I've made this ER diagram for my college project but i have to use forward engineering to see SQL code. MySQL version is 8.0.27
when i try it, it come up with error like below.
Executing SQL script in server
ERROR: Error 3734: Failed to add the foreign key constraint. Missing column 'editor_ismi' for constraint 'fk_editor_ismi' in the referenced table 'editor'
SQL Code:
-- -----------------------------------------------------
-- Table `mydb`.`kitap`
-- -----------------------------------------------------
CREATE TABLE IF NOT EXISTS `mydb`.`kitap` (
`isbn` VARCHAR(45) NOT NULL,
`editor_ismi` VARCHAR(45) NULL,
`yazar_ismi` VARCHAR(45) NULL,
`yazar_adres` VARCHAR(45) NULL,
`kitap_yili` INT NOT NULL,
`kitap_baslik` VARCHAR(45) NOT NULL,
`kitap_fiyat` VARCHAR(45) NOT NULL,
PRIMARY KEY (`isbn`),
INDEX `fk_editor_ismi_idx` (`editor_ismi` ASC) VISIBLE,
INDEX `fk_yazar_ismi_idx` (`yazar_ismi` ASC) VISIBLE,
INDEX `fk_yazar_adres_idx` (`yazar_adres` ASC) VISIBLE,
CONSTRAINT `fk_editor_ismi`
FOREIGN KEY (`editor_ismi`)
REFERENCES `mydb`.`editor` (`editor_ismi`)
ON DELETE NO ACTION
ON UPDATE NO ACTION,
CONSTRAINT `fk_yazar_ismi`
FOREIGN KEY (`yazar_ismi`)
REFERENCES `mydb`.`Yazar` (`yazar_ismi`)
ON DELETE NO ACTION
ON UPDATE NO ACTION,
CONSTRAINT `fk_yazar_adres`
FOREIGN KEY (`yazar_adres`)
REFERENCES `mydb`.`Yazar` (`yazar_ismi`)
ON DELETE NO ACTION
ON UPDATE NO ACTION)
ENGINE = InnoDB
SQL script execution finished: statements: 7 succeeded, 1 failed
Fetching back view definitions in final form.
Nothing to fetch
screenshot of my er diagram
Related
I'm having trouble with forwarding database to server. Here's log:
Executing SQL script in server
ERROR: Error 3780: Referencing column 'id_users' and referenced column 'id_users' in foreign key constraint 'fk_watch_later_users1' are incompatible.
SQL Code:
Table mydb.watch_later
CREATE TABLE IF NOT EXISTS `mydb`.`watch_later` (
`id_wl` INT NOT NULL,
`id_users` INT NULL,
`id_films` INT NULL,
PRIMARY KEY (`id_wl`),
UNIQUE INDEX `id_wl_UNIQUE` (`id_wl` ASC) VISIBLE,
INDEX `fk_watch_later_films1_idx` (`id_films` ASC) VISIBLE,
INDEX `fk_watch_later_users1_idx` (`id_users` ASC) VISIBLE,
CONSTRAINT `fk_watch_later_films1`
FOREIGN KEY (`id_films`)
REFERENCES `mydb`.`films` (`id_films`)
ON DELETE NO ACTION
ON UPDATE NO ACTION,
CONSTRAINT `fk_watch_later_users1`
FOREIGN KEY (`id_users`)
REFERENCES `mydb`.`users` (`id_users`)
ON DELETE NO ACTION
ON UPDATE NO ACTION)
ENGINE = InnoDB
SQL script execution finished: statements: 15 succeeded, 1 failed
Fetching back view definitions in final form.
Nothing to fetch
Table mydb.users:
CREATE TABLE IF NOT EXISTS `mydb`.`users` (
`id_users` INT NOT NULL,
`users_nickname` VARCHAR(45) NULL,
`users_name` VARCHAR(45) NULL,
`users_surname` VARCHAR(45) NULL,
`users_birth` DATE NULL,
PRIMARY KEY (`id_users`),
UNIQUE INDEX `id_users_UNIQUE` (`id_users` ASC) VISIBLE
) ENGINE = InnoDB;
Tell me please how can I fix it? MySQL version is 8.0.18
I'm trying to forward engineer an ER diagram in Workbench to create my schema and I'm getting an error. I'm using mySql Workbench for mac.
This is the Error message I'm getting:
Executing SQL script in server
ERROR: Error 1064: You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near '
INDEX `city_id_fk_idx` (`city_id` ASC) VISIBLE,
INDEX `county_id_idx` (`cou' at line 13
SQL Code:
-- -----------------------------------------------------
-- Table `k00243666_property_bubble`.`addresses`
-- -----------------------------------------------------
CREATE TABLE IF NOT EXISTS `k00243666_property_bubble`.`addresses` (
`address_id` INT NOT NULL AUTO_INCREMENT,
`address1` VARCHAR(45) NULL,
`address2` VARCHAR(45) NULL,
`eircode` VARCHAR(7) NULL,
`town_id` INT NULL,
`city_id` INT NULL,
`county_id` INT NULL,
PRIMARY KEY (`address_id`),
INDEX `town_id_fk_idx` (`town_id` ASC) VISIBLE,
INDEX `city_id_fk_idx` (`city_id` ASC) VISIBLE,
INDEX `county_id_idx` (`county_id` ASC) VISIBLE,
CONSTRAINT `town_id_fk`
FOREIGN KEY (`town_id`)
REFERENCES `k00243666_property_bubble`.`town` (`town_id`)
ON DELETE NO ACTION
ON UPDATE CASCADE,
CONSTRAINT `city_id_fk`
FOREIGN KEY (`city_id`)
REFERENCES `k00243666_property_bubble`.`city` (`city_id`)
ON DELETE NO ACTION
ON UPDATE CASCADE,
CONSTRAINT `county_id`
FOREIGN KEY (`county_id`)
REFERENCES `k00243666_property_bubble`.`county` (`county_id`)
ON DELETE NO ACTION
ON UPDATE CASCADE)
ENGINE = InnoDB
SQL script execution finished: statements: 5 succeeded, 1 failed
Fetching back view definitions in final form.
Nothing to fetch
Does anyone know why i'm getting this error?
My guess is that your version of MariaDB does not support VISIBLE or INVISIBLE as applied to an index definition. In any case, indices should be visible by default, so you should not even need to specify VISIBLE. Try using this syntax:
INDEX town_id_fk_idx (town_id),
INDEX city_id_fk_idx (city_id),
INDEX county_id_idx (county_id)
Here is a link to a feature request which was made to MariaDB. There does not appear to an INVISIBLE syntax for turning off indices to the optimizer. However, it presents an alternative:
ALTER TABLE addresses DISABLE KEYS;
This would make all indices invisible to the optimizer.
Executing SQL script in server
ERROR: Error 1022: Can't write; duplicate key in table 'dependent'
SQL Code:
-- -----------------------------------------------------
-- Table `mydb`.`DEPENDENT`
-- -----------------------------------------------------
CREATE TABLE IF NOT EXISTS `mydb`.`DEPENDENT` (
`Essn` CHAR(9) NOT NULL,
`Dependent_name` VARCHAR(45) NOT NULL,
`Sex` CHAR NULL,
`Bdate` DATE NULL,
`Relationship` VARCHAR(45) NULL,
PRIMARY KEY (`Dependent_name`, `Essn`),
CONSTRAINT `Essn`
FOREIGN KEY (`Essn`)
REFERENCES `mydb`.`EMPLOYEE` (`Ssn`)
ON DELETE NO ACTION
ON UPDATE NO ACTION)
ENGINE = InnoDB
SQL script execution finished: statements: 10 succeeded, 1 failed
Fetching back view definitions in final form.
Nothing to fetch`enter code here`
Am getting this error. Can some one help me on this. Thanks
hi you have primary key defined on the Dependent_name if you try to insert same name 2 times you will get error So you have to define other primary key if you expect duplicate name a common approach id to use auto increment column as primary key but you can define composite keys as well for primary key
I am trying to forward engineer a database on MySQL Workbench, but I continually am getting this error message. I feel as though it is most likely an issue with the structure of my relationships, but I cannot find a discrepancy.
Here is an image of the schema diagram.
Here is the error message I am receiving:
Executing SQL script in server
ERROR: Error 1215: Cannot add foreign key constraint
SQL Code:
-- -----------------------------------------------------
-- Table `bturpin`.`THREAD`
-- -----------------------------------------------------
CREATE TABLE IF NOT EXISTS `bturpin`.`THREAD` (
`id` INT NOT NULL AUTO_INCREMENT,
`answer` DOUBLE NULL,
`comment` VARCHAR(255) NULL,
`test_subcategory_name` VARCHAR(45) NULL,
`RATING_id` INT NOT NULL,
`RATING_INSTRUCTOR_id` VARCHAR(30) NOT NULL,
`RATING_INSTRUCTOR_LESSON_title` VARCHAR(45) NOT NULL,
`RATING_INSTRUCTOR_LESSON_COURSE_num` VARCHAR(15) NOT NULL,
`RATING_RATER_id` VARCHAR(30) NOT NULL,
PRIMARY KEY (`id`, `RATING_id`, `RATING_INSTRUCTOR_id`, `RATING_INSTRUCTOR_LESSON_title`, `RATING_INSTRUCTOR_LESSON_COURSE_num`, `RATING_RATER_id`),
INDEX `fk_THREAD_RATING1_idx` (`RATING_id` ASC, `RATING_INSTRUCTOR_id` ASC, `RATING_INSTRUCTOR_LESSON_title` ASC, `RATING_INSTRUCTOR_LESSON_COURSE_num` ASC, `RATING_RATER_id` ASC),
CONSTRAINT `fk_THREAD_RATING1`
FOREIGN KEY (`RATING_id` , `RATING_INSTRUCTOR_id` , `RATING_INSTRUCTOR_LESSON_title` , `RATING_INSTRUCTOR_LESSON_COURSE_num` , `RATING_RATER_id`)
REFERENCES `bturpin`.`RATING` (`id` , `INSTRUCTOR_id` , `INSTRUCTOR_LESSON_title` , `INSTRUCTOR_LESSON_COURSE_num` , `RATER_id`)
ON DELETE NO ACTION
ON UPDATE NO ACTION)
ENGINE = InnoDB
SQL script execution finished: statements: 14 succeeded, 1 failed
Fetching back view definitions in final form.
Nothing to fetch
Try forwarding in this order :
Manually create the fields which must have a foreign key constraint in MySQL WB
Forward engineer to your DB
Manually create the foreign key constraints in MySQL WB
Forward engineer angain
You may also consider using only integer foreign key.
This seems to be a MySQL Workbench issue with foreign key on non integer key.
Source : Error 1215: Cannot add foreign key constraint
I have been using mySQL to create a database but when I try to forward engineer my EER Diagram the database keeps sending me back the same error I have tried multiple fixes does anyone see what the problem is? The error code is 1215
Executing SQL script in server
ERROR: Error 1215: Cannot add foreign key constraint
SQL Code:
-- -----------------------------------------------------
-- Table `mydb`.`Employee`
-- -----------------------------------------------------
CREATE TABLE IF NOT EXISTS `mydb`.`Employee` (
`EID` INT NOT NULL,
`Fname` VARCHAR(45) NOT NULL,
`Lname` VARCHAR(45) NOT NULL,
`AddressID` INT NOT NULL,
`PayLevel` FLOAT NOT NULL,
`Jobtitle` VARCHAR(45) NOT NULL,
`Date of Employment` DATE NOT NULL,
PRIMARY KEY (`EID`),
CONSTRAINT `fk_Employee_Store1`
FOREIGN KEY (`EID`)
REFERENCES `mydb`.`Store` (`EID`)
ON DELETE NO ACTION
ON UPDATE NO ACTION)
ENGINE = InnoDB
SQL script execution finished: statements: 8 succeeded, 1 failed
Fetching back view definitions in final form.
Nothing to fetch
This is the parent code, multiple times I have tried switching the relationships however employee9the top code) should be a child of Store.
-- -----------------------------------------------------
-- Table `mydb`.`Store`
-- -----------------------------------------------------
CREATE TABLE IF NOT EXISTS `mydb`.`Store` (
`SID` INT NOT NULL,
`StoreName` VARCHAR(45) NULL,
`AddressID` INT NULL,
`EID` INT NOT NULL,
`CID` INT NULL,
`MID` INT NULL,
PRIMARY KEY (`SID`, `EID`),
INDEX `fk_Store_Employee1_idx` (`EID` ASC),
CONSTRAINT `fk_Store_Employee1`
FOREIGN KEY (`EID`)
REFERENCES `mydb`.`Employee` (`EID`)
ON DELETE NO ACTION
ON UPDATE NO ACTION)
ENGINE = InnoDB;
Does anyone see the problem, Btw I have checked the type's multiple times they are equivalent.
you are trying to create a foreign key in store from employee and another one in employee from store.
if this is a parent/child relation then only the primary key from the parent that is used in the child.
if you have n<->n relation then you need a new table that holds both foreign keys.
if I understand, here you need to have a new table (work) with (SID, EID) where both point to their respective tables (store and employee). Also creation order is important (parents first then child tables).
You have a foreign key constraint operating in both directions. When you're creating the tables the first to be created will fail because the second doesn't exist. I'm not even sure that MySQL will accept a circular reference like this. You should probably remove the foreign key constraint applied to mydb.store
However, if this is essential you can ask MySQL to ignore the foreign key checks while you create the table. Just execute
SET foreign_key_checks = 0;
before you create the tables and
SET foreign_key_checks = 1;
after you finish