Cast Complex JSON Dart - json

Question

the dart code below allows you to decode a json that comes from a backend inside resultValue, I have the response of the rest call with the json shown below, when I go to create the list with the values I have the following error, to what is due? how do i fix it?
JSON Link
Error:
//Line: return data.map((jsonObject) => new Manutenzione(
flutter: Errore: type 'List<String>'
is not a subtype of type 'String' in type cast
Dart code:
var urlmod = await Storage.leggi("URL") + "/services/rest/v3/processes/PreventiveMaint/instances";
final resultValue = await apiRequest(Uri.parse(urlmod), {}, UrlRequest.GET, true);
Map<String, dynamic> map = json.decode(resultValue);
List<dynamic> data = map["data"];
try {
return data
.map((jsonObject) => new Manutenzione(
["_id"] as String,
["_user"] as String,
["__user_description"] as String,
["Description"] as String,
["ShortDescr"] as String,
["_Site_description"] as String,
["_Team_description"] as String,
["_status_description"] as String,
["_Company_description"] as String,
))
.toList();
} catch (err) {
print("Errore: " + err.toString());
}
return List.empty();
}
JSON:
{
...
data: [
{
_id: value1,
_user: value2,
..
},
{
_id: value1,
_user: value2,
..
},
]
}

Answer 1

You forgot to specify jsonObject before the square brackets.
var urlmod = await Storage.leggi("URL") + "/services/rest/v3/processes/PreventiveMaint/instances";
final resultValue = await apiRequest(Uri.parse(urlmod), {}, UrlRequest.GET, true);
Map<String, dynamic> map = json.decode(resultValue);
List<dynamic> data = map["data"];
try {
return data
.map((jsonObject) => new Manutenzione(
jsonObject["_id"] as String,
jsonObject["_user"] as String,
jsonObject["__user_description"] as String,
jsonObject["Description"] as String,
jsonObject["ShortDescr"] as String,
jsonObject["_Site_description"] as String,
jsonObject["_Team_description"] as String,
jsonObject["_status_description"] as String,
jsonObject["_Company_description"] as String,
))
.toList();
} catch (err) {
print("Errore: " + err.toString());
}
return List.empty();
}