
ORDER BY `rank`;
Related
In my SQL table I have "country" and "we200326" columns. Column "we200326" contains only "1" or "NULL" entries.
I'm trying to get a total of all "1"s in column "we200326" and a total by country. I have written the following statement but it gives an error but I don't know what I did wrong (I'm very new at this):
SELECT country, we200326,
(SUM(we200326) OVER () AS Total)
(SUM(we200326) OVER (PARTITION BY country) AS CountryTotal)
FROM table_name
ORDER BY CountryTotal, Country;
The error I get is this:
MySQL said: Documentation
#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'OVER () AS Total)
(SUM(we200326) OVER (PARTITION BY country) AS CountryTotal)
' at line 2
I have searched for similar errors and found several (each time was a simple syntax error like a space or comma or so) I tried several versions but could not resolve my problem when following those instructions. Any help would be appreciated.
Window functions are available in MySQL 8.0 only.
In earlier versions, one option is to use subqueries:
select
country,
wewe200326,
(select sum(we200326) from table_name) total,
(select sum(we200326) from table_name t1 where t1.country = t.country) country_total
from table_name t
order by country_total, country
My query is:
SELECT *,
ROW_NUMBER() OVER (ORDER BY score ASC)
FROM submissions
The error message I receive is:
#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '(ORDER BY score ASC) FROM submissions LIMIT 0, 25' at line 2
I am running this query in phpMyAdmin. I notice that OVER is not colored blue, nor does is it suggested as I type, unlike other command words (ORDER, ASC, etc).
This simpler query runs just fine:
SELECT * FROM submissions
I've tried putting things in quotes, using the RANK function instead, and fiddling with whitespace, but the query still doesn't run. What is wrong here?
My guess is that you are running a version of MySQL which is earlier than 8+, one which does not support ROW_NUMBER. There are a few options for simulating ROW_NUMBER in earlier versions of MySQL. One is to use user variables:
SELECT *,
(#row_number:=#row_number + 1) AS rn
FROM submissions, (SELECT #row_number := 0) tmp
ORDER BY score;
I am trying to learn about the MySQL ROW_NUMBER() function and how to use it to generate a sequential number for each row in a result set.
What I tried so far:
SELECT e.*,
ROW_NUMBER()
OVER(PARTITION BY e.examid ORDER BY e.examid) AS id
from exam e
When I run this query, a series of errors were displayed:
3 errors were found during analysis.
An alias was previously found. (near "id" at position 68)
An alias was expected. (near " " at position 67)
Unexpected token. (near "id" at position 68)
#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '(PARTITION BY examid ORDER BY examid) as id from exam LIMIT 0, 25' at line 1
How can I go about it?
I had the same problem. This syntax works in my case:
SELECT
(ROW_NUMBER() OVER (ORDER BY id)) row_number, Field1, Field2
FROM
myTable
ORDER BY
id
Additional remark: select version() returns 10.3.20-MariaDB-log.
Change the I'd to something else because the select * statement will return an id and it will conflict with that I'd (AS id)
When executing a query I get following error
'[Err] 1064 - You have an error in your SQL syntax; check the manual
that corresponds to your MariaDB server version for the right syntax
to use near '(PARTITION by kd_lv3) as max_date , row_number()
OVER (PARTITION by kd_' at line 6'.
Query :
select kd_lv3
, nm_lv3
, kd_lv2
, kd_lv1
, date(update_date) as update_date
, max(date(update_date)) OVER (PARTITION by kd_lv3) as max_date
, row_number() OVER (PARTITION by kd_lv3) as rownum
from akun_lv3_dump
What should I do to resolve the error?
I would have commented instead of answer, but I don't have points enough.
The SQL looks good to me, but I dug into it and your query has:
(PARTITION by kd_lv3) as max_date
while your error has:
(PARTITION by kd_akun_lv3)
So, if the query you supplied is correct, that isn't what is being run - and you are possibly testing some older sql. Not sure what your environment is, but perhaps something needs refreshing...
I need to order rows in MySQL and assign a number to each row according to that order. ORDER BY is working as intended but not ROW_NUMBER().
This works:
USE my_database;
SELECT
id
,volume
FROM my_table
ORDER BY volume;
This does not work:
USE my_database;
SELECT
id
,volume
,ROW_NUMBER() over(ORDER BY volume)
FROM my_table
ORDER BY volume;
I get this error message:
SELECT id ,volume ,ROW_NUMBER() over(ORDER BY volume) FROM my_table ORDER BY volume Error Code: 1064. You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '(ORDER BY volume) FROM my_table ORDER BY vol' at line 4 0.000 sec
What am I doing wrong and how do I make it work?
I also tried RANK() and DENSE_RANK() which gives the same problem.
There are no such things as ROW_NUMBER() or RANK() in MySQL. Try the following :
USE my_database;
SET #row_number = 0;
SELECT id
, volume
, #row_number := #row_number + 1 AS rank
FROM my_table
ORDER BY volume;
The function ROW_NUMBER() does not exist in MySQL.
However, you can replicate it, possibly: http://www.mysqltutorial.org/mysql-row_number/
The row_number is a ranking function that returns a sequential number
of a row, starting from 1 for the first row. We often want to use the
row_number function to produce the specific reports we need.
Unfortunately, MySQL does not provide row_number like Microsoft SQL
Server and Oracle. However, in MySQL, you can use session variables to
emulate the row_number function.
example:
SET #row_number = 0;
SELECT
(#row_number:=#row_number + 1) AS num, firstName, lastName
FROM
employees
LIMIT 5;
MySQL introduced the ROW_NUMBER() function since version 8.0.