How to update by Ignoring null values in mysql - mysql

Question

I have my data like this,
Heading
& I want output in
Name Gender Salary
Sam M 3.45
Priya F 4.02
Please help me out.
thank you.

Answer 1

This is not a practical scenario. At least you must have a Order by column or a sequence number to manage your data set. but try something like this. Most probably, **Order by** cause you many issues wile you working with the real data set.
CREATE TEMPORARY TABLE t_names
SELECT ROW_NUMBER() OVER ( ORDER BY NAME) rowid, NAME FROM Heading
WHERE NAME IS NOT NULL;
CREATE TEMPORARY TABLE t_gender
SELECT ROW_NUMBER() OVER ( ORDER BY NAME) rowid, gender FROM Heading
WHERE gender IS NOT NULL;
CREATE TEMPORARY TABLE t_salary
SELECT ROW_NUMBER() OVER ( ORDER BY NAME) rowid, salary FROM Heading
WHERE salary IS NOT NULL;
SELECT nm.name, tg.gender, sl.salary FROM t_names nm
INNER JOIN t_gender tg ON tg.rowid = nm.rowid
INNER JOIN t_salary sl ON sl.rowid = nm.rowid
what i given you is a suggestion for your scenario. But if this is a real world scenario, better to discuss this with your team and bring up a good structure for the table with Primary key, sequence number for the table.
at least add a new column as and set it as a identity column, and then it will create a sequence for your table.
if you created a sequence number as i explained you, then there is a 99% possibility to retrieve your exact result set
CREATE TEMPORARY TABLE t_names
SELECT ROW_NUMBER() OVER ( ORDER BY seq) rowid, NAME FROM Heading
WHERE NAME IS NOT NULL;
CREATE TEMPORARY TABLE t_gender
SELECT ROW_NUMBER() OVER ( ORDER BY seq) rowid, gender FROM Heading
WHERE gender IS NOT NULL;
CREATE TEMPORARY TABLE t_salary
SELECT ROW_NUMBER() OVER ( ORDER BY seq) rowid, salary FROM Heading
WHERE salary IS NOT NULL;
SELECT nm.name, tg.gender, sl.salary FROM t_names nm
INNER JOIN t_gender tg ON tg.rowid = nm.rowid
INNER JOIN t_salary sl ON sl.rowid = nm.rowid