Robot Framework bypass HTTPError: 400 Client Error: Bad Request - json

I have a request which tend to upload a file, if a file with the same name already exists it throws a message that the file already exists. This can be considered as expected result and even though the error I would the test to pass as it is.
This is the code I am using:
Create Session mysession ${test_env}
&{headers} Create Dictionary Content-Type=application/json; charset=utf-8 Authorization=${token}
${json}= Catenate { "FileName": "File.txt", "Content": "PD94bWwg..", "UserId": "email.com" }
${value} Set Variable 2
${value} Convert To Integer ${value}
${json}= Evaluate json.loads('''${json}''') json
#Set To Dictionary ${json["FileName"]}
${json}= Evaluate json.dumps(${json}) json
${resp} POST url=${test_env}/api/nt data=${json} headers=${headers}
${log}= Log To Console ${resp.status_code} 400
Log To Console ${resp.content}
Status Should Be expected_status=any
The test stops at the POST request and does not want to read the expected_status=any and consider the test as pass.
I would appreciate any hints on how to make it pass.

Below code will verify the 400 error and will continue further execution
Run Keyword And Expect Error HTTPError: 400* POST url=${test_env}/api/nt data=${json} headers=${headers}

Related

I can't use Get Value From Json with JsonPAth parameter in Robot Framework - always have a KeyError

When I try to use "Get Value From Json" on a Json with specific JsonPath , I always have KeyError
even web simple example doesn't work for me...
When I try that code :
Library JSONLibrary
*** Test Cases ***
Example
${tmp} = Convert String To JSON {"foo": {"bar": [1,2,3]}}
Log to console tmp: ${tmp}
${values_test}= Get Value From Json ${tmp} $.foo.bar
Log to console values_test: ${values_test}
I always have this kind of Errors and log :
tmp: {'foo': {'bar': [1, 2, 3]}}
...
Resolving variable '${tmp['$.foo.bar']}' failed: KeyError: '$.foo.bar'
Can somebody Help me please ?
it is really basic example by the way and community always says that it works like that in comments..

Parse JSON with missing fields using cjson Lua module in Openresty

I am trying to parse a json payload sent via a POST request to a NGINX/Openresty location. To do so, I combined Openresty's content_by_lua_block with its cjson module like this:
# other locations above
location /test {
content_by_lua_block {
ngx.req.read_body()
local data_string = ngx.req.get_body_data()
local cjson = require "cjson.safe"
local json = cjson.decode(data_string)
local endpoint_name = json['endpoint']['name']
local payload = json['payload']
local source_address = json['source_address']
local submit_date = json['submit_date']
ngx.say('Parsed')
}
}
Parsing sample data containing all required fields works as expected. A correct JSON object could look like this:
{
"payload": "the payload here",
"submit_date": "2018-08-17 16:31:51",
},
"endpoint": {
"name": "name of the endpoint here"
},
"source_address": "source address here",
}
However, a user might POST a differently formatted JSON object to the location. Assume a simple JSON document like
{
"username": "JohnDoe",
"password": "password123"
}
not containing the desired fields/keys.
According to the cjson module docs, using cjson (without its safe mode) will raise an error if invalid data is encountered. To prevent any errors being raised, I decided to use its safe mode by importing cjson.safe. This should return nil for invalid data and provide the error message instead of raising the error:
The cjson module will throw an error during JSON conversion if any invalid data is encountered. [...]
The cjson.safe module behaves identically to the cjson module, except when errors are encountered during JSON conversion. On error, the cjson_safe.encode and cjson_safe.decode functions will return nil followed by the error message.
However, I do not encounter any different error handling behavior in my case and the following traceback is shown in Openresty's error.log file:
2021/04/30 20:33:16 [error] 6176#6176: *176 lua entry thread aborted: runtime error: content_by_lua(samplesite:50):16: attempt to index field 'endpoint' (a nil value)
Which in turn results in an Internal Server Error:
<html>
<head><title>500 Internal Server Error</title></head>
<body>
<center><h1>500 Internal Server Error</h1></center>
<hr><center>openresty</center>
</body>
</html>
I think a workaround might be writing a dedicated function for parsing the JSON data and calling it with pcall() to catch any errors. However, this would make the safe mode kind of useless. What am I missing here?
Your “simple JSON document” is a valid JSON document. The error you are facing is not related to cjson, it's a standard Lua error:
resty -e 'local t = {foo = 1}; print(t["foo"]); print(t["foo"]["bar"])'
1
ERROR: (command line -e):1: attempt to index field 'foo' (a number value)
stack traceback:
...
“Safeness” of cjson.safe is about parsing of malformed documents:
cjson module raises an error:
resty -e 'print(require("cjson").decode("[1, 2, 3"))'
ERROR: (command line -e):1: Expected comma or array end but found T_END at character 9
stack traceback:
...
cjson.safe returns nil and an error message:
resty -e 'print(require("cjson.safe").decode("[1, 2, 3"))'
nilExpected comma or array end but found T_END at character 9

__init__() got an unexpected keyword argument 'content_type' while dumping the response with application/json type in Django

Following are snippet :
record = {'polno':1,'custname':'abc','poltype':'TW'}
resp =json.dumps(record,content_type="application/json")
-->Got the error
json.dumps doesn't have a content_type argument. See the function's signature.
Just use json.dumps(record)

I m trying to use 'ffprobe' with Java or groovy

As per my understanding "ffprobe" will provide file related data in JSON format. So, I have installed the ffprobe in my Ubuntu machine but I don't know how to access the ffprobe JSON response using Java/Grails.
Expected response format:
{
"format": {
"filename": "/Users/karthick/Documents/videos/TestVideos/sample.ts",
"nb_streams": 2,
"nb_programs": 1,
"format_name": "mpegts",
"format_long_name": "MPEG-TS (MPEG-2 Transport Stream)",
"start_time": "1.430800",
"duration": "170.097489",
"size": "80425836",
"bit_rate": "3782576",
"probe_score": 100
}
}
This is my groovy code
def process = "ffprobe -v quiet -print_format json -show_format -show_streams HelloWorld.mpeg ".execute()
println "Found ${process.text}"
render process as JSON
I m able to get the process object and i m not able to get the json response
Should i want to convert the process object to json object?
OUTPUT:
Found java.lang.UNIXProcess#75566697
org.codehaus.groovy.grails.web.converters.exceptions.ConverterException: Error converting Bean with class java.lang.UNIXProcess
Grails has nothing to do with this. Groovy can execute arbitrary shell commands in a very simplistic way:
"mkdir foo".execute()
Or for more advanced features, you might look into using ProcessBuilder. At the end of the day, you need to execute ffprobe and then capture the output stream of JSON to use in your app.
Groovy provides a simple way to execute command line processes. Simply
write the command line as a string and call the execute() method.
The execute() method returns a java.lang.Process instance.
println "ffprobe <options>".execute().text
[Source]

Json parse error using POST in django rest api

I am trying to implement a simple GET/POST api via Django REST framework
views.py
class cuser(APIView):
def post(self, request):
stream = BytesIO(request.DATA)
json = JSONParser().parse(stream)
return Response()
urls.py
from django.conf.urls import patterns, url
from app import views
urlpatterns = patterns('',
url(r'^challenges/',views.getall.as_view() ),
url(r'^cuser/' , views.cuser.as_view() ),
)
I am trying to POST some json to /api/cuser/ (api is namespace in my project's urls.py ) ,
the JSON
{
"username" : "abhishek",
"email" : "john#doe.com",
"password" : "secretpass"
}
I tried from both Browseable API page and httpie ( A python made tool similar to curl)
httpie command
http --json POST http://localhost:58601/api/cuser/ username=abhishek email=john#doe.com password=secretpass
but I am getting JSON parse error :
JSON parse error - Expecting property name enclosed in double quotes: line 1 column 2 (char 1)
Whole Debug message using --verbose --debug
POST /api/cuser/ HTTP/1.1
Content-Length: 75
Accept-Encoding: gzip, deflate
Host: localhost:55392
Accept: application/json
User-Agent: HTTPie/0.8.0
Connection: keep-alive
Content-Type: application/json; charset=utf-8
{"username": "abhishek", "email": "john#doe.com", "password": "aaezaakmi1"}
HTTP/1.0 400 BAD REQUEST
Date: Sat, 24 Jan 2015 09:40:03 GMT
Server: WSGIServer/0.1 Python/2.7.9
Vary: Accept, Cookie
Content-Type: application/json
Allow: POST, OPTIONS
{"detail":"JSON parse error - Expecting property name enclosed in double quotes: line 1 column 2 (char 1)"}
The problem that you are running into is that your request is already being parsed, and you are trying to parse it a second time.
From "How the parser is determined"
The set of valid parsers for a view is always defined as a list of classes. When request.data is accessed, REST framework will examine the Content-Type header on the incoming request, and determine which parser to use to parse the request content.
In your code you are accessing request.DATA, which is the 2.4.x equaivalent of request.data. So your request is being parsed as soon as you call that, and request.DATA is actually returning the dictionary that you were expecting to parse.
json = request.DATA
is really all you need to parse the incoming JSON data. You were really passing a Python dictionary into json.loads, which does not appear to be able to parse it, and that is why you were getting your error.
I arrived at this post via Google for
"detail": "JSON parse error - Expecting property name enclosed in double-quotes":
Turns out you CANNOT have a trailing comma in JSON.
So if you are getting this error you may need to change a post like this:
{
"username" : "abhishek",
"email" : "john#doe.com",
"password" : "secretpass",
}
to this:
{
"username" : "abhishek",
"email" : "john#doe.com",
"password" : "secretpass"
}
Note the removed comma after the last property in the JSON object.
Basically, whenever you are trying to make a post request with requests lib, This library also contains json argument which is ignored in the case when data argument is set to files or data. So basically when json argument is set with json data. Headers are set asContent-Type: application/json. Json argument basically encodes data sends into a json format. So that at DRF particularly is able to parse json data. Else in case of only data argument it is been treated as form-encoded
requests.post(url, json={"key1":"value1"})
you can find more here request.post complicated post methods