How to query multiplte row in one json object - mysql

Question

table provider
table provider_properties
here I wanted the result something like
{
"provider_uuid": "b897f790-ee90-4869-9345-690380b1a0c9",
"name": "Provider 1",
"password": "112233",
"username": "provider_1",
"properties": {
"address_1": "Dubai",
"address_2": "NY"
}
}
here i tried something like
SELECT provider.*, json_object(provider_properties.key_name, provider_properties.key_value) as properties FROM provider JOIN provider_properties on provider.provider_id = provider_properties.provider_uuid;
but the problem is i am getting 2 rows

Answer 1

Since your expected results need specific formatting in json. You want to refer to JSON Formatted output. This is for shell though.
You might also want to try this...
This would give you a tabular results but in one row.
SELECT
provider.*,
p_props.properties
FROM provider
JOIN (
provider_uuid,
SELECT JSON_OBJECTAGG(
provider_properties.key_name,
provider_properties.key_value
) as properties
FROM provider_properties
GROUP BY provider_uuid
) p_props ON provider.provider_id = p_props.provider_uuid;

Answer 2

CONCAT() and REPLACE() here are used for sorting the order of columns.
I would say the use of REPLACE() here is quite risky, please test it out and see how it goes.
db<>fiddle
SELECT
p.*,
CONCAT(
'{"', 'provider_uuid": "', pp.provider_uuid, '"',
REPLACE(JSON_OBJECT('name', p.name, 'password', p.password,
'username', p.username, 'properties', pp.name_value), '{"name', ', "name')
) AS your_json
FROM provider p
JOIN (
SELECT provider_uuid, JSON_OBJECTAGG(key_name, key_value) as name_value
FROM provider_properties
GROUP BY provider_uuid
) pp ON p.provider_id = pp.provider_uuid;