SUBSTRING_INDEX get nth value - mysql

I have this code:
SET #startEndTimeCapacity = "'00:00:00', '08:00:00', 120";
SELECT SUBSTRING_INDEX(#startEndTimeCapacity, ",", 2);
results in '00:00:00', '08:00:00'.
How can I get the 2nd value '08:00:00' only?


You can apply the SUBSTRING_INDEX function twice:
for splitting at the nth value
for retrieving the last value in the previous list
Here's how:
SUBSTRING_INDEX(SUBSTRING_INDEX(#startEndTimeCapacity, ",", 2), ',', -1);
This works for any n. In this specific case n=2.

Related

mysql replace a character with another

I have a table with some values like below,
Slno
---------
IFAAA1121
IFAAA1122
IMBBB1121
IMBBB11223
My goal is to reformat the SlNo in to the below format,
Slno
---------
IF-AAA-1121
IF-AAA-1122
IM-BBB-1121
IM-BBB-11223
How is it possible ?
My query is:
UPDATE `certificate_log_uae`
SET `DeviceSerialNumberTemp` = REPLACE(LEFT(DeviceSerialNumberTemp,2),
LEFT(DeviceSerialNumberTemp,2).'-')

You can use the Substr() function to get substrings out from your input string, at various positions and lengths.
Since the length of the last substring is not fixed; we can simply specify the start position to slice the substring, and leave specifying the length parameter. It will consider the substring till the end of the overall string.
Now, just concatenate this substrings back using - appropriately.
Try the following:
UPDATE `certificate_log_uae`
SET `DeviceSerialNumberTemp` = CONCAT(SUBSTR(`DeviceSerialNumberTemp`, 1, 2),
'-',
SUBSTR(`DeviceSerialNumberTemp`, 3, 3),
'-',
SUBSTR(`DeviceSerialNumberTemp`, 6)
)

One approach would be to just build the final string you want using concatenation:
UPDATE certificate_log_uae
SET DeviceSerialNumberTemp = CONCAT(LEFT(DeviceSerialNumberTemp, 2),
'-',
SUBSTRING(DeviceSerialNumberTemp, 3, 3),
'-',
SUBSTRING(DeviceSerialNumberTemp, 6));
Demo
If you are using MySQL 8+ or later, then there is a very simple regex based solution using REGEXP_REPLACE:
SELECT
DeviceSerialNumberTemp,
REGEXP_REPLACE(DeviceSerialNumberTemp, '(.{2})(.{3})(.*)', '$1-$2-$3') AS output
FROM certificate_log_uae;
Demo

Try simple insert function:
select Slno, insert(insert(slno, 3, 0, '-'), 7, 0, '-') from tbl
Demo
To update values try:
update certificate_log_uae set
DeviceSerialNumberTemp = insert(insert(DeviceSerialNumberTemp , 3, 0, '-'), 7, 0, '-')

How can I get multiple values from string using SUBSTRING_INDEX()

I have a table where I extract some values, one column values can contain
'FLSD202-D-B-D-AB-C1-NN-A-N-LA-J-NN/UM/H7/SCT'
I want to split them become
FLSD202 AS first column
-D-B-D-AB-C1-NN-A-N-LA-J-NN AS Second column
/UM/H7/SCT AS third column
here my script but i can't get the result as i want
SELECT 'FLSD202-D-B-D-AB-C1-NN-A-N-LA-J-NN/UM/H7/SCT', SUBSTRING_INDEX(SUBSTRING_INDEX('FLXA202-D-B-D-AB-C1-NN-A-N-LA-J-NN/UM/H7/SCT', '-',1), '-', -1) FirstColumn,
CONCAT('-', SUBSTRING_INDEX(SUBSTRING_INDEX(SUBSTRING_INDEX('FLSD202-D-B-D-AB-C1-NN-A-N-LA-J-NN/UM/H7/SCT', '/',1), '/', -1), '-',-1)) SecondColumn,
CONCAT('/', SUBSTRING_INDEX(SUBSTRING_INDEX('FLSD202-D-B-D-AB-C1-NN-A-N-LA-J-NN/UM/H7/SCT', '/',3), '/', -1)) ThirdColumn
I want to use this for ALL values, not just one field..
And the '-'(dash) is dynamic and '/'(slash) is dynamic, ex :
SSS145-SS3/POP, KEEE-CDE0/NO/SA, WXAE-C-D/E/G, SAD-SEU-SFX/OPS
Thanks

I think below code will help you to complete your requirement.
SET #a = 'FLSD202-D-B-D-AB-C1-NN-A-N-LA-J-NN/UM/H7/SCT';
SET #dash_start_position = LOCATE('-',#a);
SET #slash_start_position = LOCATE('/',#a);
SELECT SUBSTRING(#a, 1, #dash_start_position-1) as First, IF(#slash_start_position IS NOT NULL AND #slash_start_position > 0, SUBSTRING(#a, #dash_start_position, #slash_start_position - #dash_start_position), SUBSTRING(#a, #dash_start_position)) as Second,SUBSTRING(#a, #slash_start_position) as Third;

alternative to splitting MySQL query result in multiple rows [duplicate]

I have a column that has comma separated data:
1,2,3
3,2,1
4,5,6
5,5,5
I'm trying to run a search that would query each value of the CSV string individually.
0<first<5 and 1<second<3 and 2<third<4
I get that I could return all queries and split it myself and compare it myself. I'm curious if there is a way to do this so MySQL does that processing work.
Thanks!

Use
substring_index(`column`,',',1) ==> first value
substring_index(substring_index(`column`,',',-2),',',1)=> second value
substring_index(substring_index(`column`,',',-1),',',1)=> third value
in your where clause.
SELECT * FROM `table`
WHERE
substring_index(`column`,',',1)<0
AND
substring_index(`column`,',',1)>5

It seems to work:
substring_index ( substring_index ( context,',',1 ), ',', -1)
substring_index ( substring_index ( context,',',2 ), ',', -1)
substring_index ( substring_index ( context,',',3 ), ',', -1)
substring_index ( substring_index ( context,',',4 ), ',', -1)
it means 1st value, 2nd, 3rd, etc.
Explanation:
The inner substring_index returns the first n values that are comma separated. So if your original string is "34,7,23,89", substring_index( context,',', 3) returns "34,7,23".
The outer substring_index takes the value returned by the inner substring_index and the -1 allows you to take the last value. So you get "23" from the "34,7,23".
Instead of -1 if you specify -2, you'll get "7,23", because it took the last two values.
Example:
select * from MyTable where substring_index(substring_index(prices,',',1),',',-1)=3382;
Here, prices is the name of a column in MyTable.

Usually substring_index does what you want:
mysql> select substring_index("foo#gmail.com","#",-1);
+-----------------------------------------+
| substring_index("foo#gmail.com","#",-1) |
+-----------------------------------------+
| gmail.com |
+-----------------------------------------+
1 row in set (0.00 sec)

You may get what you want by using the MySQL REGEXP or LIKE.
See the MySQL Docs on Pattern Matching

As an addendum to this, I've strings of the form:
Some words 303
where I'd like to split off the numerical part from the tail of the string.
This seems to point to a possible solution:
http://lists.mysql.com/mysql/222421
The problem however, is that you only get the answer "yes, it matches", and not the start index of the regexp match.

Here is another variant I posted on related question. The REGEX check to see if you are out of bounds is useful, so for a table column you would put it in the where clause.
SET #Array = 'one,two,three,four';
SET #ArrayIndex = 2;
SELECT CASE
WHEN #Array REGEXP CONCAT('((,).*){',#ArrayIndex,'}')
THEN SUBSTRING_INDEX(SUBSTRING_INDEX(#Array,',',#ArrayIndex+1),',',-1)
ELSE NULL
END AS Result;
SUBSTRING_INDEX(string, delim, n) returns the first n
SUBSTRING_INDEX(string, delim, -1) returns the last only
REGEXP '((delim).*){n}' checks if there are n delimiters (i.e. you are in bounds)

Building on #Oleksiy's answer, here is one that can work with strings of variable segment lengths (within reasonable limits), for example comma-separated addresses:
SELECT substring_index ( substring_index ( address,',',1 ), ',', -1) AS address_line_1,
IF(address_parts > 1, substring_index ( substring_index ( address,',',2 ), ',', -1), '') AS address_line_2,
IF(address_parts > 2, substring_index ( substring_index ( address,',',3 ), ',', -1), '') AS address_line_3,
IF(address_parts > 3, substring_index ( substring_index ( address,',',4 ), ',', -1), '') AS address_line_4,
IF(address_parts > 4, substring_index ( substring_index ( address,',',5 ), ',', -1), '') AS address_line_5
FROM (
SELECT address, LENGTH(address) - LENGTH(REPLACE(address, ',', '')) AS address_parts
FROM mytable
) AS addresses

It's working..
SELECT SUBSTRING_INDEX(SUBSTRING_INDEX(SUBSTRING_INDEX(SUBSTRING_INDEX(SUBSTRING_INDEX(SUBSTRING_INDEX(SUBSTRING_INDEX(
SUBSTRING_INDEX(SUBSTRING_INDEX(SUBSTRING_INDEX(col,'1', 1), '2', 1), '3', 1), '4', 1), '5', 1), '6', 1)
, '7', 1), '8', 1), '9', 1), '0', 1) as new_col
FROM table_name group by new_col;

mysql split string [duplicate]

I have a column that has comma separated data:
1,2,3
3,2,1
4,5,6
5,5,5
I'm trying to run a search that would query each value of the CSV string individually.
0<first<5 and 1<second<3 and 2<third<4
I get that I could return all queries and split it myself and compare it myself. I'm curious if there is a way to do this so MySQL does that processing work.
Thanks!

Use
substring_index(`column`,',',1) ==> first value
substring_index(substring_index(`column`,',',-2),',',1)=> second value
substring_index(substring_index(`column`,',',-1),',',1)=> third value
in your where clause.
SELECT * FROM `table`
WHERE
substring_index(`column`,',',1)<0
AND
substring_index(`column`,',',1)>5

It seems to work:
substring_index ( substring_index ( context,',',1 ), ',', -1)
substring_index ( substring_index ( context,',',2 ), ',', -1)
substring_index ( substring_index ( context,',',3 ), ',', -1)
substring_index ( substring_index ( context,',',4 ), ',', -1)
it means 1st value, 2nd, 3rd, etc.
Explanation:
The inner substring_index returns the first n values that are comma separated. So if your original string is "34,7,23,89", substring_index( context,',', 3) returns "34,7,23".
The outer substring_index takes the value returned by the inner substring_index and the -1 allows you to take the last value. So you get "23" from the "34,7,23".
Instead of -1 if you specify -2, you'll get "7,23", because it took the last two values.
Example:
select * from MyTable where substring_index(substring_index(prices,',',1),',',-1)=3382;
Here, prices is the name of a column in MyTable.

Usually substring_index does what you want:
mysql> select substring_index("foo#gmail.com","#",-1);
+-----------------------------------------+
| substring_index("foo#gmail.com","#",-1) |
+-----------------------------------------+
| gmail.com |
+-----------------------------------------+
1 row in set (0.00 sec)

You may get what you want by using the MySQL REGEXP or LIKE.
See the MySQL Docs on Pattern Matching

As an addendum to this, I've strings of the form:
Some words 303
where I'd like to split off the numerical part from the tail of the string.
This seems to point to a possible solution:
http://lists.mysql.com/mysql/222421
The problem however, is that you only get the answer "yes, it matches", and not the start index of the regexp match.

Here is another variant I posted on related question. The REGEX check to see if you are out of bounds is useful, so for a table column you would put it in the where clause.
SET #Array = 'one,two,three,four';
SET #ArrayIndex = 2;
SELECT CASE
WHEN #Array REGEXP CONCAT('((,).*){',#ArrayIndex,'}')
THEN SUBSTRING_INDEX(SUBSTRING_INDEX(#Array,',',#ArrayIndex+1),',',-1)
ELSE NULL
END AS Result;
SUBSTRING_INDEX(string, delim, n) returns the first n
SUBSTRING_INDEX(string, delim, -1) returns the last only
REGEXP '((delim).*){n}' checks if there are n delimiters (i.e. you are in bounds)

Building on #Oleksiy's answer, here is one that can work with strings of variable segment lengths (within reasonable limits), for example comma-separated addresses:
SELECT substring_index ( substring_index ( address,',',1 ), ',', -1) AS address_line_1,
IF(address_parts > 1, substring_index ( substring_index ( address,',',2 ), ',', -1), '') AS address_line_2,
IF(address_parts > 2, substring_index ( substring_index ( address,',',3 ), ',', -1), '') AS address_line_3,
IF(address_parts > 3, substring_index ( substring_index ( address,',',4 ), ',', -1), '') AS address_line_4,
IF(address_parts > 4, substring_index ( substring_index ( address,',',5 ), ',', -1), '') AS address_line_5
FROM (
SELECT address, LENGTH(address) - LENGTH(REPLACE(address, ',', '')) AS address_parts
FROM mytable
) AS addresses

It's working..
SELECT SUBSTRING_INDEX(SUBSTRING_INDEX(SUBSTRING_INDEX(SUBSTRING_INDEX(SUBSTRING_INDEX(SUBSTRING_INDEX(SUBSTRING_INDEX(
SUBSTRING_INDEX(SUBSTRING_INDEX(SUBSTRING_INDEX(col,'1', 1), '2', 1), '3', 1), '4', 1), '5', 1), '6', 1)
, '7', 1), '8', 1), '9', 1), '0', 1) as new_col
FROM table_name group by new_col;

Can MySQL split a column?

I have a column that has comma separated data:
1,2,3
3,2,1
4,5,6
5,5,5
I'm trying to run a search that would query each value of the CSV string individually.
0<first<5 and 1<second<3 and 2<third<4
I get that I could return all queries and split it myself and compare it myself. I'm curious if there is a way to do this so MySQL does that processing work.
Thanks!

Use
substring_index(`column`,',',1) ==> first value
substring_index(substring_index(`column`,',',-2),',',1)=> second value
substring_index(substring_index(`column`,',',-1),',',1)=> third value
in your where clause.
SELECT * FROM `table`
WHERE
substring_index(`column`,',',1)<0
AND
substring_index(`column`,',',1)>5

It seems to work:
substring_index ( substring_index ( context,',',1 ), ',', -1)
substring_index ( substring_index ( context,',',2 ), ',', -1)
substring_index ( substring_index ( context,',',3 ), ',', -1)
substring_index ( substring_index ( context,',',4 ), ',', -1)
it means 1st value, 2nd, 3rd, etc.
Explanation:
The inner substring_index returns the first n values that are comma separated. So if your original string is "34,7,23,89", substring_index( context,',', 3) returns "34,7,23".
The outer substring_index takes the value returned by the inner substring_index and the -1 allows you to take the last value. So you get "23" from the "34,7,23".
Instead of -1 if you specify -2, you'll get "7,23", because it took the last two values.
Example:
select * from MyTable where substring_index(substring_index(prices,',',1),',',-1)=3382;
Here, prices is the name of a column in MyTable.

Usually substring_index does what you want:
mysql> select substring_index("foo#gmail.com","#",-1);
+-----------------------------------------+
| substring_index("foo#gmail.com","#",-1) |
+-----------------------------------------+
| gmail.com |
+-----------------------------------------+
1 row in set (0.00 sec)

You may get what you want by using the MySQL REGEXP or LIKE.
See the MySQL Docs on Pattern Matching

As an addendum to this, I've strings of the form:
Some words 303
where I'd like to split off the numerical part from the tail of the string.
This seems to point to a possible solution:
http://lists.mysql.com/mysql/222421
The problem however, is that you only get the answer "yes, it matches", and not the start index of the regexp match.

Here is another variant I posted on related question. The REGEX check to see if you are out of bounds is useful, so for a table column you would put it in the where clause.
SET #Array = 'one,two,three,four';
SET #ArrayIndex = 2;
SELECT CASE
WHEN #Array REGEXP CONCAT('((,).*){',#ArrayIndex,'}')
THEN SUBSTRING_INDEX(SUBSTRING_INDEX(#Array,',',#ArrayIndex+1),',',-1)
ELSE NULL
END AS Result;
SUBSTRING_INDEX(string, delim, n) returns the first n
SUBSTRING_INDEX(string, delim, -1) returns the last only
REGEXP '((delim).*){n}' checks if there are n delimiters (i.e. you are in bounds)

Building on #Oleksiy's answer, here is one that can work with strings of variable segment lengths (within reasonable limits), for example comma-separated addresses:
SELECT substring_index ( substring_index ( address,',',1 ), ',', -1) AS address_line_1,
IF(address_parts > 1, substring_index ( substring_index ( address,',',2 ), ',', -1), '') AS address_line_2,
IF(address_parts > 2, substring_index ( substring_index ( address,',',3 ), ',', -1), '') AS address_line_3,
IF(address_parts > 3, substring_index ( substring_index ( address,',',4 ), ',', -1), '') AS address_line_4,
IF(address_parts > 4, substring_index ( substring_index ( address,',',5 ), ',', -1), '') AS address_line_5
FROM (
SELECT address, LENGTH(address) - LENGTH(REPLACE(address, ',', '')) AS address_parts
FROM mytable
) AS addresses

It's working..
SELECT SUBSTRING_INDEX(SUBSTRING_INDEX(SUBSTRING_INDEX(SUBSTRING_INDEX(SUBSTRING_INDEX(SUBSTRING_INDEX(SUBSTRING_INDEX(
SUBSTRING_INDEX(SUBSTRING_INDEX(SUBSTRING_INDEX(col,'1', 1), '2', 1), '3', 1), '4', 1), '5', 1), '6', 1)
, '7', 1), '8', 1), '9', 1), '0', 1) as new_col
FROM table_name group by new_col;